2. A 10 Mg truck hauls a 20 Mg trailer. If the unit starts from rest on a level road with a
tractive force of 20 kN between the driving wheels of the truck and the road, calculate the
acceleration of the unit and the tension in the horizontal draw-bar.
Drawbar
20 Mg Trailer
10 Mg Truck
a=0.667 m/s2
T= 13.3 KN
Oro
W​

Answers

Answer 1

Answer:

The acceleration on the unit is 0.667 m/s^2

The tension on the draw-bar is 13.34 kN

Step-by-step explanation:

The mass of the truck = 10 Mg = 10 x 10^3 kg

The mass of the trailer = 20 Mg = 20 x 10^3 kg

Tractive force from the truck = 20 kN = 20 x 10^3 N

The total mass of the unit = 10 Mg + 20 Mg = 30 Mg = 30 x 10^3 kg

The tractive force on the unit will produce an acceleration that is given as

F = ma

where

F is the tractive = 20 x 10^3 N

m is the mass of the unit = 30 x 10^3 kg

a is the acceleration of the unit = ?

substituting into the equation

20 x 10^3 = 30 x 10^3 x a

a = (20 x 10^3)/(30 x 10^3) = 0.667 m/s^2

the tension on the draw-bar T is gotten from considering only the mass that is pulled by the draw-bar which is 20 Mg

The acceleration on the unit = 0.667 m/s^2

The drawn mass = 20 Mg = 20 x 10^3 kg

The tension on the draw bar = ma = 20 x 10^3 x 0.667 = 13340 N

= 13.34 kN

Answer 2

The acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N

The given parameters are:

[tex]\mathbf{m = 10Mg}[/tex] -- mass of the truck

[tex]\mathbf{M = 20Mg}[/tex] -- mass of the trailer

[tex]\mathbf{F_T = 20kN}[/tex] --- tractive force

Start by calculating the total mass

[tex]\mathbf{M_T = m + M}[/tex]

So, we have:

[tex]\mathbf{M_T = 10Mg + 20Mg}[/tex]

[tex]\mathbf{M_T = 30Mg}[/tex]

Convert to kilograms

[tex]\mathbf{M_T = 30 \times 10^3kg}[/tex]

[tex]\mathbf{M_T = 30000 kg}[/tex]

Force is calculated as:

[tex]\mathbf{F =ma}[/tex]

So, we have:

[tex]\mathbf{20kN =30000kg \times a}[/tex]

Divide both sides by 30000

[tex]\mathbf{a = 0.00067ms^{-2}}[/tex]

The tension on the horizontal bar (i.e. the 20 Mg trailer) is:

[tex]\mathbf{T=ma}[/tex]

So, we have:

[tex]\mathbf{T=20Mg \times 0.00067ms^{-2}}[/tex]

Rewrite as:

[tex]\mathbf{T=20 \times 10^3 kg \times 0.00067m/s}[/tex]

[tex]\mathbf{T=13.4N}[/tex]

Hence, the acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N

Read more about force and acceleration at:

https://brainly.com/question/20511022


Related Questions

Help please!! Thank you

Answers

Answer:

D

Step-by-step explanation:

-3, 3, 6, 9, 15, 18, 21,

Just list all the integers in that range, and check each one to see if it matches the requirements. (You can avoid checking every single one if you notice the pattern). Then count how many matches there were.

Matches: [-3, 3, 6, 9, 15, 18, 21]
There are seven matches.
Answer D.

Solve for x (x+4)/3 = 2.

a. x = -2

b. x=2

c. x = 2/3

d. x= -10/3​

Answers

Answer:

The answer is option B

Step-by-step explanation:

[tex] \frac{x + 4}{3} = 2[/tex]

To solve it first of all cross multiply

That's

x + 4 = 6

Move 4 to the right side of the equation

The sign changes to negative

That's

x = 6 - 4

We have the final answer as

x = 2

Hope this helps you

The Bookstall Inc. is a specialty bookstore concentrating on used books sold via the Internet. Paperbacks are $1.35 each, and hardcover books are $3.50. Of the 60 books sold last Tuesday morning, 55 were paperback and the rest were hardcover. What was the weighted mean price of a book? (Round your answer to 2 decimal places.)

Answers

Answer:

dddddd okaksy ogvurn

Step-by-step explanation:

d

Find the first five terms of the sequence of partial sums. (Round your answers to four decimal places.) [infinity] (−5)n + 1 n!

Answers

Answer:

25.0000 + -37.5000 + 66.6667 + -63.5416 + 66.6667

Step-by-step explanation:

The actual formatting of the question has been attached to this response.

From the question,

Let the sequence of terms be [tex]b_{n}[/tex] i.e

[tex]b_{n}[/tex] = [tex]\frac{(-5)^{n+1} }{n!}[/tex]

Let the sequence of partial sums be [tex]S_{n}[/tex] i.e

[tex]S_{n}[/tex] = s₁ + s₂ + s₃ + . . . + sₙ

Therefore the first five terms of the sequence of partial sums will be S₅ i.e

S₅ =  s₁ + s₂ + s₃ + s₄ + s₅

Where;

s₁ = b₁

s₂ = b₁ + b₂ = s₁ + b₂

s₃ = b₁ + b₂ + b₃ = s₂ + b₃

s₄ = b₁ + b₂ + b₃ + b₄ = s₃ + b₄

s₅ = b₁ + b₂ + b₃ + b₄ + b₅ = s₄ + b₅

Where;

b₁ can be found by substituting n = 1 into equation (i) as follows;

[tex]b_{1}[/tex] = [tex]\frac{(-5)^{1+1} }{1!}[/tex]

[tex]b_{1}[/tex] = 25

[tex]b_{1}[/tex] = 25.0000

Recall that

s₁ = b₁

∴ s₁ = 25.0000 to 4 decimal places

--------------------------------------------------------------------------

b₂ can be found by substituting n = 2 into equation (i) as follows;

[tex]b_{2}[/tex] = [tex]\frac{(-5)^{2+1} }{2!}[/tex]

[tex]b_{2}[/tex] = -62.5

[tex]b_{2}[/tex] = -62.5000

Recall that

s₂ = s₁ + b₂

∴ s₂ = 25.000 + -62.5000 = -37.5000

-----------------------------------------------------------------------------------------

b₃ can be found by substituting n = 3 into equation (i) as follows;

[tex]b_{3}[/tex] = [tex]\frac{(-5)^{3+1} }{3!}[/tex]

[tex]b_{3}[/tex] = 104.1667

Recall that

s₃ = s₂ + b₃

∴ s₃ = -37.5000 + 104.1667 = 66.6667

--------------------------------------------------------------------------------

b₄ can be found by substituting n = 4 into equation (i) as follows;

[tex]b_{4}[/tex] = [tex]\frac{(-5)^{4+1} }{4!}[/tex]

[tex]b_{4}[/tex] = -130.2083

Recall that

s₄ =  s₃ + b₄

∴ s₄ = 66.6667 + -130.2083 = -63.5416

-------------------------------------------------------------------------

b₅ can be found by substituting n = 5 into equation (i) as follows;

[tex]b_{5}[/tex] = [tex]\frac{(-5)^{5+1} }{5!}[/tex]

[tex]b_{5}[/tex] = 130.2083

Recall that

s₅ = s₄ + b₅

∴ s₅ = -63.5416 + 130.2083 = 66.6667

------------------------------------------------------------------------------

Therefore, the first five terms of the partial sum is:

25.0000 + -37.5000 + 66.6667 + -63.5416 + 66.6667

Assume a random sample of size n is from a normal population. Assume a single sample t test is used to for hypothesis testing. The null hypothesis is that the population mean is zero versus the alternative hypothesis that it is not zero. If the sample size is decreased, and the Type I error rate is unchanged, then the Type II error rate will increase.a. Trueb. False

Answers

Answer:

true

Step-by-step explanation:

type 1 and type 2 are not independent of each other - as one increases, the other decreases

The force of gravity on an object varies directly with its mass. The constant of variation due to gravity is 32.2 feet per second squared. Which equation represents F, the force on an object due to gravity according to m, the object’s mass? F = 16.1m F = F equals StartFraction 16.1 Over m squared EndFraction. F = 32.2m F = F equals StartFraction 32.2 Over m squared EndFraction.

Answers

Answer:

F = 32.2m

Step-by-step explanation:

According to newton second law, the force of gravity on an object varies directly with its mass and it is expressed mathematically as Fαm i.e

F = mg where;

F is the force of gravity

m is the mass of the body

g is the proportionality constant known as the acceleration due to gravity.

If the constant of variation due to gravity is 32.2ft/s², the equation that represents F, the force on an object due to gravity according to m, the object’s mass can be gotten by substituting g = 32.2 into the formula above according to the law as shown;

F = m*32.2

F =32.2m

Hence the required equation is F = 32.2m

is perpendicular to . How many 90° angles are formed by the intersection?

Answers

Answer:

if a is perpendicular to b then four 90 degree angles are formed

Step-by-step explanation:

if a line is perpendicular to another that means that it forms a 90 degree angle on all of the angles

Answer:

Four

That is the right answer for Edmentum and Plato users

Like and Rate!

A test of abstract reasoning is given to a random sample of students before and after they completed a formal logic course. The results are given below. Construct a 95% confidence interval for the mean difference between the before and after scores. Is there evidence to suggest the logic course improves abstract reasoning? You may assume that the differences for the dependent samples are normally distributed . Before 74, 83, 75, 88, 84, 63, 93, 84, 91, 77 After 73, 77, 70, 77, 74, 67, 95, 83, 84, 75
Note : define d = before - after, then đ = 3.7 and s = 4.95
Please sketch the rejection region and show computation for the test statistic

Answers

Answer:

1. confidence interval = (0.163, 7.237)

1. confidence interval = (0.163, 7.237)2. t = 2.366

1. confidence interval = (0.163, 7.237)2. t = 2.3663. critical value of one tailed test = 1.833

Step-by-step explanation:

before after    dt(before - after)   d²

74         73          1                            1

83         77           6                          36

75         70          5                          25

88         77           11                         121

84         74           10                         100

63         67           -4                         16

93          95         -2                           4

84         83           1                            1

91           84          7                           49

77           75          2                          4

∑dt = 37    

d* = 37/10

since sample space = 10

d* = 3.7

s.d from the question = 4.95

df = 10 - 1 = 9

critical value at 0.05 significance

t(0.025 at df of 9) = ±2.262

marginal error computation:

= (2.262) × (4.945/√10)

= 2.262 × 1.5637

= 3.5370

confidence interval CI = d* + marginal error

= 3.7 ±3.5730

= (0.163, 7.237)

The logic course give an improvement on abstract reasoning. The confidence interval shows that the result is significant.

H₀: Цd = 0

H₁: Цd > 0

∝ = 0.05

t = (3.7 - 0)/(4.945/√10)

t = 3.7/1.564

t = 2.366

for a right tailed test at 0.05 significance, and df of 9, the critical value is 1.833

please refer to the attachment to see the rejection region.

{4.OA.A.3} There are 1,492 chairs in the auditorium. Ms. Jones wants to put them into 10 rows. If she splits the chairs evenly into 10 rows, how many chairs will Ms. Jones have left over?

Answers

Answer:

2 chairs will be left over.

Step-by-step explanation:

Given that

There are a total of 1492 chairs.

which are to divided in 10 rows evenly.

To find:

Number of chairs left ?

Solution:

Let the number of chairs in each row = [tex]x[/tex]

There are 10 rows so number of chairs in rows = 10[tex]x[/tex]

Let the number of chairs left = [tex]y[/tex]

Total number of chairs =10[tex]x[/tex] + [tex]y[/tex]  = 1492

The above equation is like:

Divisor [tex]\times[/tex] Quotient + Remainder = Dividend

So, we have to find the remainder in this question where we are given Divisor and Dividend.

10 [tex]\times[/tex] 149 + 2 = 1492

So, dividing 1492 with 10, we get remainder as 2.

Hence, 2 chairs will be left.

a golfer hits the golf ball. the quadratic y = -14x^2+84x gives the time x seconds when the golf ball is at height 0 feet. In total, how long is the golf ball in the air?​

Answers

Answer:  6 seconds

Step-by-step explanation:

x refers to time. Since we want to know how long it is in the air, we need to find the time (x) when the ball lands on the ground (y = 0)

0 = -14x² + 84x

0 = -14x(x - 6)

0 = -14x     0 = x - 6

0 = x         6 = x

x = 0 seconds is when the ball was hit

x = 6 seconds is when the ball landed on the ground

Find the value of angle X. x = 40 x = 55 x = 109 x = 130 I will mark as Brainliest

Answers

Answer:

130 degree

Step-by-step explanation:

Interior angles of the triangle:

81, 49, (180-x)

and by sum of all angles of triangle is 180 degree,

therefore,

81 + 49 + 180 - x = 180

x = 130 degree

is [tex]\sqrt[4]{5x^{5} }[/tex] equal [tex](\sqrt[4]{5x} )^{5}[/tex] ?

Answers

Answer: It is not

Explanation:
Fourth root 5x^5

(Fourth root 5x)^5
= fourth root 3125x^5

Solve the equation for solutions in the interval [0, 2 π). Use algebraic methods and give exact values. Support your solution graphically. cos2x = 0

Answers

Answer:

45° or 135°

Step-by-step explanation:

Cos 2x = 0

2x = cos^-1 0

2x = 90° or 270°

x= 45° or 135°

Answer:

Step-by-step explanation:

● cos 2x = 0

We khow that Pi/2 equals 0.

So

● 2x = Pi/2 or 2x= -Pi/2

Then:

● x = Pi/4 or x = -Pi/2

So the solutions are:

● x = Pi/4 + 2×k×Pi

● or x = -Pi/4 + 2×k×Pi

Where k is an integer

The picture below has a graphical solution

● Pi/4 is approximatively 0.785 and -Pi/4 is approximatively -0.785

● the output of both Pi/4 and -Pi/4 is 0

So our answer was righr

savanah solved the equation 3+4 multiplied by the absolute value of x/2+3=11 for one solution. her work is shown below. what is the other solution to the given absolute value equation: savanah's solution was x= -2

Answers

Answer:

-10

Step-by-step explanation:

Given the equation solved by savanah expressed as [tex]3+4|\frac{x}{2} + 3| = 11[/tex], IF she solved for one of the solution and got x = -2, we are to solve for the other value of x.

Note that the expression in modulus can be expressed as a positive expression and negative expression.

For the positive value of the expression [tex]|\frac{x}{2} + 3|[/tex] i.e [tex]\frac{x}{2} + 3[/tex], the expression becomes;

[tex]3+4(\frac{x}{2} + 3) = 11[/tex]

On simplification;

[tex]3+4(\frac{x}{2} + 3) = 11\\\\3 + 4(\frac{x}{2} )+4(3) = 11\\\\3 + \frac{4x}{2}+ 12 = 11\\\\3 + 2x+12 = 11\\\\2x+15 = 11\\\\Subtract \ 15 \ from \ both \ sides\\\\2x+15-15 = 11-15\\\\2x = -4\\\\x = -2[/tex]

For the negative value of the expression [tex]|\frac{x}{2} + 3|[/tex] i.e [tex]-(\frac{x}{2} + 3)[/tex], the expression becomes;

[tex]3+4[-(\frac{x}{2} + 3)] = 11[/tex]

On simplifying;

[tex]3+4[-(\frac{x}{2} + 3)] = 11\\\\3+4(-\frac{x}{2} - 3)= 11\\\\3-4(\frac{x}{2}) -12 = 11\\\\3 - \frac{4x}{2} - 12 = 11\\\\3 - 2x-12 = 11\\\\-2x-9 = 11\\\\add \ 9 \ to \ both \ sides\\\\-2x-9+9 = 11+9\\-2x = 20\\\\x = -20/2\\\\x = -10[/tex]

Hence her other solution of x is -10

Consider population data with μ = 30 and σ = 3. (a) Compute the coefficient of variation. (b) Compute an 88.9% Chebyshev interval around the population mean. Lower Limit Upper Limit

Answers

Answer:

A. 10%

B. Lower limit= 21

Upper limit = 39

Step-by-step explanation:

Mean = 30

SD = 3

a. COV = SD/|x| × 100

= 3/30 × 100

= 10%

= 0.1

B. For 88.9 chevbychev interval:

= (1 - 1/K²) = 0.889

= 1/K² = 1 - 0.889

= 1/K² = 0.111

= K² = 1/0.111

= K² = 9

= K = √9

K = 3

Lower limit = 30 - 3(3)

Lower limit = 21

Upper limit = 30 + 3(3)

Upper limit = 39

Therefore lower limit is 21 and upper limit is 39

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle. y = x2 − 4x y = 3x

Answers

Answer:

Hello your question is incomplete attached is the missing part the second curve ; y = 3x is incomplete so i would solve the problem taking the second curve as ; y = 3x + 8 ( giving you the general methodology )

answer : y = ( 5,32) , x = ( -1,8 )

area of shaded region = 90.673

Step-by-step explanation:

The given curves ; [tex]y = x^2 - 4x\\y = 3x +8[/tex]

solving the above curves simultaneously

[tex]x^2-4x = 3x + 8[/tex]

x^2 - 7x - 8 = 0

( x + 1 )(x - 8 ) = 0

hence  X = ( -1 , 8 )

Therefore y = 3x + 8

when x = -1 ,  y = -3 + 8 = 5

when x = 8 ,  y = 24 + 8 = 32

hence y = ( 5, 32 )

attached below is the sketched region

Integrating the curves to determine the shaded area in respect to x = ( -1, 8)

∫ [( 3x +8 ) - ( x^2 - 4x ) ] dx

∫ ( -x^2 +7x + 8 ) dx

= { - x^3/3  + 3x^2 + 8x }

= { - 8^3/3 + 3(64) + 64} - { -1^3/3 + 3 - 8 }

= {-170.66 + 192 + 64 } - { -1/3 - 5 }

= -170.66 + 192 + 64 + 5.333 = 90.673 ( area of the shaded region )

3 With 72 million bicycles, correct to the
nearest million, Japan is at the top of the list
of countries with most bicycles per person.
On average, Japanese people travel about
2 km by bicycle, correct to the nearest km,
each day. Calculate the upper bound for the
total distance travelled by all the bicycles in
Japan.

Answers

Answer:

  181 million km

Step-by-step explanation:

"Correct to the nearest unit" means the actual value might be 1/2 unit larger (or smaller) than the reported value.

The upper bound would be the product of the maximum number of bicycles and the maximum distance each travels:

  (72.5 · 10^6 bicycles)(2.5 km/bicycle) = 181.25 · 10^6 km

__

Since the given numbers are good to 2 significant figures (or so), we might reasonably put the upper bound as 180·10^6 km.

NEED HELP ASAP


Which point represents the center of the circle shown below?

Answers

Answer:

Point O represents the center of the circle

Step-by-step explanation:

HOPE IT HELPS. PLEASE MARK IT AS BRAINLIEST

Answer: Point O

Explanation:

Point O is in the middle of the circle

And other point are not in the middle

A political candidate has asked his/her assistant to conduct a poll to determine the percentage of people in the community that supports him/her. If the candidate wants a 10% margin of error at a 95% confidence level, what size of sample is needed

Answers

Answer:

The desired sample size is 97.

Step-by-step explanation:

Assume that 50% people in the community that supports the political candidate.

It is provided that the candidate wants a 10% margin of error (MOE) at a 95% confidence level.

The confidence interval for the population proportion is:

[tex]CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

Then the margin of error is:

[tex]MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

Compute the critical value of z as follows:

[tex]z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96[/tex]

*Use a z-table.

Compute the sample size as follows:

[tex]MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

       [tex]n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}[/tex]

          [tex]=[\frac{1.96\times \sqrt{0.50(1-0.50)} }{0.10}^{2}\\\\=[9.8]^{2}\\\\=96.04\\\\\approx 97[/tex]

Thus, the desired sample size is 97.

(-1, 4) and (-2, 2).

Answers

Answer:

Slope : 2

slope-intercept: y = 2x + 6

Point-slope (as asked): y - 4 = 2 (times) (x + 1)

standered: 2x - y = -6

Step-by-step explanation:

What is the sign of -1.69+(-1.69)

Answers

Answer: Negative sign

Adding two negative values results in another negative value.

-1.69 + (-1.69) = -3.38

It's like starting $1.69 in debt and then adding 1.69 dollars of more debt. You'll slide further into debt being $3.38 in debt total.

The sign is negative as the value of -1.69 + (-1.69) is -3.38.

What is an expression?

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

-1.69 + (-1.69)

= -1.69 - 1.69

= -3.38

This means,

The sign is negative.

Thus,

The value of -1.69 + (-1.69) is -3.38.

Learn more about expressions here:

https://brainly.com/question/3118662

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A researcher reports a 98% confidence interval for the proportion of Drosophila in a population with mutation Adh-F to be [0.34, 0.38]. Therefore, there is a probability of 0.98 that the proportion of Drosophola with this mutation is between 0.34 and 0.38. True or False

Answers

Answer:

False

Step-by-step explanation:

The 98% is confidence interval its not a probability estimate. The probability will be different from the confidence interval. Confidence interval is about the population mean and is not calculated based on sample mean. Every confidence interval contains the sample mean. There is 98% confidence that the proportion of Drosophola with his mutation is between 0.34 and 0.38.

The volume of a rectangular prism is the products it’s dimensions. If the dimensions of a rectangle prism are approximately 1.08 feet,5.25 feet, and 3.3 feet ,what is the approximate volume of the cube?Express your answer using an approximate level of accuracy.

Answers

Answer:

18.711

Step-by-step explanation:

Volume = L * W * H

V = 1.08 * 5.25 * 3.3

1.08 * 5.25 = 5.67

5.67 * 3.3 =

V = 18.711

multiple choice plz answer be the correct answer and show working out if can it has to be correct plz "multiple coordinate transfermation"

Answers

Answer:

Solution : Option B

Step-by-step explanation:

1. This point first underwent a translation of 1 unit up and 4 units left. After a translation of 1 unit up, the coordinate would be ( - 2, 8 ), and after moving 4 units left the coordinate would be ( - 6, 8 ). This is our new point after the translation.

2. Next, point ( - 6, 8 ) was reflected about the x - axis. This would make the coordinate ( - 6, - 8 ) - as it now enters the third quadrant, where all possible x and y coordinates are taken to be negative.

3. Now point ( - 6, - 8 ) is rotated 90 degrees anticlockwise about the origin. Remember that this point is in the third quadrant. If it moves anticlockwise 90 degrees, it will end up in the fourth quadrant, seemingly at point ( 8, - 6 ).

if G is the midpoint of FH, FG = 14x + 25 and GH = 73 - 2x, find FH.

Answers

Answer:

FH = 134

Step-by-step explanation:

From the question given:

G is the midpoint of FH

FG = 14x + 25

GH = 73 - 2x

FH =?

Next, we shall determine the value of x. The value of x can be obtained as follow:

Since G is the midpoint of FH, this implies that FG and GH are equal i.e

FG = GH

With the above formula, we can obtain the value of x as follow:

FG = 14x + 25

GH = 73 - 2x

x =?

FG = GH

14x + 25 = 73 - 2x

Collect like terms

14x + 2x = 73 - 25

16x = 48

Divide both side by 16

x = 48/16

x = 3

Next, we shall determine the value of FG and GH. These can be obtained as shown below:

FG = 14x + 25

x = 3

FG = 14x + 25

FG = 14(3) + 25

FG = 42 + 25

FG = 67

GH = 73 - 2x

x = 3

GH = 73 - 2x

GH = 73 - 2(3)

GH = 73 - 6

GH = 67

Finally, we shall determine FH as follow:

FH = FG + GH

FG = 67

GH = 67

FH = FG + GH

FH = 67 + 67

FH = 134

Therefore, FH is 134

Helppppp thank you!!!

Answers

Answer:

G.) 72°

Step-by-step explanation:

A regular pentagon has all it's sides equal.

And all it's internal angles = 108°

The sum of all it's internal angles= 540°

AEB = TRIANGLE

And sum of internal angles In a triangle= 180°

EBDC is quadrilateral and a quadrilateral has it's internal angles summed up to 360°

But DEB = CBE

Let DEB = X

x + x +108+108= 360

2x= 360-216

2x= 144

X= 144/2

X=72

DEB = 72°

a milha eh uma unidade usada para medir distancias. ela equivale a cerca de 1,6 quilometros. se cada carro percorrer 240 quilometros, quantas milhas tera percorrido? urgente

Answers

Classica aplicação de regra de 3:

é dito que: 1 milha = 1,6km

Logo, eis a regra de 3:

  milha           km

     1   --------    1,6

     X  --------   240

1,6X = 240.1

X = 240/1,6

X = 150milhas

Logo 240km equivalem a 150milhas

point a is at (6,-6) and point c is at (-6, -2)
Find the cooridantes of point b on AC such that AB=3/4 AC

Answers

Answer:

(-3,-3)

B=(6-9,6+3)

Layla is going to drive from her house to City A without stopping. Layla plans to drive
at a speed of 30 miles per hour and her house is 240 miles from City A. Write an
equation for D, in terms of t, representing Layla's distance from City A t hours after
leaving her house.

Answers

Answer:

D = 240 - 30t

Step-by-step explanation:

If the equation represents her distance from City A, we need to include 240 in the equation to represent the distance to the city.

Then, we need to subtract 30t from 240 in the equation because 30t represents how far she will have traveled in t hours.

So, D = 240 - 30t is the equation that will represent Layla's distance from the city.

the box plots shows the price for two different brands of shoes​

Answers

Answer:

A. The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $25.

Step-by-step explanation:

The most appropriate measure that can be used to compare the SPREAD of the data of the 2 brands plotted on a box plot, is the Interquartile range (IQR).

Interquartile range is the difference between Q3 and Q1.

Q3 is the value which lies at the end of the rectangular box, while the Q1 lies at the beginning of the box.

From the box plot given,

IQR for brand A = 80 - 70 = $10

IQR for brand B = 50 - 25 = $25

Therefore, the correct option is "A. The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $25."

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