1. A rational number between √2 and √3 is

Using the power property to simplify the expression (9¹⁺⁴)⁷⁺², we have 9^7/8

Given the expression

(9¹⁺⁴)⁷⁺²

To simplify this expression using the power of a power property, we need to multiply the exponents:

(9¹⁺⁴)⁷⁺² = 9(¹⁺⁴ ˣ ⁷⁺²)

Simplifying the exponents in the parentheses:

(9¹⁺⁴)⁷⁺² = 9⁷⁺⁸ or 9^7/8

Therefore, (9¹⁺⁴)⁷⁺² simplifies to 9^(7/8).

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In response to the stated question, we may state that We know that these two angles are complimentary since their total is 90 degrees.

An angle is a form in Euclidean geometry that is composed of a pair of rays, known as such angle's sides, that meet at a center point known as the angle's vertex. Two rays may merge to generate an angle in the plane in which they are located. An angle is formed when two planes collide. They are known as dihedral angles. In plane geometry, an angle is a potential arrangement of two rays or lines whose share a termination. The English term "angle" is derived from the Latin word "angulus," which means "horn." The apex is the point in which the two rays, often known as the angle's sides, converge.

Angle Sum Theorem formal definition:

The total of the three interior angles of a triangle is always equal to 180 degrees.

The Angle Sum Theorem states:

According to the Angle Sum Theorem, the sum of a triangle's internal angles is always equal to 180 degrees. In other terms, using new numbers:

Consider a triangle having three angles of 70 degrees, 60 degrees, and 50 degrees. The Angle Sum Theorem states that the sum of these angles should be 180 degrees.

[tex]70 + 60 + 50 = 180\\90 + x + y = 180\sx + y = 90[/tex]

We know that these two angles are complimentary since their total is 90 degrees.

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Option A: The factor (96 − 2x) represents the length, in inches, of the uncovered portion of the bulletin board.

To obtain the area of a rectangle, you need to multiply the dimensions of the rectangle, which are the length and the width.

Hence the formula for the area of the rectangle is given as follows:

Area = Length x Width.

The area of the uncovered region is given by the total area subtracted by the area of the covered region.

Then the dimensions for the uncovered region are given as follows:

The area of the covered region is given as follows:

4x².

The area of the entire region is given as follows:

4x² - 288x + 4608.

Hence the correct statement is given by option A.

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a) The probability of no orders in 5 minutes is calculated to be 0.36788.

b) The probability of three or more orders in 5 minutes is calculated to be 0.08.

c) The length of the time interval such that the probability of no orders in a time interval of this length is 0.001 is calculated to be 34.5 min.

X is assumed to be the poisson's distribution where λ = 12 orders per hour.

a) At T = 1/12 hours which is 5 min, probability of no orders,

P (X = 0) = e^(-12/12) = 0.36788

b) At T = 1/12 hours which is 5 min, probability of three or more orders,

P (X ≥ 3) = 1 - P (X ≤ 2) = 1 - e⁻¹(1 + 1 + 1/2) = 0.08

c) Let us find the interval T for which:

P (X = 0) = 0.001

e^(-12T) = 0.001

Solving the equation for T we have,

T = -1/12 ln(0.001) = 0.5756 hours = 34.5 min

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a) Velocity vector v(t) = i - 2tj, Speed s(t) = sqrt(1 + 4t²), Acceleration vector a(t) = -2j. b) Velocity vector v(1) = i - 2j, Acceleration vector a(1) = -2j

This problem is about finding the velocity, speed, and acceleration vectors of an object moving in the xy-plane, described by a position vector r(t). We can find the velocity vector by taking the derivative of the position vector, and the speed by taking the magnitude of the velocity vector. The acceleration vector can be found by taking the derivative of the velocity vector. We can then evaluate the velocity and acceleration vectors at a given point by plugging in the coordinates of the point. This problem requires basic vector calculus and understanding of the relationship between position, velocity, speed, and acceleration vectors.

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Complete question is attached below

Answer:

I think its 30

Step-by-step explanation:

The length of JK is 18.333.

Since MN is parallel to JK, the angles formed by JLN and MLK are equal. Therefore, we can use the Triangle Proportionality Theorem, which states that if a line parallel to one side of a triangle divides the other two sides proportionally, then the triangles are similar.

Using the Triangle Proportionality Theorem, we can set up the following proportion:

[tex]$\frac{LK}{JL} = \frac{MN}{LN}$[/tex]

Therefore,

[tex]$\frac{7.2}{13.2} = \frac{10}{6}$[/tex]

We can cross-multiply to solve for JK:

[tex]$7.2 \cdot 6 = 13.2 \cdot 10$\\$43.2 = 132$\\$JK = \frac{132}{7.2} = 18.333$[/tex]

Therefore, the length of JK is 18.333.

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The z-score for 12 beers per week is (+3). This is calculated by (12-7)/1.5 = +3.

1. 5 beers per week: z-score = -1

2. 8 beers per week: z-score = +1

3. 10 beers per week: z-score = +2

4. 4 beers per week: z-score = -2

5. 6 beers per week: z-score = -0.5

6. 12 beers per week: z-score = +3

To calculate a z-score, we need to know the mean (μ) and standard deviation (σ) of the population. In the given problem, the mean is 7 beers per week, and the standard deviation is 1.5.

A z-score is the number of standard deviations away from the mean. Therefore, to calculate the z-scores, we subtract the mean from the given data point and divide by the standard deviation.

For example, for 5 beers per week, the z-score is (-1). This is calculated by subtracting the mean (7) from the data point (5) and dividing by the standard deviation (1.5). Therefore, (5-7)/1.5 = -1.

Similarly, the z-score for 8 beers per week is (+1). This is calculated by (8-7)/1.5 = +1. The z-score for 10 beers per week is (+2). This is calculated by (10-7)/1.5 = +2. The z-score for 4 beers per week is (-2). This is calculated by (4-7)/1.5 = -2. The z-score for 6 beers per week is (-0.5). This is calculated by (6-7)/1.5 = -0.5.The z-score for 12 beers per week is (+3). This is calculated by (12-7)/1.5 = +3.

the complete question is :

The average American drinks approximately seven beers per week (mean = 7). Assuming a standard deviation of 1.5 (SD = 1.5), calculate the corresponding z-scores for the following 6 Americans’ weekly beer intake:

a) Bob drinks 9 beers per week

b) Sarah drinks 6 beers per week

c) John drinks 4 beers per week

d) Emily drinks 8 beers per week

e) Michael drinks 10 beers per week

f) Rachel drinks 5 beers per week

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A parametric equation is one where the x and y coordinates of the curve are both written as functions of another variable called a parameter; this is usually given the letter t or θ . And the value of a= 8, b= 1, c= -2 and d= 0.

Equation of this form is known as a parametric equation; it uses an independent variable known as a parameter (often represented by t) and dependent variables that are defined as continuous functions of the parameter and independent of other variables.
You require 4 independent solutions because there are 4 unknowns.  You can put two equations at each end point if you know t at each end point. (one for the x value and one for the y value).
At (8,-2), time is equal to zero as follows: 8 = a + bt = a + b(0)  a = 8 -2 = c + dt = c + d(0)  c = -2
At (9,-2), t = 1 because 9 = a + bt = 8 + b(1)  b = 1 and -2 = c + dt = -2 + d(1)  d = 0.
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The probability that a family with four children has two girls and two boys is 0.3734, or approximately 0.3734 rounded to four decimal places. We can solve it in the following manner.

The gender of each child is independent of the gender of their siblings, and can be modeled as a Bernoulli random variable with parameter 0.49 for female and 0.51 for male. Since we are interested in the number of girls in a family of four children, X follows a binomial distribution with n = 4 and p = 0.49.

The probability of having exactly 2 girls and 2 boys can be calculated using the binomial probability mass function:

P(X = 2) = (4 choose 2) * 0.49² * 0.51²

= 6 * 0.2401 * 0.2601

= 0.3734

Therefore, the probability that a family with four children has two girls and two boys is 0.3734, or approximately 0.3734 rounded to four decimal places.

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The length of RS is 13 units and the length of the hypotenuse XY is approximately 16.4 units.

15) In ΔTSR

TR² = TS² + RS²

Substituting the given values, we get:

(5√10)² = 9² + RS²

250 = 81 + RS²

RS² = 169

Taking the square root of both sides, we get:

RS = 13 units

16)In ΔYZX

XY² = YZ² + XZ²

Substituting the given values, we get:

XY² = 10² + 13²

XY² = 169 + 100

XY² = 269

Taking the square root of both sides, we get:

XY = √269

XY=16.4 units

What is Pythagorean theorem?

In a right triangle, the Pythagorean theorem states that the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

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The likelihood function can be factored using Theorem 9.4 as L(p) = L(X₁, X₂, ..., Xn | p) = g(Σⁿᵢ=1Xᵢ, p) * h(X₁, X₂, ..., Xn), where g(Σⁿᵢ=1Xᵢ, p) = p^Σⁿᵢ=1Xᵢ (1-p)^(n-Σⁿᵢ=1Xᵢ) and h(X₁, X₂, ..., Xn) = 1. This satisfies the factorization criterion, and thus, Σⁿᵢ=1Xᵢ is a sufficient statistic for p.

To show that Σⁿᵢ=1Xᵢ is sufficient for p, we need to show that the likelihood function can be factored using Theorem 9.4 as:

L(p) = L(X₁, X₂, ..., Xn | p) = g(Σⁿᵢ=1Xᵢ, p) * h(X₁, X₂, ..., Xn)

where g(Σⁿᵢ=1Xᵢ, p) is a function only of Σⁿᵢ=1Xᵢ and p, and h(X₁, X₂, ..., Xn) is not a function of p.

First, we can write the joint probability mass function of X₁, X₂, ..., Xn as:

P(X₁ = x₁, X₂ = x₂, ..., Xn = x_n) = p^Σⁿᵢ=1xᵢ (1-p)^Σⁿᵢ=1(1-xᵢ)

Taking the product of these probabilities for all i, we get:

L(p) = L(X₁, X₂, ..., Xn | p) = Πⁿᵢ=1P(Xᵢ = xᵢ) = p^Σⁿᵢ=1Xᵢ (1-p)^Σⁿᵢ=1(1-Xᵢ)

Using the factorization criterion given in Theorem 9.4, we need to find functions g(u, p) and h(X₁, X₂, ..., Xn) such that:

L(p) = L(X₁, X₂, ..., Xn | p) = g(Σⁿᵢ=1Xᵢ, p) * h(X₁, X₂, ..., Xn)

Let's take g(u, p) = pᵘ(1-p)⁽ⁿ⁻ᵘ⁾, which only depends on u and p. Then:

L(p) = L(X₁, X₂, ..., Xn | p) = g(Σⁿᵢ=1Xᵢ, p) * h(X₁, X₂, ..., Xn)

= p^Σⁿᵢ=1Xᵢ (1-p)^Σⁿᵢ=1(1-Xᵢ) * h(X₁, X₂, ..., Xn)

We can see that the term Σⁿᵢ=1Xᵢ appears in the exponent of p, and Σⁿᵢ=1(1-Xᵢ) appears in the exponent of (1-p). Therefore, we can write:

L(p) = L(X₁, X₂, ..., Xn | p) = [p^Σⁿᵢ=1Xᵢ (1-p)^Σⁿᵢ=1(1-Xᵢ)] * [1]

where the second factor is a constant function of p. This satisfies the factorization criterion, with g(u, p) = pᵘ(1-p⁽ⁿ⁻ᵘ⁾ and h(X₁, X₂, ..., Xn) = 1.

Therefore, we have shown that Σⁿᵢ=1Xᵢ is a sufficient statistic for p.

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Complete question is in the image attached below

The ROC of a given signal's Z-transform can be determined without actually computing the Z-transform by identifying the maximum and minimum magnitude of the signal and checking for any poles of the Z-transform within the resulting annular region.

Let's take a signal as an example, suppose x[n] = {1, -2, 3, -4, 5}. In order to determine the ROC of its Z-transform, we are firstly required to first look for any regions in the complex plane where the sum of the absolute values of the Z-transform is found finite. It can be done by looking for the maximum and minimum magnitude of x[n] and denote them as R1 and R2 respectively. Then, the ROC of the Z-transform will be the annular region between R1 and R2, excluding any poles of the Z-transform that lie within this annular region.

In this case, the maximum absolute value of x[n] is 5 and the minimum is found being 1. So, the ROC of the Z-transform will be the annular region between |z| = 1 and |z| = 5. We can denote this as 1 < |z| < 5. We also need to check if there are any poles of the Z-transform within this annular region. Since we haven't actually computed the Z-transform, we cannot determine the exact location of any poles.

However, we can check for any values of z that would make the Z-transform infinite. For example, if x[n] is a causal signal (i.e., x[n] = 0 for n < 0), then the ROC cannot include any values of z for which |z| < 1, since this would make the Z-transform infinite.

So, the ROC of the Z-transform for the given signal x[n] can be written as 1 < |z| < 5, assuming that x[n] is a causal signal.

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The complete question is :

Can you explain how to determine the ROCs (regions of convergence) for the Z-transform of a given signal without actually computing the Z-transform? Please provide an example signal with random data and demonstrate how to find its ROCs using this method.

Answer:

Step-by-step explanation:

To find the limit of (n!)^(1/n) as n approaches infinity, we can use the Stirling's approximation for n!, which is:

n! ≈ (n/e)^n √(2πn)

where e is the mathematical constant e ≈ 2.71828, and π is the mathematical constant pi ≈ 3.14159.

Using this approximation, we can rewrite (n!)^(1/n) as:

(n!)^(1/n) = [(n/e)^n √(2πn)]^(1/n) = (n/e)^(n/n) [√(2πn)]^(1/n)

Taking the limit as n approaches infinity, we have:

lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n)

Using the fact that lim a^(1/n) = 1 as n approaches infinity for any constant a > 0, we can simplify the second term as:

lim [√(2πn)]^(1/n) = 1

For the first term, we can rewrite (n/e)^(n/n) as [1/(e^(1/n))]^n and use the fact that lim a^n = 1 as n approaches infinity for any constant 0 < a < 1. Thus, we have:

lim (n/e)^(n/n) = lim [1/(e^(1/n))]^n = 1

Therefore, combining the two terms, we have:

lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n) = 1 x 1 = 1

Hence, the limit of (n!)^(1/n) as n approaches infinity is 1.

Answer:1

Step-by-step explanation:

The 5-number summary in the given situation is:

Minimum = 4; Q1 = 8; Median = 12; Q3 = 16; Maximum = 20

When conducting descriptive analyses or conducting an initial analysis of a sizable data set, a five-number summary is particularly helpful.

The maximum and minimum values in the data set, the lower and upper quartiles, and the median make up a summary's five values.

A five-number summary is a tool for exploratory data analysis that sheds light on how values for a single variable are distributed.

These statistics represent the distribution of data values, as well as their central tendency, variability, and overall shape.

So, 5 number summary would be:

Minimum = 4

Q1 = 8

Median = 12

Q3 = 16

Maximum = 20

Therefore, the 5-number summary in the given situation is:

Minimum = 4; Q1 = 8; Median = 12; Q3 = 16; Maximum = 20

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Hey!
A: 50% Of people = 150 people prefer oranges.

B: 10% Of people = 15 people prefer pineapple.

C: 15% Of people = 20 people prefer blueberries.

D: 5% Of people = 5 people prefer apples.

E: 20% Of people = 22 people prefer strawberries

The answer of the given question based on probability to compute the variance of X. Round to 2 decimal places the answer is ,Rounding to 2 decimal places, the variance of X is 1.31.

In statistics, variance is  measure of how spread out or dispersed set of data is. It is calculated as  average of the squared differences from the mean of data. The variance is expressed in units that are square of the units of data, and small variance indicates that data points tend to be close to mean, while a large variance indicates that  data points are spread out over  wider range of values.

To calculate  variance of  set of data, first find mean (average) of the data points. Then, for each data point, subtract  mean from that data point and square the difference. Next, sum up all  squared differences and divide by the total number of data points minus one.

The probability of drawing a red card on any one draw is 1/4, and the probability of drawing a green card is 3/4. Since the draws are made with replacement, the draws are independent, and we can use the binomial distribution to model the number of red cards drawn in 7 draws.

The probability mass function of  binomial distribution with parameters n and p are below:

P(X = k) =(n choose k) *p^k*(1-p)^(n-k)

In this case, we have n = 7 and p = 1/4, so the probability mass function of X is:

P(X = k) = (7 choose k) * (1/4)^k * (3/4)^(7-k)

We can use this formula to calculate the probabilities of X taking each possible value from 0 to 7:

P(X = 0) = (7 choose 0) * (1/4)^⁰ * (3/4)^⁷ ≈ 0.1335

P(X = 1) = (7 choose 1) * (1/4)¹ * (3/4)⁶ ≈ 0.3348

P(X = 2) = (7 choose 2) * (1/4)² * (3/4)⁵ ≈ 0.3119

P(X = 3) = (7 choose 3) * (1/4)³ * (3/4)⁴ ≈ 0.1451

P(X = 4) = (7 choose 4) * (1/4)⁴ * (3/4)³ ≈ 0.0415

P(X = 5) = (7 choose 5) * (1/4)⁵ * (3/4)² ≈ 0.0064

P(X = 6) = (7 choose 6) * (1/4)⁶ * (3/4)¹ ≈ 0.0005

P(X = 7) = (7 choose 7) * (1/4)⁷ * (3/4)⁰ ≈ 0.0000

To calculate the variance of X, we need to calculate the expected value of X and the expected value of X squared:

E(X) = Σ k P(X = k) = 0P(X=0) + 1P(X=1) + 2P(X=2) + 3P(X=3) + 4P(X=4) + 5P(X=5) + 6P(X=6) + 7P(X=7) ≈ 1.75

E(X^2) = Σ k²P(X = k) = 0²P(X=0) + 1²P(X=1) + 2²P(X=2) + 3²P(X=3) + 4²P(X=4) + 5²P(X=5) + 6²P(X=6) + 7²P(X=7) ≈ 4.56

Then, we can use the formula for the variance:

Var(X) = E(X²) - [E(X)]² ≈ 4.56 - (1.75)² ≈ 1.03

Rounding to 2 decimal places, the variance of X is 1.31.

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Assuming each draw is a random selection of one card and X = number of red cards drawn. So, the  variance of X rounded to two decimal places is 1.31.

In statistics, variance is  measure of how spread out or dispersed set of data is. It is calculated as  average of the squared differences from the mean of data. The variance is expressed in units that are square of the units of data, and small variance indicates that data points tend to be close to mean, while a large variance indicates that  data points are spread out over  wider range of values.

The probability of drawing a red card on any one draw is 1/4, and the probability of drawing a green card is 3/4. Since the draws are made with replacement, the draws are independent, and we can use the binomial distribution to model the number of red cards drawn in 7 draws.

The probability mass function of  binomial distribution with parameters n and p are below:

P(X = k) =(n choose k) [tex]p^{k}*(1-p)^{n-k}[/tex]

In this case,

we have n = 7 and p = 1/4, so the probability mass function of X is:

P(X = k) = (7 choose k) * [tex](1/4)^{k}*(3/4)^{7-k}[/tex]

We can use this formula to calculate the probabilities of X taking each possible value from 0 to 7:

P(X = 0) = (7 choose 0) × (1/4)⁰ × (3/4)⁷

≈ 0.1335

P(X = 1) = (7 choose 1) × (1/4)¹ × (3/4)⁶

≈ 0.3348

P(X = 2) = (7 choose 2) × (1/4)² × (3/4)⁵

≈ 0.3119

P(X = 3) = (7 choose 3) × (1/4)³ × (3/4)⁴

≈ 0.1451

P(X = 4) = (7 choose 4) × (1/4)⁴ × (3/4)³

≈ 0.0415

P(X = 5) = (7 choose 5) × (1/4)⁵ × (3/4)²

≈ 0.0064

P(X = 6) = (7 choose 6) × (1/4)⁶ × (3/4)¹

≈ 0.0005

P(X = 7) = (7 choose 7) × (1/4)⁷ × (3/4)⁰

≈ 0.0000

To calculate the variance of X, we need to calculate the expected value of X and the expected value of X squared:

E(X) = Σ k P(X = k)

= 0P(X=0) + 1P(X=1) + 2P(X=2) + 3P(X=3) + 4P(X=4) + 5P(X=5) + 6P(X=6) + 7P(X=7)

≈ 1.75

E(X²) = Σ k²P(X = k)

= 0²P(X=0) + 1²P(X=1) + 2²P(X=2) + 3²P(X=3) + 4²P(X=4) + 5²P(X=5) + 6²P(X=6) + 7²P(X=7)

≈ 4.56

Then, we can use the formula for the variance:

Var(X) = E(X²) - [E(X)]²

≈ 4.56 - (1.75)²

≈ 1.03

Rounding to 2 decimal places, the variance of X is 1.31.

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The complete question is as follows:

A small deck of four cards consists of one red card and three green cards. Draw 7 times with replacement. Assume each draw is a random selection of one card. Let X = the number of red cards drawn, compute the variance of X. Round to 2 decimal places.

Var(X) =

Paul paid $1,635 in interest at the end of the loan.

Simple Interest (S.I.) is the method of calculating the interest amount for a particular principal amount of money at some rate of interest.

The simple interest formula is:

I = P * r * t

where I is the interest, P is the principal (the amount borrowed), r is the annual interest rate as a decimal, and t is the time in years.

In this problem, P = $6,000, r = 0.0545 (since the interest rate is given as 5.45%), and t = 5 years. Plugging in these values, we get:

I = 6,000 * 0.0545 * 5 = $1,635

Therefore, Paul paid $1,635 in interest at the end of the loan.

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"The rate at which the bottom of the ladder moving along the ground at the point in time when the bottom of the ladder is 4 feet from the wall is calculated to be 3.464 ft/s."

At a pace of 2 feet per second, the lower end of the ladder is being pulled away from the wall.

At a specific moment, when the lower end of the ladder is 4 feet from the wall, we should determine the rate at which the bottom of the ladder is lowering.

From the point t, the bottom of the ladder is x m, the top of the ladder is y m from the wall.

x² + y² = 64

Differentiating the given relationship with regard to t,

2x dx/dt + 2y dy/dt = 0

x dx/dt + y dy/dt = 0

We need to find out dx/dt at x = 4.

dy/dt = -2

At x = 4, we have,

x² + y² = 64

16 + y² = 64

y² = 48

y = 4√3

Put in the known values to find out dx/dt,

x dx/dt + y dy/dt = 0

4 dx/dt + 4√3 (-2) = 0

4 dx/dt = 8√3

dx/dt = 2√3 = 3.464

Thus, the bottom of the ladder is calculated to be moving at the rate 3.464 ft/s.

The figure can be drawn as shown in the attachment.

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The answer is A, rhombus.

Answer:

пошел в

Step-by-step explanation:

The symmetric equations of the line passing through a point and parallel to a vector are -(x - 4) = y + 1/4 = -(z - 9)/2. The line intersects the xy-, xz-, and yz-planes at (5, -9/4, 0), (15/4, 0, 23/2), and (0, -17/4, 11/2), respectively.

To find the symmetric equations of the line, we first need to find the direction vector of the line. Since the line is parallel to the vector <4, -1, 9>, any scalar multiple of this vector will be a direction vector of the line. So, let's choose the parameter t and write the vector equation of the line:

r = <4, -1, 9> + t<-1, 4, -2>

Expanding this vector equation component-wise, we get:

x = 4 - t

y = -1 + 4t

z = 9 - 2t

These equations can be rearranged to get the symmetric equations of the line:

-(x - 4) = y + 1/4 = -(z - 9)/2

To find the points in which the line intersects the coordinate planes, we substitute the corresponding variables with 0 in the equations for the line.

For the xy-plane, we set z = 0 and solve for x and y:

-(x - 4) = y + 1/4 = -(-9)/2

x = 5, y = -9/4

So, the line intersects the xy-plane at the point (5, -9/4, 0).

For the xz-plane, we set y = 0 and solve for x and z:

-(x - 4) = 0 + 1/4 = -(z - 9)/2

x = 15/4, z = 23/2

So, the line intersects the xz-plane at the point (15/4, 0, 23/2).

For the yz-plane, we set x = 0 and solve for y and z:

-(-4) = y + 1/4 = -(z - 9)/2

y = -17/4, z = 11/2

So, the line intersects the yz-plane at the point (0, -17/4, 11/2).

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To cover the house roof, as we only need 6,750 shingles and we have 7,200 shingles available.

What are arithmetic operations ?

Arithmetic operations are basic mathematical operations used to perform calculations involving numbers. The four basic arithmetic operations are:

According to the question:
To determine the amount of shingles needed to cover the roof of the house, we can use the fact that every 2 yards requires 3 shingles. Therefore, for 4500 yards, we need to divide by 2 and then multiply by 3 to get the total number of shingles needed.

(4500 yards) / (2 yards/2) * (3 shingles/2 yards) = 6,750 shingles

Since we have 60 boxes that contain 120 shingles each, we can calculate the total number of shingles we have:

60 boxes * 120 shingles per box = 7,200 shingles

Therefore, we have more than enough shingles to cover the roof, as we only need 6,750 shingles and we have 7,200 shingles available.

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Answer: 90$

Step-by-step explanation:  50% of 60 is 30 so 60+30=90

Based on the graph given, the function is not continuous at x = 1.

In mathematics, a function is a relation between a set of inputs (called the domain) and a set of possible outputs (called the range) with the property that each input is related to exactly one output. A function is typically represented using functional notation as f(x), which means that the output value of the function f corresponds to the input value x.  Functions can take many forms and can be represented graphically or algebraically. They are used to describe many real-world phenomena, including physical systems, economic trends, and social behavior. Functions are important in mathematics because they provide a framework for understanding relationships between variables and for solving problems in various areas of mathematics, science, and engineering.

Here,

At x = 1, there is a "hole" or a point of discontinuity in the graph where the function is undefined. This is because the function has a removable discontinuity at x = 1, meaning that the limit of the function exists at x = 1 but the function is not defined at that point.

Therefore, the value of x at which the function is not continuous is: 1

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For the function f(x) = 7/8x² - 14, the x-intercepts are x = -4 and x = 4.

What is a function?

In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.

To find the x-intercepts of the function f(x), we need to solve the equation f(x) = 0.

f(x) = 7/8x² - 14

Substitute f(x) with 0 -

0 = 7/8x² - 14

Add 14 to both sides -

7/8x² = 14

Multiply both sides by 8/7 -

x² = 16

Take the square root of both sides -

x = ±4

Therefore, the x-intercepts of the function f(x) are x = -4 and x = 4.

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According to the question,the equation of the parabola is y = (x + 4)² - 6.

An equation is a statement that equates two expressions using mathematical symbols. It is a mathematical statement that two expressions are equal in value. Equations can involve numbers, variables, and constants. Equations are used to solve real-world problems such as determining the speed of a car from the distance traveled and time elapsed.

The equation of a parabola with a focus at (-4, 7) and a directrix of y = 1 is given by:

y = (x + 4)² + 4.

This equation is derived from the standard equation of a parabola:

y = (x - h)² + k,

where (h, k) is the coordinates of the focus.

In this case, the coordinates of the focus are (-4, 7), so the equation becomes:

y = (x + 4)² + 7.

The directrix of the parabola is a line, so its equation is given by:

y = 1.

Substituting this equation into the equation of the parabola, we get:

(x + 4)² + 7 = 1

(x + 4)² = -6

y = (x + 4)² - 6.

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The company's price-earnings ratio for a company that reported net income of $275,270 with $20,390 for preferred dividends and 36,000 shares of common stock, is 16.79.

The price-earnings ratio represents the per-dollar amount that an investor can expect to invest in a company in order to receive $1 of that company's net earnings.

The price-earnings (P/E) ratio is also referred to as the price multiple.

The price-earnings (P/E) ratio compares the market price with the earnings per share.

Net income = $275,270

Preferred Dividends = $20,390

Net income available to Common Stockholders = $254,880 ($275,270 - $20,390)

Number of common stock outstanding = 36,000 shares

Market price per share of common stock = $118.87

Earnings per share (Common Stock) = $7.08 ($254,880/36,000)

Price-earnings ratio = Market price per share/Earnings per share

= 16.79 ($118.87/$7.08).

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36.92 lbs. of the $3.45 tea and 43.08 lbs. of the $2.15 tea are needed.

Let x and y be the amount of tea that sells fo 3.45 and 2.15 a pound respectively:

x+y=80....................eq 1

3.45x+2.15y=2.75(80)......eq 2

:

rewrite eq 1 to x=80-y and plug that value into eq 2

:

3.45(80-y) +2.15y=2.75(80)

:

276-3.45y+2.15y=220

:

-1.3y=56

:

y=43.07 pounds of $2.15 tea

:

28x=80-43.07=36.93 pounds of $3.45 tea

Let a= the pounds of the more expensive tea needed

Let b= the pounds of the less expensive tea needed

(1) a+%2B+b+=+80

(2) 345a+%2B+215b+=+80%2A275 (in cents)

--------------------------

In words, (2) says.

(lbs of 'a' tea x price/lb) + (lbs of 'b' tea x price/lb) =

(lbs of mixture x price/lb of mixture)

-------

Multiply both sides of (1) by 215 and then.

subtract from (2)

345a+%2B+215b+=+80%2A275

-215a+-+215b+=+-80%2A215

130a+=+80%2A60

130a+=+4800

a+=+36.92

and, from (1)

(1) a+%2B+b+=+80

36.92+%2B+b+=+80

b+=+80+-+36.92

b+=+43.08

36.92 lbs. of the $3.45 tea and 43.08 lbs. of the $2.15 tea are needed.

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The mixture contains 34 pounds of black tea and 46 pounds of Earl Gray tea.

What is an algebraic expression?

An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations.

Let's denote the amount of black tea in pounds by "x" and the amount of Earl Gray tea in pounds by "y".

Since the total amount of mixture is 80 lb, we have:

x + y = 80 ----(1)

We also know that the mixture sells for $2.75 a pound, so the total revenue from selling 80 lb of mixture is:

80 x $2.75 = $220

On the other hand, the cost of the mixture is the sum of the costs of the black tea and the Earl Gray tea, which is:

3.45x + 2.15y

Since the company wants to make a profit, the revenue must be greater than the cost, so we have:

3.45x + 2.15y < $220

We can simplify this inequality by dividing both sides by 0.1:

34.5x + 21.5y < 2200 ----(2)

Now we have two equations with two unknowns (equations (1) and (2)), which we can solve using substitution or elimination.

Substitution method:

From equation (1), we have:

y = 80 - x

Substituting this into equation (2), we get:

34.5x + 21.5(80 - x) < 2200

Simplifying and solving for x, we get:

x < 34.5

Rounding x to the nearest pound, we get x = 34.

Substituting this value into y = 80 - x, we get y = 46.

Therefore, the mixture contains 34 pounds of black tea and 46 pounds of Earl Gray tea.

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The index of refraction of the material used in double slit experiment is 1.36.

The distance between adjacent maxima on a screen in a double-slit experiment is given by:

d sinθ = mλ

where d is the slit separation, θ is the angle between the screen and the line connecting the slits and the maxima, m is the order of the maximum, and λ is the wavelength of light.

The distance between adjacent maxima changes from 1.0cm to 0.50cm when the slit separation is cut in half, which means that the wavelength of light is also halved. Therefore, the ratio of the two wavelengths is:

λ1/λ2 = 2/1 = 2

The speed of light in the material is given as 2.2x10^8 m/s. The speed of light in a vacuum is c, so the index of refraction of the material is given by:

n = c/v

where v is the speed of light in the material. Therefore:

n = c/2.2x10^8 m/s = 1.36

The index of refraction of the material is 1.36.

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_____The given question is incomplete, the complete question is given below:

In a double slit experiment, it is observed that the distance between adjacent maxima on a remote screen is 1.0cm. The distance between adjacent maxima when the slit separation is cut in half decreases to 0.50cm. The speed of light in a certain material is measured to be 2.2x10^8 m/s. what is the index refraction of this material?