x^4-x^2+x-1 is divided by x-1

Hi there!

[tex]\large\boxed{x = -3}[/tex]

Begin by distributing the 5:

5(2x) + 5(-12) = -90

Simplify:

10x - 60 = -90

Add 60 to both sides:

10x = -90 + 60

10x = -30

Divide both sides by 10:

x = -3

Answer:

x = -3

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

~

First, divide 5 from both sides of the equation:

5(2x - 12) = -90

(5(2x - 12))/5 = (-90)/5

2x - 12 = -90/5

2x - 12 = -18

Next, add 12 to both sides of the equation:

2x - 12 (+12) = -18 (+12)

2x = -18 + 12

2x = -6

Finally, divide 2 from both sides of the equation:

(2x)/2 - (-6)/2

x = -6/2

x = -3

-3 is your answer for x.

~

Al plantear un sistema de ecuaciones lineales, encontramos que el número de obreros que contrató el ingeniero civil fue 50.

Para encontrar el número de obreros que el ingeniero contrató debemos plantear un sistema de ecuaciones lineales de dos ecuaciones con dos incógnitas, tal como sigue:

[tex] M - 1400*x = -8000 [/tex]   (1)

[tex] M - 1200*x = 2000 [/tex]   (2)

En donde:

M: es la incógnita igual al monto de dinero del ingeniero

x: es la incógnita igual al número de obreros

De la ecuación (1) tenemos:

[tex] M = 1400*x - 8000 [/tex]   (3)

Podemos encontrar el valor de x (número de obreros), introduciendo la ecuación (3) en la ec (2):

[tex] 1400*x - 8000 - 1200*x = 2000 [/tex]

[tex] 200*x = 10000 [/tex]

[tex] x = 50 [/tex]

El monto de dinero inicial del ingeniero sería entonces (ec 3):

[tex] M = 1400*50 - 8000 = 62000 [/tex]

Por lo tanto, el número de obreros que contrató el ingeniero es 50.

Puedes aprender sobre otro método de resolución de sistemas de ecuaciones lineales ingresando acá: https://brainly.com/question/10831551?referrer=searchResults                                    

Espero que te sea de utilidad!

Cheese required for 1 pizza = ½ pound

So, cheese required for 19 pizzas

= 19 × ½ pounds

= 19/2 pounds

= 9½ pounds

So, Hailey needs 9½ pounds of cheese to make 19 pizzas.

The solution is 9.5 pounds

The number of pounds of cheese Hailey need to make 19 pizzas is 9.5 pounds

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of pounds of cheese for 19 pizzas be A

Now , the equation will be

The number of pounds of cheese for 1 pizza = 1/2 pounds

So , the number of pounds of cheese for 19 pizzas = 19 x number of pounds of cheese for 1 pizza

Substituting the values in the equation , we get

The number of pounds of cheese for 19 pizzas = 19 x ( 1/2 )

The number of pounds of cheese for 19 pizzas = 19/2

The number of pounds of cheese for 19 pizzas = 9.5 pounds

Therefore , the value of A is 9.5 pounds

Hence , the number of pounds of cheese is 9.5 pounds

To learn more about equations click :

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They could complete the job together in 2.4 days

The known parameters are;

The number of days it would take Michelle to complete the landscaping job = 6 days

The number of days it would take Danielle to complete the landscaping job = 4 days

The unknown parameter;

The number of days can the job be completed if they work together

The process of finding the solution;

The rate at which Michelle works = 1/6 of the landscaping work per day

The rate at which Danielle works = 1/4 of the landscaping work per day

Method;

Find their combined work rate, from which the time would take them to complete the job together can be found

Let, C, represent their combined work rate

Therefore, we have;

C = (1/6 + 1/4) = 5/12 of the landscaping (work) job/(per) day

The number of days they could complete the, 1, job = 1 job(work)/(5/12 (work)job/day) = 12/5 days = 2.4 days

∴ The number of days they could complete the job together = 2.4 days.

Learn more about unit rate here;

https://brainly.com/question/19605901

Answer:

[tex]{ \tt{(2x + y)( {n}^{2} - 3xy + {y}^{2} )}} \\ = { \tt{(2x {n}^{2} - 3 {x}^{2}y + 2x {y}^{2} + {n}^{2}y - 3x {y}^{2} + {y}^{3} )}} \\ = { \tt{ {y}^{3} - xy(y + 3x) + {n}^{2} y }}[/tex]

Hello!

(2x+y) (n2-3xy+y2)

2x* n²= 2xn²

2x* -3xy = -6x²y

2x* y² = 2xy²

y*n² = yn²

y*-3xy = -3xy²

y* y² = y³

=>

2xn²- 6x²y + 2xy² +yn²- 3xy² +y³

Answer:

The vertex is at (2,1)

Step-by-step explanation:

The vertex form of a quadratic is

y = a(x-h)^2 +k  where (h,k) is the vertex

f(x) = 3(x - 2)^2 + 1.

The vertex is at (2,1)

Answer:

x=y=-2

Step-by-step explanation:

Comparing these ordered pairs, we will get

4^(1/x)=1/2 and 9^(1/y)=1/3

x=-2 and y=-2

Answer:

x = y = - 2

Step-by-step explanation:

Using the rule of radicals/ exponents

[tex]a^{\frac{m}{n} }[/tex] = [tex]\sqrt[n]{a^{m} }[/tex] , [tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] , [tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]

Given

[tex]\sqrt[x]{4}[/tex] = [tex]\frac{1}{2}[/tex] , then

[tex]\sqrt[x]{2^{2} }[/tex] = [tex]\frac{1}{2}[/tex]

[tex]2^{\frac{2}{x} }[/tex] = [tex]2^{-1}[/tex]

Since the bases on both sides are equal, both 2 , then equate exponents

[tex]\frac{2}{x}[/tex] = - 1 ( multiply both sides by x )

2 = - x , that is

x = - 2

Similarly

[tex]\sqrt[y]{9}[/tex] = [tex]\frac{1}{3}[/tex] , then

[tex]\sqrt[y]{3^{2} }[/tex] = [tex]\frac{1}{3}[/tex]

[tex]3^{\frac{2}{y} }[/tex] = [tex]3^{-1}[/tex]

Equating the exponents gives

[tex]\frac{2}{y}[/tex] = - 1 ⇒ - y = 2 ⇒ y = - 2

Answer:

Hi I'm going to answer the question is 0

Step-by-step explanation:

-2x(-8)(10x+1)=0

Multiply -2 times -8 is 16

16x(10x+1)=0

Use the distributive property to multiply 16x by 10x+1

[tex] {160}^{2} + 16 = 0 \\ [/tex]

Factor out x.

x(160x+16)=0

To find equation solutions, solve x=0 and 160x+16=0

x=0

x=

[tex] - \frac{1}{10} [/tex]

Answer:

Find the GCD (or HCF) of numerator and denominator

GCD of 63 and 9 is 9

Divide both the numerator and denominator by the GCD

63 ÷ 9

9 ÷ 9

Reduced fraction:  

7/1

Therefore, 63/9 simplified to lowest terms is 7/1.

Step-by-step explanation:

Answer:

Step-by-step explanation:

there is no number of 7 or greater.

P(≥7)=0/6=0

Answer:

The vertical line test is basically a way to determine whether or not a graph is a function.  All three of the options are accurate, so I would select all three.

Let me know if you have any other questions!

Answer:

x =  127º

Step-by-step explanation:

y = 127º    {Corresponding angles}

x = y      {Vertically opposite angles}

x = 127º

Answer:

its 5/4! haha i used to be good at this when i was in 6th grade:)

Answer:

5

Step-by-step explanation:

median means the number in the middle

The best answer from the choices provide is x = -1 or x = -1

Given the expression

[tex]x^2 + 2x + 1 = 0[/tex]

Factorizing the given expression

[tex](x^2 +x)+(x + 1) = 0\\[/tex]

Factor out the common variable from both brackets

[tex]x(x+1)+1(x+1)=0\\(x+1)(x+1)=0\\x+1 \ and \ x+1=0\\x =0-1 \ and \ x=0-1\\x=-1 \ and \ x =-1[/tex]

Hence the best option is x = -1 or x = -1

Learn more about factorization here: https://brainly.com/question/16099992

The solutions for [tex]f(x) = x^{2}+2\cdot x + 1 = 0[/tex] are [tex]x_{1} = x_{2} = -1[/tex].

We can estimate the roots by a numerical approach, which consists in evaluating the quadratic function ([tex]f(x) = x^{2}+2\cdot x + 1 = 0[/tex]) for a set of values of [tex]x[/tex]. We consider the set of values between [tex]-4\le x \le 4[/tex]:

[tex]\,\,\,\,\,\,x \,\,\,\,\,\,\,\,f(x)\\-4\,\,\,\,\,\,\,\,\,\,\,\,9\\-3\,\,\,\,\,\,\,\,\,\,\,\,4\\-2\,\,\,\,\,\,\,\,\,\,\,\,1\\-1\,\,\,\,\,\,\,\,\,\,\,\,0\\.\,\,\,0\,\,\,\,\,\,\,\,\,\,\,\,\,1\\.\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,4\\.\,\,\,2\,\,\,\,\,\,\,\,\,\,\,\,\,9\\.\,\,\,3\,\,\,\,\,\,\,\,\,\,\,\,\,16\\.\,\,\,4\,\,\,\,\,\,\,\,\,\,\,\,\,25\\[/tex]

According to the previous input, we conclude that roots of the quadratic formula are [tex]x_{1} = x_{2} = -1[/tex].

The solutions for [tex]f(x) = x^{2}+2\cdot x + 1 = 0[/tex] are [tex]x_{1} = x_{2} = -1[/tex].

Answer:

Step-by-step explanation:

Answer:

x ≈ -0.73151

Step-by-step explanation:

answer is 19

the explanation is in the attachment

Answer:

IU=161

Step-by-step explanation:

Angle Formed by Two Secants=  1/2 (difference of Intercepted Arcs)

42 = 1/2 (7m+5 - (3m-1))

Distribute the minus sign

42 = 1/2 (7m+5 - 3m+1))

Combine like terms

42 = 1/2 ( 4m+6)

Distribute the 1/2

42 = 2m+3

Subtract 3 from each side

42-3 = 2m+3-3

39 = 2m

Divide by 2

19.5 = m

The sum of the arcs = 360

IU+ 3m-1 + 7m+5 = 360

IU +10m+4 = 360

IU +10(19.5) +4 = 360

IU +195+4 = 360

IU = 360 - 199

IU=161

Answer:

=5×12÷[-12÷{15+(-9)}]

=5×12÷[-12÷6]

=5×12÷(-2)

=-30

Step-by-step explanation:

Answer:

It's D:5.3

Step-by-step explanation:

√28 =5.29

Round off therefore is 5.3

Answer:

Step-by-step explanation:

I would begin by distributing the L. It will be easier in the end to do it this way. There are a couple of ways you can do this, but distribution is the easiest. After you distribute the L you have

T = 2L + LRS

Next subtract the 2L to get

T - 2L = LRS. Lastly, to isolate the R, divide away the LS to get

[tex]\frac{T}{LS}-\frac{2L}{LS}[/tex] = R  In that second term, the L's cancel each other out, leaving us with

[tex]\frac{T}{LS}-\frac{2}{S}[/tex] = R

Answer:

Domain x ≥ - 5

Range y ≥ - 2

Step-by-step explanation:

x ≥ - 5

y ≥ - 2

Answer:

10x²−9x

Step-by-step explanation:

10x²−10x−6+x+6

=10x²−10x−6+x+6

Combine Like Terms:

=10x²−10x−6+x+6

=(10x²)+(−10x+x)+(−6+6)

=10x²−9x

Answer:

10x^2=9x

Step-by-step explanation:

Add them together into one equation

10x^2 - 10x - 6 + x + 6

Now add like terms. The -6 and 6 cancel eachother out since they equal 0

10x^2 - 10x +x

You should get 10x^2 - 9x

Answer: don't know

Step-by-step explanation:

Answer:

B.5: 5^2(-3)(+7)

Step-by-step explanation:

1. 5 is the HCF of the three numbers, so it goes outside the brackets. 5(^4+4^3−21^2).

2. ^2 is also a factor, so now its 5^2(^2+4-21)

3. Factor by Grouping 5^2(^2−3+7−21)

4. Factor by Grouping 5^2((−3)+7(−3))

5. Factor by Grouping 5^2(−3)(+7)

Thats your final answer.

Step-by-step explanation:

the scanned description is very hard to understand.

so I think what happened :

16x² - 9 = 16

then the first error :

sqrt(16x²) - sqrt(9) = sqrt(16)

that is wrong, as you cannot split a + or - operation inside a sqrt function into + or - separate sqrt results of the parts.

so, correctly, the only possible transformation involving sqrt for both sides :

sqrt(16x² - 9) = sqrt(16)

but it would be even easier to clean up the various constant numbers with each other.

so,

16x² - 9 = 16

16x² = 25

and now we trashes the square root

sqrt(16x²) = sqrt(25)

4x = 5

x = 5/4 or x = -5/4

and I cannot see or understand for my life what the second equation was, as Daniel did something wrong, so I cannot deduct the original equation out of a supposedly wrong

y³ - 1 = 7

Answer:

C

Step-by-step explanation:

Using exterior angle property, we have 97+4x+7=17x+13. 13x=91, x=7

Using Pythagorean theorem

[tex]\\ \sf\longmapsto BC^2=AB^2+AC^2[/tex]

[tex]\\ \sf\longmapsto BC^2=7^2+3^2[/tex]

[tex]\\ \sf\longmapsto BC^2=49+9[/tex]

[tex]\\ \sf\longmapsto BC^2=58[/tex]

[tex]\\ \sf\longmapsto BC=\sqrt{58}[/tex]

Answer:

+1/2

Step-by-step explanation:

its the negative reciprocal