Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 ​ (2)=2x−1

The type of correlation not associated with scatterplots is an indefinite correlation

Correlation or dependence is any statistical relationship, whether causal or not, between two random variables or bivariate data.

Correlation can only be between -1 and 1 but not outside these values.

Hence the type of correlation not associated with scatterplots is an indefinite correlation

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[tex]\longrightarrow{\green{π=3.14}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \sqrt{ {\pi}^{2} } \\ \\ = \pi \\ \\ = \frac{22}{7} \\ \\ ( \: or \: ) \\ \\ = 3.14 \\ \\ (∵ \sqrt{( {a})^{2} } = a)[/tex]

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

[tex]\pi = 3.14 \\ \\ \sqrt{\pi {}^{2} } \\ \sqrt{ {3.14}^{2} } \\ |3.14| \\ \\ = 3.14[/tex]

Final Answer: 3.14

Step By Step Explanation:

Alternate Forms:

Answer:

B'(2,4) & C'(1,0)

Step-by-step explanation:

According To the Question,

Given, We have an ∆ABC that has coordinates A(3, 1), B(5, 5) and C(4, 1).

Now, After a translation, the coordinates of A' are (0,0) .

Then, the coordinate of B' & C' Also changes the same as like A' .

A(3,1) ⇒ A'(0,0)      {here from x-axis it reduce 3 and from y-axis it reduce 1}

Same as Above,

B(5,5) ⇒ B'(2,4)

&, C(4,1) ⇒ C'(1,0) .

Answer:

43 hours

Step-by-step explanation:

[tex]\frac{y}{1} :\frac{408}{9.5}[/tex]

y × 9.5 = 408 × 1

9.5y = 408

9.5y ÷ 9.5 = 408 ÷ 9.5

[tex]y=42\frac{18}{19}[/tex]

43 hours

Answer:

25

Step-by-step explanation:

Moving it down does not change the length.

Answer:

Two hours

Step-by-step explanation:

The Royal Flush:

$65 + $30(per hour) = $95(for one hour)

$95 + $30 = $125(for two hours

The Leaky Faucet:

$35 + $45(per hour) = $80(for one hour)

$80 + $45 = $125(for two hours)

Therefore, it would take two hours for both of the repair services to have the same total.

Answer:

274

Step-by-step explanation:

202 + 6(9 + 3) =

PEMDAS says parentheses first

202 + 6(12) =

Then multiply

202 +72

Then add

274

Answer:

274

Step-by-step explanation:

202 + 6(9 + 3)

202 + 6(12)

202 + 72

274

Answer:

Es ydjwj rjsbt djeiweke

Answer:

The probability to get the vowel is 1/4.

Step-by-step explanation:

The number of elements in sample space, n(S) = 20

The number of elements in event, n (E) = 5

The probability to get the vowel is

[tex]P(E) =\frac{n(E)}{n(S)}\\\\P(E)=\frac{5}{20}\\\\P(E) = \frac{1}{4}[/tex]

Answer:

Last option

Step-by-step explanation:

First method :

Red Line:

Take 2 coordinates through which the line passes. Let it be (0, 7) and (14, 0).

[tex]slope, m=\frac{ 0-7}{14-0} = -\frac{7}{14} = -\frac{1}{2}[/tex]

[tex]Equation : (y - 7) = -\frac{1}{2}(x)[/tex]

                [tex]2y - 14 = -x\\2y + x = 14\\4y + 2x = 28[/tex]                  [tex][ multiply \ by \ 2 \ on \ both \ sides][/tex]

Blue Line:

Take coordinates through which the line passes.

Let it be (-4, -12) and (-10, -9).

[tex]slope, m = \frac{-9 + 14}{-10} = \frac{5}{-10} = -\frac{1}{2}[/tex]

[tex]equation : (y + 12) = -\frac{1}{2} (x+4)\\[/tex]

              [tex]y = -\frac{1}{2}x - 2 - 12\\\\y = -\frac{1}{2}x -14\\\\2y = -x - 28\\\\-2y = x +28[/tex]

Second Method:

From the graph it is clear the lines are parallel. The slopes of line parallel to each other are equal. So convert each equation into standard line equation form :y = mx + b

And check for set of equation whose slope are same.

First set :

[tex]y = 10x - 15 \\\\=> slope = 10\\\\-9x + 2y = 10\\2y = 9x + 10\\\\y = \frac{9}{2}x + 5 => slope = \frac{9}{2}[/tex]

Slopes are not equal.

Second set :

[tex]2y = 2x + 5\\y = x + \frac{5}{2}\\slope = 1\\\\\\3x -4y = -5\\4y = 3x + 5\\\\\y = \frac{3}{4}x + \frac{5}{4}\\\\slope = \frac{3}{4}[/tex]

Slopes are not equal.

Third set :

[tex]y = 3x +10 \\slope = 3\\\\\\2x - 3y = -6\\3y = 2x +6\\\\y = \frac{2}{3}x + 2\\\\slope = \frac{2}{3}[/tex]

Slopes are not equal.

Fourth set :

[tex]2x + 4y = 28\\4y = -2x +28\\\\y = -\frac{1}{2}x + 7\\\\slope = -\frac{1}{2}\\\\\\-2y = x + 28\\\\y = -\frac{1}{2}x - 14\\\\slope = -\frac{1}{2}[/tex]

Slopes are same.

Answer:

200 ft^3

Step-by-step explanation:

Volume of rectangular prism equation is

[tex]V=lwh[/tex]

steps in attachment

Answer:

£72000

Step-by-step explanation:

According to the Question,

Thus, 5 ⇒ 9000 People

So, 4 ⇒ 7200 People(Men)

      1 ⇒ 1800 People(Women)

Thus, The amount of money made from tickets sold to men is 7200 total Men x £10 Per Ticket Cost ⇒ £72000.

Answer:

Square root of 12

Square root of 20

Step-by-step explanation:

An irrational number contains an infinite decimal.

All other numbers are perfect squares, resulting in whole numbers.

The square root of 9 is 3 because 3 × 3 = 9.

The square root of 12 is 3.464....

The square root of 16 is 4.

The square root of 20 is 4.472....

The square root of 25 is 5.

Step-by-step explanation:

First, given that we must use point slope form, we can define that as

y - y₁ = m (x-x₁), with m being the slope .

To find the slope, we can use the equation

[tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]. Two points on the graph are (0, 1) and (1, 3). For these points, when calculating the slope, 0 and 1 represent x₁ and y₁ respectively, while 1 and 3 represent x₂ and y₂ respectively Using this formula, we can plug our points in to get

[tex]\frac{3-1}{1-0} = 2/1 = 2[/tex]

as our slope. Therefore, our equation is

y - y₁ = 2 (x-x₁).

For our first point, (0,1), we can simply plug 0 in for x₁ and 1 in for y₁ to get

y - 1 = 2(x-0) as one equation

Next, for (1,3) we can plug 1 for x₁ and 3 for y₁ to get

y - 3 = 2 (x-1) as our other equation

Given:

In a right angle triangle, the measures of two legs are 5 ft and 5.6 ft. The measure of the hypotenuse is x.

To find:

The value of x.

Solution:

Pythagoras theorem: In a right angle triangle,

[tex](Hypotenuse)^2=(Base)^2+(Perpendicular)^2[/tex]

Using Pythagoras theorem, we get

[tex](x)^2=(5)^2+(5.6)^2[/tex]

[tex]x^2=25+31.36[/tex]

[tex]x^2=56.36[/tex]

Taking square root on both sides, we get

[tex]x=\sqrt{56.36}[/tex]

[tex]x=7.50733[/tex]

[tex]x\approx 7.5[/tex]

The measure of missing side is 7.5 ft. Therefore, the correct option is D.

Answer:

B. Evidence

Step-by-step explanation:

Reference: like when your drawing something and you want to make sure that you draw the hair the same way some other person did.

Cite: That’s when you give the credits to someone or something 90% sure

Hope this helps :)

Answer:

23

Step-by-step explanation:

The absolute value of any number is just the positive version of that number. For example the absolute value of -12 is 12.

Hope this helps! :)

Answer:

(3p+10q)

Step-by-step explanation:

9p^2 - 100q^2

Rewriting

(3p)^2 - (10q)^2

This is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(3p-10q) (3p+10q)

Answer:

( 3p + 10 q)

Step-by-step explanation:

9 p ² - l00 q ²

(3p)² - ( 10 q) ²

( a ² - b ² = ( a + b) ( a - b) )

( 3p - 10 q) ( 3 p + 10 q)

Answer:

2 1/6 or 13/6

Step-by-step explanation:

Equation: [tex]\frac{1}{3}[/tex] × 6[tex]\frac{1}{2}[/tex]

Distribute: (1/3) ( 6 + 1/2)

(1/3)(6) + (1/3)(1/2)

2 + 1/6

2 1/6 or 13/6

Answer: [tex]\text{m}\angle T=45^{\circ}[/tex]

Step-by-step explanation:

Given: In ΔSTU, [tex]\text{m}\angle S = (2x+10)^{\circ}[/tex] , [tex]\text{m}\angle T = (3x-9)^{\circ}[/tex], [tex]\text{m}\angle U = (6x-19)^{\circ}[/tex]

To find: [tex]\text{m}\angle T[/tex].

We know that the sum of all the angles of a triangle is [tex]180^{\circ}[/tex].

In ΔSTU,

[tex]\text{m}\angle S+\text{m}\angle T+\text{m}\angle U=180^{\circ}\\\\ 2x+10+3x-9+6x-19=180\\\\ 11x-18=180\\\\11x =180+18\\\\11x=198\\\\x=\frac{198}{11}\\\\ x=18[/tex]

[tex]\text{m}\angle T = (3(18)-9)^{\circ}\\\\=(54-9)^{\circ}\\\\= 45^{\circ}[/tex]

Hence, [tex]\text{m}\angle T=45^{\circ}[/tex]

4x + 5 = 3x +4

4x - 3x = 4-5

x = -1

value of x is equal to -1

Answer:

x = -1

Step-by-step explanation:

4x + 5 = 3x +4 (subtract 3x from both sides)

-3x        -3x

=1x         =0

rewrite: x + 5 = 4 (subtract 5 from both sides)

                  -5  -5

                  =0  =-1

Therefore x = -1 (Please mark brainliest hope i helped :)

Answer:

8r6s3 – 13r5s4 + r4s5 – 5r3s6 it is D

Step-by-step explanation:

The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.

Given that;

The expression is,

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

Now, We can find the difference as;

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

⇒ (8r⁶s³ – 9r⁵s⁴ – 4r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ – 5r³s⁶

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Thus, The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

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Answer:

i beleive its option number 1

Answer:

first graph

Step-by-step explanation:

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Then g(x) = | x | - 4 is the graph of f(x) shifted down by 4 units

This is represented by the first graph on the left

Answer:

SA= 882cm^2

Step-by-step explanation:

SA=2( width*length + hight*length + hight*width )

SA=2( 9*20+ 9*20+ 9*9)

SA= 2*441

SA=882cm^2

Answer: y = 1x + 3

Step-by-step explanation:

If you plot it, you see the slope is 1/1, and the y-intercept is at (0, 3).

===========================================================

Explanation:

set A = dice values greater than 4 = {5,6}

set B = dice values 4 or less = {1,2,3,4}

Sets A and B are considered complementary because one or the other must happen. You must either roll something larger than 4 (set A) or you must roll something from set B.

There are 4 items in set B out of 6 possible outcomes. That leads us to the answer 4/6 = 2/3

Answer:

[tex]\int\limits {\int\limits_R {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Step-by-step explanation:

Given

[tex]x - y = 0[/tex]

[tex]x - y = 7[/tex]

[tex]x + y = 0[/tex]

[tex]x + y = 6[/tex]

Required

Evaluate [tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex]

Let:

[tex]u=x+y[/tex]

[tex]v =x - y[/tex]

Add both equations

[tex]2x = u + v[/tex]

[tex]x = \frac{u+v}{2}[/tex]

Subtract both equations

[tex]2y = u-v[/tex]

[tex]y = \frac{u-v}{2}[/tex]

So:

[tex]x = \frac{u+v}{2}[/tex]

[tex]y = \frac{u-v}{2}[/tex]

R is defined by the following boundaries:

[tex]0 \le u \le 6[/tex]  ,  [tex]0 \le v \le 7[/tex]

[tex]u=x+y[/tex]

[tex]\frac{du}{dx} = 1[/tex]

[tex]\frac{du}{dy} = 1[/tex]

[tex]v =x - y[/tex]

[tex]\frac{dv}{dx} = 1[/tex]

[tex]\frac{dv}{dy} = -1[/tex]

So, we can not set up Jacobian

[tex]j(x,y) =\left[\begin{array}{cc}{\frac{du}{dx}}&{\frac{du}{dy}}\\{\frac{dv}{dx}}&{\frac{dv}{dy}}\end{array}\right][/tex]

This gives:

[tex]j(x,y) =\left[\begin{array}{cc}{1&1\\1&-1\end{array}\right][/tex]

Calculate the determinant

[tex]det\ j = 1 * -1 - 1 * -1[/tex]

[tex]det\ j = -1-1[/tex]

[tex]det\ j = -2[/tex]

Now the integral can be evaluated:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex] becomes:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{x^2 - y^2}} \, *\frac{1}{|det\ j|} * dv\ du[/tex]

[tex]x^2 - y^2 = (x + y)(x-y)[/tex]

[tex]x^2 - y^2 = uv[/tex]

So:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{|det\ j|}\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *|\frac{1}{-2}|\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{2}\, dv\ du[/tex]

Remove constants

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 {\int\limits^7_0 {ue^{uv}} \, dv\ du[/tex]

Integrate v

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 \frac{1}{u} * {ue^{uv}} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 e^{uv} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{u*7} - e^{u*0}]du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{7u} - 1]du[/tex]

Integrate u

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7u} - u]|\limits^6_0[/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -(\frac{1}{7}e^{7*0} - 0)][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -\frac{1}{7}][/tex]

Open bracket

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} - 6 -\frac{1}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} -\frac{43}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{42} -\frac{43}{7}][/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]