10 pointssss!!!!!:))
write the formula of the function y whose graph is shown.
a).
[tex]y = \frac{2}{x} [/tex]

b).
[tex]y = \frac{1}{ x } + 2[/tex]

c).
[tex]y = \frac{1}{x - 2} [/tex]


plss, I need helpp!!!!​

Answer:

x = - 1, x = - 0.5

Step-by-step explanation:

Given

2x(x + 1.5) = - 1 ← distribute parenthesis on left side

2x² + 3x = - 1 ( add 1 to both sides )

2x² + 3x + 1 = 0 ← in standard form

(2x + 1)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - 0.5

Answer:

A, it's the only one with a number greater then 1

Answer:

5.53°

Explanation:

Law of sines.

Considering only this customer's premiums, deductible, and claims, the break-even period after which the customer could make a $10,000 claim for property damage without the insurance company suffering a loss is 15 months.

At this break-even period, the company will not make a profit or a loss.

Data and Calculations:

Monthly insurance premium payable = $600 (assumed to be paid monthly)

Deductible on the insurance policy = $1,000

Minimum coverage = 30/50/10

Coverage for injury or death to one person = $30,000

Coverage for injury or death to two or more people = $50,000

Coverage for damage to property = $10,000

Average accidents every year = 2

Total claims cost to the insurance before deductibles = $40,000 ($30,000 + $10,000)

Break-even period = 15 ($10,000 - $1,000)/$600

This break-even period is computed by deducting the deductible from the claim that the customer makes, and then dividing the result by the monthly insurance premium.

Thus, the customer could make a $10,000 claim for property damage without the insurance company suffering a loss after 15 months' break-even period.  

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The depth of the mirror of the cross-section of a searchlight would be 8.33 cm if the light bub has a vertex at 3 cm and the mirror is 20 centimeters across at the origin.

A cross-section is perpendicular to the axis of the symmetry goes through the vertex of the parabola. The cross-sectional shape of the mirrored section of most searchlights or spotlights is parabolic.

Given:

a = 3

y = [tex]\frac{20}{2}[/tex] cm = 10 cm

Solution:

from the equation [tex]y^{2} = 4ax[/tex]

[tex]y^{2} = 4*3*x\\ y^{2} = 12x[/tex]

putting x, 10 cm in the equation

[tex]x=\frac{10^{2} }{12} \\\\x= \frac{100}{12} \\\\x= 8.33 cm[/tex]

thus, the depth of the mirror would be - 8.33 cm

Learn more about other problems of the parabola:

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Answer:

-13 1/2 < -6/8

Step-by-step explanation:

*Any negative in either the numerator or denominator will make the entire fraction negative.

1/2  = .5

-13 1/2 = -13.5

-6/8 = -3/4

-3/4 = -0.75

-6/8 = -0.75

-13 1/2 = -13.5

Which means:

-13 1/2 < -6/8

Hope this helped.

Answer:

[tex] < [/tex]

Step-by-step explanation:

[tex] \frac{6}{8} [/tex]

Is close to 0 (to positive) you can use a time line to determine which is a correct answer

Answer:

According to me,

Step-by-step explanation:

I think you first have to calculate a°,this can be done by first finding c°

c°=180-125

=55°

opposite angles in a quadrilateral add up to 180

therefore a°=180-55

=125

therefore angle d

180-125

=55

I hope this helps

Answer:

37.5%

Step-by-step explanation:

150/450 = .375 = 37.5%

The percentage is 150 grams out of 400 grams will be 37.5%.

The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol '%' is used to symbolize it.

The percentage is given as,

Percentage (P) = [Initial value - Final value] / Initial value x 100

It is given that the difference between the initial and final value is 15 grams and the initial value is 400 grams.

Then the percentage is 150 grams out of 400 grams will be

P = (150 / 400) x 100

P = 0.375 x 100

P = 37.5%

Thus, the percentage is 150 grams out of 400 grams will be 37.5%.

More about the percentage link is given below.

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Step-by-step explanation:

0 10

0-6

this is the answer. I am sure

The value of numbers are 6 and 10 which are a distance of 2 units from 8 on a number line.

Number line is a horizontal line where numbers are marked at equal intervals one after another form smaller to greater.

We have to given that;

Number line is shown in figure.

And, We have to find the value of numbers which are a distance of 2 units from 8 on a number line.

Now,

We can find the value of numbers as;

⇒ | 8 - 2 | = 6

⇒ | 8 + 2 | = 10

Therefore, The value of numbers are 6 and 10 which are a distance of 2 units from 8 on a number line.

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Answer:

hello,

answer C

Step-by-step explanation:

area of the rectangle=2b*b=2b²

area of the half cercle= [tex]\\\dfrac{\pi*(\frac{c}{2})^2}{2} =\dfrac{\pi*c^2}{8} \\[/tex]

Area in blue= 2b²-πc²/8

Answer:

29/14

Step-by-step explanation:

Start by working out the LCM of these (or any common denominator). A common denominator for 4 and 7 is 28 cuz 4 x 7 = 28.

3/4 = 21/28

4/7 = 16/28

3/4 = 21/28

(21+16+21)/28 = 58/28 which can simplify to 29/14

hi

Golden rule : you can only add or substract fraction if and only if they have the same denominator.

so two solutions :

you see that one denominator is a multiple of the second. so you multiply all the fraction by this multiple.

ex : 1/3 + 5/6

here I can easely convert 1/3 into a fraction with 6 as 6 is 3x2.

so : 1x2 = 2 and 3x2 = 6

1/3 is 2/6

so. 1/3 +5/6 = 2/6 +5/6

fraction have same denominator, I add numerators : 2/6 +5/6 =7/6

if it not that evident, you multiply fraction A up and down by denominator of fraction B.

and you multiply up and down fraction B by denomonator of fraction A

let' s see with your exemle :

3/4 +4/7+3/4 = ?

first I add fraction with same denominator :

3/4+3/4+4/7 = 6/4 +4/7

fraction A is 6/4.

I multiply up and down by denominator fractiok B which is " 7"

so. 6/4 = 6x7/4×7 = 42/28

let's apply method to fraction B whixh is 4/7 . let' multiply up and down by denominator of fraction A which is " 4"

so : 4/7 = 4x4 /7x4 = 16/28

now we have :

6/4 +4/7 = 42/28 +16/28

both my fractions have same denominator "28" so I add numerator :

42/28 +16/28 = 58/28

Now must wonder if 58/28 can be simplify. Good trick is to decompose numbers, and in prime number is the best way to do

58 = 2x29

28 = 7x2x2

so 58/28= (2×29)/ (7x2x2)

when there is same number up and down I can cross it out .

so here one "2" up and down can be rule out

so 58/28 = 2x29 /7×2×2 = 29/7x2 =29/14

I can not symplify more, so calculus is over.

in short :

3/4+4/7+3/4 = 6/4+4/7

= 42/28 +16/28

=58/28

= 29/14

Answer:

b) 6

Step-by-step explanation:

x - 4 = 2

x = 2 + 4

x = 6

Answer:

(-4, -1)

Step-by-step explanation:

The solution to the system of equations on a graph is the point in which they intersect. Therefore, the solution is (-4, -1).

Answer:

Individual package would be 3.83

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

Answer:

y= - 1.4

x= 0.2

Step-by-step explanation:

2x-Y= -1

x-2y=4

Answer: $1.1x

Step-by-step explanation:

At the end of year 1, it will increase by 10%:

[tex]x+0.1x=x(1+0.1)=1.1x[/tex]

Answer:

Step-by-step explanation:

3) Surface area of cube = 6a² where a is side of the cube.

a)  a = 6 cm

Surface area of cube = 6 * 6*6 = 216 cm²

b) a = 4.5 cm

Surface area of cube = 6 * 4.5 * 4.5 = 121.5 cm²

4)  Area of cuboid = A = 2(lb + bh + hl)

a) l = 10 cm ; h = 6 cm  ; A = 376 cm²

  A = 376

2(lb + bh + hl) = 376

2(10b + 6b + 60) = 376

2*( 16b + 60) = 376

 2*16b + 2*60 = 376

     32b + 120 = 376

        32b  = 376 - 120

          32b = 256

             b = 256 / 32

b = 8 cm

5) Surface area  of cube = 150 cm²

6a² = 150

Divide both sides by 6

a² = 150/6

a² = 25 = 5*5

a = 5 cm

6)  l = 15 cm ; b = 12 cm ; h = 10cm

Lidless. so area of top portion is not included

Surface area of lidless cuboid = 2(hb + hl) + lb

                                                  = 2*(10*12 + 10*15) + (15*12)

                                                  = 2*(120 + 150) + 180

                                                  = 2* 270 + 180

                                                  = 540 + 180

                                                   = 720 cm²

Step-by-step explanation:

Q5:Find the length of each side of the cube whose Total surface area are given below:

(B)2400cm^2

Solution:

T.S.A= 6a^2 [ we have to find a]

2400=6a^2

2400/6=a^2

400=a^2

a=squareroot of 400

=20

So, 20cm is the length of a cube.

[tex]\to \bold{|x-5.67|=0.02}\\\\[/tex]

heaviest[tex]\bold{=5.69\ g\\\\}[/tex]

lightest[tex]\bold{=5.65\ g\\\\}[/tex]

Evaluating each expression:  

[tex]\to \bold{q = -8}\\\\ \to \bold{r = -6}\\\\ \to \bold{t=3}[/tex]

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Answer:

(3x + 1)(x + 6)

3x^2 + 19x + 6

3x^2 + 18x + x + 6

3x^2 + 18x + x + 6

3x(x + 6) + x + 6

3x(x + 6) + x + 6

(3x + 1)(x + 6)

Haven't done this in a pretty long time so I might be wrong

Answer:

[tex]A' = (-2,2)[/tex]

[tex]B' = (2,2)[/tex]

[tex]C' = (2,-2)[/tex]

Step-by-step explanation:

Given

[tex]A = (-6,6)[/tex]

[tex]B = (6,6)[/tex]

[tex]C = (6,-6)[/tex]

[tex]k = \frac{1}{3}[/tex]

Required

The new coordinates

To do this, we simply multiply the coordinates of [tex]\triangle ABC[/tex] by the factor of dilation.

i.e.:

[tex]A' = A * k[/tex]

[tex]B' = B * k[/tex]

[tex]C' = C * k[/tex]

So, we have:

[tex]A' = (-6,6) * \frac{1}{3}[/tex]

[tex]A' = (-2,2)[/tex]

[tex]B' = (6,6) * \frac{1}{3}[/tex]

[tex]B' = (2,2)[/tex]

[tex]C' = (6,-6) * \frac{1}{3}[/tex]

[tex]C' = (2,-2)[/tex]

Answer:

D

Step-by-step explanation:

Answer:

It's D on there

Step-by-step explanation:

Answer:

Solution given:

Right angled triangle ABC is drawn where <C=[tex]\theta[/tex]

we know that

[tex]\displaystyle Sin\theta=\frac{opposite}{hypotenuse} =\frac{AB}{AC}[/tex]

[tex]\displaystyle Cos\theta=\frac{adjacent}{hypotenuse}=\frac{BC}{AC} [/tex]

Now

left hand side

[tex] \displaystyle {sin}^{2} \theta + {cos}^{2} \:\theta[/tex]

Substituting value

[tex](\frac{AB}{AC})²+(\frac{BC}{AC})²[/tex]

distributing power

[tex]\frac{AB²}{AC²}+\frac{BC²}{AC²}[/tex]

Taking L.C.M

[tex]\displaystyle \frac{AB²+BC²}{AC²}[/tex]....[I]

In ∆ABC By using Pythagoras law we get

[tex]\boxed{\green{\bold{Opposite²+adjacent²=hypotenuse²}}}[/tex]

AB²+BC²=AC²

Substituting value of AB²+BC² in equation [I]

we get

[tex]\displaystyle \frac{AC²}{AC²}[/tex]

=1

Right hand side

Answer:

It is 3/2, I got it right on my exam.

Step-by-step explanation:

Dilation is a transformation that allows you to resize an object. The dilation factor of the given point is 3/2.

Dilation is a transformation that allows you to resize an object. Dilation is a technique for making items bigger or smaller. This transformation yields a picture that is identical to the original shape. However, there is a size discrepancy in the form.

Given the dilation of the k around the origin as K = (2,4) → (3,6), therefore, the point k is dilated 1 unit to the right and 2 units upwards.

Let the dilation factor be represented by a, then,

2 × a = 3

a = 3/2

Similarly for the y-axis,

4 × a = 6

a = 6/4 = 3/2

Hence, the dilation factor of the given point is 3/2.

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Answer:

4x + 1

Step-by-step explanation:

(8x + 2) - (4x + 1)

subtract the terms that are common,,

8x-4x=4x

2-1=1

therefore, it would be 4x + 1

if you need more help with these, feel free to sub to gauthmath on subreddit

Answer:

i think

third option is correct.

cosY = 8 / 17, cotY = 8 / 15, secY = 17 / 8 is the required trigonometric functions of the same angle. Option C is correct

These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operations.

Here,
cosY = 8 / 17, cotY = 8 / 15, secY = 17 / 8
Is the trigonometric function of the same angle,
cosY = 1 / SecY
8 / 17 = 1 / secY
secY = 17 / 8
Now,
P = √[17² - 8²]
P = 15
CotY = 8 / 15

Thus, trigonometric functions in option C are of the same angle.

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Answer:

hope it helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

S is the midpoint of QR.

⇒ RS = QS    

QR ⊥ PS

⇒ ∠RSP = ∠QSP = 90°

In ΔPSR & ΔPSQ,

Statement                     Reason

RS ≅ QS                       S is midpoint of QR

∠RSP ≅ ∠QSP              QR ⊥ PS

PS ≅ PS                         Reflexive property

ΔPSR ≅ ΔPSQ               Side Angle Side - S A S Congruent

PR≅  PQ                        CPCTC

Answer:

[tex]area \: of \: a \: squre = {a}^{2} \\ {a}^{2} = 176 \\ a = 13.26m \\ perimeter = 4a = 4 \times 13.26 = 53.04m^2 \\ thank \: you[/tex]

Answer:

Concept:

Here, we need to know how to find the area and perimeter of the square.

Area (square) = s²

Perimeter (square) = 4s

Solve:

Given information

Area = 1764 m²

Given formula

A = s²

Substitute values into the formula

1764 = s²

Square root both sides

√s² = √1764

[tex]\boxed{s=42m}[/tex]

--------------------------------------------------------------------------------------------------------

Given information

s = 42 m

Given formula

P = 4s

Substitute values into the formula

P = 4 (42)

Simplify by multiplication

[tex]\boxed{P=168m}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

a.2×1= 2 + 3×1=3 +4×2=8 now we have to put this ans and the ans is 13.

b. 5×1×2=10 + 3×1×2=6+ 7×2×2=28 now also we have to put this ans and this ans is 13