3. A force of 70N is applied to a 10kg box with a friction force of 30N opposing it's motion. The box starts
from rest and reaches a speed of 5m/s. Determine the distance over which the force acts on the box.

Answers

Answer 1

The distance over which the force acts on the box, given that 70 N is applied to the 10 Kg box is 3.125 m

How do I determine the distance ?

We'll begin by obtaining the acceleration of the box. Details below:

Force applied = 70 NForce of friction = 30 NNet force = Force applied - Force of friction = 70 - 30 = 40 N Mass of box = 10 KgAcceleration (a) =?

Net force = mass × acceleration

40 = 10 × acceleration

Divide both sides by 10

Acceleration = 40 / 10

Acceleration = 4 m/s²

Finally, we shall determine the distance. Details below

Initial velocity (u) = 0 m/sFinal velocity (v) = 5 m/s Acceleration(a) = 4 m/s²Distance (s) =?

v² = u² + 2as

5² = 0² + (2 × 4 × s)

25 = 0 + 8s

25 = 8s

Divide both side by 8

s = 25 / 8

s = 3.125 m

Thus, we can conclude that the distance covered is 3.125 m

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Related Questions

how long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot?

Answers

4.71 s long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot.

What is the center of the gravity?

The average position of an object's weight is known as its center of gravity. Any object's travel through space may be entirely explained in terms of how its gravitational center moves from one location to another and, if it is free to spin, how it rotates around that center of gravity. Calculations combining gravitation and dynamics may be made much simpler by treating an object's mass as though it were concentrated at a single location.

Briefing:

T=2π√(l/g)

T=2π√(5.53/9.81)

T=4.71

T =4.71 s

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based on its surface temperature of 6,000 k, most photons that leave the sun's surface lie in which region of the electromagnetic spectrum?

Answers

Most photons that leave the sun's surface have a surface temperature of 6,000 K, which corresponds to the visible light region of the electromagnetic spectrum.

The electromagnetic spectrum is a continuous range of wavelengths and frequencies that includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The wavelengths and frequencies of these different types of electromagnetic radiation are all different and correspond to different regions of the spectrum.

The visible light region of the electromagnetic spectrum is the portion of the spectrum that can be seen by the human eye. It ranges from about 400 nanometers (nm) to about 700 nm in wavelength, and corresponds to frequencies of about 7.5 x 10^14 Hz to about 4.3 x 10^14 Hz. Photons with wavelengths and frequencies in this range have enough energy to excite the photoreceptors in the human eye, allowing us to see them.

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consider the harmonic oscillator with dynamics written as with parameters . if the initial position and velocity of the oscillator are given by , what is the position of the oscillator at seconds?

Answers

The position of the oscillator at seconds is  ( A cos ( ω t + ϕ ) where A is the amplitude and ϕ is the initial phase and   f = 1/T = ω/2π.

What is the mean position in oscillation?

Equilibrium or Mean Position: It is a state in which the body is in when there is no net force pushing against it. When a particle is oscillating, it is in its phase This is a representation of the particle's vibrational state at a particular instant.

Is the oscillation period measured in seconds?

The period of an oscillating system is the length of time it takes for a cycle to be completed. A system's period is a time measurement, and in physics, it's typically represented by the capital letter T. Although seconds are the most common, period is measured in time units relevant to that system.

What is the equation for an oscillating period?

Time, or T, is the oscillation's period, hence ωT = 2π or T = 2π/ω. The formula  f = 1/T = ω/2π. gives the reciprocal of the period, or the frequency f, in oscillations per second.

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Three point charges are arranged in a straight line. The point charges are q1 = 10.0 μC, q2 = –40.0 μC, and q3 = –30.0 μC. Charge q1 is 10.0 cm from charge q2, and charge q3 is 20.0 cm from charge q2. Determine the magnitude of the net electric force on charge q1.

Answers

Let us find first the forces at 1, 2 & 3 points.

We know that ke= 8.99 * 109N.m2 / C2

The forces are: -

F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2

F1 = 359.6 N

F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2

F2 = 29.96 N

F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2

F3 = 269.7 N

Now,

The net force on q1 is F1 – F2,

i.e. F1 + F2 = 359.6 + 29.96

F(q1) = 389.56 N to the left

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A car travels down a road at a certain velocity, vcar. The driver slows down so that the car is traveling only a third as fast as before. Which of the following is the correct expression for the resulting velocity?

a. 2vcar
b. 1/3vcar
c. -1/2vcar
d. -2vcar

Answers

The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.

What is velocity?

The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.

A car travels down a road at a certain velocity, is Vcar.

Let the initial velocity of the car travel downward be -V car

It is also, given, that the driver slows down so that the car is traveling only half as fast as before.

Resulting velocity = -1/2 vcar

Therefore, the correct option is c. -1/2vcar.

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which sentence correctly describes when the triple-alpha process occurs in the life cycle of an average-mass star

Answers

Three helium-4 nuclei (alpha particles) are turned into carbon by a series of nuclear fusion processes known as the triple-alpha process.

What results from the triple-alpha procedure as the finished product?

The triple-alpha process and the alpha process are two classes of nuclear fusion reactions that stars use to change helium into heavier elements. The alpha process is also referred to as the alpha ladder. [1] Only helium is used in the triple-alpha process, which also yields carbon.

Which statement concerning alpha particles in an atom is accurate?

Two protons and two neutrons make up alpha particles, which are identical to helium nuclei and have a positive charge.

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a 7.00-kg mass is hung from the bottom end of a vertical spring fastened to an overhead beam. the object is set into vertical oscillations having a period of 2.60 seconds. what is the force constant of the spring?

Answers

The force constant of the spring is 42.1 m.

What is force?

Force is a physical quantity that is related to the interaction between two objects. It is a vector quantity, meaning it has both magnitude and direction. Force can be thought of as a push or a pull between two objects. When one object exerts force on another object, the second object experiences an equal and opposite reaction force. Some of the most common examples of force include friction, gravity, electric fields, and magnetism. Force is a key concept in physics, as it is often used to explain the motion of objects and the behavior of physical systems.

The force constant, or spring constant, of the spring can be calculated using the equation:

k = (4π^2m)/T^2. In this equation, m is the mass of the object and T is the period of oscillation.

Therefore, the force constant of the spring is

k = (4π^2*7.00kg)/(2.60s)^2 = 42.1 N/m.

This means that if a 1 N force is applied to the spring, it will stretch by 42.1 m.

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sir lancelot, who weighs 800 n, is assaulting a castle by climbing a uniform ladder that is 5.0 m long and weighs 180 n. the bottom of the ladder rests on a ledge and leans across the moat in equilibrium against a frictionless, vertical castle wall. the ladder makes an angle of 53.1 deg with the horizontal. lancelot pauses one third of the way up the ladder. (a) find the normal force and friction forces on the base of the ladder. (b) find the minimum coefficient of static friction needed to prevent slipping at the base. (c) find the magnitude and direction of the contact force on the base of the ladder. (that is, the vector sum of the forces at the base.)

Answers

(a) The normal force is 267.7 N and frictional force is 980 N.

(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.

(c) The direction of the contact force is 1016 N.

∈(t) = 0

N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )

N₂ = 267.7 N

(a) Normal force F(d) = N₂ = 267.7 N

Frictional force N = 800 + 180

                         N = 980 N

(b) The minimum coefficient of static friction,

F(d) = μ N₁

μ = F / N₁

μ = 267.7 / 980

μ = 0.27

(c) The direction of the contact force,

R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]

R = 1016 N

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you work at a garden store for the summer. you lift a bag of fertilizer with a force of 131 n, and it moves upward with an acceleration of 0.790 m/s2. (a) what is the mass (in kg) of the fertilizer bag?

Answers

Mass of the fertilizer bag is 165.82 kg

Briefing:

According to Newton's law,

F = m*a

So, m= F/a

m= 131/0.790

m= 165.82 kg

What is mass?

Mass is the measure of matter of a body.

What is Newton's laws?

Newton has stated three laws of motion. The first law states that every object will remain at rest or in uniform motion in a straight line unless an external force compels it to change its state of action .

The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

The third law states that every action has an equal and opposite reaction.

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what is the current through the heating element of an electric toaster oven if the heater has a resistance of 5 ohms and it is connected to 120 volts?

Answers

Answer:

24 A

Explanation:

Ohm's Law:  V = IR, so I = V/R

I = 120V/5Ω = 24 A

light is projected onto a semi-conductive surface. however, no electrons are ejected. if the intensity is held constant but the frequency of light is increased, what will happen?

Answers

When the intensity of light is constant, but its frequency is increased, then the number of photons emitted will also increase.

The electrons are emitted from a conductive material when light of sufficient frequency strikes it and causes vibration of electron holes pairs present inside the material. This conductive motion causes the electricity to be generated. There is a minimum frequency which must be reached so that electrons are emitted from the surface. This frequency is called as threshold frequency. Photons are energy packets. The formula which relates energy with frequency is given as:

E = hv,

where, E = energy of photon

h = Planck's constant

v = frequency

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boat moves north at a velocity of 2.5 m/s while the current moves downstream at 6.0 m/s east. What is the resultant velocity of the boat, relative to an observer on the shore?

A) 4.5 m/s, NE
B ) 4.5 m/s, SE
C ) 6.5 m/s, NE
D ) 6.5 m/s, SE
E) 8.5 m/s, NE

Answers

Relative to the observer in on the shore, the velocity of the boat is 6.5 m/s, NE.

What is relative velocity?

The velocity of an object in relation to another observer is known as its relative velocity.

We cay say that the relative velocity is equal to the vector difference between the velocities of two objects. The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.

The diagram below shows the calculation where AC is relative speed, AB is speed of the boat and BC is the speed of stream.

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a vertical spring has a spring constant of 100 n/m. when an object is attached to the bottom of the spring, the spring changes from its unstretched length of 0.50 to a length of 0.65 m. the magnitude of the weight of the object is

Answers

Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N

what is the kinetic energy of a 60.0 g tennis ball traveling at 177.0 kilometers per hour? report your answer in joules (j).

Answers

The kinetic energy is 939.87 J.

what is kinetic energy?

Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. The object will be moving at a new, constant speed once the work is done because energy has been transferred to it.

A particle, an object, or a collection of particles can move because of kinetic energy, which is the force that drives motion. Kinetic energy is used by objects in motion like a person walking, a baseball being thrown, food falling from a table, and charged particles in an electric field.

Kinetic energy = 1/2mv²

Kinetic energy =  1/2×0.06×177²

Kinetic energy = 939.87 J.

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9. A piece of iron with a mass of 9.8 g has an initial temperature of 32.6°C. As it is heated, it absorbs 365J of energy. What is the final temperature of the iron? (The specific heat of iron is .46 J/g °C)

Answers

The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.

What is Specific heat capacity?

The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).

The specific heat capacity of a material can be calculated by the formula:

Q = m × c × ΔT

where, Q = heat energy,

m = mass of the material,

c = specific heat capacity,

ΔT = change in temperature

The final temperature of the piece of iron can be calculated by the formula:

Q = m × c × ΔT

ΔT = (Final temperature - initial temperature)

365J = 9.8 × 0.46 × ΔT

365J = 4.508 × ΔT

ΔT = 80.96

ΔT = Final temperature = initial temperature

ΔT = (T - 32.6)

80.96 = (T - 32.6)

T = 80.96 + 32.6

T = 113.56°C

Therefore, the final temperature of the piece of iron is 113.56°C.

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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?

Answers

The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.

To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.

Now, we know that momentum =mass × velocity

So, initial momentum of first object=6.2×3=18.6Kg-m/sec

Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec

Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg

Now, both objects are moving with common velocity, so assume both have velocity v

=>So, final momentum of both objects is =14.2×v

according to law of conservation of momentum

=>18.6+25=14.2v

=>43.6=14.2v

=>v=43.6/14.2

=>v=3.07m/sec

Hence, final velocity of objects are 3.07m/sec.

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Which choice below explains what is happening in a liquid as it turns into a gas?
a. The particles speed up and spread apart
b. The particles speed up and come closer together
c. The particles slow down and spread apart
d. The particles slow down and come closer together

Answers

Answer:

a

Explanation:

As you add thermal energy the particles spread apart and are moving faster ..... a certain volume of water produces a much larger volume of steam as energy is added.....that is how steam engines work !

The adjacent figure shows a solid 'S' of weight 15N connected to a thread and put on an inclined plane. 1) a-Is the weight of solid 'S' a contact force or a force acting from a distance? b- List the characteristics of the weight of solid 'S'. Thread Inclined plane c- Represent the weight of solid 'S' by a vector. Choose a convenient scale. 2) a- Name the other forces acting on solid 'S' and indicate their types. b- Represent each force by a vector without respecting a scale. c- List the characteristics of each of the above forces. (Without the magnitude) 3) The thread is cut and solid 'S' moves as shown in the adjacent figure a- Name the new force that acts on solid 'S' and indicate its type. b- List the characteristics of this force.(scale 1cm-1.3N). Thread Inclined plane Solid 'S' Solid 'S'​

Answers

Answer:

Here is answer

Explanation:

a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.

b) The characteristics of the weight of solid 'S' are:

It acts in the downward direction.

It is a gravitational force that is exerted by the Earth on the solid 'S'.

It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).

c) The weight of solid 'S' can be represented by a vector as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

[/asy]

a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.

b) These forces can be represented by vectors as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));

label("$N$", (7.5sqrt(2),7.5), NE);

draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));

label("$F_f$", (-7.5sqrt(2),-7.5), SW);

[/asy]

c) The characteristics of these forces are:

The normal force acts perpendicular to the surface of the inclined plane.

The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.

The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.

The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.

a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.

b) The characteristics of the gravitational force are:

It acts in the downward direction.

It is a force that is exerted by the Earth on the solid 'S'.

Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):

[asy]

unitsize(1cm);

draw((0,0)--(0,-1.3),Arrow(6));

label("$W$", (0,-0.65), S);

[/asy]

newton's second law in 1 dimension: what magnitude net force is required to accelerate a 1200-kg car uniformly from 0 m/s to 27.0 m/s in 10.0 s?

Answers

The required force is F = 3240 N.

As a result,

1200 kg is the car's mass.

Initial speed of the vehicle, u = 0.

The car's final speed is 27 meters per second.

Thus we have to first calculate the acceleration and then substitutes its value in the force formula

Taking time, t = 10 s

F = m a, where a represents the vehicle's acceleration, is the formula for the required force.

a= v - u / t

thus a = 27 - 0/ 10

a = 27/ 10

F = 1200 X 27 / 10

F = 3240 N.

Therefore, this is the necessary solution.

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a uniform meter stick of mass 24 g with two weights hanging from it is balanced on a knife edge at the 40 cm mark. a weight of mass 96 g hangs from the 9 cm mark. at which cm mark must the other weight of mass 96 g be located to keep the meter stick balanced?

Answers

The second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.

To determine the location of the second weight that will keep the meter stick balanced, we need to consider the principles of equilibrium.

The weight of the meter stick can be calculated as follows:

Weight of meter stick = mass * acceleration due to gravity

= 24 g * 9.8 m/s^2

= 235.2 N

The total weight of the two hanging weights is 96 g + 96 g = 192 g = 1.92 N.

The sum of the forces acting on the meter stick is equal to zero when:

235.2 N + 1.92 N = 0

This equation tells us that the sum of the forces acting on the meter stick is equal to zero when the total weight of the two hanging weights is equal to the weight of the meter stick.

To determine the location of the second weight, we also need to consider the moments about the pivot point. The moment of a force is calculated as the product of the force and the distance from the pivot point. The moments about the pivot point are equal to zero when the sum of the moments of the forces on one side of the pivot point is equal to the sum of the moments of the forces on the other side of the pivot point.

The moment of the weight of the meter stick about the pivot point is calculated as follows:

Moment of the weight of meter stick = force * distance from pivot point

= 235.2 N * 0.4 m

= 94.08 N*m

The moment of the weight hanging from the 9 cm mark about the pivot point is calculated as follows:

Moment of weight hanging from 9 cm mark = force * distance from pivot point

= 1.92 N * 0.09 m

= 0.1728 N*m

To keep the meter stick balanced, the moment of the second weight must be equal in magnitude but opposite in direction to the moment of the weight hanging from the 9 cm mark. The moment of the second weight can be calculated as follows:

Moment of second weight = force * distance from pivot point

= 1.92 N * distance from pivot point

Substituting the value of the force and setting the moment equal to the negative of the moment of the weight hanging from the 9 cm mark, we get the following equation:

1.92 N * distance from pivot point = -0.1728 N*m

Solving for the distance from the pivot point, we find that the second weight must be located at a distance of 0.09 m from the pivot point, or 9 cm. This is the same distance from the pivot point as the weight hanging from the 9 cm mark.

Therefore, the second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.

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which is a major difference between what we've seen in discovered exoplanets and our own solar system?

Answers

The major difference between what we've seen in discovered exoplanets and our own solar system is that extrasolar planet orbits tend to be closer and more eccentric than in our Solar System.

Exoplanet:

Any planet outside of our solar system is an exoplanet. The majority of exoplanets orbit other stars, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic center.

All of the planets in our solar system orbit around the Sun. Planets that orbit around other stars are called exoplanets.

Exoplanets are very hard to see directly with telescopes. They are hidden by the bright glare of the stars they orbit.

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A 100 kg car starts from 20 m/s and speeds up to 41 m/s in 7 seconds. Determine the car's
acceleration.

Answers

Answer: 3 m/s^2

Explanation:

Acceleration equals change in velocity (speed) divided by total time.

a = (v2-v1)/t

a = (41 m/s - 20 m/s) / 7 s

a = 3 m/s^2

Mass is irrelevant in this question.

A 1.5 kg block is on a 15° frictionless incline plane.

a) What is the normal force?

b) What is the downhill force?

c) What is the acceleration?

Answers

Answer:

Below

Explanation:

Normal force will be   mg cos 15° = 1.5*9.81 cos 15°   Newtons

Downplane force will be  mg sin 15° = 1.5 * 9.81  sin 15°    N

Acceleration

F = ma

F/m = a

1.5 ( 9.81) sin 15° / 1.5   m/s^2  = a

40 POINTS HELPP

The Anthropocene is still considered an informal designation because International Union of Geological Sciences (IUGS), the international organization that names and defines epochs, has not officially designated it an epoch. Their criteria for the designation of a new epoch are that there should be evidence of human impacts and change in the rock record.

What activities and impact could humans be responsible for that might be reflected in the rock record and thus determine the beginning of the Anthropocene?

(Minimum of two sentences please)

Answers

Answer:

One example of an activity that could be reflected in the rock record and contribute to the beginning of the Anthropocene is the widespread use of fossil fuels, which has led to an increase in atmospheric carbon dioxide concentrations and a corresponding shift in the Earth's climate. Another potential contributor to the Anthropocene is the proliferation of plastic and other synthetic materials, which are becoming ubiquitous in the geologic record and may persist for thousands of years.

what are the magnitude and location (with respective to point a) of the resultant force on the horizontal gate? the gate width is w. fluid density is r. you can leave your answer in terms of variables (w, r, and g).

Answers

The magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.

What is magnitude?

Magnitude is a measure of the size or intensity of a physical quantity. It is usually defined as the absolute value of the numerical value of the physical quantity, and is often expressed in terms of a unit of measurement. Magnitude can refer to a variety of different physical quantities, such as size, intensity, brightness, or energy. Magnitude can also refer to the relative size or intensity of two or more physical quantities, when compared to each other.

The resultant force on the horizontal gate is equal to the sum of the hydrostatic forces acting on the gate.
Since the gate is horizontal, the hydrostatic forces acting on the gate will be equal to the pressure difference between the top and bottom of the gate.
This pressure difference is equal to the product of the fluid density, gravitational acceleration, and the gate width.
Therefore, the magnitude of the resultant force on the gate will be:
F = w * r * g
The location of the resultant force on the gate will be at the center of the gate, which is point A.
Therefore, the magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.

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a simple pendulum is 4.00 m long. (a) what is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 6.00 m/s2?

Answers

The time period of the small oscillations for the simple pendulum is found to be  3.14 seconds.

The pendulum is located in an elevator that is accelerating upwards with an acceleration of 6m/s² and length of the pendulum is 4m.

Because the elevator is accelerating in the upper direction the net acceleration of the pendulum will be (10 + 6)m/s².

The period of small accelerations for this pendulum will be given by the relation,

T = 2π(l/a)

Where,  l is the length of pendulum and a is the net acceleration.

Putting values,

T = 2π(4/16)

T = 2π(1/2)

T = π seconds.

T = 3.14 seconds.

So, the time period of this small oscillations for this pendulum is 3.14 second.

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Study the following systems: SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radio. SYSTEM B: Electricity is used to power a radio. Which system (A or B) is more energy efficient and explain why.

Answers

The system that is more energy efficient is system A because it makes use of electricity to produce more results.

What is energy efficiency?

Energy efficiency is the use of less energy to perform the same task or produce the same result.

Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.

Energy efficiency has the following benefits:

It saves moneyIt increases the resilience and reliability of the electric gridIt provides environmental, community, and health benefits

According to this question, the following applies:

SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radioSYSTEM B: Electricity is used to power a radio

Based on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.

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1.
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What is the net force exerted on a 150.0kg race-car driver while the race car is accelerating from 0 to 58.7m/s i
3.50s?

Answers

Answer:

2515.7N

Explanation:

First step is to find the acceleration:

U = 0 and V =58.7 m/s

a = (V-U)/t

where, t = 3.5s

a = 58.7/3.5

so, in order to find the net force,

F= ma

= 150kg × 58.7/3.5

= 2515.7 N

A student wants to make a simple model of the solar system to help him compare how long it would take for a spaceship to travel between different planets.

Which of the following things is essential for him to do in order to think about how long it would take?

this are the opions
He must make sure that the model of each planet looks like the planet it represents, but he does not need to accurately represent the relative distances between the planets because the most important thing is that models look like the thing they are modeling.


He must accurately represent the relative distances between the planets, but he does not need to make sure that the model of each planet looks like the planet it represents because only the relevant aspects of the thing being modeled need to be modeled accurately.


He must accurately represent the relative distances between the planets and also make sure that the model of each planet looks like the planet it represents, because a model should be as much like the thing being modeled as possible.


He does not need to accurately represent the relative distances between the planets, and he does not need to make sure that the model of each planet looks like the planet it represents, because there are always some differences between a model and the thing being modeled.

Answers

Answer:

To make a simple model of the solar system that can be used to compare the time it would take for a spaceship to travel between different planets, the student must accurately represent the relative distances between the planets. This is because the time it would take for a spaceship to travel between two planets depends on the distance between those planets, so accurately representing the distances between the planets is essential for thinking about how long it would take for a spaceship to travel between them.

It is not necessary for the student to make sure that the model of each planet looks like the planet it represents, although this may help make the model more understandable. The most important thing is that the model accurately represents the relative distances between the planets.

In summary, the student must accurately represent the relative distances between the planets in order to think about how long it would take for a spaceship to travel between different planets in the solar system.

a simple harmonic oscillator takes 11.5 s to undergo five complete vibrations. (a) find the period of its motion. s (b) find the frequency in hertz. hz (c) find the angular frequency in radians per second. rad/s

Answers

The required values are a) T = 2.3 seconds, b)  f = 0.434 Hz, c) ω = 2.7 rd/s.

Which of the following motions is simply harmonic?

Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.

According to question:

Given,

Time = 11.5 seconds to five complete vibrations.

a) Time period is time taken to complete one vibration,

So T = 11.5/5 = 2.3 seconds

b) Frequency(f) = 1/T

f = 1/2.3 = 0.434 second inverse.

c) By using formula of angular frequency ω = 2π/T

ω = 2π/2.3 = 2.7 hz

Thus, final values are a) T = 2.3 seconds, b)  f = 0.434 second inverse, c) ω = 2.7 rd/s.

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