do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
which of the following is not a rational number
A.2
B.-3
C.0.5
they are all rational..
Which of the following answer choices correctly expresses the number 64?
A. 4'6
B. 4'5
C. 4'4
D. 4'3
Answer:
4’3
Step-by-step explanation:
Took test
Answer:
4’3
Step-by-step explanation:
Use a number line to represent the following. (a) {-4,-1, 0, 2, 3}
Step-by-step explanation:
sorry I couldn't draw it properly but that is it...
I hope it helps
Answer:
Step-by-step explanation:
Draw a line and divide it into 13 equal parts.
Mark 0 in the middle of number line.
Mark negative numbers to the left of zero and mark positive numbers to the right of zero.
Independent Practice
x
0
1
2
3
4
y
2
1.5
1
0.5
0
Which kind of function best models the data in the table? Write an equation to model the data.
A.
linear; y= 1 2 x+2
B.
quadratic; y=− x 2
C.
quadratic; y=− 1 2 x 2
D.
linear; y=− 1 2 x+2
Answer:
D. linear; y = - 1/2x + 2
Step-by-step explanation:
As the values of x increase by 1, the values of y decrease by 0.5. This means that we have a negative linear relationship of 1/2. In other words, the slope is -1/2. Our y-intercept is 2 since when x = 0, y = 2. So, D is the correct choice.
Write an equation for the line that passes through (-5, 4) and (-4, 2).
Answer:
y = - 2x - 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 5, 4) and (x₂, y₂ ) = (- 4, 2)
m = [tex]\frac{2-4}{-4-(-5)}[/tex] = [tex]\frac{-2}{-4+5}[/tex] = [tex]\frac{-2}{1}[/tex] = - 2 , then
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 4, 2 ) , then
2 = 8 + c ⇒ c = 2 - 8 = - 6
y = - 2x - 6 ← equation of line
Horizontal and parallel lines e and f are cut by transversals c and d. All angles are described clockwise, from uppercase left. At the intersection of lines e and c, the angles are: 1, 2, 4, 3. At the intersection of lines f and c, the angles are 5, 6, 8, 7. At the intersection of lines e and d, the angles are: 9, 97 degrees, 12, 11.
At the intersection of lines f and d, the angles are 13, 14, 16, 15.
What is the measure of Angle15?
A. mAngle15 = 77°
B. mAngle15 = 83°
C. mAngle15 = 93°
D, mAngle15 = 97°
Answer:
jnkj
Step-by-step explanation:
jnojn[jn[
Go Long Telephone Company charges a flat rate of $18.75 per month plus $0.18 per minute. To Call Telephone Company charges a flat rate of$12.51 per month plus $0.42 per minute. How many minutes would a customer need to use in order for the bill from Go Long and Via Call to be equal at the end of the month?
9514 1404 393
Answer:
26 minutes
Step-by-step explanation:
Let x represent the number of minutes used. The charges will be equal when ...
18.75 +0.18x = 12.51 +0.42x
6.24 = 0.24x . . . . . . . . . . . . . . . subtract 0.18x+12.51
26 = x . . . . . . . . . . . . . . . divide by 0.24
A customer using 26 minutes will receive the same bill from either company.
Match the number with its opposite -5.4
A force of 9 lb is required to hold 35lb crate on a hill. What angle does the hill make with the horizontal?
Answer: [tex]14.9^{\circ}[/tex]
Step-by-step explanation:
Given
Applied force is 9 lb to hold of 35 lb crate on a hill
Suppose the hill makes an angle of [tex]\theta[/tex] with horizontal
There will be two component of weights i.e. along and perpendicular to the hill
Only the component along the hill pulls the crate backwards
So,
[tex]\Rightarrow 35\sin \theta=9\\\\\Rightarrow \sin\theta =\dfrac{9}{35}\\\\\Rightarrow \theta =14.89^{\circ}\approx 14.9^{\circ}[/tex]
Pls help me with this problem
[tex]3x - 8 = 4x - 17 \\ \\ \sf \longmapsto \: 3x + 4x = - 17 + 8 \\ \\ \sf \longmapsto \: 7x = - 9 \\ \\ \sf \longmapsto \: x = \frac{ - 9}{7} [/tex]
What is the fraction called that is used to convert one unit to another?
Answer:
ratio
Step-by-step explanation:
by using a conversion factor and a fraction, a ratio can be created to convert one unit to another.
56s+8 write your answer as a product with a whole number greater than 1
Answer:
Hello,
Step-by-step explanation:
[tex]Factorizing \ the\ expression\ \\56s+8=7*8*s+1*8=8(7*s+1)\\[/tex]
y = -4(x + 6)(x - 8)
How do you write this in standard form?
Answer:
[tex]y = -4x^2 + 8x + 192[/tex]
Step-by-step explanation:
Hi there!
Standard form: [tex]y=ax^2+bx+c[/tex]
[tex]y = -4(x + 6)(x - 8)[/tex]
Use the distributive property to multiply (x+6) and (x-8)
[tex]y = -4(x(x - 8) + 6(x - 8))\\y = -4(x^2 - 8x + 6x - 48)\\y = -4(x^2 - 2x - 48)[/tex]
Multiply the parentheses by -4
[tex]y = -4x^2 + 8x + 192[/tex]
I hope this helps!
To the nearest tenth of a second, the ball is in the air for s.
Answer:
2.4
Step-by-step explanation:
Took the assignment
Answer:
2.4 seconds is the correct answer.
Step-by-step explanation:
Just completed it.
Triangle ABC is shown below with line DE passing through the center:
Triangle ABC is shown with line DE running horizontally through the center of the figure.
If triangle ABC is dilated by a scale factor of three about the center of the triangle, dilated line D'E' will (6 points)
be parallel to the original line
shift three units to the right
be perpendicular to the original line
pass through points D and E
Answer:
D'E' be parallel to the original line
Step-by-step explanation:
Given
[tex]\triangle ABC[/tex]
Line [tex]DE[/tex]
[tex]k = 3[/tex] -- scale factor
Required
The relationship between [tex]DE[/tex] and [tex]D'E'[/tex]
When [tex]\triangle ABC[/tex] is dilated by a scale factor of 3, [tex]\triangle A'B'C'[/tex] will be three times as big as [tex]\triangle ABC[/tex].
Also:
Line [tex]D'E'[/tex] will be three times as long as [tex]DE[/tex]
Since no further transformation is done on [tex]\triangle ABC[/tex] and line [tex]DE[/tex], then [tex]D'E'[/tex] will be parallel to [tex]DE[/tex]
A 12-member jury is to be selected from 15 men and 13 women. Find the probability that this jury has 6 or 7 males.
Answer:
The right solution is "0.5545".
Step-by-step explanation:
According to the question,
The probability of having 6 or 7 males will be:
= [tex]P(6 \ males)+ P(7 \ males)[/tex]
= [tex]\frac{15_C_6\times 13_C_6}{28_C_{12}} + \frac{15_C_7\times 13_C_5}{28_C_{12}}[/tex]
= [tex]\frac{5005\times 1716+6435\times 1287}{30421755}[/tex]
= [tex]\frac{16870425}{30421755}[/tex]
= [tex]0.5545[/tex]
If 1125 = 3^m × 5^n ;find the value of m and n.
9514 1404 393
Answer:
m = 2
n = 3
Step-by-step explanation:
1125 = 9·125 = 3^2 · 5^3
m = 2
n = 3
_____
Additional comment
Using divisibility rules, you can keep dividing by the obvious factors until the quotient is 1.
1125/5 = 225
225/5 = 45
45/5 = 9
9/3 = 3
3/3 = 1 . . . . . . 5 is a factor 3 times; 3 is a factor 2 times.
Find the equation of the line:
Answer:
y = -1/4x - 2
Step-by-step explanation:
y = -1/4x - 2
Victoria's favorite cookie recipe uses 170170170 grams of butter for every 250250250 grams of flour. Victoria's daughter made cookies using 340340340 grams of butter for every 400400400 grams of flour. What will Victoria think of her daughter's cookies?
Answer:
Step-by-step explanation:
Victoria used : 170 g of butter for 250 g of flour.
So, 1 g of flour requires = 170/250 g of butter = 0.68 g of butter.
Victoria's daughter used: 340 g butter for 400 g flour
So, 1 g of flour requires = 340/400 g of butter = 0.85 g of butter
Thus, the cookies are not good made by the daughter as the butter is not in appropriate proportion.
Brown’s time for running a mile in gym class is 9.9 minutes, Ray’s time is 9.47 minutes and Malcolm’s time is 9.76 minutes. Who ran the mile in less time?
Given:
Brown’s time for running a mile in gym class = 9.9 minutes
Ray’s time for running a mile in gym class = 9.47 minutes
Malcolm’s time for running a mile in gym class = 9.76 minutes
To find:
Who ran the mile in less time?
Solution:
It is given that the time taken by Brown, Ray and Malcolm to cover a mile are 9.9 minutes, 9.47 minutes and 9.76 minutes respectively.
9.47 < 9.76 < 9.9
Since, 9.47 minutes is the lowest time, therefore Ray can run a mile in less time.
Find range
of
f(x) =
[tex]1 \div ( |x| - x)[/tex]
Step-by-step explanation:
We need to find thr range if
[tex] \frac{1}{ (|x| - x)} [/tex]
The absoulte value of something is positive.
So
[tex] \frac{1}{x - x} = \frac{1}{0} [/tex]
This function isn't possible so no range exist.
Complete the standard form equation representing the quadratic relationship displayed above, where a, b, and c are constants.
Answer:
Y =-10X +5
Step-by-step explanation:
x1 y1 x2 y2
1 -5 0 5
(Y2-Y1) (5)-(-5)= 10 ΔY 10
(X2-X1) (0)-(1)= -1 ΔX -1
slope= -10
B= 5
Y =-10X +5
Answer:
y = -2x2 + 8x + 5.
Step-by-step explanation:
what is -10/19÷-5/7 but not converted into a decimal please!
Answer:
14/19
Step-by-step explanation:
Dividing fractions is the same as multiplying by the reciprocal:
-10/19 ÷ -5/7
-10/19 x -7/5
Multiply the numerators by each other, as well as the denominators:
70/95
Simplify by dividing both the numerator and denominator by 5:
= 14/19
So, the answer is 14/19
PLEASE HELP HURRY!!!!!!!!!
What is the length of PC¯¯¯¯¯?
Enter your answer as a decimal in the box. Round your final answer to the nearest hundredth.
____ cm
Description of drawing:
Circle A with a tangent and a secant. Point B at 11 o clock, point C at 12 o clock, and point D at 7 o clock are on the circle. Point P is at 11 o clock outside of the circle. Tangent P C and secant B D intersect at point P. Segment P B is labeled as 4 centimeters. Segment B D is labeled as 52 centimeters.
Answer:
PC = 14.42 cm
Step-by-step explanation:
If a tangent and secant are drawn from a point outside a circle, then the product of the lengths of the segments of the secant is equal to the square of the length of the tangent.
PC² = PB × BD
PC² = 4 × 52
PC² = 208
PC = [tex]\sqrt{208}[/tex]
PC = 14.42 cm
The length of PC=14.42 cm.
when a tangent and secant are drawn from a point outside a circle, then the multiplication of the lengths of the segments of the secant is equal to the square of the length of the tangent.
What is the relation between the tangent and secant line?
PC² = PB × BD
Use the given value in above formula we get,
PC² = 4 × 52
PC² = 208
[tex]PC = \sqrt{208}[/tex]
Therefore we get the value of PC is,PC = 14.42 cm.
Therefor the length of PC=14.42 cm.
To learn more about the tangent line visit:
https://brainly.com/question/6617153
Which graph represents an odd function?
y
6
4
.
2
.
O
-6..
4
-2.
2.
.
B
х
لند
4
9
TV
Answer:
the odd graph represented is
y
6
4
1st graph represents the odd function because it is symmetric about origin
What is Graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
For a function f to be odd, it should satisfy the following equation:
f(-x) = -f(x)
For a function f to be even
f(-x)=f(x)
The graph of an odd function will always be symmetric about the origin.
By observing the graphs we can say that:
1st graph is symmetric about origin and hence it is an odd function.
2nd graph is symmetric about y-axis.Hence it is not an odd function.
Hence, 1st graph represents the odd function because it is symmetric about origin
To learn more on Graph click:
https://brainly.com/question/17267403
#SPJ7
How many units the function y = |x - 8| is translated from the parent function?
Answer:
8 Units, let me know if you didn't understand anything.
Step-by-step explanation:
Translation is the simple movement of just left, right, up or down. when dealing with the absolute value function here are the transformations.
A|B(x - C)| + D where A is the vertical stretch that multiplies all y values by A save where y=D. B is the horizontal shrink, so you divide all x values by B except for where x=C. C is the horizontal shift, which is a translation. C makes ALL points on the graph move to the right by C or if C is negative it moves them to the left. it could also look like |x + C|. keep in mind, +C is actually -C because - -C = C. D shifts up and down, so it is also a translation. if D is positive it moves up and if D is negative it moves down.
Nowthe only transformation in your problem is -8, which is a horizontal shift to the right. so the graph moves 8 to the right. There is your answer, 8 units.
Can someone help me out
Answer: [tex]V=3369.3ft^3[/tex]
Step-by-step explanation:
[tex]V=\frac{4}{3}\pi r^3\\V=\frac{4}{3}\pi (9.3)^3\\V=3369.3ft^3[/tex]
Help me to solve this fast ( prove it)
Step-by-step explanation:
sec⁴A + tan⁴A = 1 + (2tan²A/cos²A)
LHS = sec⁴A + tan⁴A
= (sec²A)² + (tan²A)² {using formula of a²+b²)
= (sec²A-tan²A) + 2tan²A.sec²A
= 1 + {2tan²A.(1/cos²A)}
= 1 + (2tan²A/cos²A)
What is the explicit formula for the geometric sequence with this recursive formula
Answer:
Hello,
Answer A
Step-by-step explanation:
[tex]a_1=-6\\\\a_2=a_1*(\dfrac{1}{4} )^1\\\\a_3=a_2*(\dfrac{1}{4} )^1=a_1*(\dfrac{1}{4} )^2\\\\\\\\a_n=a_1*(\dfrac{1}{4} )^{n-1}\\\\Answer\ A\\[/tex]
. State the length of the missing side. Note: This quadrilateral is a parallelogram.
7.7
Step-by-step explanation:
In a parallelogram opposite sides are congruent.
The length of the missing side TQ in the parallelogram is 7.7.
Here, we have, from given figure that, SRQT is a parallelogram.
now, we have,
To find the length of the missing side TQ in the parallelogram,
we can use the properties of a parallelogram.
In a parallelogram, opposite sides are equal in length.
Therefore, we can determine the length of TQ by finding the length of its opposite side, SR.
Given that SR = 7.7,
we know that TQ must also have a length of 7.7.
So, we get,
the length of the missing side TQ in the parallelogram is 7.7.
To learn more on parallelogram click:
brainly.com/question/6166074
#SPJ4
