1) A couple is expecting the birth of a baby boy. They will name the child by choosing a first name
and middle name from this list of their favorite boys' names: Jacob, Jonah, Joshua, Jeremy,
James, Joseph. The first name will be different from the middle name.
How many different two-part names are possible? (Example: Joseph Jeremy, Jeremy Joseph,
and Joshua James are three different, valid two-part names; Jacob Jacob is not a valid
possibility.)
a) 36
b) 12
c) 30
d) 11

Answer:

B 2 m

Step-by-step explanation:

2 cm and 2 mm are way to small they are less than the size of a cell phone

2 km is way to large it is larger than a car

Answer:

ᴀꜱ ᴡᴀʀᴍ ᴀꜱ ꜱᴜɴ

ᴀꜱ ꜱɪʟʟʏ ᴀꜱ ꜰᴜɴ

ᴀꜱ ᴄᴏʟᴅ ❄️ ᴀꜱ ᴀ ᴛʀᴇᴇ

ᴀꜱ ꜱᴄᴀʀʏ ᴀꜱ ꜱᴇᴀ

ᴀꜱ ʜᴏᴛ ᴀꜱ ꜰɪʀᴇ

ᴀꜱ ᴄᴏʟᴅ ᴀꜱ ɪᴄᴇ

ꜱᴡᴇᴇᴛ ᴀꜱ ꜱᴜɢᴀʀ

ᴀɴᴅ ᴇᴠᴇʀʏᴛʜɪɴɢ ɴɪᴄᴇ

ᴀꜱ ᴏʟᴅ ᴀꜱ ᴛɪᴍᴇ ⌛

ᴀꜱ ꜱᴛʀᴀɪɢʜᴛ ᴀꜱ ʟɪɴᴇ ➖

ᴀꜱ ʀᴏʏᴀʟ ᴀꜱ ᴀ ᴀɴɢᴇʟ☺️

ᴀꜱ ʙᴜᴢᴢᴇᴅ ᴀꜱ ʙᴇᴇ

ᴀꜱ ꜱᴛᴇᴀʟᴛʜ ᴀꜱ ᴛɪɢᴇʀ

ꜱᴍᴏᴏᴛʜ ᴀꜱ ɢʟɪᴅᴇʀ

ᴘᴜʀᴇ ᴀꜱ ʜᴇᴀʀᴛ ❤️

ᴘᴜʀᴇ ᴀꜱ ɪ ᴡᴀɴɴᴀ ʙᴇ

Step-by-step explanation:

Answer:2 and 6

Step-by-step explanation:

Given

In 4 years Craston's age will be the same as Terrins age is now

Suppose the present of Craston's and Terrins are [tex]x[/tex] and [tex]y[/tex] respectively

According to the question

[tex]\Rightarrow x+4=y\\\Rightarrow y-x=4\quad \ldots(i)[/tex]

In 2 years Terrin will be twice as old  as craston

[tex]\Rightarrow (y+2)=2(x+2)\\\Rightarrow y-2x=4-2\\\Rightarrow y-2x=2\quad \ldots(ii)\\[/tex]

Solving (i) and (ii) we get

[tex]x=2,y=6[/tex]

Thus, the present age of Craston and Terrins are [tex]2[/tex] and [tex]6[/tex]

Answer:

hello,

answer C

Step-by-step explanation:

As |a| ≥0,

f(|a|)=|a|+5

Answer:

Yes ,because of SAS similarity theorem

Step-by-step explanation:

In ΔYOM , ΔTON

∠YOM = ∠TON        

[tex]\frac{OY}{OT}=\frac{96}{84}=\frac{8}{7}\\\\\frac{OM}{ON}=\frac{104}{91}=\frac{8}{7}[/tex]

SAS similarity theorem

Answer:

Hello,

Answer C

Step-by-step explanation:

[tex]\dfrac{96}{104}=? \dfrac{84}{91} \\\\Calculating\ crossed\ products\\96*91=8736\\104*84=8736\\they\ are\ equals\\\\\\\dfrac{YO}{MO} =\dfrac{OT}{ON} \\\\\\Triangles\ are\ similar\ because \ SAS \theorem\\\\[/tex]

Answer:

always

Step-by-step explanation:

they would all have the same gradient & be parallel to each other!

ie. A || B ,   B || C

in this case, A || C ^^

Answer:

always

Step-by-step explanation:

have the same gradient & be parallel to each other

Answer:

[tex]\displaystyle lne^4 = 4[/tex]

General Formulas and Concepts:

Algebra II

Natural Logarithms ln and Euler's number e

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle lne^4[/tex]

Step 2: Evaluate

Answer:

Step-by-step explanation:

Given,

Radius of a circle = 17m

Therefore,

Area in terms of pi

[tex] = \pi {r}^{2} [/tex]

[tex] = \pi \times 17m \times 17m[/tex]

[tex] = 289\pi {m}^{2} (ans)[/tex]

Answer:

A = 289π m²

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius ) , then

A = π × 17² = 289π m²

Answer:

D

Step-by-step explanation:

Slope is (1/8) and y intercept can be found by setting x=0.

At the start, it's given that x₁ (0) = 80 lb and x₂ (0) = 30 lb.

The amounts of salt in either tank change according to

dx₁/dt = (2 gal/min) (x₂/(100 - t ) lb/gal) - (3 gal/min) (x₁/(100 + t ) lb/gal)

dx₂/dt = (3 gal/min) (x₁/(100 + t ) lb/gal) - (2 gal/min) (x₂/(100 - t ) lb/gal)

To break this down a bit, consider tank A, for instance:

• solution flows in from B at a rate of 2 gal/min

• the volume of liquid in tank B after t minutes is

100 gal + (2 gal/min - 3 gal/min) (t min) = (100 - t ) gal

because the tank starts with 100 gallons of liquid, and 2 gallons are pumped in while 3 gal are pumped out each minute

• at any time t, the solution in B contains x₂ pounds of salt

• the concentration of the solution in A is then x₂/(100 - t ) lb/gal

• multiplying this by the inflow rate tells you how much salt is moving around each minute

꙰  Hello there mohammedsaquibali45 ! My Name is ⚝Tobie⚝ and I'm glad you asked! Let me walk you step by step in order to comprehend the question better!   ꙰  

i

{x}^{2}-5x-10x+50

x

2

−5x−10x+50

ii Collect like terms.

{x}^{2}+(-5x-10x)+50

x

2

+(−5x−10x)+50

iii Simplify.

{x}^{2}-15x+50

x

2

−15x+50

(x - 10)(x - 5) = ...

= x^2 + (-10 + (-5))x + (-10•(-5))

= x^2 - 15x + 50

Answer:

Figures A,D are polygons.

Reason:

Polygon is a closed figure with atleast three strange lines and angles.

Answer:

Area: 24 sq units

Step-by-step explanation:

Area of a rectangle formula:

A = 0.5bh

Given:

b = 6

h = 8

Work:

A = 0.5bh

A = 0.5(6)(8)

A = 3(8)

A = 24

Answer: A = 24 unit²

Concept:

The area is the quantity that expresses the extent of a two-dimensional region, shape, or planar lamina, in the plane.

Area (triangle) = bh/2

b = base

h = height

Solve:

Given information

1 unit = 1 grid

b = 6 grids = 6 × 1 = 6 units

h = 8 grids = 8 × 1 = 8 units

Given expression

A = bh / 2

Substitute values into the expression

A = (6) (8) / 2

A = 48 / 2

A = 24 units²

Hope this helps!! :)

Please let me know if you have any questions

Answer: 1/32

Step-by-step explanation:

Answer:

its 80 meters longs

Step-by-step explanation:

if it is wrong just go look it up

Answer:

8.44 m

Step-by-step explanation:

SohCahToa is a good way to remember that Sin = opposite/hypotenuse, Cosine = adjacent/hypotenuse and Tangent = opposite/adjacent. In this case, we have to use tangent. So tan 37° = x/11.2. Multiply both sides by 11.2 and you get tan 37° × 11.2 = x; The height of the school is x so the height of the school is 8.44 m

Answer

6372 - power 4

Step-by-step explanation:

Answer:

25:4

Step-by-step explanation:

The ratio of the sides is 5:2

The ratio of the areas is the scale factor squares

5^2 : 2^2

25:4

Answer:

1 = tenths place

7= hundredths place

8= thousandths place

9= ten-thousandths place

Step-by-step explanation:

8m+4m-6m-12

12m-6m-12

12m-6m

-6m

Answer:

Equation A is true; Equation B is not

Step-by-step explanation:

There is a standard formula for the "difference of cubes" that is:

x^3 - y^3 = (x - y)(x^2 + xy + y^2)

and this perfectly matches equation A.

Equation B has the square of n (n^2) on the left side but not on the right side.  Thus this is not an identity.

Answer:

a=6

Step-by-step explanation:

12-2a=3(a-6)

or,12-2a=3a-18

or,12-5a=-18

or,-5a=-30

or,a=6

hope this helps

Answer:

-1

Step-by-step explanation:

Mode is the number that appears most often

−1, 0, 3, 4, −3, −1

-1 appears twice which is more than any other number

-1 is the mode

Answer:

510°

Step-by-step explanation:

Total Time from 8:10pm to 9:35pm is 1hour 25mins= 85mins

Movement of the minute hand from one point around the clock and back to the same point gives a complete rotation of 360°

if 60mins = 360°

85mins=

[tex] \frac{85}{60} \times 360[/tex]

= 510 degrees

Answer:

Step-by-step explanation:

I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:

[tex]x-9=\sqrt{x}+3[/tex] then subtract 3 from both sides to get

[tex]x-12=\sqrt{x}[/tex] and then square both sides to get

[tex]x^2-24x+144=x[/tex] and get everything on one side to solve for x by factoring:

[tex]x^2-25x+144=0[/tex] and factor that however it is you have learned to factor second-degree polynomials to get that

x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:

[tex]\frac{16-9}{\sqrt{16}+3 }=1[/tex]  If 16 is a solution, then this statement will be mathematically true.

[tex]\frac{7}{4+3}=1[/tex]  and   [tex]\frac{7}{7}=1[/tex] so 16 works. Let's try 9:

[tex]\frac{9-9}{\sqrt{9}+3 }=1[/tex]  We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.

x = 16 is the only solution.

Answer:

x =  16

Step-by-step explanation:

[tex]\frac{x-9}{\sqrt{x}+3}=1[/tex]

Cross multiply,

x - 9 = √x + 3

Subtract 3 from both sides

x - 9 - 3 = √x

x - 12 = √x

Square both sides

(x -12)² = (√x)²

x² - 2 * x*12 + 12² = x

x² - 24x + 144 = x

x² - 24x + 144 - x = 0

x² - 25x + 144 = 0

Sum = -25

Product = 144

Factors = -9 , -16            {(-9)+(-16) = -25  & (-)*(-16) = 144}

x² - 25x + 144 = 0

x² - 16x - 9x + (-9)*(-16) = 0

x(x - 16) - 9(x - 16) = 0

(x - 16) (x - 9) = 0

x - 16 = 0     ; x - 9 = 0

x = 16          ; x = 9

x = 9 is  an extraneous solution.

When we plug in 9 in the LHS of the equation,

LHS = [tex]\frac{9-9}{\sqrt{9}+3}[/tex]

       [tex]= \frac{0}{3+3}[/tex]

        = 0 ≠ RHS

So, x = 16 is the only  solution

The current price of the mask is $1 per mask and there is expected demand of 6000 masks per week.

If the company plans to increase the price the demand for the masks will decrease.

Revenue  = 6000 * x

Total revenue will be  $6,000 if the price of mask is $1. If price of mask increase by 10% then quantity will be declined to 5850 masks [6000 - 150].

New price = $ 1 * 110% = $1.10

Revenue = 5850 masks * $ 1.10 = $6,435.

Then correct answer is Revenue will increase if price of mask is increased.

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