-2x - 4 > 8 how much is this

Answer:

hope it helps, appreciate if you can give brainliests

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

Answer:

770

Step-by-step explanation:

12 month ×60 per month

Plus 50 set up fee

=770

Answer:

$17.25

Step-by-step explanation:

The tip is 15% of $15.00, or 0.15 * 15 = $2.25

We add that to the meal's cost, which is $15.00

15.00 + 2.25 = 17.25

Answer:

After 5 seconds

Step-by-step explanation:

One is given the following expression to model to the flight path of a ball:

[tex]h=-16t^2+80t[/tex]

In this problem, one is asked to find the time at which the ball lands on the ground. The easiest way to do so is to factor the expression. Take out factors that both terms have in common. The one will set the equation equal to zero, as this is the height at which one wants to find the time for. Finally, use the zero product property to solve. The zero product property states that any number times zero equals zero. Apply these ideas to the given function:

[tex]h=-16t^2+80t[/tex]

Factor the expression; both terms have a common factor of (-16t):

[tex]h=-16t^2+80t[/tex]

[tex]h=-16t(t-5)[/tex]

Set the equation equal to zero to solve for when the ball has a height of zero or rather lands on the ground:

[tex]h=-16t(t-5)[/tex]

[tex]0=-16t(t-5)[/tex]

Now use the zero product property, this states that any number times zero equals zero. Set each of the factors equal to zero, and solve to find the value of (t) for which the factor will equal zero:

[tex]0=-16t(t-5)[/tex]

[tex]0=-16t[/tex]                          [tex]t - 5 =0[/tex]

Solve for the value (t) using inverse operations,

[tex]0=-16t[/tex]                            [tex]t - 5 =0[/tex]

(divide by (-16)                   (add (5))

[tex]0=t[/tex]                                     [tex]t=5[/tex]

As one can see, the ball started on the ground, therefore at (0) seconds, its height was (0). Then, after (5) seconds the ball landed on the ground, therefore, after (5) seconds its height was again (0).

Answer:

8

Step-by-step explanation:

6x+5=53

6x=48

6x/6=48/6

x=8

Answer:

The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical

Step-by-step explanation:

The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in opposite side of the axis as if we're seeing it in a mirror.

If we study it more, you will find that its symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

If you're reflecting a point (x,y) along x axis, then its abscissa will stay same but ordinates will negate. Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along y axis, the resultant image of the point will be (-x,y)

Therefore, The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

Learn more about reflection;

https://brainly.com/question/12950057

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Answer:

17/30 (0.56)

Step-by-step explanation:

18/20-4/12

Reduce the fraction with 2 and 4: 9/10-1/3

Write all numerators above the least commmon denominator 30: 27-10/30

Subtract: 27-10/30 = 17/30

Answer:

y = 1/3mx + b

Step-by-step explanation:

x = 3(y - b)/m

~Multiply m to both sides

mx = -3b + 3y

~Add 3b to both sides

mx + 3b = 3y

~Divide everything by 3

1/3mx + b = y

y = 1/3mx + b

Best of Luck!

[tex]\\ \rm\longmapsto x=\dfrac{3(y-b)}{m}[/tex]

[tex]\\ \rm\longmapsto mx=3(y-b)[/tex]

[tex]\\ \rm\longmapsto mx=3y-3b[/tex]

[tex]\\ \rm\longmapsto 3y=mx+3b[/tex]

[tex]\\ \rm\longmapsto y=\dfrac{1}{3}mx+b[/tex]

Answer:

a) 16/25

b)3/2

Step-by-step explanation:

all explaination is in picturw below

Answer:

6  19 /24

Step-by-step explanation:

find the lcd and add

Answer:

10 inches

Step-by-step explanation:

radius = 5 inches

Diameter = radius x 2 = 5 x 2 = 10 inches

Answer:

5(x+4)

Step-by-step explanation:

It's basically asking for the sum of a number and four to be multiplied by 5. Since the sum is made up of the unknown number and four, you'd put four and the unknown number in parenthesis while putting five on the outside, making it 5(x+4).

Answer:

Um srry I am a hack I like this app Haha I hadked this girls brainy hehehe

Answer:

Below.

Step-by-step explanation:

I cant draw you a picture but it will be one right triangle inside the other where the vertical tower will be one leg common to 2 triangles and the base of the 2 triangles will be x and x+10 metres.

Tan 30 = h/ (x + 10)

tan 45 = h/x        where h is the height of the tower.

From the second equation  x = h / tan45

Substituting in the first equation;

tan30 = h / (h/tan45 + 10

Tan 30 = 1/ √3 and tan 45 = 1 so

1/ 1.732 = h/ (h + 10)

0.5774 = h/(h + 10)

h = 0.5774h + 57.74

0.4226 h = 57.74

h = 136.6 m to nearest tenth.

Answer:

semoga jawapan ini dapat membantu

Answer:

Below,...

Step-by-step explanation:

Your equation:

[tex]\frac{63}{7-(2*3)} =\frac{63}{7-6} =\frac{63}{1}=63[/tex]

Hope it helps,... Chow,...!

Answer:

2400

which is not having any remainder as 2400÷60=40

Step-by-step explanation:

Answer:

purple.orang.blue.yellow and green

purple.orang.blue.yellow and green

Answer:

x=-3

Step-by-step explanation:

-4(-2x+5)-5x+5=-24

8x-20-5x+5=-24

3x-15=-24

3x=-9

x=-3

I hope that this helped you!

AB = AD [Given]

BC = CD [Given]

AC = AC [Same line segment]

So, ΔABC ≅ ΔADC [By SSS congruence criteria]

So, ∠ABC = ∠ADC [CPCT (Corresponding parts of congruent triangles)]

Hence, proved.

Answer:

I hope it will help U.

Answer:

15.1 (rounded to the nearest tenth decimal point)

Step-by-step explanation:

The explanation is, this is simple maths, nothing else. Let me know if it helps. Thank you

-8/10,-12/15,-16/20,-20/25,-24/30,etc.

The number sets that apply to -4/5 is the fractions.

Fractions represent the parts of a whole or collection of objects.

A fraction has two parts. The number on the top of the line is called the numerator and the number on the top of the line is called the denominator.

Now the given number is,

-4/5

-4/5 is a fraction. A fraction has two components numerator and denominator. This can positive or negative. Other example of fractions include 1/2,3/2,-5/2,-1/3.

The numbers who are not fractions are 0, 3, 6, 7.7.

Thus, the number sets that apply to -4/5 is the fractions.

To learn more about fractions:

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Answer:

63

Step-by-step explanation:

6x + 3y - 9

x = 6

y = 9

6(6) + 3(9)

36 + 27

= 63

Answer:

[tex]2(a + 1) \times (3a + 5)[/tex]

Step-by-step explanation:

[tex]6(a + 1 {)}^{2} + 4(a + 1)[/tex]

➡️ [tex]2(a + 1) \times (3(a + 1) + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 3 + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 5)[/tex]

Answer:

D) 3

Step-by-step explanation:

There are 3 lines/graphs

I hope this helps!

Answer:

43.4 yd

Step-by-step explanation:

[tex]45^{2}[/tex]-[tex]12^{2}[/tex]

2025-144=1881

[tex]\sqrt{1881}[/tex]

43.37049

43.4

Answer:

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Step-by-step explanation:

1. Approach

One is given the following information:

[tex]cos(2\theta)=-\frac{2}{5}[/tex]

One can rewrite this as:

[tex]cos(2\theta)=-0.4[/tex]

Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.

Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]).  Substitute the given information into the ratio and simplify.

2. Solve for [tex](cos(\theta))[/tex]

Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

[tex]-0.4=2(cos^2(\theta))-1[/tex]

Inverse operations,

[tex]-0.4=2(cos^2(\theta))-1[/tex]

[tex]0.6=2(cos^2(\theta))[/tex]

[tex]0.3=cos^2(\theta)[/tex]

[tex]\sqrt{0.3}=cos(\theta)[/tex]

Since this angle is found in the third quadrant its value is actually:

[tex]cos(\theta)=-\sqrt{0.3}[/tex]

3. Solve for [tex](sin(\theta))[/tex]

Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

[tex]-0.4=1-2(sin^2(\theta))[/tex]

Inverse operations,

[tex]-0.4=1-2(sin^2(\theta))[/tex]

[tex]-1.4=-2(sin^2(\theta))[/tex]

[tex]0.7=sin^2(\theta)[/tex]

[tex]\sqrt{0.7}=sin(\theta)[/tex]

Since this angle is found in the third quadrant, its value is actually:

[tex]sin(\theta)=-\sqrt{0.7}[/tex]

4. Solve for [tex](tan(\theta))[/tex]

One can use the following identity to solve for [tex](tan(\theta))[/tex];

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

Substitute the values on just solved for and simplify,

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

Rationalize the denominator,

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Answer:

i have no idea that's why I need ur help