Answer:
Step-by-step explanation:
None
They are both imaginary or complex. You can check that out by calculating the discriminate. If you get a minus answer, then there are no real roots. Let's try it.
a = - 2
b = - 4
c = - 6
D = sqrt(b^2 - 4*a * c)
D = sqrt( (-4)^2 - 4*(-2)(-6) )
D = sqrt( 16 - 48)
D = sqrt(-32) which is negative and there are no real roots.
find x you know
|8-x|=x^2+x
Given positive integers x and y such that x doesn't equal y and $1/x+1/y=1/18$ what is the smallest possible value for x+y?
Answer:
Hello,
[tex]\boxed{Answer: 75}[/tex]
Step-by-step explanation:
x,y integers, x,y >0 ,x≠y
[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\[/tex]
[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\\begin{array}{|c|c|c|c|}y-18&y&x&x+y\\---&---&---&---\\1&19&18+324=342&362\\2&20&18+162=180&200\\3&21&126&147\\4&22&99&121\\6&24&108&132\\12&30&45&75\\18&36&36&72\\\end{array}\\\\\\\boxed{Answer: 75}\\\\[/tex]
8. Colleen times her morning commute such that there is an equal likelihood that she will arrive early or late to work on any given day. If she always arrives either early or late, what is the probability that Colleen will arrive late to work no more than twice during a five-day workweek
Solution :
Case I :
If Collen is late on [tex]0[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} $[/tex]
[tex]$=\frac{1}{32}[/tex]
Case II :
When Collen is late on [tex]1[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_1$[/tex]
[tex]$=\frac{1}{32} \times 5$[/tex]
[tex]$=\frac{5}{32}[/tex]
Case III :
When Collen was late on [tex]2[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_2$[/tex]
[tex]$=\frac{1}{32} \times 10$[/tex]
[tex]$=\frac{5}{16}[/tex]
Therefore, the [tex]\text{probability}[/tex] that Collen will arrive late to work no more than [tex]\text{twice}[/tex] during a [tex]\text{five day workweek}[/tex] is :
[tex]$=\frac{1}{32} + \frac{5}{32} + \frac{5}{16} $[/tex]
[tex]$=\frac{1}{2}$[/tex]
Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial
function.
f(x) = 2^(5x-6)
h(x) = 3x^5 - 2x^3 - 4x + 7
x=4
x=7
x = 6
x=5
Answer: ¿Hablas español porque no entiendo esto? Si lo haces, ¿puedes decirme en español?
Step-by-step explanation:
[tex]\sqrt{x^{2} +4x+4[/tex] -3=0
Answer:
Given,
[tex] \sqrt{ {x}^{2} + 4x + 4} - 3 = 0 \\ = > \sqrt{ {x}^{2} + 4x + 4} = 3 \\ = > {( \sqrt{ {x}^{2} + 4x + 4} })^{2} = {3}^{2} \\ = > {x}^{2} + 4x + 4 = 9 \\ = > {x}^{2} + 4x + 4 - 9 = 0 \\ = > {x}^{2} + 4x - 5 = 0 \\ = > {x}^{2} + 5x - x - 5 = 0 \\ = > x(x + 5) - 1(x + 5) = 0 \\ = > (x - 1)(x + 5) = 0 \\ \\ \sf \: either \: x - 1 = 0 \: \: \: \: \\ = > x = 1 \: \: \\ \\ \sf \: or \\ x + 5 = 0 \\ = > x = - 5 \\ \\ \green{ \boxed{ \bf \: \: \: \: \: x = 1 \: \: or \: - 5}}[/tex]
But if we put the value of x = 5 then it doesn’t satisfy the equation.
So,
X = 1
Answer:
The answer is [tex]x=1[/tex].
Step-by-step explanation:
To solve this problem, start by factoring the equation using the perfect square trinomial rule, which is states that the middle term is the first term multiplied by the last term, and then multiplied by 2. The formula for the perfect square trinomial rule looks like [tex]a^2+2ab+b^2[/tex], where [tex]a=x[/tex] and [tex]b=2[/tex]. The equation will look like [tex]\sqrt{(x+2)^2}-3=0[/tex].
Next, pull out the terms from under the radical, assuming positive real numbers, which will look like [tex]x+2-3=0[/tex]. Then, simplify the equation by subtracting 3 from 2, which will look like [tex]x-1=0[/tex]. Finally, add 1 to both sides of the equation, and the answer will be [tex]x=1[/tex].
find the next three sequence of 1,3, 9, 27,
Answer: 81, 243, 729
Step-by-step explanation:
STEP ONE: Find a pattern in the sequence
3 ÷ 1 = 3
9 ÷ 3 = 3
27 ÷ 9 = 3
As we can see from the given sequence, each number multiplies 3 to get the next term.
STEP TWO: Find the next three terms
27 × 3 = 81
81 × 3 = 243
243 × 3 = 729
Hope this helps!! :)
Please let me know if you have any questions
please solve part c.d.e and f
SEE THE IMAGE FOR SOLUTION
HOPE IT HELPS
HAVE A GREAT DAY
Sally and Mia run a furniture making company. They work together to build and paint custom dressers.
Sally charges a $100 flat fee for each dresser she builds, plus $420 for each hour she spends building.
Mia charges a $150 flat fee for each dresser she paints, plus $390 for each hour she spends painting.
a) Represent what Sally charges for one dresser as a polynomial. Remember to define any variables!
b) Represent what Mia charges for one dresser as a polynomial. Remember to define any variables!
c) Write a new SIMPLIFIED polynomial that represents their total charges, together, for one dresser.
Answer:
y = 250 + 810x
Step-by-step explanation:
Let
y = total charges
x = cost per hour
Sally: building
y = 100 + 420x
Mia: painting
y = 150 + 390x
Find their total charges of building and painting
Add the total charges of both of them
y = 100 + 420x + 150 + 390x
y = 250 + 810x
Which expression best estimates 6 and three-fourths divided by 1 and two-thirds?
Which expression best estimates 6 and three-fourths divided by 1 and two-thirds?
Answer: The expression is 7/2.
Someone please explain this to me like you would a child
thank you
Answer:
12 degrees
Step-by-step explanation:
Answer:
15 degrees
Step-by-step explanation:
okay haha
so basically the cosine of an angle is the side adjacent to it, divided by the hypotenuse. the sine is the side opposite to that angle divided by the hypotenuse, and the tangent is the side opposite to that angle divided by the side adjacent to it.
in this case we are given the angle and the side opposite to it which is 10, and we are also given the hypotenuse of 39.
what trig function deals with opposite and hypotenuse?
the answer is sine
so we would find the sine of that angle which equals to opposite over hypotenuse:
sin(angle) = 10/39
but, they are asking for the inverse trig function. the inverse of sine is arcsin.
so :
arcsin(10/39) = angle
in a calculator, this would be equal to about 14.857 which is closest to 15.
Does 8in to 1ft reduce it or enlarge it
Answer:
enlarge it
Step-by-step explanation:
I ft = 12 inches
Thus 8 in → 12 in makes the transformation larger.
Thus going from 8 in to 12 in is an enlargement
Write all the possible two-digit numbers which can be formed using the digits 0,3,5
Answer:
i) where the digits can repeat
1. 30
2. 50
3. 33
4. 55
5. 35
6. 53
ii) where the digits cannot be repeated
1. 30
2. 50
3. 35
4. 53
A parabola is graphed below.
What is the equation in vertex form of this parabola?
A
y=2(x−2)2−3
B
y=2(x+2)2−3
C
y=12(x−2)2−3
D
y=12(x+2)2−3
thank you so much! please hurry <3
Answer:
B
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here the vertex = (- 2, - 3 ) , then
y = a(x - (- 2))² - 3 , that is
y = a(x + 2)² - 3
To find a, substitute any point on the graph into the equation
Using the coordinates of the y- intercept (0, 5 )
5 = a(0 + 2)² - 3 ( add 3 to both sides )
8 = a(2)² = 4a ( divide both sides by 4 )
2 = a
y = 2(x + 2)² - 3 → B
Can anyone help me with this?
I thing it lies on the negativity side of the number line between -2,24
helpppp please.......
The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).
This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).
[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]
[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]
note1: I use the identity [tex]\tan^2(\theta)+1 = \sec^2(\theta)[/tex] which is derived from the pythagorean trig identity [tex]\sin^2(\theta)+\cos^2(\theta) = 1[/tex]note2: based on the previous note, we can say [tex]\tan^2(\theta) = \sec^2(\theta)-1[/tex]So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.
Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.
Lucia quiere repartir 4/5 litros de leche entre sus dos hijos en partes iguales. ¿Cuánto le dará a cada hijo?
What is the length of the altitude of the equilateral triangle below?
A. /240
B. 144
C. 12
D. 4
E. 12/3
F. 4/3
Answer:
its C option which is 12
Answer:
A
Step-by-step explanation:
Using Pythagoras' identity in either of the 2 right triangles
a² = (4[tex]\sqrt{3}[/tex] )² + (8[tex]\sqrt{3}[/tex] )² = 48 + 192 = 240 ( take square root of both sides )
a = [tex]\sqrt{240}[/tex] → A
When finding ordered pairs for a table of values for a function, the selection of x-coordinates can be
random
True
O False
Question 12
What is the value of x in the following equation?
2/3x + 2 = 4
Gabriella has a smart phone data plan that costs $25 per month that includes 10 GB of data, but will charge an extra $15 per GB over the included amount. How much would Gabriella have to pay in a month where she used 5 GB over the limit? How much would Gabriella have to pay in a month where she used went over by x x GB?
What is the area for the circle?
Answer:
108 squared centimeters
Step-by-step explanation:
Let's exchange π for 3:
area = πr^2
= 3r^2
Now, as you can see, the radius of this circle is 6. Let's plug in the value of r:
area = 3r^2
= 3 · 6^2
Simplify 6^2:
area = 3 · 6^2
= 3 · 36
Multiply 3 by 36:
area = 3 · 36
area = 108
108 squared centimeters
please find the answer
there are options given below
plz give answer asap
Answer
33.3
Step-by-step explanation:
if u multiply the 2, and then find the ratio of them in comparison to the number under, you will find the rate decreases by 10 percent every time, the first situation it is 4/8 = 5/10, second situation is it 32/80= 4/10, and htis situation is most like 3/10, right ? so the answer would be 33.3 :)
Find the largest prime factor of 18! + 19! + 20!
Answer: Prime Factors for 18: 2, 3, and 3
Prime Factors for 19: 19
Prime Factors for 20: 2, 2, and 5
Can you mark brainlest
Step-by-step explanation:
factorize the expression:
mn² + mnp + 3mn + 3mp
Answer:
(mn+3m)(n+p)
Step-by-step explanation:
Answer:
(mn + 3m)(n + p)
Step-by-step explanation:
Factorize by grouping:
[tex]mn^2+mnp\\mn(n+p)\\\\3mn+3mp\\3m(n+p)\\\\(mn+3m)(n+p)[/tex]
what is 5 divided by 20.9
Answer:
0.23923444976
1. Ms. Rogers earns $___ each month. She pays 25% of her earnings, or $____ in federal taxes and 6% of her earnings, or $____ in state taxes. She pays ____ % of her earnings, or $____ for insurance. After these deductions, Ms. Rogers takes home $_____
131.76
8
175.68
549
2,196
1,339.56
Answer:
2,196; 549; 131.76; 8; 175.68; 1339.56
Step-by-step explanation:
2,196 is the biggest number, so use that as the first number.
.25x2196=549
.06x2196=131.76
.08x2196=175.68
2196-(549+131.76+175.68)=1339.56
16789047+65390-49532578=?
Answer:
-32678141
Step-by-step explanation:
Your classmate is unsure about how to use side lengths to determine the type of triangle. How would you explain this to your classmate?
Answer:
To determine the type of triangle using side lengths, you could use the converse of the Phythagorean theorem, acute triangle inequality theorem, and the obtuse inequality theorem. For example, if the square of the longest side of a triangle is greater than the sum of the squares of the other two sides, than its obtuse. And if the square of the longest side is less than the sum of the squares of the other two sides, then it would be acute. And if the square of the longest side is equal to the sum of the squares of the two other sides, then it would be a right triangle.
Step-by-step explanation:
it marks it correct on edge and it is not a sample answer.
have a jolly day!
write an equation of the function in the form y=a(b)^x -c that has a y intercept of -6, asymptote of y= -2 and goes through (2,-18)
Step-by-step explanation:
Asymptote: y = 2 y-intercept: (0,8)
Step-by-step explanation:
The given function is
f(x) = 6(0.5)^{x} + 2f(x)=6(0.5)
x
+2
This function is of the form:
f(x) = a {b}^{x} + cf(x)=ab
x
+c
where y=c is the horizontal asymptote.
By comparing , we have c=2 hence the horizontal asymptote is
y = 2y=2
To find the y-intercept, we put x=0 into the function to get:
f(0) = 6(0.5)^{0} + 2 = 6 + 2 = 8f(0)=6(0.5)
0
+2=6+2=8
Therefore the y-intercept is (0,8).
Menos 10 * 12 * -4 + 40 * -2 * 6 - 2 por favor
Answer:
-2
Step-by-step explanation:
-10 x 12 x -4 + 40 x -2 x 6 - 2
-120 x -4 - 80 x 6 - 2
480 - 480 - 2
0 - 2
-2
