3. Amelia is at the mall buying more
school clothes. She purchases one pair
of jeans for $32.00 and 2 tops for
$23.99 each. If sales tax is $5.80, what
was the final cost of her clothes

What is the answer?

Answer:

1/2

please mark me brainliest

Find the percentage of the people who like Chocolate = chocolate/ total x 100

Percentage = 125/300 = 0.41666 x 100 = 41.6667 = 41.67 ( round as needed)

A full circle is 360 degrees.

The central angle = percentage of chocolate x 360:

0.416666 x 360 = 150

The central angle for chocolate is 150 degrees

Answer:

is 5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

So first when dividing fractions you need to invert and multiply. Thus the fraction becomes:

1/4 * 20/1.

When simplified it becomes 20/4 which is 5.

HOPE THIS HELPED

Answer:

Step-by-step explanation:

40905

40509

50095

40059

Is greatest to least. You want it to go the other way around.

40059

40095

40509

40905

The smallest number is determined by the number on the right. Then your keep going left to get to the largest. The answer is the second one down.

Answer:

Step-by-step explanation:

( C ). 112°

Answer:

2°C

Step-by-step explanation:

outdoor temperature

Answer:

There is no Image

So Instead

There should be the lowest extreme aka 0, and hights extreme (Whatever number is last) Then you've got average (The Middle) and n the middle of it is the median.

Answer:

.75

Step-by-step explanation:

8 red marbles, 3 blue marbles, and 1 green marble = 12 marbles

P( not blue) = marbles that are not blue / total

                     =(8red+1 green) / 12

                     =9/12

                      = 3/4

                       .75

Answer:

t = d/r; t = 5

Step-by-step explanation:

Hi there!

1) Isolate t

d = rt

Divide both sides by r

d/r = rt/r

d/r = t

t = d/r

2) Solve for t when distance is 40 and the rate is 8

t = d/r

Replace d with 40 and rate with 8

t = 40/8

t = 5

I hope this helps!

Answer:

104

Step-by-step explanation:

The measure of angle 4 for the given parallel lines and angle is equal to 26°.

In the figure the parallel lines and the transversal forms angle 1 , angle 2 , and angle 4.

As per the diagram,

Angle 1 is vertically opposite angle to angle 2.

This implies,

Measure of angle 1 = Measure of angle 2.

Here, Measure of angle 1 =  26 degrees.

⇒ Measure of angle 2 = 26 degrees ( vertically opposite angles)

Now , Angle 2 and angle 4 are corresponding angles.

⇒measure of angle 2 = measure of angle 4

⇒ Measure of angle 4 = 26 degrees.

Therefore, the measure of angle 4 is equal to 26°.

Learn more about measure here

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Answer:

$680

Step-by-step explanation:

original price=$800

discount = 15%

discount in dollars= $800 *15%

discount=$120

cost=$800-$120

cost=$680

Answer:

X=2

Step-by-step explanation:

8-x=6

there the answer is 2

Answer: give me brainliest

Step-by-step explanation:

ax+by=a-b

ax=a-b-by

x=a-b-by/a←

bx-ay=a+b

substituting

b(a-b-by/a)-ay=a+b

ab-b²-b²y/a-ay=a+b

ab-b²-b²y-a²y/a=a+b

ab-b²-(b²+a²)y=a²+ab

-(b²+a²)y=a²+ab-ab+b²

(b²+a²)y=-(a²+b²)

y=-(a²+b²)/a²+b²

y=-1←

substituting value of y

x=a-b-b(-1)/a

x=a-b+b/a

x=a/a

x=1

9514 1404 393

Answer:

 B.  25 people

Step-by-step explanation:

The remainders tell you the number will be 1 more than some multiple of the least common multiple (LCM) of 2, 3, and 4. The LCM is 3·4 = 12, so we want some multiple (n) of that such that 12n+1 is a multiple of 5. We know this is the case for n=2.

The least number of people who could be in the club is 2·12+1 = 25.

Answer:

-9x+20

Step-by-step explanation:

Answer:

1/3÷5

=1/3×1/5

=1/15

each child receive 1/15 of cake

Answer:

7

Step-by-step explanation:

no need to panic !

it is actually totally easy.

we have the complete, big angle at U (imagine you turn VU around U into UT) = 178 degrees.

VT is almost a straight line (then that angle would be 180 degrees). but only almost ...

anyway, the other 2 angles are just parts of the big angle, and we see that together they sum up to the big angle, as there is no other space for a part of the big angle left.

so

(14x - 11) + (12x + 7) = 178

14x - 11 + 12x + 7 = 178

26x - 4 = 178

26x = 182

x = 7

Answer:

x = 3

Step-by-step explanation:

Given

[tex]2^{3x+1}[/tex] = [tex]2^{10}[/tex]

Since bases on both sides are equal, both 2, then equate the exponents

3x + 1 = 10 ( subtract 1 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Answer:

Your answer is K= 60

I hope it's helps you

Answer:

3

Step-by-step explanation:

This is a classic puzzle!  If you pick out three socks, and they have only 2 colors, you'll get at least one match because they can't be 3 different colors.

Answer:

15/22

Step-by-step explanation:

3/11 ÷ 2/5

3/11 x 5/2

3/11 x 5/2 = 15/22

3/11 divided by 2/5 is equal to 15/22.

Here, we have,

To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction.

The reciprocal of a fraction is obtained by flipping the numerator and denominator.

Let's calculate 3/11 divided by 2/5:

(3/11) ÷ (2/5)

To divide, we multiply by the reciprocal:

(3/11) * (5/2)

Now, multiply the numerators together and the denominators together:

(3 * 5) / (11 * 2) = 15/22

Therefore, 3/11 divided by 2/5 is equal to 15/22.

To learn more on division click:

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Answer:

A

Step-by-step explanation:

in step 1, when expanding the bracket, ken needed to do 2×5y AS WELL as 2×-1 which they didn't do. the correct answer after the first step should be 10y-2=18

Step-by-step explanation:

1) -4

2) -8, -6, -4, -3, 0, 3, 5

3) (a) -8 + 5 - 3 - 2

-13 + 5

-8

(b) -7 - 9 + 4 + 3

-7 - 9 + 7

-9

Answer:

47.06 United States Dollar

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

It looks like the limit you want to compute is

[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]

Rewrite the limand with an exponential and logarithm:

[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Now, since the exponential function is continuous at 0, we can write

[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Let M denote the remaining limit.

We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:

[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]

Simplify and rewrite this in terms of sin and cos :

[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]

As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]

This again yields 0/0. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]

Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with

[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]

Then the original limit is

[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]

Answer:

Step-by-step explanation:

First off, your polynomial should be a third degree, not a second degree. That's probably why you didn't get someone to answer this for you already.

If x + 2k is a factor of that polynomial, then by the Zero Product Property

x + 2k = 0 and x = -2k. That means that, by the factor theorem, f(-2k) = 0 (which means that if you plug -2k in for all the x's you get a zero). Therefore,

[tex]3(-2k)^3+6k(-2k)^2-14(-2k)-3=0\\-24k+24k+28k-3=0\\28k-3=0\\28k=3\\k=\frac{3}{28}[/tex]

Answer:

the answer is in picture