10;11;15;15;17;22;11 what is the mode of this data?

Answer:

x = 6

Step-by-step explanation:

To get rid of the fraction at the left side of the equation, multiply both sides by 4

20x + 60 = 180 now subtract 60 from both sides

20x = 120 divide both sides by 20

x = 6

Answer:

54°

Step-by-step explanation:

All the angle measures of a triangle must add up to equal 180°. So,

59°+67°+x°=180°

x=54°

We must write and solve a system of equations to see how many of each type of coin Carlos has.

The answer is:

We start by defining the variables:

We know there are 46 coins in total, thus:

x + y + z= 46

The number of pennies and dimes is the same, thus:

x = y

The total value of the coins in the box is $4.09, then:

x*$0.01 + y*$0.10 + z*$0.25 = $4.09

So we can write the system of equations:

x + y + z= 46

x = y

x*$0.01 + y*$0.10 + z*$0.25 = $4.09

First, we can replace x by y in the first and third equations (by using the second one) to get:

2y + z =  46

y*$0.11 + z*$0.25 = $4.09

Now we can isolate z in the first equation to get:

z = 46 - 2y

And replace that in the other equation:

y*$0.11 + (46 - 2y)*$0.25 = $4.09

Now we can solve the equation for y:

y*$0.11 + (46 - 2y)*$0.25 = $4.09

y*$0.11 + $11.50 - y*$0.50 = $4.09

y*($0.11 - $0.50) = $4.09 - $11.50

y*(-$0.39) = -$7.41

y = (-$7.41)/(-$0.39) = 19

if y = 19, then x = 19

By using the first equation:

x + y + z = 46

19 + 19 + z = 46

z = 46 - 19 - 19  = 8

We can conclude that:

If you want to learn more about systems of equations, you can read:

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Answer:

See below

Step-by-step explanation:

Extreme values of a function are found by taking the first derivative of the function and setting it equal to 0. To determine if it's a minimum or maximum, we set the second derivative equal to 0 and determine if its positive or negative respectively.

Let's do [tex]f(x)=3x^4+2x^3-5x^2+7[/tex] as an example

By using the power rule where [tex]\frac{d}{dx}(x^n)=nx^{n-1}[/tex], then [tex]f'(x)=12x^3+6x^2-10x[/tex]

Now set [tex]f'(x)=0[/tex] and solve for [tex]x[/tex]:

[tex]0=12x^3+6x^2-10x[/tex]

[tex]0=2x(6x^2+3x-5)[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-3\pm\sqrt{3^2-4(6)(-5)}}{2(6)}[/tex]

[tex]x=\frac{-3\pm\sqrt{9+120}}{12}[/tex]

[tex]x=\frac{-3\pm\sqrt{129}}{12}[/tex]

[tex]x=-\frac{3}{12}\pm\frac{\sqrt{129}}{12}[/tex]

[tex]x=-\frac{1}{4}\pm\frac{\sqrt{129}}{12}[/tex]

[tex]x_1=0,x_2\approx0.6965,x_3=-1.1965[/tex]

By plugging our critical points into [tex]f(x)[/tex], we can see that our extreme values are located at [tex](0,7)[/tex], [tex](0.6965,5.956)[/tex], and [tex](-1.1965,2.565)[/tex].

The second derivative would be [tex]f''(x)=36x^2+12x-10[/tex] and plugging in our critical points will tell us if they are minimums or maximums.

If [tex]f''(x)>0[/tex], it's a minimum, but if [tex]f''(x)<0[/tex], it's a maximum.

Since [tex]f''(0)=-10<0[/tex] then [tex](0,7)[/tex] is a local maximum

Since [tex]f''(0.6965)=15.822>0[/tex], then [tex](0.6965,5.956)[/tex] is a local minimum

Since [tex]f''(-1.1965)=27.18>0[/tex], then [tex](-1.1965,2.565)[/tex] is a global minimum

Therefore, the extreme values of [tex]f(x)=3x^4+2x^3-5x^2+7[/tex] are a global minimum of [tex](-1.1965,2.565)[/tex], a local minimum of [tex](0.6965,5.956)[/tex], and a local maximum of [tex](0,7)[/tex].

Hope this example helped you understand! I've attached a graph to help you visualize the extreme values and where they're located.

To prove that tan(u - v) does not equal tan u - tan v, we start by assuming values for u and v.

To do this, we assume the following values

[tex]\mathbf{u = 75}[/tex]

[tex]\mathbf{v = 45}[/tex]

So, we have:

[tex]\mathbf{tan(u - v) \ne tan(u) - tan(v)}[/tex]

Substitute the assumed values for u and v

[tex]\mathbf{tan(75 - 45) \ne tan(75) - tan(45)}[/tex]

Subtract 45 from 75

[tex]\mathbf{tan(30) \ne tan(75) - tan(45)}[/tex]

Using a calculator, calculate the values of tan(30), tan(45) and tan(75)

So, we have:

[tex]\mathbf{0.5774 \ne 3.7321 - 1}[/tex]

Subtract 1 from 3.7321

[tex]\mathbf{0.5774 \ne 2.7321}[/tex]

Notice that the expression on the left-hand side and the expression on the right-hand side are not equal.

Hence, [tex]\mathbf{tan(u - v) \ne tan(u) - tan(v)}[/tex] is true

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Answer:

lower left

Step-by-step explanation:

v+3<=6.5

v<=3.5

-18 is less than 3.5

Step-by-step explanation:

It can't be the first one because [tex]v=-18[/tex] and were saying [tex]-v[/tex] and to negatives make a positive so our equation is

[tex]18+3[/tex] ≤[tex]-6.5[/tex] which is incorrect

The one below the first one is incorrect

It's correct since our equation is

[tex]-18+3\leq 6.5[/tex] which is correct

The top right one is correct because our equation is

[tex]18+3\leq 6.5[/tex] which is incorrect

The one below that is correct because our equation is

[tex]-18+3\geq 6.5[/tex] which is incorrect

Answer:

c = 2.

Step-by-step explanation:

When the first part of the function has the value 0,  f(x) will also be 0 if the c wasn't there.

So the value of c is 2.

From the given graph n is a positive odd number.

Exponential function, as its name suggests, involves exponents. But note that, an exponential function has a constant as its base and a variable as its exponent but not the other way round (if a function has a variable as the base and a constant as the exponent then it is a power function but not an exponential function).

From the graph,

All the values of the graph are positive values (even for the negative values of x), but in the left side we can see that the function decreases and is different than the right side.

So this is not an even function, then n must be an odd number (n odd allows us to have negative values for y = f(x) that happen when x + k is negative).

Also, we can see that the function increases, if n was a negative number, like: n = -N

We would have: [tex]f(x)=\frac{a}{(x+k)^{\frac{1}{N} }} +c[/tex]

So in this case x is in the denominator, so as x increases, we would see that the value of y decreases, but that does not happen, so we can conclude that the value of n must be positive.

Then n is a positive odd number.

Therefore, n is a positive odd number.

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Answer:

parallel, perpendicular are opposite

Answer:

PARALLEL PERPENDICULAR

Step-by-step explanation:

Answer:

Gross Pay for 1 paycheck

Deductions for federal tax, state tax, and city tax hope it helps :)

Step-by-step explanation:

The net monthly income of Jason is $194.68 and the net annual salary is 23324.16.

Gross pay of an employee is basically sum of his basic pay, dearness allowance, any other allowance only. Public providend fund, income tax are not deducted from it.

1) Gross paycheck=2*40*25.5=$2040.

2) Federal tax=2040*21%=$428.4

3) State tax=25=$25

4) City tax=2040*12%=$244.8.

5) Deductions=2040*12.45=$252.96.

6) Net monthly income=2*(Gross pay-federal tax-state tax-city tax-deductions-deductions for F.IC.A. or social security tax)

=2*[2040-428.4-25-244.8-252.96-117]

=1943.68

7) Net annual salary=12* net monthly income.

=1943.68*12  ( 1year= 12 months)

=$23324.16

Hence the net monthly income of Jason is $194.68 and the net annual salary is 23324.16.

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Answer: x=-2

Step-by-step explanation:

Add three to both sides of the equation

4x-3=2x+7

4−3+3=2−7+3

simplify

4=2−4

4−2=2x-4−2

simplify

2=−4

Divide both sides of the equation by the same term

2=−4

2/2=−4/2

=−2

Answer: x = 5

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.x=5

Answer:

Yep, they are all correct

Both the answers are correct

Answer:

25x - 4

Step-by-step explanation:

10x + 2 + 8x + 7x - 6

= 25x - 4

A parallelogram is a figure which has its opposite sides to be equal and parallel. The missing reason in the proof is:

B. Substitution Angle Angle Postulate.

A parallelogram is a type of quadrilateral that has its opposite sides to be equal and parallel. The sum of its internal angles is [tex]360^{o}[/tex].

To prove that ∠ BAD ≅ ∠ DCB, we have:

Given parallelogram ABCD;

<BAC ≅ <ACD (alternate angle theorem)

<DAC ≅ <ACB (alternate angle theorem)

<BAC + <DAC = <BAD

Also,

<BCA + <DCA = <BCD

Therefore,

<BAD ≅ <DCB (Substitution Angle Angle Postulate)

Thus, the missing reason in the partial proof is:

option B. Substitution Angle Angle Postulate

A sketch is attached to this question for more clarifications.

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Answer:

Step-by-step explanation:

1.

all the lines with slope 2 are parallel with each-other

all the lines with slope 1/3 are parallel with each-other

2.

all lines have positive slope so they go upward from left to right

3.

slope 2 is steeper then slope 1/3

4.

the distance between the parallel lines with slope (1/3) is greater for the lines with the slope 2

Btw also found a spelling mistake in the question:instead of newtons you put netwons-      lol-

btw  

Rounded to the nearest thousandth would be 4.444 Newtons (same units you solved for k with)

But anyway here you go:

Answer:

19 or 17

Step-by-step explanation:

Answer:

X = 25

Step-by-step explanation:

To find the hypotenuse of a right triangle you use pythagorean theorm Where C = Hyp

A = Leg1

B = Leg 2

A^2 + B^2 = C^2

7^2 + 24 ^2 = x^2

49 +  576 = x^2

625 = X^2    (Square root both sides)

25 = x

-- Gage Millar, Algebra 1/2 tutor

Answer:

229

Step-by-step explanation:  do 1000-771 and u get the answer

Answer:

229

Step-by-step explanation:

To find how many are left, do the total minus the amount found:

1000 - 771 = 229

The number is 3947

It should be noted that 36 hundreds will be equal to:

= 36 × 100

= 3600

It should be noted that 34 tens will be:

= 34 × 10

= 340

7 ones will be:

= 7 × 1

= 7.

Therefore, the sum will be:

= 3600 + 340 + 7 = 3947

Answer:

3947

Step-by-step explanation:

Answer:

What do you need help with?

Step-by-step explanation:

Answer:

what is the problem?

Step-by-step explanation:

Answer:

The discount is $77, and the discount percent is 5%

Step-by-step explanation:

Discount: $1,540 - $1,463 = $77

Discount percent: $1,463 / $1,540 = 0.95, 1.00 - 0.95 = 0.05, 0.05 = 5%

Answer:

1/4, 3/5

Step-by-step explanation:

0.8/3.2=8/32=1/4

0.3/0.5=3/5

Answer:

x-2y=12

Solve for y

x-2y=12

Subtract x on both sides

-2y=-x + 12

Divide both sides by -2

y=\frac{1}{2}x - 6y=21x−6

the domain is {-3,-1,0,2,5}

Domain are the set of x values

Range are the set of y values

We are given with domain x, we need to find out y values using the equation y=\frac{1}{2}x - 6y=21x−6

when x=-3 , y=\frac{1}{2}(-3)-6=\frac{-15}{2}=-7.5y=21(−3)−6=2−15=−7.5

when x=-1 , y=\frac{1}{2}(-1)-6=\frac{-13}{2}=-6.5y=21(−1)−6=2−13=−6.5

when x=0 , y=\frac{1}{2}(0)-6=-6y=21(0)−6=−6

when x=2 , y=\frac{1}{2}(2)-6=-5y=21(2)−6=−5

when x=5 , y=\frac{1}{2}(5)-6=\frac{-7}{2}=-3.5y=21(5)−6=2−7=−3.5

Range is {-7.5, -6.5, -6 , -5, -3.5}

Step-by-step explanation:

solve the equation ? 1 equation with 2 variables ? that is not possible.

what you mean is probably find the range.

x - 2y = 12

-2y = -x + 12

2y = x - 12

y = (x - 12)/2 = (1/2)x - 6

x = -3

y = 1/2 × -3 - 6 = -1.5 - 6 = -7.5

x = -1

y = 1/2 × -1 - 6 = -0.5 - 6 = -6.5

x = 0

y = 1/2 × 0 - 6 = -6

x = 2

y = 1/2 × 2 - 6 = 1 - 6 = -5

x = 5

y = 1/2 × 5 - 6 = 2.5 - 6 = -3.5

so, the corresponding range of the function is

{-7.5, -6.5, -6, -5, -3.5}

2 − 3 = −5

First we need to Add 3 to both sides of the equation:

2 − 3 + 3 = −5 + 3

Then we simplify:

2 = −5 + 3

 2 = −2

Now we divide both sides of the equation by the same term:

2 / 2 = −2 / 2

Final answer: = −1

I hope this helps!

Answer:

Y= - 1

Step-by-step explanation:

2y-3= - 5

  +3    +3

   2y= -2

   /2    /2

Y= -1

Step 1: Add 3 to both sides because you want to cancel out the 3 so you do the opposite of what is say's. For example, if it says 2y-3 add 3 or 2y+3 subtract 3 from both sides.

Step 2: Add 3 to -5 which would be -2

Step 3: Since you're "multiplying" Y to 2 you're going to divide 2 to get Y by itself. So 2/2 cancels out and now you're left with y

Step 4: Divide 2 form -2 and you get -1

Let me know if you have any questions and I hope this helps

Answer:

Proof below.

Step-by-step explanation:

Let f(n)=10+ n^2 - (n - 2)^2.

We want to prove f is even for integer n > or = 1.

Let's show f is even for the base case, n=1.

f(1)=10+1^2-(1-2)^2

f(1)=10+1-(-1)^2

f(1)=11-(1)

f(1)=10

f(1) is even.

Let's assume the for some integer k > or = 1 , we have f(k) is even. This means there is some integer m so that f(k)=2m.

Note: f(k)=10+ k^2 - (k - 2)^2.

We want to show f(k+1) is even.

f(k+1)=10+ (k+1)^2 - ([k+1] - 2)^2

f(k+1)=10+ (k+1)^2 - (k-1)^2

f(k+1)=10+ ((k+1)^2 - (k-1)^2)

That difference is a difference of squares. Let's try factoring it.

f(k+1)=10+ (k+1-[k-1])(k+1+[k-1])

f(k+1)=10+ (2)(2k)

Multiply:

f(k+1)=10+4k

Turns out we didn't even need to use our induction hypothesis since 10+4k is 2(5+2k) which makes f(k+1) even given the factor of 2 present.

This proves for all integers n>=1 that f(n) is even.

We could have this without induction then. Let's do that here below this line.

-------------------

10+ n^2 - (n - 2)^2

10+[n^2 - (n - 2)^2]

Factor difference of squares:

10+(n-(n-2))(n+(n-2))

Simplify:

10+(2)(2n-2)

Factor:

2[5+(2n-2)]

Because of the factor of 2, the given expression is always even for integer n.

Step-by-step explanation:

option A is correct answer

Answer:

Should be C if not then A

Step-by-step explanation: