you work at a garden store for the summer. you lift a bag of fertilizer with a force of 131 n, and it moves upward with an acceleration of 0.790 m/s2. (a) what is the mass (in kg) of the fertilizer bag?

Answers

Answer 1

Mass of the fertilizer bag is 165.82 kg

Briefing:

According to Newton's law,

F = m*a

So, m= F/a

m= 131/0.790

m= 165.82 kg

What is mass?

Mass is the measure of matter of a body.

What is Newton's laws?

Newton has stated three laws of motion. The first law states that every object will remain at rest or in uniform motion in a straight line unless an external force compels it to change its state of action .

The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

The third law states that every action has an equal and opposite reaction.

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Related Questions

Classify the type of reaction below.
C2H6 + O2
--> CO2 + H2O
a. Synthesis
b. Decomposition
c. Combustion
d. Single Replacement
e. Double Replacement

Answers

Answer: Synthesis

Explanation: You are combining multiple Elements

Maddy tripped and accidentally threw her phone off the hollywood cliff at 5m/s. It landed 20 away from the base of the cliff. how high is the cliff then?

Answers

The height of the cliff, given that her phone landed 20 m away when she accidentally threw her phone with a velocity of 5 m/s is 78.4 m

How do I determine the height of the cliff?

To determine the height of the cliff, we must first obtain the time taken for her phone to reach the ground. This is obtained as follow:

Horizontal velocity (u) = 5 m/sHorizontal distance (s) = 20 mTime taken (t) =?

s = ut

20 = 5 × t

Divide both sides by 5

t = 20 / 5

t = 4 s

Finally, we shall determine the height of the cliff. Details below:

Time taken (t) = 4 sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = ?

h = ½gt²

h = ½ × 9.8 × 4²

h = 4.9 × 16

h = 78.4 m

Thus, the height of the cliff is 78.4 m

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what force must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2500 kg car (a big car) resting on the slave cylinder? the master cylinder has a 1.93 cm diameter, while the slave's is 24.9 cm. 1900 n 150 n 15 n 4.1e 06 n 74 n

Answers

The force that must be exerted on the master cylinder of the hydraulic lift to support the weight of car is  147.2 N .

The Pascal's Law states that the relation between the pressure , force and area is given as :

Pressure = Force/Area ;

given that the diameter of the master cylinder is = 1.93 cm ;

so radius of master cylinder = 1.93/2 = 0.965 cm = 0.00965 m ;

the diameter of slave cylinder is = 24.9 cm ;

the radius of the slave cylinder = 24.9/2 = 12.45 m = 0.1245 m ;

Area of slave cylinder (A₁)= π(0.1245)² = 0.0486 m²

Area of the master cylinder (A₂) =  π(0.00965)² = 0.000292 m² ;

given mass of the car = 2500 Kg ,

the force exerted will be : F = m*a

F₁ = 2500*9.8 = 24500 N ;

F₁/A₁ = F₂/A₂

So , 24500/0.0486 = F₂/0.000292

F₂ = (24500/0.0486)×0.000292

F₂ = 147.2 N

Therefore , the force exerted on the master cylinder is 147.2 N  .

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a vertical spring scale can measure weights up to 210 n . the scale extends by an amount of 13.5 cm from its equilibrium position at 0 n to the 210 n mark. a fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.15 hz . part a ignoring the mass of the spring, what is the mass m of the fish?

Answers

sheesh sheesh                                                    

Explanation:

1. a 1.4 x 103 kg car is westbound at a velocity of 37.0 km/h when it collides with a 2.0 x 103 kg truck northbound at a velocity of 35 km/h. if these two vehicles lock together upon collision, what is the initial velocity of the vehicles after collision? (7.2 m/s 37o w of n) 2. a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision? (2.4 m/s 56o w of n) 3. a 4.0 x 104 n truck moving west at a velocity of 8.0 m/s collides with a 3.0x104 n truck heading south at a velocity of 5.0 m/s. if these two vehicles lock together upon impact, what is their velocity?(5.0 m/s 25o s of w)

Answers

The velocity of vehicles after the collision is 15.82m/sec if car mass is 1.4 × 10³kg and truck mass is 2×10³kg

We know that we need to conserve the momentum of watermelon in a certain direction. Also,we know that initial momentum of watermelon is zero,it means that according to law of conservation of momentum final momentum should be zero.

We know that momentum =mass × velocity

So,initial momentum of car is =1.4 × 10³kg × 37km/hr

Similarly,,initial momentum of truck=2×10³kg × 35km/hr

Now,it is given that both vehicles lock together,so total mass of both vehicles is =1.4 × 10³kg +  2×10³kg=3.4 ×10³kg

Assume final velocity of both vehicle is v

So,following the law of conservation,we get

=>1.4 × 10³kg × 37 + 2×10³kg × 35 = 3.4 ×10³ ×v

=>51.8 ×10³ + 2×10³=3.4×10³ ×v

=>53.8 ×10³ kg-m/sec = 3.4×10³ ×v

=>v = 53.8/3.4

=>v=15.82m/sec

Hence,final velocity of both vehicle after collision is 15.82m/sec.

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Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.

Answers

The volume of the toy is 80 ml.

To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.

In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.

The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.

It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.

Answer:

Volume of the toy: [tex]80\; {\rm mL}[/tex].

Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)

Explanation:

The graduated cylinder initially measures the volume of water in this cylinder:

[tex]V(\text{water}) = 70\; {\rm mL}[/tex].

Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:

[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].

Rearrange to find the volume of the toy:

[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].

To find the average density of this toy, divide mass by volume:

[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].

Newton's third law states that any action will have a(n) _______ and ______ reaction.

Answers

Newton's third law states that any action will have a(n) equal and opposite reaction.

1. Find the force due to gravity if the mass of the object is 2300 kg
and the mass of the other object is 4000 kg. The distance
between the two objects is 0.150 m.

Answers

The force due to gravity will be 0.0272 Newtons.

What exactly does gravitational force signify?

The force between two mass-containing objects that are drawn toward one another is referred to as the gravitational pull. There is gravity everywhere around us. For instance, it maintains the planets in our solar system in orbit around the Sun. Additionally, because to gravity, the Moon maintains its orbit around the Earth.

How to calculate gravitational force in the above question?

Despite being weak and appealing, gravitational forces exist.

Given, mass of one object= 2300 kg

mass of another object= 4000 kg

distance between the two objects= 0.150 m

value of G is universal, [tex]G= 6.67[/tex]×[tex]10^{-11}[/tex] [tex]N m^{2} / kg^{2}[/tex]

the equation is, [tex]F=G\frac{M1 . M2}{d^{2} }[/tex]

                       [tex]F=0.0272 N[/tex]

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a typical tendon has a strength of 16000 pounds per square inch (psi). let's assume the achilles tendon is roughly rectangular in cross section with dimension of .4 inches x .2 inches. you can use this to calculate the force at which the achilles tendon will start to fail. at what force might the achilles tendon start to fail (in pounds, lb)?

Answers

An average tendon can withstand 16000 per square inch of force (psi). The Achilles tendon may begin to fail at a force of F = 1280 pounds.

How does science define force?

That meaning of the term "force" is obvious. At this point, it is quite acceptable to refer to a force as a push or possibly a pull. An item does not "have energy in it" or "encompass energy." A force is applied to one thing by another. A factor is anything that affects non-living things as well.

Inertia or a force?

Inertia is what holds the cosmos together. Literally. That could prevent matter from having the electric forces necessary to produce its system layout. Vibrating particles generate heat and rotational motion, which operate to counteract inertia.

Briefing:

Area of tendon 0.4×0.2

=0.08 square inch.

0.08 square inch tendon =16000×0.08

F =1280 pound.

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The diagram below represents a wave.
What is the speed of the wave if its wavelength is 3.0 m?

Answers

The speed of the wave is determined as 18 m/s.

option D is the correct answer.

What is the speed of the wave?

The speed of the wave is the rate of change of wave's displacement with time.

The speed of the wave is calculated by applying the formula relating speed, wavelength and frequency of the wave as shown below.

v = fλ

where;

v is the speed of the wavef is the frequency of the waveλ is the wavelength of the wave

The frequency of the wave is calculated as follows;

f = 1 / T

where;

T is the period of the wave

The period of a wave is the time taken for the wave to complete one cycle.

In the picture given, 3 cycles of the wave = 0.5 s

1 cycle of the wave = ?

= 0.5 s / 3

= 0.16667 s

f = 1 / T

f = 1 / 0.16667

f = 6 Hz

The speed of the wave is calculated as follows;

v = fλ

v = 6 Hz  x  3 m

v = 18 m/s

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a point at an antinode of the standing wave on the wire travels from its maximum upward displacement to its maximum downward displacement in 8.40 msms . what is the wire'??s mass?

Answers

The relation between the time-period of the transverse wave for the third harmonic and the time between the maximum displacement and minimum displacement is [tex]=16.3 \mathrm{~g}[/tex]

[tex]$$T_3=2 t$$Substitute$8.40 \mathrm{~ms}$[/tex]

for t in the above expression.

[tex]$$T_3=2(8.4 \mathrm{~ms})\left(\frac{10^{-3} \mathrm{~s}}{1 \mathrm{~ms}}\right)$$[/tex]

The wave velocity can be given by the following expression [tex]=0.0168 \mathrm{~s}[/tex]

[tex]v=\frac{\lambda_3}{T_3}[/tex]

Here,

[tex]$$\lambda_3$$[/tex]

is the frequency of third harmonics and

[tex]$$T_3$$[/tex]

is the time-period of third harmonics.

Substitute [tex]$0.1296 \mathrm{~m}$[/tex] for

[tex]$$\lambda_3$$[/tex]

and

[tex]$0.0168 \mathrm{~s}$ for$T_3$[/tex]

[tex]\begin{aligned}& v=\frac{0.1296 \mathrm{~m}}{0.0168 \mathrm{~m}} \\& =7.714 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]

The expression of the wave velocity is given by the following expression.

[tex]v=\sqrt{\frac{T}{m / L}}[/tex]

Rearrange the above expression for

[tex]$$m$$[/tex]

[tex]\text { Substitute } 5.00 \mathrm{~N} \text { for } T, 0.1944 \mathrm{~m} \text { for } L \text {, and } 7.714 \mathrm{~m} / \mathrm{s} \text { for } v \text { in the above expression. }[/tex]

[tex]\begin{gathered}m=\frac{(5.00 \mathrm{~N})(0.1944 \mathrm{~m})}{(7.714 \mathrm{~m} / \mathrm{s})^2} \\=(0.0163345 \mathrm{~kg})\left(\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}\right) \\=16.3 \mathrm{~g}\end{gathered}[/tex]

The anti-nodes in the standing waves are at a distance half a wavelength. The time-period is twice the time from maximum displacement to minimum displacement of the anti-node.

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A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?

Answers

Answer:

5 m

Explanation:

Displacement is the straight-line distance from the starting point to the end point.  Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).  

d² = 3² + 4² = 25

d = [tex]\sqrt{25}[/tex] = 5 m

Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)

one cannot peer all the way back and directly observe the big bang because the universe's density was so low. true false

Answers

True. The Big Bang Theory is the current scientific explanation for the origin and evolution of the universe. According to this theory, the universe was initially in a state of extremely high density and temperature, and it has been expanding and cooling since its inception.

One reason we cannot directly observe the Big Bang is that the universe's density was so low at that time that there were no solid particles, such as atoms or molecules, that could have formed into stars or galaxies. Instead, the universe was filled with a hot, ionized plasma that was too diffuse to be observed by telescopes. Another reason is that the expansion of the universe has caused the light and other electromagnetic radiation that was emitted during the Big Bang to become redshifted, or stretched out in wavelength, over time. This means that the light from the earliest moments of the universe has shifted into the microwave and radio frequency ranges, which are not visible to the human eye. Therefore, while we can infer some details about the conditions of the early universe based on observations of the cosmic microwave background radiation and the large-scale structure of the universe, we cannot directly observe the Big Bang itself.

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7. What is the weight of a ball with a mass of 0.77 kg? (hint: how fast is gravity?)

Answers

Answer:

While on the earth, any object with a mass of 0.77 kg weighs 7.546 newtons (1.698 pounds).

On the moon, the same 0.77-kg object would weigh 1.232 newtons (0.277 pound)

Explanation:

a dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to a frequency of 15 rpm in 10.0 s. assume the merry-go-round is a uniform disk of radius 2.5 m and has a mass of 330 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. calculate the torque required to produce the acceleration, neglecting frictional torque. what force is required at the edge?

Answers

Refer to the photo taken.

two planets are identical, except planet x has an atmosphere of mostly nitrogen and planet y has an atmosphere of mostly carbon dioxide. what can you determine about the planets

Answers

Two planets are identical, except planet x has an atmosphere of mostly nitrogen and planet y has an atmosphere of mostly carbon dioxide therefore what we can determine about the planets is that x is Earth while y is Venus.

What is Atmosphere?

This is referred to as the envelope of gases surrounding the earth or another planet and it makes life possible by providing different organisms with air to breathe

In the atmosphere of the planet Venus there is a high concentration of carbon dioxide as it is made up of  it is made of 96.5% of CO₂ and a 3% of nitrogen.

On the other hand in the atmosphere of the planet Earth, there is a high concentration of nitrogen which is about 78% and is therefore the reason why they were chosen as the correct choices.

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it’s actually 7th grade science no physics pls answer it’s a lot of points

What do the historical communication technologies in these photos have in common?
(pictures are shown below)

Answers

All the tools of communication such as the drum, telegraph et cetra were used for emergency communication.

What is communication?

We know that communication has to do with the art of sending and receiving information between two people who may or may not be at the same place. We know that the dissemination of information is a very important aspect of life and we have always tried to invent means of communication especially at times when we have an emergency situation that needs a kind of an immediate remedy.

We can see that all the kinds of communication gadgets that have been show here are all from a period that is far behind the kind of civilization that we have to day and the kind of thge communication gadgets that are quite available to the people that are around today.

However, all the tools shown could be used to send information in times of emergency.

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9. a soap bubble is 100 nm thick and illuminated by white light incident perpendicular to its surface. what wavelength and color of visible light is most constructively reflected, assuming the same index of refraction as water?

Answers

When a soap bubble 100 nm thick and illuminated by white light incident perpendicular to its surface, then wavelength, λ is calculated =  5.32 *10^-7 m.

What is index of refraction?

The ratio of the speed of light in a vacuum, c, to the speed of light in a medium, c' is called as index of refraction. One of the consequence of this difference in speed is that when light goes from one medium to another at an angle, then the propagation vector in the new medium has a different angle with respect to normal.

Given, t= 100nm= 100 * 10 ^-9  n= 1.33

ΔФ1 = λ/4

ΔФ2 = 2√2 t λ n/2 λ

=2 t n

=2 * 100 * 10 ^-9 * 1.33

= 2.66 *10^-7

2.66 *10^-7= λ/2

λ=  5.32 *10^-7 m.

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a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:

Answers

The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

How to find velocity ?

To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:

Mass flow rate = Density * Flow rate

= Density * (Area * Velocity)

Where:

Density is the density of the fluid

Flow rate is the volume flow rate, or the rate at which volume flows through the pipe

Area is the cross-sectional area of the pipe

Velocity is the velocity of the fluid

The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.

The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:

A = pi * r^2

Where:

A is the cross-sectional area of the pipe

r is the radius of the pipe

The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:

A = pi * (1.5 cm)^2

= 7.07 cm^2

The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:

A = pi * (3 cm)^2

= 28.27 cm^2

Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:

(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)

Solving for v, the velocity on the narrow side, you get:

v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)

= 11.6 m/s

The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

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Uing two billiard ball and 3 to 4 entence decided experiment to demontrate the law of conervation of momentum. (4 point)

Answers

So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.

What is momentum?Momentum is a commonly used term in sports. A team that has the momentum is on the move and is going to take some effort to stop. A team that has a lot of momentum is really on the move and is going to be hard to stop. Momentum is a physics term; it refers to the quantity of motion that an object has. A sports team that is on the move has the momentum. If an object is in motion (on the move) then it has momentum.Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving. Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.

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1. A car moving 11 m/s accelerates at 1.5 m/s². How fast is it moving after it accelerates for 50
seconds?
Type a response (show work please)

Answers

We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.

what an acceleration is?

acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.

What prompts accelerating?

An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.

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John walks to the pizza place for lunch. He walks 2 km north, then 1 km east. To get home, he walks 2 km west and 1 km south. What distance did he travel? What is his displacement?

Answers

Answer:

The total distance covered is 3 km and the displacement is 2.24 km.

Explanation:

For the total distance covered by Anthony, we just add all of the distances.

1 km (going east) + 1 km (going east again) + 1 km (going south) = 3 km

Hence, the his total distance covered when he went to the pizza place is 3 km.

Solving for the displacement is a different matter. We cannot just add all of the distances. From analysis of the problem, Anthony traveled and formed a right triangle. He traveled 1 km east twice, making it 2 km east in total, then he traveled 1 km south.

When dealing with a right triangle with 2 sides given (for this problem the two sides are the 2 km east and the 1 km south), we use the Pythagorean Theorem.

Solution:

c² = a² + b²  (Pythagorean Theorem)

c will be the longest side of the right triangle

a and b will be the other sides of the right triangle

c = √ (a² + b²)

c = √ (2² km + 1² km)

c = √5 km

c = 2.2361 km ≈ 2.24 km

Therefore, the displacement of Anthony is 2.24 km.

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a car accelerates uniformly from rest to 25 m/s over a distance of 30 meters. what is the acceleration of the car?

Answers

Answer:

a=25/24 m/s^2

Explanation:

I’m going to assume you mean the final velocity is 25m/s.

v^2=u^2+2as

625=0+2a300

a=25/24 m/s^2 or 1.0416^_ (period 1) ^m

9. A piece of iron with a mass of 9.8 g has an initial temperature of 32.6°C. As it is heated, it absorbs 365J of energy. What is the final temperature of the iron? (The specific heat of iron is .46 J/g °C)

Answers

The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.

What is Specific heat capacity?

The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).

The specific heat capacity of a material can be calculated by the formula:

Q = m × c × ΔT

where, Q = heat energy,

m = mass of the material,

c = specific heat capacity,

ΔT = change in temperature

The final temperature of the piece of iron can be calculated by the formula:

Q = m × c × ΔT

ΔT = (Final temperature - initial temperature)

365J = 9.8 × 0.46 × ΔT

365J = 4.508 × ΔT

ΔT = 80.96

ΔT = Final temperature = initial temperature

ΔT = (T - 32.6)

80.96 = (T - 32.6)

T = 80.96 + 32.6

T = 113.56°C

Therefore, the final temperature of the piece of iron is 113.56°C.

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disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m.

Answers

If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.

Which definition of distance suits you best?

How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :

s = 1.925 meters

What is the definition of a distance?

In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."

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5. if the star sirius emits 23 times more energy than the sun, why does the sun appear brighter in the sky? include the terms luminosity and apparent brightness in your response.

Answers

The star Sirius is indeed brighter but our Sun appears to be brighter because it is closer to us.

The intrinsic luminosity of Sirius is exactly 25.4 times more than the sun but if we compare the distances of these stars, Sirius is 8.6 light years away from us and the Sun is just 8 light minutes away from us. This marks the obvious reason why our Sun appears more bright.

Even mathematically, it can be justified as the apparent brightness of any luminous object depends on the inverse square of the distance of that luminous object. Therefore the sun's light energy dominates our sky and we can't see any traces of Sirius from the earth.

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a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. How much work was done by the dog ?

Answers

The work done by the dog is 0.81J.

What is work done?

Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.

It is said that no work is done if the object does not move.

The work done on an object is the amount of energy transferred to an object through work.

According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:

Force = mass × acceleration

Force = 0.75kg × 9.8m/s²

Force = 7.35N

Work done = 7.35N × 0.11m = 0.81J

Therefore, 0.81J is the work done by the dog.

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when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?

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You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.

What three sorts of solar occurrences are there?

Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.

How can I follow the cycle of solar activity the best?

The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.

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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?

Answers

The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.

To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.

Now, we know that momentum =mass × velocity

So, initial momentum of first object=6.2×3=18.6Kg-m/sec

Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec

Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg

Now, both objects are moving with common velocity, so assume both have velocity v

=>So, final momentum of both objects is =14.2×v

according to law of conservation of momentum

=>18.6+25=14.2v

=>43.6=14.2v

=>v=43.6/14.2

=>v=3.07m/sec

Hence, final velocity of objects are 3.07m/sec.

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what would happen if you dropped, at the same time, particles of different shapes from a boat into still water

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Explanation:

If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.

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