y = 2 3 x − 5 y = −2x + 3 On a coordinate plane, 2 lines intersect at (negative 3, negative 3). She determined that the solution is (–3, –3). Is she correct? If not, explain why.

Answer:

34.64 cm

Step-by-step explanation:

sin 60 = [tex]\frac{x}{40}[/tex]

sin 60 (40) = x

34.64 = x

equilateral triangles have 60° angles.

sin Ф = [tex]\frac{opposite}{hypotenuse}[/tex]

hypotenuse is 40. All sides are 40.

x = opposite or height of triangle.

Answer:

perimeter of a square is l+l+l+l

16+16+16+16=64

Answer:

4√2 cm

Step-by-step explanation:

Perimeter of square = 4a = 16cm

a = 16 / 4

a = 4 cm

Length of each side = 4 cm

Diagonal^2 = side^2 + side^2

= 4^2 + 4^2

= 16 + 16

Diagonal^2 = 32

Diagonal = 4√2 cm

Answer:

2nd option

Step-by-step explanation:

[tex]\frac{7\pi }{12}[/tex] is an angle in the second quadrant

Thus to find the reference angle, subtract from π , that is

r = π - θ

Answer:

142 [tex]cm^3\\[/tex]

Step-by-step explanation:

You have to do [tex](7*5)+(5*3)+(7*3)+(7*3)+(5*7)+(3*5)[/tex].

This equals 142 [tex]cm^3\\[/tex].

Answer:

The answer is 142cm

Step-by-step explanation:

Answer: [tex]\$125,971.2[/tex]

Step-by-step explanation:

Given

Principal amount [tex]P=\$100,000[/tex]

Rate of interest [tex]r=8\%[/tex]

Time period [tex]t=3\ yr[/tex]

Amount in compound interest is given by

[tex]\Rightarrow A=P\left(1+r\%\right)^t\\\Rightarrow A=100,000(1+0.08)^3\\\Rightarrow A=\$125,971.2[/tex]

Thus, the amount accruing for loan is [tex]\$125,971.2[/tex]

Even function:

A function is said to be even if its graph is symmetric with respect to the , that is:

Odd function:

A function is said to be odd if its graph is symmetric with respect to the origin, that is:

So let's analyze each question for each type of functions using examples of polynomial functions. Thus:

FOR EVEN FUNCTIONS:

1. When  becomes  

1.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

We know that the graph  intersects the y-axis when , therefore:

So:

So the y-intercept of  is one unit less than the y-intercept of

1.2. Effects on the regions where the graph is increasing and decreasing

Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function  increases and decreases in the same intervals of

1.3 The end behavior when the following changes are made.

The function is shifted one unit downward, so each point of  has the same x-coordinate but the output is one unit less than the output of . Thus, each point will be sketched as:

FOR ODD FUNCTIONS:

2. When  becomes  

2.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is one unit less. So the graph is shifted one unit downward again.

An example is shown in Figure 1. The graph in blue is the function:

and the function in red is:

So you can see that:

2.2. Effects on the regions where the graph is increasing and decreasing

The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of

In Figure 1 you can see that both functions increase at:

and decrease at:

2.3 The end behavior when the following changes are made.

It happens the same, the output is one unit less than the output of . So, you can write the points just as they were written before.

So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.

FOR EVEN FUNCTIONS:

3. When  becomes  

3.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

As we know, the graph  intersects the y-axis when , therefore:

And:

So the new y-intercept is the negative of the previous intercept shifted one unit upward.

3.2. Effects on the regions where the graph is increasing and decreasing

In the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

3.3 The end behavior when the following changes are made.

Each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward, that is:

FOR ODD FUNCTIONS:

4. When  becomes  

4.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept shifted one unit upward.

4.2. Effects on the regions where the graph is increasing and decreasing

In this case it happens the same. So in the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

4.3 The end behavior when the following changes are made.

Similarly, each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward.

Answer:

11/15 = 73%

Step-by-step explanation:

because in total there are 15 cards and 4 of them is not green. You would want to see what is the probability of other colored carded after leaving out the green ones.

The probability that both cards drawn from the box are not green is 27/52.

To determine the probability that both cards drawn from the box are not green, we need to calculate the probability of each individual draw and multiply them together.

Initially, the box contains a total of 6 red index cards, 3 yellow index cards, and 4 green index cards.

For the first draw, there are a total of 13 cards in the box. Since we are interested in the probability of not drawing a green card, there are 13 - 4 = 9 non-green cards. Therefore, the probability of not drawing a green card on the first draw is 9/13.

For the second draw, there will be 12 cards left in the box. Since one green card has already been removed, there are now 12 - 3 = 9 non-green cards remaining. Thus, the probability of not drawing a green card on the second draw is 9/12.

To find the overall probability, we multiply the probabilities of each individual draw:

(9/13) * (9/12) = 27/52

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Answer:

every single angle is 90°

Step-by-step explanation:

remember that,

4 angles will form if two lines intersect and the sum of those 4 angles is 360°

we are given the sum of 3 angles i.e 270

so one of the angles should be

[tex] \displaystyle {360}^{\circ} - {270}^{\circ}[/tex]

simplify substraction:

[tex] \displaystyle {90}^{\circ}[/tex]

therefore since one of the angles is 90° the intercepting lines are Perpendicular as a result every single angle formed by the two intercepting lines is 90°

Answer:

90°

Step-by-step explanation:

We know that sum of angle around a point is 360° . Here its already given that sum of three Angles out of 4 is 270°

Therefore :-

Measure of remaining one angle ,

Therefore the measure of the fourth angle is 90°

Answer:

Step-by-step explanation:

Eq. 1 )   −5x−3y−9=0

Eq. 2)   4x−18y−54=0

there are two routes to solve this,   Substitution or  elimination,  I'll go for the 2nd one because I can see that the y values are a multiple of each other :)

    6 *( −5x−3y−9=0 )

Eq. 3) -30x -18y =54

subtract Eq. 2 from Eq. 3  :)

-30x -18y =54

-( 4x−18y=54)

-34x = 0

so according to the equations then x =0 but,  that's not really a full answer, so now we should go back and try the other method, substitution,

then:

-5x = 9 +3y

x = - 9/5 + (-3/5)y

now plug that into Eq. 2

4( - 9/5 + (-3/5)y ) - 18y = 54

-36/5 + (-12/5)y -18y = 54

(-12/5)y - (90/5)y = 54+36/5

-(102/5)*y =270/5+36/5

-(102/5)y = 306/5

y = (-5/102)*(306/5)

y = -306/102

y = -3

then plug in for either equation

-5x-3( -3) = 9

-5x + 9 = 9

-5x = 0

x = 0

now we have the full answer

check it by plugging in both x and y into the 2nd equation

4(0) - 18(-3) = 54

54= 54

this seems good  

Answer:

The distance between the two points is about 7.1 units.

Step-by-step explanation:

We want to find the distance between the two points (-3, 6) and (2, 1).

To find the distance between any two points, we can use the distance formula:

[tex]\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Let (-3, 6) be (x₁, y₁) and (2, 1) be (x₂, y₂). Substitute:

[tex]\displaystyle d=\sqrt{((2)-(-3))^2+((1)-(6))^2}[/tex]

Simplify:

[tex]\displaystyle d=\sqrt{(5)^2+(-5)^2}[/tex]

Evaluate:

[tex]d=\sqrt{25+25}=\sqrt{25(2)}=5\sqrt{2}\approx 7.1\text{ units}[/tex]

The distance between the two points is about 7.1 units.

Answer:

14 m/s²

Step-by-step explanation:

From the question

a ∝ F/m.............. Equation 1

Where a = aceleration, m = mass, F = force

make F the subject of the equation

F = ma............ equation 2

Given: m = 7 kg, a = 4 m/s²

Therefore,

F = 7(4)

F = 28 N

For another object whose mass is 2 kg,

Make a the subject of equation 2

a = F/m

a = 28/2

a = 14 m/s²

Answer:

Step-by-step explanation:

Answer:

∠EFD

Step-by-step explanation:

Δ ABC similar ΔDEF

Trick is to keep the letters in the same order. A for D, B for E, and C for F

∠BCA

Where is the B?

second.

What's the second letter in other triangle?

E.

C is the third. F is the third in the other.

A is first. D is first.

Answer:

D.

Step-by-step explanation:

x = number of glasses of iced tea

y = number of glasses of lemonade

The total number of glasses is

x + y

The total number of glasses is 44

x + y = 44

This is not a choice, but the answer must be equivalent to this equation.

Solve for x by subtracting y from both sides.

x = 44 - y

Answer: D.

The substitution method is used in elimination to find the solution to the equation.

A set of two linear equations with two variables is called a system of linear equations. They create a system of linear equations when evaluated collectively.

The given equation in the problem is;

Equation P: a - b = 9

Equation Q: a+b=5

The value obtained from the equation P is;

a - b = 9

a=b+9

Substitute the value in the equation Q;

a+b=5

b+9+b=5

2b=9-5

b=2

The value of a is;

a-b=9

a-2=9

a=9+2

a=11

Hence the value of a and b will be 11 and 2.

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Answer:

y axis then translate x+1,y+1

Answer: 286 possibilities

Step-by-step explanation:

It's a combination because the order of countries doesn't matter in this scenario.

[tex]_{n} C_{r} =\frac{n!}{r!(n-r)!}=\frac{13!}{10!(13-10)!}=\frac{13!}{10!(3)!}=\frac{13!}{10!(3)!}\\\\=\frac{6227020800}{3628800(6)}=\frac{6227020800}{3628800(6)}=\frac{6227020800}{21772800}=286[/tex]

I hope this is right

Answer:

A

Step-by-step explanation:

Start with the 3.

You know that there is a difference of 4 between (say) 2 and 5. The 3 is a sign that the sequence is increasing.  The members of the sequence are going up.

n - 1 means that the nth terms is calculated as an and uses the number of terms to be n-1. That means that the first term is a1 which is the starting point of the sequence.

The answer is an = a1 + (n-1)*d

d = 3

a1 = - 7

So let's try the formula out.

a4 = -7 + (4 - 1)*3

a4 = -7 + 3 * 3

a4 = -7 + 9

a4 = 2

Is 2 the 4th term in the series? Yes it is!

Answer:

She's, "HOT"!

Step-by-step explanation:

Answer:

If you are camping in a rural setting and look up at the night sky, it can appear

If you are camping in a rural setting and look up at the night sky, it can appear as if there are many more stars visible compared to what you would see in a city or suburban area.

We have,

There is less light pollution in rural areas, allowing for a clearer view of the stars.

Here are some reasons why the night sky can appear different when camping in a rural setting:

Less light pollution:

Clearer atmosphere:

Different orientation:

Altitude:

Relaxation and focus:

Thus,

If you are camping in a rural setting and look up at the night sky, it can appear as if there are many more stars visible compared to what you would see in a city or suburban area.

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Answer:

[tex](x -12)(x + 12)[/tex]

Step-by-step explanation:

Given

See attachment for chart

Required

The factors of [tex]x^2 - 144[/tex]

First, express [tex]x^2 - 144[/tex] as [tex]ax^2 + bx + c[/tex]

So, we have:

[tex]x^2 - 144 = x^2 + 0x - 144[/tex]

Compare the above expression to: [tex]ax^2 + bx + c[/tex]

We have:

[tex]ax^2 + bx + c = x^2 + 0x - 144[/tex]

So:

[tex]a =1[/tex]

[tex]b =0[/tex]

[tex]c = -144[/tex]

and

[tex]a * c = d * e[/tex]

Calculate ac

[tex]a* c = 1 * -144[/tex]

[tex]a* c = -144[/tex]

Rewrite as:

[tex]a* c = -12 * 12[/tex]

Recall that:

[tex]a * c = d * e[/tex]

Hence:

[tex]d = -12; e = 12[/tex]

So, on the x chart, we have:

        ac

d                  e

        b

This gives:

        -144

-12                  12

        0

The factors are

[tex](x + d)(x + e)[/tex]

[tex](x -12)(x + 12)[/tex]

Answer:

✔ (x – 12)

 and  

✔ (x + 12)

Step-by-step explanation:

ST = ST (Common)

RT = TQ (Given)

∠ RTS = ∠ SQT (Both 90°)

So, ∆ RTS ≅ ∆ QTS (By SAS congruency rule)

So, RS = QS (By C.P.C.T.)

=> 2x + 8 = 8x - 4

=> 8 + 4 = 8x - 2x

=> 12 = 6x

=> 12/6 = x

=> 2 = x

SR = 2x + 8 (Given)

=> SR = 2(2) + 8 (Putting the value of x)

=> SR = 4 + 8

=> SR = 12

Answer:

Step-by-step explanation:

Answer:

biggafigure a

mnn

Step-by-step explanation:

Answer:

a) 83,b) -4,c) 48,d) 16,e) 8

Answer:

[tex]\displaystyle A = \frac{32}{3}[/tex]

General Formulas and Concepts:

Calculus

Integrals

Integration Rule [Reverse Power Rule]:                                                                   [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                        [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                             [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                           [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Area of a Region Formula:                                                                                       [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

Curve: x³ + 2x² - 3x

Interval: [-3, 1]

Step 2: Find Area

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Answer:

[tex]x=15[/tex]°

Step-by-step explanation:

The sum of degree measures in a full angle (a circle) is (360) degrees. This means that the sum of all of the angles in this diagram is (360) degrees, as the angles form a full arc. Therefore, one can form an equation by adding up all of the angles and setting the equation equal to (360) degrees. Then one can substitute each angle value with the equation that is used to represent it, simplify, and use inverse operations to solve for the value of (x).

[tex](m<AMB)+(m<BMC)+(m<CMD)+(m<AMD)=(360)[/tex]

Substitute,

[tex](46)+(4x-2)+(9x+6)+(8x-5)=360[/tex]

Simplify,

[tex](46)+(4x-2)+(9x+6)+(8x-5)=360[/tex]

[tex]21x+45=360[/tex]

Inverse operations,

[tex]21x+45=360[/tex]

[tex]21x=315[/tex]

[tex]x=15[/tex]

Answer:

the angle <ABC is equal to 65°

Given:

The expression is:

[tex]2x^3+mx^2+nx+c[/tex]

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

[tex]m+n=-6[/tex]

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

[tex]P(x)=2x^3+mx^2+nx+c[/tex]

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

[tex]P(2)=P(-1)[/tex]              ...(i)

Substituting [tex]x=-1[/tex] in the given polynomial.

[tex]P(-1)=2(-1)^3+m(-1)^2+n(-1)+c[/tex]

[tex]P(-1)=-2+m-n+c[/tex]

Substituting [tex]x=2[/tex] in the given polynomial.

[tex]P(2)=2(2)^3+m(2)^2+n(2)+c[/tex]

[tex]P(2)=2(8)+m(4)+2n+c[/tex]

[tex]P(2)=16+4m+2n+c[/tex]

Now, substitute the values of P(2) and P(-1) in (i), we get

[tex]16+4m+2n+c=-2+m-n+c[/tex]

[tex]16+4m+2n+c+2-m+n-c=0[/tex]

[tex]18+3m+3n=0[/tex]

[tex]3m+3n=-18[/tex]

Divide both sides by 3.

[tex]\dfrac{3m+3n}{3}=\dfrac{-18}{3}[/tex]

[tex]m+n=-6[/tex]

Hence proved.