(2.05 MC) Triangle PQR is transformed to Triangle P'Q'R'. Triangle PQR has vertices P(4,0), Q(0,-4) and R(-8,-4). Triangle P'Q'R' has vertices P'(1,0), Q'(0,-1), and R'(-2,-1). Part A: What is the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' Part B: Write The Coords of triangle P"Q"R" obtained after P'Q'R' is reflected about the y-axis Part C: Are the two Triangles PQR and P"Q"R" congruent?

Answers

Answer 1

Answer:

Part A: The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4

Part B:

P''(-1, 0)

Q''(0, -1)

R''(2, -1)

Part C:

The two Triangles PQR and P''Q''R'' are not congruent

Step-by-step explanation:

The coordinates of triangle PQR are;

P(4, 0)

Q(0, 4)

R(-8, -4)

The coordinates of triangle P'Q'R' are;

P'(1, 0)

Q'(0, -1)

R'(-2, -1)

Part A:

The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' can be found from the ratio of the respective coordinates as follows;

The ratio of the x, and y coordinates of the points are;

P'/P  = x'/x = 1/4, y'/y =0/0

R'/R = x'/x = -2/-8 = 1/4, y'/y =-1/-4 = 1/4

Therefore, the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' = 1/4

Part B: For reflection across the y-axis, we have;

Pre-image (x, y) becomes the image, (-x, y)

Therefore, we have;

Reflection of P'(1, 0) about the y-xis becomes P''(-1, 0)

Reflection of Q'(0, -1) about the y-xis becomes Q''(0, -1)

Reflection of R'(-2, -1) about the y-xis becomes R''(2, -1)

Part C:

The two Triangles PQR and P''Q''R'' are similar but they are not congruent as the dimensions of PQR are larger than the dimensions of the sides of triangle P''Q''R''.

Answer 2

(A) The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R'  is 1/4

(B) Coordinates of Δ P"Q"R"

P" (-1,0)

Q"(0,-1)

R"(2,-1)

(C) Triangles PQR and P"Q"R" are not congruent.

Given

ΔPQR is transformed into ΔP'Q'R'

Coordinates of P, Q, R are

P (4,0),

Q(0,-4)

R(-8,-4)

Coordinates of P'Q'R' are

P'(1,0)

Q'(0,-1)

R'(-2,-1)

(A) By Distance formula we can find the distance between P Q and P'Q'

Distance formula = [tex]D= \sqrt{(X_2-X_1)^2+(Y_2-Y_1)^2 }[/tex]

Where D = Distance between two points [tex](X_1.Y_1) \; and\; (X_2.Y_2)[/tex]

from distance formula we can write that

[tex]PQ = \sqrt{(0-4)^2+ (-4-0)^2} }\\[/tex]

PQ = [tex]4\sqrt{2}[/tex]

Similarly

P'Q'= [tex]\sqrt{2}[/tex]

PQ /P'Q' = 4

hence the scale factor of dilation is 1/4 (Compression)

(B )The Coordinates of Reflection about y axis can be written for a point

[tex](x,y ) \; as \; (-x,y)[/tex]

So the Coordinated of Δ P"Q"R" can be written as

P" (-1,0)

Q"(0,-1)

R"(2,-1)

(C) ΔPQR  and ΔP"Q"R" are similar triangles but they are not  congruent because their sides  are not equal in size.

For more information please refer to the link below

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Related Questions

Solve two-step equations. -5/2 a + 5 = 25

Answers

Answer:

a = -8

Step-by-step explanation:

-5/2 a + 5 = 25

Subtract 5 from each side

-5/2 a + 5-5 = 25-5

-5/2 a = 20

Multiply each side by -2/5

-2/5 *-5/2 a = 20*-2/5

a = -8

Quadrilateral ABCD is inscribed in a circle. m∠A is 64°, m∠B is (6x + 4)°, and m∠C is (9x − 1)°. What is m∠D?

Answers

Answer:

m∠D = 97.34°

Step-by-step explanation:

Concept used"

sum of all angles of Quadrilateral is 360 degrees.

If any Quadrilateral is inscribed in circles then sum of opposite angle of that Quadrilateral is 180 degrees

________________________________________________

Given

Quadrilateral ABCD is inscribed in a circle

thus,

pair of opposite angles will be

m∠A and m∠C

m∠B and m∠D

thus,

m∠B + m∠D = 180

Thus,

m∠A + m∠C = 180

64+  (9x - 1) = 180

9x = 180 - 63 + 1 = 118

x = 118/9 = 13.11

thus, value of

m∠B is (6x + 4)°

m∠B = (6*13.11 + 4)°  = 82.66°

m∠B + m∠D = 180

82.66 + m∠D = 180

m∠D = 180 - 82.66 = 97.34°

Thus,

m∠D is 97.34°

Which statement best explains why the sine of an acute angle is equal to the cosine of the angles complement

Answers

Answer:

Option (B)

Step-by-step explanation:

From the figure attached,

ΔABC is a right triangle.

Cosine and Sine ratios from the given triangle will be,

SinA = [tex]\frac{\text{Opposite side}}{Hypotenuse}[/tex]

        = [tex]\frac{a}{c}[/tex]

CosB = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

         = [tex]\frac{a}{c}[/tex]

Therefore, both the ratios (Sine and Cosine) will be equal as [tex]\frac{a}{c}[/tex]

Option (B) will be the correct option.

What is the 1st mistake...

Answers

Answer:

[tex]\huge\boxed{Step \ 3}[/tex]

Step-by-step explanation:

In Step # 3, We need to divide rather than to subtract. So, the first mistake is done in step 3.

Answer:

[tex]\Large \boxed{\mathrm{Step \ 4}}[/tex]

Step-by-step explanation:

[tex]20 +20 \div 4-2[/tex]

Division should be performed first, not subtraction.

[tex]20+5-2[/tex]

A rectangular box with a square base contains 24 cubic feet. if the height of the box is 18 inches, how many feet are there in each side of the base?

Answers

Answer:

4

Step-by-step explanation:

V = Lwh

the volume (given) = 24 ft^3

the height (given) = 18" = 1.5'

24 = L*w*1.5

divide both sides by 1.5

16 = Lw

You need to find the number of feet in each side of the base

since the box has a square base

L = W

AND, found above, L*w = 16

so 4*4= 16

Answer - 4

If x =2.3,5x.3= DONT MAKE ANSWERS THAT DONT MAKE ANY SENSE OR YOU WILL GET REPORTED

Answers

Answer:

34.5

Step-by-step explanation:

5 times x(2.3) = 11.5.

11.5 times 3 is 34.5

you put 2.3 in place of x because x was the unknown value, but now that we know it is 2.33 we plug it in.

What is the tangent ratio of KJL? (Question and answers provided in picture.)

Answers

Answer:

Option (1)

Step-by-step explanation:

The given triangle JKL is an equilateral triangle.

Therefore, all three sides of this triangle will be equal in measure.

Side JK = JL = KL = 48 units

Perpendicular LM drawn to the base JK bisects the base in two equal parts JM and MK.

By applying tangent rule in ΔJML,

tan(∠KJL) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

                = [tex]\frac{\text{LM}}{\text{JM}}[/tex]

                = [tex]\frac{\text{LM}}{24}[/tex]

Since, Sin(K) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

Sin(60)° = [tex]\frac{\text{LM}}{48}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{\text{LM}}{48}[/tex]

LM = 24√3

Now, tan(∠KJL) = [tex]\frac{\text{LM}}{24}[/tex]

                          = [tex]\frac{24\sqrt{3} }{24}[/tex]

Therefore, Option (1) will be the answer.

In the figure shown, what is the measure of angle x? (5 points) 115 degrees 130 degrees 145 degrees 150 degrees

Answers

Answer:

x=115

Step-by-step explanation:

180 - (115) =65(triangle)

65 + x = 180(on a line)

x=180-65

x = 115

Answer:

115 degrees

Step-by-step explanation:

the person above me is right, but there is an easier way.

Just add 50 and 65 degrees and boom you have your answer.

someone help me really quick

Answers

Answer:

u^18

Step-by-step explanation:

(u^3)^6

=

u^(3*6)

=

u^18

Hope this helps!

The Nguyen family and the Reed family each used their sprinklers last summer. The Nguyen family's sprinkler was used for 15 hours. The Reed family's sprinkler was used for 25 hours. There was a combined total output of 1175L of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour? Nguyenfamily'ssprinkler:Lperhour Reedfamily'ssprinkler:Lperhour

Answers

Answer:

Nguyen family's sprinkler: 20 L per hour Reed family's sprinkler: 35 L per hour

Step-by-step explanation:

Let n and r represent the output in liters per hour of the Nguyen and Reed family sprinklers, respectively. Then we have ...

  15n +25r = 1175 . . . . total sprinkler output

  n + r = 55 . . . . . . . . . sum of two output rates

The second equation tells us we can substitute n = 55 -r into the first equation:

  15(55 -r) +25r = 1175

  10r = 1175 -825 . . . . . . subtract 825

  r = 350/10 = 35 . . . . . . divide by 10

  n - 55 -35 = 20 . . . . . . find n from r

Nguyen family's sprinkler: 20 L per hour

Reed family's sprinkler: 35 L per hour

Hunter is copying an angle. His work so far follows. Explain the importance of his next step, which is drawing a line through A and Y using a straightedge.

This is to check to make sure that A is in the right place, since it was drawn using the arcs.

Using a straightedge ensures that there is a line passes through A and Y.

Because a line was drawn through point L, a similar line should be drawn through the corresponding point on ∠AYZ.

This is the other ray that will make up the angle ∠AYZ and will complete the construction.

Answers

Answer:

  This is the other ray that will make up the angle ∠AYZ and will complete the construction.

Step-by-step explanation:

The point of the construction is to copy the angle. That is, the end result must be an angle with identical measure to the original. The construction so far has no angle at Y. Drawing ray YA will complete the construction and create the desired angle. That is, YA ...

  This is the other ray that will make up the angle ∠AYZ and will complete the construction.

\large 6\cdot\frac{6+2^2}{6+2-6}

Answers

Answer:

30

Step-by-step explanation:

Given the expression [tex]\large 6\cdot\frac{6+2^2}{6+2-6}[/tex], on simplification we have;

[tex]= \large 6\cdot\frac{6+2^2}{6+2-6}\\\\= \large 6\cdot\frac{6+4}{8-6}\\\\= \large 6\cdot\frac{10}{2}\\\\= 6* 5\\\\= 30[/tex]

Hence the equivalent value of the expression is 30

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Answers

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

[tex]Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds[/tex]

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

[tex]\frac{200}{60} = \frac{10}{3} \approx 3.33[/tex]   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

[tex]\frac{200}{65} = \frac{40}{13} \approx 3.08[/tex]   loops per minute

then the period is:

[tex]\frac{13}{40} =0.325\,\,\,minutes[/tex]

Therefore runner B has the smaller period

Hello, a quick question which number is least to greatest 0.359, 0.35, 1

Answers

Answer:

0.35, 0.359, 1

Step-by-step explanation:

0.359 = 359 thousandths

0.35 = 0.350 = 350 thousandths

1 = 1.000 = 1000 thousandths

Since 350 < 359 < 1000, then from least to greatest you get

0.35, 0.359, 1

What is 51⁄6 as an improper fraction? For Seneca Learning:

Answers

Answer:

Step-by-step explanation:

[tex]5\frac{1}{6}=\frac{(5*6)+1}{6}=\frac{31}{6}[/tex]

Answer:

31/6 (improper fraction).

Step-by-step explanation:

5 1/6 = (6 × 5) + 1/6 = 31/6

31/6 is the improper fraction.

Given \qquad m \angle LONm∠LONm, angle, L, O, N is a straight angle. \qquad m \angle MON = 8x - 13^\circm∠MON=8x−13 ∘ m, angle, M, O, N, equals, 8, x, minus, 13, degrees \qquad m \angle LOM = 7x - 17^\circm∠LOM=7x−17 ∘ m, angle, L, O, M, equals, 7, x, minus, 17, degrees Find m\angle MONm∠MONm, angle, M, O, N:

Answers

Answer:

[tex] \boxed{99°}[/tex]

Step-by-step explanation:

m<MON = 8x - 13°

m<LOM = 7x - 17°

To find : m <MON

First, we have to find the value of x :

Create an equation

[tex] \mathrm{8x - 13 + 7x - 17 = 180}[/tex] ( sum of angle in straight line )

Collect like terms

[tex] \mathrm{15x - 13 - 17 = 180}[/tex]

Calculate

[tex] \mathrm{15x - 30 = 180}[/tex]

Move constant to R.H.S and change its sign

[tex] \mathrm{15x = 180 + 30}[/tex]

Calculate the sum

[tex] \mathrm{15x = 210}[/tex]

Divide both sides of the equation by 15

[tex] \mathrm{ \frac{15x}{15} = \frac{210}{15} }[/tex]

Calculate

[tex] \mathrm{x = 14}[/tex]

Now, let's find the value of m<MON

[tex] \mathrm{8x - 13}[/tex]

Plug the value of x

[tex] \mathrm{ = 8 \times 14 - 13}[/tex]

Calculate the product

[tex] \mathrm{ = 112 - 13}[/tex]

Calculate the difference

[tex] \mathrm{ = 99}[/tex] °

Hope I helped!

Best regards!

Answer:

48

Step-by-step explanation:

because i say so

What’s up guys, pls help 19b)
Thanks

Answers

Answer:

90°

Step-by-step explanation:

As given in the figure:

[tex]AC \perp CE\\

\therefore m\angle ACE = 90\degree \\ [/tex]

The sum of the numerator and denominator of a
fraction is 12. If the denominator is increased by 3,
the fraction becomes 1/2.
Find the fraction.
plz answer step by step​

Answers

[tex]x+y=12\\\dfrac{x}{y+3}=\dfrac{1}{2}\\\\x=12-y\\2x=y+3\\\\2(12-y)=y+3\\24-2y=y+3\\3y=21\\y=7\\\\x=12-7=5\\\\\dfrac{x}{y}=\dfrac{5}{7}[/tex]

Help? It hard I try my best on a Separate picese

Answers

Answer: 508.81

============================================

Work Shown:

3 & 1/2 = 3 + 1/2 = 3 + 0.5 = 3.5

3.5% = 3.5/100 = 0.035

r = 0.035 is the decimal form of [tex]3\frac{1}{2}\%[/tex] which is used along with

P = 500 (principal deposit)n = 12 (compounding 12 times a year)t = 0.5 (6 months is half a year)

to get the following

A = P*(1+r/n)^(nt)

A = 500*(1+0.035/12)^(12*0.5)

A = 508.81405074594

A = 508.81

Extra info: Gabe earned A-P = 508.81 - 500 = 8.81 dollars in interest.

surface area of sphare​

Answers

Surface area of sphere is what referred to as Total surface area or lateral surface area because here the surface is curved everywhere.

[tex] \large{ \boxed{ \rm{ \orange{Surface \: area \: of \: sphere = 4\pi {r}^{2} }}}}[/tex]

Total surface area of other 3-D shapes:

Cuboid = 2(lb + bh + hl)Cube = 4s²Cylinder = 2πr(r + h)Cone = πr(l + r)Hemisphere = 3πr²

Lateral surface area of these shapes:

Cuboid = 2h(l + b)Cube = 6s²Cylinder = 2πrhCone = πrlHemisphere = 2πr²

━━━━━━━━━━━━━━━━━━━━

A certain pole has a cylinder-like shape, where the base's radius is 10 centimeters and the height is 2 meters. What calculation will give us the estimated surface area of the pole in square centimeters?

Answers

Answer:

2 pi •10•210

Step-by-step explanation:

Khan academy

Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB

Answer: m∠DEA = _________, m∠ADB =_______

Answers

Answer:

The values of the angles are;

m∠DEA = 62°, m∠ADB = 45°

Step-by-step explanation:

Specify an arc or an angle three letters  

Angle opposite an arc on the circumference

m DA ≅ m CB = 62°  (Arc between parallel lines are congruent)

∠CAB = 1/2 × m CB = 1/2 × 62° = 31° (Angle at the center = 2 × Angle st the circumference)

∠DBA = 31° (Angle at the center m DA = 2 × Angle st the circumference)

m∠DAB = 104° (Given)

∠ADB = 180° - m∠DAB - ∠DBA = 180° - 104° - 31° = 45° (Interior angles of triangle ΔADB

m∠ADB = 45°

∠AEB = 180 - ∠CAB - ∠DBA = 180° - 31° - 31° = 118°

∠AEB ≅ ∠COD (Vertically opposite angles)

∠DEA ≅ ∠CEB (Vertically opposite angles)

∠AEB + ∠COD + ∠DEA + ∠CEB = 360° (Sum of angles at a point)

118° + 118° + ∠DEA + ∠CEB = 360°

∠DEA + ∠CEB = 360° - 118° - 118° = 124°

Given that ∠DEA = ∠CEB we have;

2 × ∠DEA = 124°

∠DEA = 124°/2 = 62°

m∠DEA = 62°.

The temperature in Anchorage, Alaska at 6:00 am was 2°C. If the temperature drops 2 degrees each hour, what is the temperature in degrees celsius at 2:00 pm

Answers

Answer:

-12°C

Step-by-step explanation:

6AM = 2°C

8AM= -2°C

10AM= -6°C

12AM= -8°C

2PM= -12°C

the temperature in degrees Celsius at 2:00 pm would be -14°C.

To find the temperature in degrees Celsius at 2:00 pm, we need to determine the number of hours that have passed from 6:00 am to 2:00 pm, and then calculate the temperature decrease accordingly.

From 6:00 am to 2:00 pm, a total of 8 hours have passed (6 hours from 6:00 am to 12:00 pm, and 2 hours from 12:00 pm to 2:00 pm).

Given that the temperature drops 2 degrees Celsius each hour, we can multiply the number of hours (8) by the rate of temperature decrease (2 degrees/hour):

Temperature decrease = 8 hours × 2 degrees/hour = 16 degrees

Starting with a temperature of 2°C at 6:00 am, if the temperature drops 16 degrees Celsius over 8 hours, we can subtract 16 from the initial temperature:

Temperature at 2:00 pm = 2°C - 16°C = -14°C

Therefore, the temperature in degrees Celsius at 2:00 pm would be -14°C.

Learn more about temperature here

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Jess receives a $15000 salary for working as an engineer. If Jess has to spend $6000 of her salary on expenses each year, then what percent of Jess's money does she have to spend? Round your answer to the nearest whole number if necessary.

Answers

Answer:

Jess will have to spend 40% of her salary

Step-by-step explanation:

Jess salary = $15,000

Jess expenses = $6,000

what percent of Jess's money does she have to spend

Percentage of Jess expenses = Jess expenses / Total salary × 100

= 6,000 / 15,000 × 100

= 0.4 × 100

= 40%

Jess will have to spend 40% of her salary

NEED IN 10 MIN. WILL GIVE BRAINLEST Solve the triangle. B = 36°, a = 41, c = 17

Answers

Answer:

Yes this is a Triangle

36 degrees of any side then 41 would connct to 36 and 17 would connects to 36 and 41! If this is Khan Academy your asking out of its a Yes, it is a Triangle

HOPE IM THE BRANLIESS UwU

Answer:

It is a triangle:

Step-by-step explanation:

b² = a² + c² - 2(a)(c)cos(B)  

b² = 41² + 20² - 2(41)(20)cos(36)

b² = 754.2121292

b = 27.46292281

b = 27.463

A = 41, B = 27.4, C = 17

Jake ran 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday he ran 1 fewer miles then he ran on Monday. How many miles did he run in all? PLEASE SHOW YOUR WORK I WILL MARK YOU BRAINLIEST AND PLEASE EXPLAIN

Answers

Answer:

Jake ran 10 1/6 miles in total

Step-by-step explanation:

4 1/4 + 2 2/3 - (4 1/4-1).

                  v

6 11/12 + 3 1/4

          v

6 11/12 + 3 3/12 = 10 1/6

Jake ran 10 1/6 miles in total (Mon, Tues, Wed).

Answer:

61/6 or 10.1666666667

Step-by-step explanation:

Monday = 4  1/4

Tuesday = 2  2/3

Wednesday = Monday - 1

=> Monday = 17/4 miles

=> Tuesday = 8/3 miles

=> Wednesday = 17/4 - 4/4 = 13/4 miles.

=> (17/4 + 13/4) + 8/3

=> 30/4 + 8/3

=> Take the LCM of the denominators.

=> LCM = 12

=> 90/12 + 32/12

=> 122/12

SImplify 122/12

=> 61/6 or 10.1666666667

55÷11[120÷2{4+(10+5-7)}]​

Answers

Answer:

3600

Step-by-step explanation:

First, solve the innermost brackets first.

=> 55/11 [120 /2{4 + (10 + 5 - 7)}]

=> 55/11 [120 /2{4 + (8)}]

=> 55/11 [120 /2{4+8}]

=> 55/11 [120 /2{12}]

=> 55/11[ 60 x 12]

=> 55/11 [720]

=> 5 [720]

=> 3600

3600

Hope it helps ❄️

solve equation show all steps what is 2x-3x+5=18

Answers

Answer:

x = -13

Step-by-step explanation:

2x-3x+5=18

Combine like terms

-x +5 = 18

Subtract 5 from each side

-x +5-5 = 18-5

-x = 13

Multiply each side by -1

x = -13

Answer:

[tex]\huge \boxed{{x=-13}}[/tex]

Step-by-step explanation:

[tex]2x-3x+5=18[/tex]

[tex]\sf Combine \ like \ terms.[/tex]

[tex]-1x+5=18[/tex]

[tex]\sf Subtract \ 5 \ from \ both \ sides.[/tex]

[tex]-1x+5-5=18-5[/tex]

[tex]-1x=13[/tex]

[tex]\sf Multiply \ both \ sides \ by \ -1.[/tex]

[tex]-1x \times (-1)=13 \times (-1)[/tex]

[tex]x=-13[/tex]

If you draw a rectangle that has a width of 12 centimeters and an area of 48 centimeters, what is the length of the rectangle?

Answers

Answer:

length=4 cm

Step-by-step explanation:

Area of rectangle= length * width

48=l*12

length=48/12

length=4 cm

Bismah is building 5 raised garden beds in a community garden. Each raised garden bed will need 1 7 8 bags of soil. How many bags of soil will Bismah need for all 5 raised garden beds?

Answers

Answer:

890 if it’s 178 bags per garden bed

Step-by-step explanation:

since 1 raised garden bed is supposedly 178 bags, 5 would be 890 since it’s just 5x178. if it’s not 178 bags (which would make sense since 178 is a big number), just multiply 5 by that number and if it’s a decimal round up to the next whole number if it’s about how many bags Bismah needs to buy, since you can’t by 1/2 of a bag

Bismah will need a total of 890 bags of soil for all the 5 raised garden. beds.

What is Multiplication?.

Multiplication is one of the basic operations in mathematics where a number is added repeatedly to itself up to the times as the value of the other number.

That is, if a number p is multiplied to another number q, p × q, implies that p is added repeatedly to itself q times or q is added repeatedly to itself up to p times.

Number of garden beds Bismah has raised = 5

Number of bags of soil needed for a garden bed = 178 bags

Number of  bags of soil needed for 5 garden bed = 178 × 5 bags

                                                                                   = 890 bags

Hence Bismah would need 890 bags of soil for the 5 raised garden beds in the community garden.

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Find the missing term in thegeometric sequence.13,[ ? ],208 What is the value of x for the given equation?4 2(x + 7) = 3(x + 5)X= how do u say james Morris in Spanish The circle shown above has a radius of 5 units, and the central angle of the sector that is shaded is 25 radians. Determine the area of the shaded sector, in terms of . Enter the area of the sector. Qu caractersticas crees que deben tener los mtodos anticonceptivos para ser eficaces en el control de la natalidad? Compute each matrix sum or product if it is defined. If an expression is undefined. Explain why. Let A = (3 4 0 -4 -1 4), B = (8 1 -4 -5 2 -4), C = (1 -1 3 1) and D = (3 -2 4 5). - 2A, B - 2A, AC, CDCompute the matrix product -2A.A. -2A = B. The expression-2A is undefined because A is not a square matrix. C. The expression-2A is undefined because matrices cannot be multiplied by numbers. D. The expression 2A is undefined because matrices cannot have negative coefficients. Which of the following correlation values represents a perfect linear relationship between two quantitativevariables? Select all that apply.A. 0B. 9c. -1D. 1E. .5 the coefficient of 6x Need help 24 to 28 giving 30 points Complete each congruency statement and name the rule used. If you cannot show the triangles are congruent from the given information, leave the triangle's name blank and write CNBD for "Cannot be determined" in place of the rule. ANT _____ by _____ A catering company prepared and served 375 meals at an anniversary celebration last week using 3 workers. The week before, 2 workers prepared and served 225 meals at a wedding reception a1. Calculate the labor productivity for each event. (Round your answers to 1 decimal place.) Anniversary Wedding meals/worker meals/worker a2. For which event was the labor productivity higher? Anniversary Wedding Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. The height (in feet) of a rocket launched from the ground is given by the function f(t) = -16t2 + 160t. Match each value of time elapsed (in seconds) after the rockets launch to the rocket's corresponding instantaneous velocity (in feet/second). algebra pyramid please answer !! be the first to be marked as a brainliest . The words monolithic pour, rebar, and ridgepole would be used by a______. What is the best pregame meal for an athlete? A. chips and a sport drink B. hamburger with fries and a soda C. pasta with meat sauce, fruit, and milk D. steak dinner with vitamin water In science class, Jake mixed water with differing amounts of an unknown liquid. After mixing the liquids, he heated 20 milliliters (ml) of each mixture and observed how quickly it boiled. The table shows his results. 8 is subtracted from the square of a number Compare the functions shown below: f(x) cosine graph with points at 0, negative 1 and pi over 2, 1 and pi, 3 and 3 pi over 2, 1 and 2 pi, negative 1 g(x) x y 6 11 5 6 4 3 3 2 2 3 1 6 0 11 h(x) = 2 cos x + 1 Which function has the greatest maximum y-value? A bond with a par value of $1,000 and an annual coupon has a yield to maturity of 5.60% and a current price of $975. If the bond has 18 years to maturity, what is its current yield? If a schema is not given, you may assume a table structure that makes sense in the context of the question. (using sql queries) Find all Employee records containing the word "Joe", regardless of whether it was stored as JOE, Joe, or joe.