Answer:
All of the above is the answer
Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough is commonly used with transverse waves!
Answer:
yes Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough are commonly used with transverse waves!
Explanation:
what changes must be done to the wire to increase its conductance.
Answer:
- Decreasing the resistance
- Using a shorter length
- Using a smaller area wire
Explanation:
Formula for conductance in wires is;
G = 1/R
Where;
G is conductance
R is resistance
This means that increasing the resistance leads to a larger denominator and thus a smaller conductance but to decrease the denominator means larger conductance.
Thus, to increase the conductance, we have to decrease the resistance.
Resistance here has a formula of;
R = ρL/A
Where;
ρ is resistivity
L is length of wire
A is area
Thus, to decrease the resistance, we will have to use a shorter length and smaller area of wire.
How do human activities lead to change in the weather?
Answer:
There is overwhelming evidence that human activities, especially burning fossil fuels, are leading to increased levels of carbon dioxide and other greenhouse gases in the atmosphere, which in turn amplify the natural greenhouse effect, causing the temperature of the Earth's atmosphere, ocean, and land surface to ...
How much Voltage is required to run 0.025 A of current through a 24 resistor?
Use AV = IR.
A. 960 V
B. 0.60 V
C. 1.7 V
D. 0.0010 V
OPTIONS:-
A. 960 V
B. 0.60 V
C. 1.7 V
D. 0.0010 V
FORMULA :- V= I× R
WHERE
I -> CURRENT
R -> RESISTANCE
so your answer:-
V= IR
[tex]V = 0.025 \times 24 \\ V = \frac{ \cancel{25}}{ \cancel{1000} {}^{ \: \: \: 40} } \times 24 \\ V = \frac{ \cancel4 \times 6}{ \cancel4 \times 10} \\ V = 0.60Volts[/tex]
so your ANSWER is OPTION B.
V = 0.60 Volts (V)
Two planetoids with radii R1 and R2 and local accelerations g1 and g2 are separated by a centre-to-centre distance D, and are members of a simple two-body system. A rocket is located on planetoid 1 and is scheduled to launch from this planetoid to a point between the planetoids where the net gravitational force on the rocket by the two planetoids is zero. At what distance from the centre of planetoid 1 is the zero gravitational point? Choose R1 = 1400m, R2 = 1000m, g1 = 7.5m/s2, g2 = 5.3m/s2 and D = 4800m. [5 points]
Answer:
Therefore, the gravitational zero points between two planetoids lie at a distance of 3000 m from the center of planetoid 1.
Explanation:
From Newton’s gravitation formula, the expression of the mass (M) of the planet of radius R is given as,
[tex]F_{G} = mg_{1}\\ \left ( \frac{GMm}{{R_{1}}^{2}} \right )=mg_{1}\\\\M= \frac{gR^{2}}{G}\rightarrow \left ( 1 \right )[/tex]
Let's take x to be the distance of the zero gravitational points from the center of the planetoid 1.
Thus, the distance of the zero gravitational points from the center of the planetoid 2 is (D-x).
At zero gravitational point, the gravitational force between the planets and the rocket must be equal.
In the image below, a free-body diagram represents the forces of several vehicles driving across a bridge. Assume that the bridge is in statio equilibrium and that it has zero weight, and solve for the unknown reaction force
A. 10,800 N
B. 65,200 N
C. 120,200 N
D. 53,400 N
Answer:
The answer is "57,400 N".
Explanation:
[tex]\Sigma F_y=0 \ \ \ \ \ \ \text{static equilibrium}\\\\\to 121,200+R=17800+150,000+10800\\\\R=57,400\ N[/tex]
The answer is 57,400 N because the choices are wrong.
how to find work done by load
Which Connects the ovary and uterus
given that the 180N weight causes a total extension of 30cm ,determine the spring constant of each spring (the weight of each spring is neglible)
Answer:600N/m
Explanation: Given ;
Applied force(F) = 180N
Total extension (l) = 30cm =0.30m
Spring constant(K) =?
From Hooke's law
F= kx
therefore k= F/x
k = 180N/0.3m
600N/m
the mass of piece of granite is 15.6g when it is suspended can a mass of 5.5g of water is displaced find the dencity of granite
Answer:
2836.36 kg/m³
Explanation:
Applying,
Densty of granite(D')/Density of water(D) = weight of granite(W')/weight of water displaced(W)
D'/D = W'/W................... Equation 1
Make D' the subject of the equation
D' = W'D/W............... Equation 2.
From the question,
Given: W' = mg = 9.8(15.6/1000) = 0.15288 N, W = 9.8(5.5/1000) = 0.0539 N, Constant: D = 1000 kg/m³
Substitute these values into equation 2
D' = 1000(0.15288)/0.0539
D' = 2836.36 kg/m³
what means 10² what we call this
we call it as well as 100 . so easey
Answer:
10 squared
Explanation:
10 squared
In Depth:
Let have a square that has a side length of 10.
A square four sides are equal and if we find the area of a squared, our formula is
[tex] {s}^{2} [/tex]
Our in this instance,
[tex] {10}^{2} [/tex]
or we call it
[tex]10 \: \: squared[/tex]
Why gases are easily compressed?
Answer:
photosynthesis is the process by which green leaves prepare their food in the presence of sunlight,air and water
What current flows through a 2.54cm diameter rod of pure silicon that is 20cm long when 1000V is applied?
Answer: [tex]0.0039\ A[/tex]
Explanation:
Given
Diameter of the rod [tex]d=2.54\ cm[/tex]
length of rod is [tex]l=20\ cm[/tex]
Resistivity of silicon is [tex]\rho=6.4\times 10^2\ \Omega-m[/tex]
cross-section of the rod [tex]A[/tex]
[tex]\Rightarrow A=\dfrac{\pi d^2}{4}\\\\\Rightarrow A=\dfrac{3.142\times 2.54^2\times 10^{-4}}{4}\\\\\Rightarrow A=5.067\times 10^{-4}\ m^2[/tex]
Resistance of rod is R
[tex]\Rightarrow R=\dfrac{\rho l}{A}[/tex]
[tex]\Rightarrow R=\dfrac{640\times 0.20}{5.067\times 10^{-4}}\\\\\Rightarrow R=25.26\times 10^4\ \Omega[/tex]
Current is given by
[tex]\Rightarrow I=\dfrac{V}{R}\\\\\Rightarrow I=\dfrac{1000}{25.26\times 10^4}\\\\\Rightarrow I=0.0039\ A[/tex]
Help please please
is calculate total distance travelled
Here's the fact that you need to know:
"The AREA under a speed/time graph is the distance traveled during the time covered by the graph."
Now ... What's the area of that nice trapezoid on the graph ?
Hint: Area of a trapezoid is
(1/2) • (height) • (base-1 + base-2)
A spinning top completes 6.00x10^3 rotations before it starts to topple over. The average speed of the rotations is 8.00x10^2 rpm. Calculate how long the top spins before it begins to topple
Answer:
Explanation:
This is simple logic. If the top can spin 6000 times before it starts to topple, and each minute the top can spin 800 times,
6000/800 = 7.50 minutes
The spinning top spins for approximately 450 seconds (or 7.5 minutes) before it begins to topple over.
To calculate the time it takes for the spinning top to begin toppling over, we can use the average speed and the number of rotations.
Given:
Number of rotations = 6.00 × 10^3 rotations
Average speed of rotations = 8.00 × 10^2 rpm (revolutions per minute)
To find the time, we need to convert the average speed from rpm to revolutions per second (rps). We can do this by dividing the average speed by 60 (as there are 60 seconds in a minute):
Average speed in rps = (8.00 × 10^2 rpm) / 60
Average speed in rps ≈ 13.33 rps
Now, we can calculate the time it takes for the spinning top to complete the given number of rotations:
Time = Number of rotations / Average speed in rps
Time = (6.00 × 10^3 rotations) / (13.33 rps)
Dividing these values:
Time ≈ 450 seconds
Therefore, the spinning top spins for approximately 450 seconds (or 7.5 minutes) before it begins to topple over.
To know more about spinning top spins
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Water, H2O ,and methane ,CH4, are both covalent substances . why is water a liquid at room temperature while methane is a gas ? A. Carbon compounds tend to be gases . B. Water has a stronger intermolecular forces
Un tren viaja inicialmente a 16m/s se acelera constantemente a razón de 2m/s2 en la misma dirección. ¿Cuán lejos viajará en 20s?
Answer:
d = 720 s
Explanation:
The question says, "A train initially traveling at 16m / s accelerates constantly at a rate of 2m / s2 in the same direction. How far will it travel in 20s?"
Initial speed, u = 16 m/s
Acceleration, a = 2m/s²
We need to find the distance covered by it in 20 seconds. Let the distance is d. Using the second equation of motion,
[tex]d=ut+\dfrac{1}{2}at^2\\\\d=16\times 20+\dfrac{1}{2}\times 2\times 20^2\\\\d=720\ m[/tex]
So, it will cover 720 m in 20 seconds.
An image of a car with height of 14 cm occurred in the mirror which is located at a T-intersection.if the car height is 140 cm and the radius of the curvature of the mirror is 60 cm, how far is the car from the mirror?
Answer:
The distance of the car from the mirror is 10 times the distance of the image of the car from the mirror
Explanation:
The parameters of the mirror image are;
The height of the car's image, h' = -14 cm (The image is inside the mirror and therefore, -ve)
The height of the car, h = 140 cm
The radius of curvature of the mirror, R = 60 cm
The mirror formula is given as follows;
[tex]\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}[/tex]
Where;
u = The distance of the car from the mirror
v = The distance of the image of the car from the mirror
f = The focus of the mirror ≈ R2
The focus of convex mirrors is negative, therefore, f = -62 cm/2 = -32
[tex]The \ magnification,\, m = \dfrac{h'}{h} = \dfrac{v}{u}[/tex]
Therefore, we get;
[tex]The \ magnification,\, m = \dfrac{14}{140} = \dfrac{v}{u}[/tex]
14·u = 140·v
∴ u = 140·v/14 = 10·v
The distance of the car from the mirror = 10 × The distance of the image of the car from the mirror
A 3.00 kg box sliding west at 2.00 m/s makes an inelastic collision with a second box sliding 1.50 m/s east. Afterwards, they both come to a stop. What was the mass of the second box?
Let west be the negative direction, and east be positive. Then the total momentum of the system is conserved such that
(3.00 kg) (-2.00 m/s) + m (1.50 m/s) = 0
Solve for m :
m = (3.00 kg) (2.00 m/s) / (1.50 m/s) = 4.00 kg
A stone is thrown, run a velocity of 15m/s is projected of an elevation of 30° to the horizontal calculate the time rate of flight
Answer:
1.53 seconds
Explanation:
Applying,
T = 2usin∅/g................ Equation 1
Where, T = time of flight, u = initial velocity, ∅ = angle of projectile to the horizontal, g = acceleration due to gravity
From the question,
Given: u = 15 m/s, ∅ = 30°
Constant: g = 9.8 m/s²
Substitute these values in equation 1
T = 2(15)(sin30°)/9.8
T = 15/9.8
T = 1.53 seconds
Hence the time rate of flight is 1.53 seconds
A sound wave traveling at 340 m/s is generated by a 480 Hz tuning fork.
How long is the sound wave?
Answer:
Wavelength = 0.7083 meters
Explanation:
Given the following data;
Speed of wave = 340 m/s
Frequency = 480 Hz
To find how long is the sound wave, we would determine its wavelength;
Mathematically, the wavelength of a waveform is given by the formula;
Wavelength = velocity/frequency
Wavelength = 340/480
Wavelength = 0.7083 meters
6. The electric force between two charged objects is influenced by
Answer:
the amount of each charge and the distance between them. ... Coulomb's law states the the electric force between two charges is proportional to the product of the two charges and inversally proportional to the square distance that separates their centers.
a &b
1 point
98. In the change in temperature
1°C > 1K
1°C < 1K
1°C = 1 K
1°C > 1.8K
a
Explanation:
1 degree celcious is the change
write some uses of magnetic force
Answer:
television,radios, microwave ovens, telephone system and computer
the distance between any two bodies is 10 M and the gravitational force between them is 3.2×10-⁹m. if the mass of one object is 40 kg, calculate the mass of another body. (And:119.9 kg)
Answer:
0.8 x 10^-9 kg
Explanation:
Given,
Distance ( R ) = 10 m
Force ( F ) = 3.2 x 10^-9 N
Mass ( m1 ) = 40 kg
To find : Mass ( m2 ) = ?
Formula : -
F = m1.m2 / R^2
m2 = FR^2 / m1
= 3.2 x 10^-9 x 10 / 40
= 3.2 x 10^-9 / 4
= ( 3.2 / 4 ) x 10^-9
m2 = 0.8 x 10^-9 kg
Using your Periodic Table, which of the following elements below has the largest atomic radius? A.) Aluminum B.) Sodium C.) Sulfur, D.) Fluorine
Answer:
sodium
Explanation:
it is highly reactive metal.
Answer:
aluminium
Explanation:
In a period , as we go from left to right in a periodic table, atomic number increases .
Differentiating electrons enters into same shell hence the effective nuclear charge decreases .
Hence atomic radius decreases along period.
Conculsion:
Aluminium is the element which has greater atomic radius and sulphur has smaller atomic radius.
PLS HELP ME I DONT HAVE MUCH TIME LEFT
The Euler buckling load of a 160-cm-long column will be _____ times the Euler buckling load of an equivalent 120-cm-long column.
1.78
0.56
0.75
2.37
1.33
0.42
Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 3 cm and 8 cm.
201 cm4
18 cm4
128 cm4
4 cm4
24 cm4
Answer:
A certain source of 12V with an internal resistance 1colomb is connected to 5colomb external resistance what is the current
A force of 1250N is used to move a 50kg body along a rough horizontal plane. if the coefficient of fiction is 1.2 what is the acceleration of the body from rest
Answer:
Explanation:idek
The net force acting on the body will be 250 N since there is significant friction also. Thus, the acceleration of the 50 Kg body is 5 m/s².
What is friction?Friction is a kind of force acting on a body to resist it from motion. Thus, frictional force will always be negative. The frictional force acting on a body is the the product of the coefficient of friction and the normal force.
Here the normal force = 1250 N
coefficient of friction = 1.2
Frictional force = 1250 N × 1.2 = 1500 N
Net force = 1500 N - 1250 N = 250 N
Acceleration = net force/ mass
= 250 N/50 Kg
= 5 m/s²
Therefore, the acceleration of the body from rest is 5 m/s².
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Which model of the universe is the most widely accepted, and what does it
predict?
The world’s tallest building is the Burj Khalifa which stands at 828 m above the ground. An eccentric billionaire CEO has an office on the top floor. He insists on having a personal elevator installed that consists only of a giant spring that spans from the basement to his office when it is uncompressed. If his mass is 120 kg, what spring constant in N/m is required so that he momentarily comes to rest on the ground floor?
Answer:
The spring constant is approximately 2.84 N/m
Explanation:
The height of the building, h = 828 m
The mass of the billionaire that has an office on the top floor, m = 120 kg
Gravitational potential energy, P.E. = m·g·h
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
The gravitational potential energy of the billionaire at the top floor is therefore;
P.E. of billionaire at top floor = 120 kg × 9.81 m/s² × 828 m = 974,721.6 J
The elastic potential energy of the spring, [tex]P.E._{spring}[/tex] is given as follows;
[tex]P.E._{spring} = \dfrac{1}{2} \cdot k \cdot h^2[/tex]
Where;
k = The spring constant of the spring in N/m
h = The extension of the spring = The height of the building = 828 m
Given that the energy of the spring is conserved, we have;
[tex]P.E._{spring}[/tex] = P.E. of billionaire = 974,721.6 J
Plugging in the values gives;
[tex]P.E._{spring} = 974,721.6 \ J = \dfrac{1}{2} \times k \times (828 \ m)^2[/tex]
Therefore;
2*974,721.6/(828^2)
[tex]k = \dfrac{2 \times 974,721.6 \ J}{(828 \ m)^2} \approx 2.84 \ N/m[/tex]
The spring constant, k ≈ 2.84 N/m.
