Answer:
3x+4
Step-by-step explanation:
You have to combine like terms to get 3x+4.
Find the slope of
(-3,6)(5,-4)
Answer:
Slope: -5/4
Step-by-step explanation:
Slope formula: [tex]\frac{y^2-y^1}{x^2-x^1}[/tex]
Plug in:
[tex]\frac{-4-6}{5-(-3)}[/tex]
Solve:
[tex]\frac{-4-6}{5-(-3)}[/tex]
-4 - 6 = -10
5-(-3) = 8
-10 5
----- = - -----
8 4
The answer is -5/4
Hope this helped.
In the circle below, if arc AC = 66°, and arc BD = 146, find the measure of
Select one:
a. 146
b. 212
C. 66
d. 106
Answer:
D. 106°Step-by-step explanation:
m∠BPD = m∠APC = 1/2(mAC + mBD) = 1/2(66° + 146°) = 1/2(212°) = 106°Answer:
By applying intersecting chords angle theorem:-
[tex]m\angle BPD= 106[/tex]° [tex]=1/2(BD+AC)[/tex]
[tex]=1/2(146+66)[/tex]
[tex]=1/2\time(212)[/tex]°
[tex]m\angle BPD=106[/tex]°
Answer:- D) 106°
OAmalOHopeO
What is the value of the expression below when z=10z=10 and w=4w=4? 2z-3w 2z−3w
Answer:
8
Step-by-step explanation:
more details
2(10)-3(4)
20-12
8
how do i find perimeter and area of this triangle?
Answer:
u should use a ruler and multiplied
Step-by-step explanation:
I dont know the step by step sorry
The length of a rectangular field is 6 metres longer than its width. If the area of the field is 72 square metres, What are the width and the length of the field?
Answer:
Let's call the length of the field "l", and the width of the field "w".
If the area of the field is 72 square meters, then we have:
l x w = 72
And if the length is 6 meters longer than the width, we have:
l = w+6
So looking at the first equation (l x w = 72), we can substitute the l for a w+6.
And we obtain:
(w+6) x (w) = 72
Which simplifies to w^2 + 6w = 72.
This quadratic equation is pretty easy to solve, you just need to factor it.
w^2 + 6w - 72 = 0
(w-6)(w+12)
This leaves the roots of the quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.
So, the width of the rectangular field is 6, and the length of the field is 12.
Let me know if this helps!
Answer:
we assume one side is x and other side must be x+6 and when we multiple it together we can find x²+6x =72
Step-by-step explanation:
one side is 6 and. other is 12 so the lenght= 12 the width=6
what is the relation that represents the relation
Answer:
what can i help u with
Step-by-step explanation:
I really can't help u with that sorry i am bad at math
What is an equation of the line that passes through the points (0, 8) and (-8, -4)?
Answer:
y = 1.2x + 2
Step-by-step explanation:
slope = (8 - 2)/(5 - 0) = 6/5y-intercept = (0, 2)y = (6/5)x + 2y = 1.2x + 2
Answer:
y=1.5x +8
Step-by-step explanation:
A triangle can have at most___ right angle
О
2
4
1
a right angle can have at least 2
What is a simplified form of 1 − sin^2 θ?
Answer:
cos^2(θ)
Step-by-step explanation:
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.
Answer:
Step-by-step explanation:
I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):
** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.
** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.
** Due east has an angle measure of 0 degrees
Now let's begin.
We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:
[tex]A_x=50cos(89.75)[/tex] so
[tex]A_x=.22[/tex]
[tex]B_x=200cos(0)[/tex] so
[tex]B_x=200[/tex] and we need to add those results together. Due to the rules for adding significant digits properly, the answer is
[tex]C_x=200[/tex] (and remember I am counting that as 3 sig fig's even though it's only 1).
Now for the y components:
[tex]A_y=50sin(89.75)[/tex] so
[tex]A_y=50[/tex] (which I'm counting as 2 sig fig's)
[tex]B_y=200sin(0)[/tex] so
[tex]B_y=0[/tex] and we need to add those results together.
[tex]C_y=50[/tex]
Now for the resultant magnitude:
[tex]C_{mag}=\sqrt{(200)^2+(50)^2}[/tex] and that gives us a final magnitude of
[tex]C_{mag}=206[/tex] m
Now for the angle:
Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so
[tex]tan^{-1}(\frac{50}{200})=14[/tex]
The girl is 206 meters from her starting point at an angle of 14 degrees
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNKW THE ANSWER!!
Answer: will be D
Step-by-step explanation:
If x−2/4=2, then x=10
Answer:
True.
Step-by-step explanation:
[tex]\frac{(10)-2}{4}=2\\\\\frac{8}{4}=2\\\\2=2[/tex]
Answer the question
Answer:
1,041,958.5, or 104,195 1/2
Step-by-step explanation:
All you have to do is 15787.25 times 66, because 15787.25 is the price for on acre, so 66 acres will be 15787.25 times 66. If you want to put it in fraction form, you can do 15787 1/4 times 66. I hoped you liked this answer!
Xochitl went to the store to buy some cherries. The price per pound of the cherries is $4 per pound and she has a coupon for $3.50 off the final amount. With the coupon, how much would Xochitl have to pay to buy 3 pounds of cherries? Also, write an expression for the cost to buy pp pounds of cherries, assuming at least one pound is purchased
Xochitl needs to pay $8.50 to buy 3 pounds of cherries.
The expression for the cost to buy p pounds of cherries would be
$(4p - 3.50)
What is an equation?An equation is written in the form of variables and constants separated by the operation of multiplication and division,
An equation states that terms in different forms on both sides of the equality sign are equal.
Multiplication and division do not separate the terms of an equation.
Given, The price per pound of the cherries is $4 per pound and she has a coupon for $3.50 off the final amount.
Therefore, The cost of 3 pounds of cherries before the discount would be,
= $(3×4).
= $12.
And after the discount, it would be $(12 - 3.50).
= $8.50.
An expression for the cost to buy p pounds of cherries would be,
= $(4p - 3.50)
learn more about equations here :
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ASAP!!! PLEASE
A pair of equations is shown below: y = 2x − 1 y = 4x − 5 Part A: In your own words, explain how you can solve the pair of equations graphically. Write the slope and y-intercept for each equation that you will plot on the graph to solve the equations. (6 points) Part B: What is the solution to the pair of equations? (4 points)
Step-by-step explanation:
526 133 3821
P: 12345
j _o _I _n g _I _r l
o. n z-oo-o-m
Find derivative of 3x^2+4 using limits
The derivative of a function f(x) is defined as
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]
For f(x) = 3x ² + 4, we have
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x+h)^2+4) - (3x^2+4)}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x^2+2xh+h^2) - 3x^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{6xh+3h^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}(6x+3h) = \boxed{6x}[/tex]
What is the volume of the solid? Let π=3.14
.
The volume of the solid as shown in the task content is; 2786.2cm³.
What is the volume of the solid?It can be obtained from the task content that the solid given is a Cone.
On this note, the volume of the cone can be evaluated by means of the formula;
V = (1/3)π r²h where(r =22/2 = 11 and h=22).
Hence, Volume, V = (1/3) ×3.14× (11)²×22 = 2786.2cm³.
Read more on volume;
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Chase took a taxi from his house to the airport. The taxi company charged a pick-up fee of $1.20 plus $4.75 per mile. The total fare was $48.70, not including the tip. Write and solve an equation which can be used to determine x, the number of miles in the taxi ride. write the equation
32 x square Y - 2 y cube
Answer:
207y
Step-by-step explanation:
Can someone answer this pls
Answer:
maximum/minimum value for f(x) = ax2 + bx + c: Put the quadratic in standard form f(x) = a(x − h)2 + k, and the absolute
Step-by-step explanation:
maximum/minimum value is k and it occurs at x = h. If a > 0, then the parabola opens up, and it is a minimum functional value of f.
The lengths of the sides of a triangle are 4,5 and 6 if the length of the longest side of a similar triangle is 15,what is the length of the shortest side of the triangle
Answer:
The length of the shortest side of the triangle is 10.
Step-by-step explanation:
Given that the lengths of the sides of a triangle are 4, 5 and 6, if the length of the longest side of a similar triangle is 15, to determine what is the length of the shortest side of the triangle, the following calculation must be performed :
6 = 15
4 = X
4 x 15/6 = X
10 = X
Therefore, the length of the shortest side of the triangle is 10.
The topic= Direct and Inverse Proportions
It is given that y is directly proportional to x and y=36 and when x=12
(a)
An equation connecting to x and y
(b)
That value of y when x=5
(c)
The value of x when y=12
Please help me answer my hw, thank you!
Answer:
A) 3
B)60
C)4
Step-by-step explanation:
y = kx
36 = 12k
A)k=3
~~~~~~~~~~
b) 60
12*5
c) 4
12/3
Can someone help me with this question? Will give brainliest.
Answer:
5.2561
step by step explanation:
using BODMAS, multiplication comes before addition.
Therefore,
[tex] \sqrt{1.13 + (2.84 \times 9.33)} [/tex]
[tex] \sqrt{1.13 + 26.4971} [/tex]
[tex] \sqrt{27.6272} [/tex]
Therefore the answer is
5.2561
Write an equation of the graph (shown below) in slope intercept form.
Let the lengths of each side of △ABC having area equal to 1 be as follows: AB = 2, BC = a and CA = b. Let CD be a perpendicular line from point C to AB. Answer the following questions.
(1) Given AD = x, write a²+(2√3-1)b² in the form of x.
(2) Find the value of x at which a²+(2√3 - 1)b² is the lowest and the magnitude of ∠BAC.
Need help! Please show your work too. Thanks!
Answer:
Part 1)
[tex]\displaystyle \left((2-x)^2 + 1)\right) + (2\sqrt{3} - 1 ) \left(x^2 + 1\right)[/tex]
Or simplified:
[tex]\displaystyle = 2\sqrt{3}x^2 - 4x + 4 + 2\sqrt{3}[/tex]
Part 2)
The value of x for which the given expression will be the lowest is:
[tex]\displaystyle x = \frac{\sqrt{3}}{3}\approx 0.5774[/tex]
And the magnitude of ∠BAC is 60°.
Step-by-step explanation:
We are given a ΔABC with an area of one. We are also given that AB = 2, BC = a, and CA = b. CD is a perpendicular line from C to AB.
Please refer to the diagram below.
Part 1)
Since we know that the area of the triangle is one:
[tex]\displaystyle \frac{1}{2} (2)(CD) = 1[/tex]
Simplify:
[tex]\displaystyle CD = 1[/tex]
From the Pythagorean Theorem:
[tex]\displaystyle x^2 + CD^2 = b^2[/tex]
Substitute:
[tex]x^2 + 1 = b^2[/tex]
BD will simply be (2 - x). From the Pythagorean Theorem:
[tex]\displaystyle (2-x)^2 + CD^2 = a^2[/tex]
Substitute:
[tex]\displaystyle (2-x)^2+ 1 = a^2[/tex]
We have the expression:
[tex]\displaystyle a^2 + (2\sqrt{3} - 1) b^2[/tex]
Substitute:
[tex]\displaystyle = \boxed{\left((2-x)^2 + 1)\right) + (2\sqrt{3} - 1 ) \left(x^2 + 1\right)}[/tex]
Part 2)
We can simplify the expression. Expand and distribute:
[tex]\displaystyle (4 - 4x + x^2 + 1)+ (2\sqrt{3} -1)x^2 + 2\sqrt{3} - 1[/tex]
Simplify:
[tex]\displaystyle = ((2\sqrt{3} -1 )x^2 + x^2) + (-4x) + (4+1-1+2\sqrt{3})[/tex]
Simplify:
[tex]\displaystyle = 2\sqrt{3}x^2 - 4x + 4 + 2\sqrt{3}[/tex]
Since this is a quadratic with a positive leading coefficient, it will have a minimum value. Recall that the minimum value of a quadratic always occur at its vertex. The vertex is given by the formulas:
[tex]\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)[/tex]
In this case, a = 2√3, b = -4, and c = (4 + 2√3).
Therefore, the x-coordinate of the vertex is:
[tex]\displaystyle x = -\frac{(-4)}{2(2\sqrt{3})} = \frac{1}{\sqrt{3}} =\boxed{ \frac{\sqrt{3}}{3}}[/tex]
Hence, the value of x at which our expression will be the lowest is at √3/3.
To find ∠BAC, we can use the tangent ratio. Recall that:
[tex]\displaystyle \tan \theta = \frac{\text{opposite}}{\text{adjacent}}[/tex]
Substitute:
[tex]\displaystyle \tan \angle BAC = \frac{CD}{x}[/tex]
Substitute:
[tex]\displaystyle \tan \angle BAC = \frac{1}{\dfrac{\sqrt{3}}{3}} = \sqrt{3}[/tex]
Therefore:
[tex]\displaystyle\boxed{ m\angle BAC = \arctan\sqrt{3} = 60^\circ}[/tex]
which of the following represents…
Help anyone can help me do this question,I will mark brainlest.
Answer:
Question 3: 220 centimeters
Question 4: 31.4 millimeters
Step-by-step explanation:
Question 3:
Formula for circumference: 2πr
2πr
Exchange π for 22/7
2 · (22/7) · r
Exchange r (radius) for 35
2 · (22/7) · 35
Simplify:
2 · (22/7) · 35
44/7 · 35
220; 220 centimeters
Question 4:
Formula for circumference: 2πr
2πr
Exchange π for 3.14
2 · 3.14 · r
Exchange r (radius) for 5
2 · 3.14 · 5
Simplify:
2 · 3.14 · 5
6.28 · 5
31.4; 31.4 millimeters
Answer:
220 cm31.4 mmStep-by-step explanation:
Concept:
Here, we need to know the idea of circumference.
The circumference is the perimeter of a circle. The perimeter is the curve length around any closed figure.
Circumference = 2πr
Solve:
Question # 1
r = 35 cm
π = 22/7
Circumference = 2πr
Circumference = 2 (22/7) (35)
Circumference = 2 (110)
Circumference = 220 cm
Question # 2
r = 5 mm
π = 3.14
Circumference = 2πr
Circumference = 2 (3.14) (5)
Circumference = 10 (3.14)
Circumference = 31.4 mm
Hope this helps!! :)
Please let me know if you have any questions
If the length of the shorter arc AB is 22cm and C is the center of the circle then the circumference of the circle
is:
Answer:
22= 2(pi)(r)(45/360)
28.01
C=176
Step-by-step explanation:
Enter the location of the point as an ordered pair.
5
-5
-6
Answer:
(4,1)
Step-by-step explanation:
(4,1) is the correct answer. Answered by Gauthmath
8. If a prism is 15cm high with its base a triangle having sides 6cm, 8cm and 10cm. Find its volume. (a) 350cm (b) 30cm (c)460cm3 (d)90cm3
Answer:
360cm³
Step-by-step explanation:
Volume of a triangular prism = Base area * Height of prism
Height of prism = 15cm
Base area = 1/2 * 6 * 8
Base area = 24cm²
Volume of the prism = 15 * 24
Volume of the prism = 360cm³