19. Divide 6/13 by 6/12.
A. 12/13
B. 13/12
c. 1/12
D.9/16

Answer:

[tex]\displaystyle f(3x) = \frac{6x + 5}{3x + 4}[/tex]

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f(x) = \frac{2x + 5}{x + 4}[/tex]

Step 2: Find

Step-by-step explanation:

each point should be at a 2. the center is 0,0

Answer:

Jose has 5.2 meters of fabric left.

Step-by-step explanation:

5.6 - 0.4 = 5.2

Answer:

Answer:Amy used 4 41-cent stamps and 8 6-cent stamps.

Step-by-step explanation:

Let x represent the number of 41-cent stamps that Amy used. Let y represent the number of 6-cent stamps that Amy used.

41 cents = 41/100 = $0.41

6 cents = 6/100 = $0.06

She uses 41-cent stamps and 6-cent stamps to pay $2.12 in postage. It means that

0.41x + 0.06y = 2.12

Multiplying through by 100, it becomes

41x + 6y = 212

6y = 212 -41x

We would test for corresponding values of x and y that satisfies the equation and they must be whole numbers.

If x = 3,

6y = 212 - 41 × 3 = 89

y = 89/6 = 14.8333

If x = 4,

6y = 212 - 41 × 4 = 48

y = 48/6 = 8

Answer:Amy used 4 41-cent stamps and 8 6-cent stamps.

Step-by-step explanation:

Let x represent the number of 41-cent stamps that Amy used. Let y represent the number of 6-cent stamps that Amy used.

41 cents = 41/100 = $0.41

6 cents = 6/100 = $0.06

She uses 41-cent stamps and 6-cent stamps to pay $2.12 in postage. It means that

0.41x + 0.06y = 2.12

Multiplying through by 100, it becomes

41x + 6y = 212

6y = 212 -41x

We would test for corresponding values of x and y that satisfies the equation and they must be whole numbers.

If x = 3,

6y = 212 - 41 × 3 = 89

y = 89/6 = 14.8333

If x = 4,

6y = 212 - 41 × 4 = 48

y = 48/6 = 8

Answer:

r = 3 2/3

s = -0.444333

Step-by-step explanation:

Multiply the top equation by 2

14r - 6s = 52

2r -  6s =   8          Subtract the two equations

12r = 44                 Divide by 12

r = 44/12

r = 3 8/12

r = 3 2/3

2r - 6s = 8

2*(2 2/3) - 6s = 8

2*2.6667 - 6s = 8

5.3334 - 6s = 8              Subtract 5.3334 from both sides.

- 6s = 2 2/3                    Divide by - 6

s = - 0.4443333

Answer:

D is the answer

Step-by-step explanation:

plug the -2's in line 1 & 2 then 4 in 2 and 3

the 1&2 , and the 2 and 3 numbers have to match

Using the conditions for continuity, we find that the function D.) is continuous.

A function f(x) is said to be continuous at a point x = a, in its domain if the following three conditions are satisfied:

Since for -4 <= x < -2, -2 <= x < 4 and 4 <= x <= 8, the function f(x) is defined by straight lines , the function will be continuous for all x ≠ -2 and 4. Now for x = -2, 4, let us check all the three conditions:

A.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 + 6 = 4

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit, the function is not continuous at x = -2. No need to check further.

B.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 -2 = -4

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit, the function is not continuous at x = -2. No need to check further.

C.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 + 4 = 2

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit is equal to f(-2), the function is continuous at x = -2.

f(4) = 25 - 3*4 = 13

left hand limit = 0.5 * (4)² = 8

right hand limit = 25 - 3*4 = 13

Since, left hand limit is not equal to right hand limit, the function is not continuous at x = 4.

D.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 + 4 = 2

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit is equal to f(-2), the function is continuous at x = -2.

f(4) = 20 - 3*4 = 8

left hand limit = 0.5 * (4)² = 8

right hand limit = 20 - 3*4 = 8

Since, left hand limit is not equal to right hand limit is equal to f(-2), the function is continuous at x = 4.

Thus, the function is continuous.

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Answer:

Infinitely many solutions.

They must satisfy [tex]y = \frac{1}{5}(x - 5)[/tex]

Step-by-step explanation:

Given

[tex]x - 5y = 5[/tex]

[tex]-x + 5y = -5[/tex]

Required

The best description

Add both equations

[tex]x - x - 5y + 5y = 5 - 5[/tex]

[tex]0+0 =0[/tex]

[tex]0 = 0[/tex] ---- this means that the system has infinitely many solutions.

Make y the subject in: [tex]-x + 5y = -5[/tex]

Add x to both sides

[tex]5y = x - 5[/tex]

Divide through by 5

[tex]y = \frac{1}{5}(x - 5)[/tex]

Hence, they must satisfy: [tex]y = \frac{1}{5}(x - 5)[/tex]

Answer:

x=70

y=30

z=20

Step-by-step explanation:

x=180-110 (angles on a straight line)

y=180-110-40 (angle sum of triangle)

z= 180-90-70 (angle sum of triangle)

Answer:

x=70°

y=30°

z=20°

Step-by-step explanation:

x=180°-110°(anlges on a straight line)

x=70°

y+110°+40°=180°(sum of angles of triangle)

y+150°=180°

y=180°-150°

y=30°

z+x+90°=180°(sum of angles of triangle)

z+70°+90°=180°

z+160°=180°

z=180°-160°

z=20°

Answer:

To solve for x, you must multiply by the reciprocal.

In this case, multiply both sides by [tex]\frac{3}{2}[/tex] .

When doing this the result will be x = 3

Answer:

It should be 8.6 yards, as 238.64÷3.14 = 74.

√74 = 8.60, or 8.6 :)

Answer/Step-by-step explanation:

✔️-72 ÷ (-2)

The division of two negative numbers will give us a positive number. i.e. - ÷ - = +

Therefore:

-72 ÷ (-2) = 36

✔️-72 ÷ 2

The division of a negative number and a positive number will give us a negative number. i.e. - ÷ + = -

Therefore:

-72 ÷ 2 = -36

✔️72 ÷ (-2)

The division of a positive number and a negative number will give us a negative number. i.e. + ÷ - = -

Therefore:

72 ÷ (-2) = -36

9514 1404 393

Answer:

  0.5

Step-by-step explanation:

The "enclosed area" can be taken to mean different things. Here, we consider it to mean the finite area bounded between the two curves, regardless of which curve is higher value than the other.

The area is bounded on the interval [0, 2]. On half that interval y1 > y2; on the other half, y2 > y1. This means the integral of the area between the curves will be different for one part of the interval than for the other. (The curves are symmetric about the point (1, 0).)

The area on the interval [0, 1] is given by the integral ...

  [tex]\displaystyle\int_0^1{(y_1-y_2)}\,dx=\int_0^1{((x-1)^3-(x-1))}\,dx\\\\=\int^1_0{(x(x-1)(x -2))}\,dx=\left.(\frac{x^4}{4}-x^3+x^2)\right|^1_0=\boxed{\frac{1}{4}}[/tex]

The area on the interval [1, 2] is the integral of the opposite integrand, but has the same value.

The positive area over the whole interval from 0 to 2 is 1/4+1/4 = 1/2.

If you simply integrate y2-y1 or y1-y2 over that interval, the result is 0.

Without any extra conditions, the answer could be 3, and the simplest polynomial with the given roots would be

(x + 5) (x - (1 + 4i )) (x + 4i )

= x ³ + 4x ² + (11 - 4i ) x + 80 - 2i

If the polynomial is supposed to have only real coefficients, then any complex roots must occur along with their complex conjugates:

(x + 5) (x - (1 + 4i )) (x - (1 - 4i )) (x + 4i ) (x - 4i )

= x ⁵ + 3x ⁴ + 23x ³ + 133x ² + 112x + 1360

and then the degree would be 5.

Answer:

mark me as brinalist if answers are correct

Answer:

i put in 3 to make 23436 because 36 is divisible by 6

Answer:

Kindly check explanation

Step-by-step explanation:

A.)

H0 : μ = 5000

H0 : μ > 5000

xbar = 6671 ; s = 8185.21 ; n = 52 ; α = 0.05

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (6671 - 5000) ÷ (8185.21/√52)

T = 3.814

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at 3.814; 51 = 0.000185

Pvalue < α ; Reject H0 and conclude that average birth is greater than 5000

B)

H0 : μ = 6000

H0 : μ < 6000

xbar = 4187 ; s = 4386 ; n = 52 ; α = 0.01

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (4187 - 6000) ÷ (4386/√52)

T = - 2.981

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at - 2.981; 51 = 0.0022

Pvalue < α ; Reject H0 and conclude that average death is less than 6000

C.)

H0 : μ < 2500

H0 : μ ≥ 2500

xbar = 2744 ; s = 3134.41 ; n = 52 ; α = 0.05

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (2744 - 2500) ÷ (3134.41/√52)

T = 0.561

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at 0.561; 51 = 0.289

Pvalue > α ; Fail to Reject H0 and conclude that average marriage is not greater Tha or equal to 2500

D.)

H0 : μ = 4000

H0 : μ ≤ 4000

xbar = 1451 ; s = 1217 ; n = 52 ; α = 0.01

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (1451 - 4000) ÷ (1217/√52)

T = - 15.10

Pvalue from Test statistic : ; df = n - 1 = 52-1= 51

Pvalue at - 15.10; 51 = 0.000001

Pvalue < α ; Reject H0 and conclude that average divorce is less eqaul to 4000

9514 1404 393

Answer:

  1/3; geometric

Step-by-step explanation:

Apparently, your sequence is ...

  81, 27, 9, 3, 1, ...

The differences between these numbers vary, but the ratio of each to the one before is a constant:

  27/81 = 9/27 = 3/9 = 1/3

The sequence is geometric with a common ratio of 1/3. The next number in the sequence is (1)(1/3) = 1/3.

Answer:

[tex]g(x) = \frac{-2}{x-1}+5\\\\[/tex]

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

[tex]g(x) = \frac{5x-7}{x-1}\\\\g(x) = \frac{5x-5-2}{x-1}\\\\g(x) = \frac{(5x-5)-2}{x-1}\\\\g(x) = \frac{5(x-1)-2}{x-1}\\\\g(x) = \frac{5(x-1)}{x-1}+\frac{-2}{x-1}\\\\g(x) = 5+\frac{-2}{x-1}\\\\g(x) = \frac{-2}{x-1}+5[/tex]

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation [tex]g(x) = \frac{-2}{x-1}+5\\\\[/tex] to the form [tex]g(x) = \frac{a}{x-h}+k\\\\[/tex]

We can see that

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.

Answer:

Plastic is 22.5 pounds and aluminum is 32.5 pounds.

Step-by-step explanation:

total junk = 55 pounds

Value of plastic = $ 1.60 per pound

Value of aluminum = $ 1.28 per pound

Total value= $ 77.60

Let the plastic is p and the aluminum is 55 - p.

Total cost

77.60 = 1.6 p + (55 - p) x 1.28

77.60 =  1.6 p + 70.4 - 1.28 p

7.2 = 0.32 p

p = 22.5 pounds

So, plastic is 22.5 pounds and aluminum is 32.5 pounds.

Answer:

33.51 cm

Step-by-step explanation:

240/360 = 2/3 (Arc length is 2/3 of the total circumference)

C = 2[tex]\pi[/tex]r             ( Calculate the total circumference)    

C = 2(8)[tex]\pi[/tex]

C = 50.265

2/3(50.265)      (Take 2/3 of the circumference. times 2 divide by 3)

33.51

Use a calculator and leave the answer to C and then multiply and divide. You get a more precise answer.

The exact arc length is [tex]\frac{32\pi}{3}[/tex] radians.

The arc length in approximate form is 33.49 radians.

[tex]s = r\times \theta[/tex]

where r is the radius of the circle and [tex]\theta[/tex] is the central angle in radians.

Radians = Degrees ×[tex]\frac{\pi}{180^{\circ}}[/tex]

For given question,

We have been given a circle with a 8-cm radius associated with a central angle of 240 degrees.

[tex]r=8~cm,~\theta=240^{\circ}[/tex]

First we convert angle in radians.

[tex]\theta=240^{\circ}\\\\\theta=240^{\circ} \times \frac{\pi}{180^{\circ}}\\\\ \theta=\frac{4\pi}{3}[/tex]

Using the formula of the arc length,

[tex]s=8\times \frac{4\pi}{3} \\\\s=\frac{32\pi}{3}[/tex]

The exact answer of the arc length is [tex]s=\frac{32\pi}{3}[/tex]

Substitute the value of [tex]\pi = 3.14[/tex]

So, the arc length would be,

[tex]\Rightarrow s=\frac{32\times \pi}{3}\\\\\Rightarrow s=\frac{32\times 3.14}{3}\\\\\Rightarrow s=33.49[/tex]radians

Therefore, the exact arc length is [tex]\frac{32\pi}{3}[/tex] radians.

the arc length in approximate form is 33.49 radians.

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Answer:

a) The expression for the number of bacteria is [tex]P(t) = 100\cdot e^{1.131\cdot t}[/tex].

b) There are 2975 bacteria after 3 hours.

c) The rate of growth after 3 hours is about 3365.3 bacteria per hour.

d) A population of 10,000 will be reached after 4.072 hours.

Step-by-step explanation:

a) The population growth of the bacteria culture is described by this ordinary differential equation:

[tex]\frac{dP}{dt} = k\cdot P[/tex] (1)

Where:

[tex]k[/tex] - Rate of proportionality, in [tex]\frac{1}{h}[/tex].

[tex]P[/tex] - Population of the bacteria culture, no unit.

[tex]t[/tex] - Time, in hours.

The solution of this differential equation is:

[tex]P(t) = P_{o}\cdot e^{k\cdot t}[/tex] (2)

Where:

[tex]P_{o}[/tex] - Initial population, no unit.

[tex]P(t)[/tex] - Current population, no unit.

If we know that [tex]P_{o} = 100[/tex], [tex]t = 1\,h[/tex] and [tex]P(t) = 310[/tex], then the rate of proportionality is:

[tex]P(t) = P_{o}\cdot e^{k\cdot t}[/tex]

[tex]\frac{P(t)}{P_{o}} = e^{k\cdot t}[/tex]

[tex]k\cdot t = \ln \frac{P(t)}{P_{o}}[/tex]

[tex]k = \frac{1}{t}\cdot \ln \frac{P(t)}{P_{o}}[/tex]

[tex]k = \frac{1}{1}\cdot \ln \frac{310}{100}[/tex]

[tex]k\approx 1.131\,\frac{1}{h}[/tex]

Hence, the expression for the number of bacteria is [tex]P(t) = 100\cdot e^{1.131\cdot t}[/tex].

b) If we know that [tex]t = 3\,h[/tex], then the number of bacteria is:

[tex]P(t) = 100\cdot e^{1.131\cdot t}[/tex]

[tex]P(3) = 100\cdot e^{1.131\cdot (3)}[/tex]

[tex]P(3) \approx 2975.508[/tex]

There are 2975 bacteria after 3 hours.

c) The rate of growth of the population is represented by (1):

[tex]\frac{dP}{dt} = k\cdot P[/tex]

If we know that [tex]k\approx 1.131\,\frac{1}{h}[/tex] and [tex]P \approx 2975.508[/tex], then the rate of growth after 3 hours:

[tex]\frac{dP}{dt} = \left(1.131\,\frac{1}{h} \right)\cdot (2975.508)[/tex]

[tex]\frac{dP}{dt} = 3365.3\,\frac{1}{h}[/tex]

The rate of growth after 3 hours is about 3365.3 bacteria per hour.

d) If we know that [tex]P(t) = 10000[/tex], then the time associated with the size of the bacteria culture is:

[tex]P(t) = 100\cdot e^{1.131\cdot t}[/tex]

[tex]10000 = 100\cdot e^{1.131\cdot t}[/tex]

[tex]100 = e^{1.131\cdot t}[/tex]

[tex]\ln 100 = 1.131\cdot t[/tex]

[tex]t = \frac{\ln 100}{1.131}[/tex]

[tex]t \approx 4.072\,h[/tex]

A population of 10,000 will be reached after 4.072 hours.

Answer:

Step-by-step explanation:

commission = 0.7% of $12,500

= 0.007×$12,500

= $87.5

Answer:

remember the chain rule:

h(x) = f(g(x))

h'(x) = f'(g(x))*g'(x)

or:

dh/dx = (df/dg)*(dg/dx)

we know that:

z = 4*e^x*ln(y)

where:

y = u*sin(v)

x = ln(u*cos(v))

We want to find:

dz/du

because y and x are functions of u, we can write this as:

dz/du = (dz/dx)*(dx/du) + (dz/dy)*(dy/du)

where:

(dz/dx)  = 4*e^x*ln(y)

(dz/dy) = 4*e^x*(1/y)

(dx/du) = 1/(u*cos(v))*cos(v) = 1/u

(dy/du) = sin(v)

Replacing all of these we get:

dz/du = (4*e^x*ln(y))*( 1/u) + 4*e^x*(1/y)*sin(v)

          = 4*e^x*( ln(y)/u + sin(v)/y)

replacing x and y we get:

dz/du = 4*e^(ln (u cos v))*( ln(u sin v)/u + sin(v)/(u*sin(v))

dz/du = 4*(u*cos(v))*(ln(u*sin(v))/u + 1/u)

Now let's do the same for dz/dv

dz/dv = (dz/dx)*(dx/dv) + (dz/dy)*(dy/dv)

where:

(dz/dx)  = 4*e^x*ln(y)

(dz/dy) = 4*e^x*(1/y)

(dx/dv) = 1/(cos(v))*-sin(v) = -tan(v)

(dy/dv) = u*cos(v)

then:

dz/dv = 4*e^x*[ -ln(y)*tan(v) + u*cos(v)/y]

replacing the values of x and y we get:

dz/dv = 4*e^(ln(u*cos(v)))*[ -ln(u*sin(v))*tan(v) + u*cos(v)/(u*sin(v))]

dz/dv = 4*(u*cos(v))*[ -ln(u*sin(v))*tan(v) + 1/tan(v)]

Answer:

C.

Step-by-step explanation:

For an angle to be supplementary to another angle, they must be equal to 180. Angles 6, 10, 13, and 9 are all supplementary to angle 16. Although there are more choices in different answers it wouldn't work with question, so C is the right answer.

Angle 16 is supplementary to angle 9 by the Same Side Interior Angles Theorem, which makes it supplementary to angle 10 by the Alternate Exterior Angles Theorem, which is also congruent to angle 13 by the Vertical Angles Theorem, which is also supplementary to angle 6 by the Alternate Exterior Angles Theorem.

Answer:

Step-by-step explanation:

P=R3000.00

T=3 years

SI=R905

SI=P\times R\times T\\R905=R3000\times \frac{r}{100}\times 3SI=P×R×T

R905=R3000×  

100

r

​

×3

R905=\frac{R9000r}{100}R905=  

100

R9000r

​

R905=\frac{R905}{R90}R905=  

R90

R905

​

r=\frac{R905}{R90.}r=  

R90.

R905

​

r=10.06\%r=10.06%

9514 1404 393

Answer:

  A.  7.2

Step-by-step explanation:

In this geometry, all of the right triangles are similar. This means corresponding sides have the same ratio.

  short side/hypotenuse = x/12 = 12/20

Multiplying by 12 gives ...

  x = 12(12/20) = 144/20

  x = 7.2

Answer:

C

Step-by-step explanation:

p=20+1