3 An un calibrated mercury in glass thermometer immersed in melting ice. The length of the mercury thread is 25 mm when the thermometer immersed in steam from pure water boiling under a pressure of 1 atmosphere the length of the thread is 200 mm what is the temperature in degree centigrade when the length of the thread is 95mm.​

Answer: its C

Explanation:

Answer:

1) C. 2.5 x 10⁴ Pa

2) C. 75 cm³

Explanation:

Question 1.

Given the following data;

To find the final pressure, P2, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P1V1 = P2V2

Making P2 the subject of formula, we have;

P2 = (P1V1)/V2

Substituting into the formula, we have;

P2 = (1 * 10⁵ * 5)/20

P2 = (500,000)/20

Final pressure, P2 = 25,000 Pa or 2.5 x 10⁴ Pa.

Question 2.

Given the following data;

To find the final volume, we would use Boyle's law;

Mathematically, Boyles law is given by;

PV = K

P1V1 = P2V2

Making V2 the subject of formula, we have;

V2 = (P1V1)/P2

Substituting into the formula, we have;

V2 = (190 * 30)/76

V2 = 5700/76

Final volume, V2 = 75 cm³

Answer:

A is the answer!

Explanation:

Edge 2021

Answer:

A

Explanation:

Edge

Answer:

A) 30h

B) Scalar quantity

Explanation:

Part A

[Note: v represents speed, d represents distance, and t represents time]

Given:

[tex]d = 600 km[/tex]

[tex]v = 20 km/h[/tex]

Required:

[tex]t = ?[/tex]

Analysis:

[tex]v = \frac{d}{t} \\t = \frac{d}{v}[/tex]

Solution:

[tex]t = \frac{d}{v} \\t = \frac{600 km}{20 km/h} \\t = 30 h[/tex]

Statement:

Therefore, the ship was sailing for 30 hours.

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Part B

This is a scalar quantity because time only has magnitude and can never be given direction so it can never be a vector quantity.

For saving lives  the most important safety feature on a car is B. Safety Belt

Safety features of  a car is a feature of a product designed to ensure or increase safety.

Air bag and Anti-lock brakes are the supplemental protection and designed to work best with combination with seat bells.

Air bag reduce the chance that upper body or head will strike the vehicle's interior during a crash alongside with belt that will  also hold your upper body

so, the primary safety feature is seat belt and Air bag and Anti-lock brakes  comes in secondary safety feature  as they increases the safety and risk of getting an injury during any accident

correct answer is B. Safety Belt

learn more about Safety features

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Explanation:

TEMPLE HINDUS MOSQUE MUSLIMS TEMPLE HINDUS MOSQUE MUSLIMS

C. Your feet push down on the ground, and the ground pushes up on your feet.

When Your feet push down on the ground, and the ground pushes up on your feet. This is the correct example of action and reaction pair. The correct option is C.

Newton's third law of motion states that " for every action, there is an equal and opposite reaction".

This means that if object "1" exerts a force on object "2", then object "2" will exert an equal and opposite force on object "1".

In mathematical terms, the third law can be expressed as:

F₁₂ = - F₂₁

Where

F₁₂ = the force exerted by object "1" on object "2",

F₂₁ =the force exerted by object "2" on object "1".

The negative sign indicates that the two forces are equal in magnitude but opposite in direction.

This law applies to all objects in the universe, and it is essential for understanding how objects interact with each other. It explains how a rocket is propelled into space, how a person can walk on the ground, and how a bird can fly through the air.

For example: when a person walks on the ground, their foot exerts a force on the ground. According to Newton's third law, the ground will then exert an equal and opposite force on the foot, pushing the person forward. This allows the person to walk and move forward.

Similarly, when a bird flies through the air, the bird's wings exert a force on the air, and the air exerts an equal and opposite force on the bird, lifting it up and allowing it to fly.

Here in the question,

When you push down on the ground with your feet, the ground pushes up on your feet with an equal and opposite force. This pair of forces are equal in magnitude and opposite in direction, satisfying the conditions of Newton's third law of motion.

Whereas,

Option A describes two separate forces acting on you, but these are not action-reaction pairs because they are not equal in magnitude and opposite in direction.

Options B and D both describe forces acting in opposite directions, but they are not action-reaction pairs because they do not involve two objects interacting with each other.

Therefore, in option C Your feet push down on the ground, and the ground pushes up on your feet, which is the correct option.

To learn more about Newton's law of motion  click:

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Answer:

The answer should be: 1.20 A

Explanation:

Answer:

Explained below

Explanation:

Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.

Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.

Answer:

C. 14.93 m

Explanation:

The given frequency of the wave, f = 100 Hz

The given equation for the wave speed, v, is presented as follows;

v = f × λ

The speed of sound in water, v = 1,493 m/s

Therefore, we get;

The wavelength, λ = v/f

∴ λ = 1,493 m/s/(100 Hz) = 14.93 m

The wavelength, λ = 14.93 m.

Answer:

focal length :

[tex]{ \tt{f = \frac{r}{2} }} \\ focal \: length = \frac{36}{2} = 18 \: cm[/tex]

From linear magnification:

[tex]{ \tt{ \frac{1}{m} + 1 = \frac{u}{f} }} \\ \frac{1}{9} + 1 = \frac{u}{18} \\ \\ u = \frac{18 \times 10}{9} \\ u = 20 \: cm[/tex]

The object must be at 20 cm

Answer:

3. Step 1; An action potential depolarizes the axon terminal at the presynaptic membrane

2. Step 2; Calcium ions enter the axon terminal

4. Step 3; Acetylcholine is released from storage vesicles by exocytosis

5. Step 4; Acetylcholine binds to receptors on the postsynaptic membrane

1. Step 5; Chemically gated ion channels on the postsynaptic membrane are opened

Explanation:

3. The cholinergic synapse starts at the point of arrival of an electrochemical impulse or action potentials at the synaptic knob of the axon terminal of a presynaptic neuron membrane

2. The arrival of the action potential at the axon terminal causes the calcium ion Ca²⁺ channels to open and Ca²⁺ enters into the synaptic knob, resulting in the fusion of the presynaptic membrane and synaptic vesicles

4. The fusion enables the release into the synaptic cleft of many acetylcholine (ACh) transmitter molecules by exocytosis

5. Some of the ACh are transported across the synaptic cleft and bind to postsynaptic neuron membrane embedded ACh receptors

1. The binding of the ACh neurotransmitter molecules to receptors on the membrane of the dendrites of a neuron it leads to the opening of ion channels

Answer:

the work done by the two students is 28,875 J

Explanation:

Given;

applied force, f = 825 N

distance through which the car is pushed, d = 35 m

The work done by the two students who pushed the 825 N across 35 m lot is calculated as follows;

Work done = force x distance

Work done = 825 N x 35 m

Work done = 28,875 Nm = 28,875 J

Therefore, the work done by the two students is 28,875 J

Answer:

I) 6.4 × 10^(6) m

II) 5.29 × 10^(-11) m

Explanation:

Standard form is how we write very large number in such a way that it is easier to read.

Thus;

I) radius of the earth = 6 400 000 m

What we will now have is;

6.4 × 10^(6) m

II) radius of hydrogen atom = 0.000 000 000 0529 m

What we will have is;

5.29 × 10^(-11) m

Answer:

i. 6.4 × 10⁶ m.

ii. 5.29 × 10⁻¹¹ m.

Explanation:

To express a number in standard form, we write it in the form a × 10ⁿ where 1 ≤ a < 10 and n is an integer.

(i) radius of the earth= 6 400 000 m

To express the radius of the earth = 6 400 000 m in standard form, we count the number of decimal places after the first digit. We have 6 decimal places after digit 6. So, we put a decimal point between digit 6 and 4. So, we have 6.4. Since we have 6 decimal places after the six digit, the exponent of our base which is 10 is 6.

So, writing 6 400 000 in the form in a × 10ⁿ, we have a = 6.4 and n = 6. So, in standard form we have 6.4 × 10⁶ m.

So, 6 400 000 =  6.4 × 10⁶ m in standard form.

(ii) radius of hydrogen atom = 0.000 000 000 0529 m

To express the radius of hydrogen atom = 0.000 000 000 0529 m in standard form, we count the number of decimal places after the decimal point including the first non-zero digit. We have 11 decimal places after the decimal point up to and including the first non-zero digit which is digit 5. So, we put a decimal point after the first non-zero digit,5. So, we have 5.29. Since we have 11 decimal places after the decimal point, the exponent of our base which is 10 is -11. The exponent is negative since the digit places are taken after the decimal point.

So, writing 0.000 000 000 0529 m in the form in a × 10ⁿ, we have a = 5.29 and n = -11. So, in standard form we have 5.29 × 10⁻¹¹ m.

So,  0.000 000 000 0529 m = 5.29 × 10⁻¹¹ m in standard form.

Answer: Given: h₀=5cm

p=30cm

hi

f=45cm

require: q=?

hi=?

formulas:

1/f=1/p+1/q

hi/h₀=q/p

calculations:1/q=1/f-1/p

1/q=1/45-1/30

1/q=0.022=0.033

1/q=  =    -0.011

q=1/-0.011

q=   -90.91cm

hi=p × h₀/q

hi=30ₓ5/-90.91

hi=150/-90.91

hi= -1.65cm

image is virtual , erect and diminished

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Answer:

mass is 56.25 N

Explanation:

F=ma

325=4m

m=325/4

Answer:

[tex]V_1 = {2 \: m}^{3} [/tex]

[tex]T_1 = 303 \: k[/tex]

[tex]V_2 = 2(V_1) = 2(2) = 4 \: {m}^{3} [/tex]

[tex]T_2 = ?[/tex]

Here, it's mentioned that the pressure is constant.

[tex]\implies V \propto T \\ [/tex]

[tex]\implies \dfrac{V_1}{V_2} = \dfrac{T_1}{T_2} \\ [/tex]

[tex]\implies \dfrac{2}{4} = \dfrac{303}{T_2} [/tex]

[tex]\implies \dfrac{T_2}{4} = \dfrac{303}{2} [/tex]

[tex]\implies T_2 = \dfrac{303 \times 4}{2} [/tex]

[tex]\implies T_2 = \dfrac{1212}{2} [/tex]

[tex]\implies T_2 = 606 \: k [/tex]

[tex]Option \: (b)[/tex]

Explanation:

Second STATEMENT SAYS REGARDING TO THE CHEMICAL poison

Answer:

Evaluate the solution.

Explanation:

A technological design is designed as the design and study of a solution that can be provided from the solution by identifying the root cause or problem and trying to solve by various means.

A good technological design requires the minimum effort and resources while meeting the requirement of the problem.

The steps involved in the technological design are :

1. search and identify the problem or need.

2. design a solution

3. Implement a solution.

4. Evaluate the solution.

Therefore, the final step or the fourth step in the process of a technological design is " evaluating or communicating the final design solution".

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

[tex]\sf{\qquad{\qquad{\underline{\underline{ Projectile~motion }}}}}[/tex]

If an object is given an initial velocity in any direction and then allowed to travel freely under gravity only, it is called a projectile motion.

It is basically 3 types

The path followed by a projectile is called its trajectory.

Projectile motion is when an object moves in a bilaterally symmetrical, parabolic path.

The path that the object follows is called its trajectory.

Projectile motion only occurs when there is one force applied at the beginning, after which the only influence on the trajectory is that of gravity

By the work-energy theorem, the total work done on the mass as it swings is

W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J

No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.

If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.

Now, if w is the amount of work done by friction/air resistance, then

(176.4 N) h - w = 153 J

If you know the starting height h, then you can solve for w.

Answer:

55

Explanation:95-40=55

i hope i did the math right if i didnt please tell me

Answer:

a)  [tex]F_{net}=0[/tex]

b)  [tex]T=0[/tex]

Explanation:

From the question we are told that:

Dimensions:

[tex]L*B=22.0*35.0cm[/tex]

Current [tex]I=1.40A[/tex]

Magnetic field [tex]B=1.40[/tex]

Therefore

[tex]Area=L*B[/tex]

[tex]A=22.0*35.0cm[/tex]

[tex]A=770cm=>770*0^{-4}[/tex]

a)

Generally Force on Looping gives

[tex]F_1-F_2[/tex]

[tex]F_3=F_4[/tex]

Therefore

[tex]F_{net}=0[/tex]

b)

Generally the equation for Torque is mathematically given by

[tex]T=i*Asin \theta[/tex]

Since A and B are on opposite direction

[tex]\theta=180[/tex]

Therefore

[tex]T=1.40*770*10^{-4}sin 180[/tex]

[tex]T=0[/tex]

Answer:

B

Explanation:

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Answer:

39%.

Explanation:

Spain produces electricity from wind energy was 18%, from hydropower is 14%, 5% from solar energy, and 2% from other renewable sources in the year 2016. About 39% of energy comes from renewable resources while on the other hand, 61% of energy comes from non-renewable resources such as petroleum. Spain has the capability to fulfill all its energy needs from renewable resources.

Answer:

5.66 m

Explanation:

From online sources, the speed in item 3 being referred to was discovered to be 7.62 m/s

Now, let's get the time of flight from one of Newton's equation of motion;

S = ut + ½gt²

Considering the vertical component, we have u = 0 m/s.

Thus;.

S = ½gt²

Plugging in the relevant values;

2.7 = ½ × 9.8 × t²

t² = 2.7/4.9

t = √(2.7/4.9)

t = 0.7423 s

Now, when we consider the horizontal component of the motion, we have;

S = vt

Where;

S is the distance the fish will travel horizontally before hitting the water.

v = 7.62 m/s

t = 0.7423

Thus

s = 7.62 × 0.7423

s ≈ 5.66 m

Answer:

a. i. 35.96 μC  b. i. 11.98 μC ii. 24.04 μC

Explanation:

We need to find the total capacitance of the system C.

The total capacitance of the parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is C' = 1.47 μF + 2.95 μF = 4.42 μF.

C' = 4.42 μF is in series with the 4.89 μF capacitor and for a series combination of capacitors, we have the total capacitance, C from

1/C = 1/4.42 μF + 1/4.89 μF

1/C = (4.42 μF + 4.89 μF)/(4.42 μF × 4.89 μF)

1/C = 9.31 μF/21.6138 μF²

C = 21.6138/9.31 μF

C = 2.32 μF

So, the total charge in the circuit Q = CV where C = total capacitance = 2.32 μF and v = voltage = 15.5 V

So, Q = CV

Q = 2.32 μF × 15.5 V

Q = 35.96 μC

i. The charge on the 4.89 μF capacitor

Since the 4.89 μF is in series with C', the total charge flowing i the circuit is the total charge in the 4.89 μF capacitor. So, its charge Q = 35.96 μC

b. The charge in the 1.47 μF and 2.95 μF capacitors.

To find the charge in the 4.89 μF and 2.95 μF capacitors, we need to find the voltage across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor. The voltage, V' across the 4.89 μF capacitor, since Q = CV', V' = Q/C = 35.96 μC/4.89 μF = 7.35 V

So, the voltage V" across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor, C' is V" = 15.5 V - V' (since V' + V" = 15.5 V).

So, V" = 15.5 V - V'

V" = 15.5 V - 7.35 V

V" = 8.15 V

i. The charge on the 1.47 μF capacitor

Using Q' = CV" where Q' = charge across capacitor, C = 1.47 μF and V" = 8.15 V.

So, Q' = CV"

Q' = 1.47 μF × 8.15 V

Q' = 11.98 μC

ii. The charge on the 2.95 μF capacitor

Using Q" = CV" where Q' = charge across capacitor, C = 2.95 μF and V" = 8.15 V.

So, Q" = CV"

Q" = 2.95 μF × 8.15 V

Q" = 24.04 μC