Write the equation of the line that passes through the points (8, –1) and (2, –5) in standard form, given that the point-slope form is y + 1 = (x – 8).

Answer:

C

Step-by-step explanation:

3(17x-6.5) =108

=17x-6.5=36

=17x =36 +6.5

= 17x=42.4

=x =2.5

Answer:

x= 2.5

Step-by-step explanation:

3(17x-6.5)=108

Divide each side by 3

3/3(17x-6.5)=108/3

17x - 6.5 = 36

Add 6.5 to each side

17x-6.5+6.5=36+6.5

17x = 42.5

Divide by 17

17x/17 = 42.5/17

x= 2.5

Answer:

Area of parallelogram = 21

Step-by-step explanation:

A = BH

Plug in

A = 7×3

Solve

A = 21

The answer will be 21.

Answer:

71.9

Step-by-step explanation:

Whenever you want to round a number to a particular digit, look only at the digit immediately to its right. For example, if you want to round to the nearest tenth, look to the right of the tenths place: This would be the hundredths place digit. Then, if it is 5 or higher, you get to add one to the tenths digit.

After rounding 71.916476787 to 1 decimal place we get 71.9.

We round numbers to get an approximate value of the given number in more compact form and which is easy to work with.

According to the given question we have to round 71.916476787  to 1 decimal place.

So, to round 71.916476787 to 1 decimal place we'll look at the digit of 2 decimal place here in this number it is 1 hence it is less than 5 so we can make all the digits after 1 decimal places zero and rewrite this number as

71.900000000 and we know zeroes are meaning less to the right of the decimal so this can be written as 71.9.

learn more about rounding of numbers :

https://brainly.com/question/28562556

#SPJ2

Step-by-step explanation:

Disclaimer: When writing this on the paper use the theta symbol, I'm using x since I'm on mobile.

2.

i).

[tex] \sin(x) \tan(x) \sec(x) = \tan {}^{2} (x) [/tex]

[tex] \sin(x) \sec(x) \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \sin(x) \frac{1}{ \cos(x) } \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \frac{ \sin(x) }{ \cos(x) } \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \tan( x) ) \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \tan {}^{2} (x) = \tan {}^{2} (x) [/tex]

iii).

[tex] \sec {}^{2} (x) (1 - \sin {}^{2} ( x ) ) = 1[/tex]

[tex] \sec {}^{2} (x) ( \cos {}^{2} (x) ) = 1[/tex]

[tex] \frac{1}{ \cos {}^{2} (x) } \cos {}^{2} (x) = 1[/tex]

[tex]1 = 1[/tex]

v).

[tex] \cot {}^{2} (a) - \cos {}^{2} (a) = \cot {}^{2} (a) \cos {}^{2} (a) [/tex]

[tex] \frac{ \cos{}^{2} (x) }{ \sin {}^{2} (x) ) } - \cos {}^{2} (x) [/tex]

Factor out cosine

[tex] \cos {}^{2} (x) ( \frac{1}{ \sin {}^{2} (x) } - 1) [/tex]

Simplify

[tex] \cos {}^{2} (x) ( \frac{1 - \sin {}^{2} (x) }{ \sin(x) } [/tex]

[tex] \cos {}^{2} (x( \frac{ \cos {}^{2} (x) }{ \sin {}^{2} (x) } ) = [/tex]

[tex]( \cos {}^{2} ( x ) ( \cot {}^{2} (x) )[/tex]

set x=0 to get insights.

at x=0 to the functions are

-2(0-2)²+3 = -5

-2(0+2)²-3 = -11

-2(0-2)²+3 = -5

-2(0-2)²-3 = -11

weird, for some reason option 1 and 3 seem to be the same, maybe that's an accident by the author.

maybe a + was intended inside the parentheses, dunno.

option 1 and 3 seem fine, although I think there is an error in the options. they shouldn't be exactly the same

Answer:

            Boys          Girls               Total

Walk      19              22                   41

Bus        23              10                   33

Cycle     40             56                   96

Total      82              88                  170

Step-by-step explanation:

<TOS=122° [being vertically opposite angle]

Answer:

angleTOS =122°

EXPLANATION:

[ If two straight lines intersect at point O, vertically opposite angles are equal]As vertically opposite angles are equal; Hence AngleTOS=QOR=122°

Answer:

8r+8pg-pq

Step-by-step explanation:

The subtractable pg cancels out one of the 9 pg's. So 9 pg-1 pg= 8 pg

Hope this helps!

There are 30 possible combinations of teachers.

Given that at Tubman Middle School, there are 6 English teachers and 5 science teachers, to determine, if each student takes one English class and one science class, how many possible combinations of teachers are there, the following calculation must be performed:

To calculate possible combinations, the number of options A must be multiplied by the number of options B. Thus, the calculation would be as follows.

Therefore, there are 30 possible combinations of teachers.

Learn more about combinations in https://brainly.com/question/24180105.

Answer: x>12

so i think x is 16.

Answer:

18.8

Step-by-step explanation:

Surface area=2*pi*r*(r+h)=2*pi*1*(3)=18.8

Answer:

x=4sqrt3 a=4 b=3  ,y=8sqrt3 c=8 d=3

Step-by-step explanation:

because this is a 30-60-90 triangle, it is easy to find the side lengths. the longer leg is sqrt(3) times the shorter leg so x= 12/sqrt(3) or 4sqrt(3). the hypotenuse is 2 times the shorter leg so y= 8sqrt(3)

The coldest time of day in Mumbai is 5 hours after midnight.

Since the average temperature t hours after midnight in Mumbai, India, is given by:

T(t)=24.5-5.5sin((2pi(t+1))/24)

We have that

T(t) = 24.5 - 5.5sin((2π(t+1))/24)

The coldest time of day is when T(t) is minimum.

T(t)  is minimum when 5.5sin((2π(t+1))/24) is minimum where t is the coldest time of day at minimum temperature, T(t).

Since for a sine function, -1 ≤ sinФ ≤ 1, the minimum value of sinФ = -1.

So, T(t) = 24.5 - 5.5sin((2π(t+1))/24) is minimum when

5.5sin((2π(t+1))/24) is minimum.

Also, -5.5sin((2π(t+1))/24) = 5.5 × -1 at minimum temperature T(t)

So, 5.5 × -1 = 5.5 × -sin((2π(t+1))/24)

So, -sin((2π(t+1))/24) = -1

sin((2π(t+1))/24) = 1

Taking inverse sine of both sides, we have

sin⁻¹sin((2π(t+1))/24) = sin⁻¹(1)

((2π(t+1))/24) = π/2

Multiplying both sides by 24, we have

(2π(t+1))/24 × 24 = π/2 × 24

(2π(t+1)) = 12π

Dividing both sides by 2π, we have

2π(t+1)/2π = 12π/2π

t + 1 = 6

t = 6 - 1

t = 5 hours

So, the coldest time of day in Mumbai is 5 hours after midnight.

Learn more about average temperature here:

https://brainly.com/question/19388300

Answer:

-10

Step-by-step explanation:

Answer:

(x-3)(5x+4)

x=3 x=-4/5

Answer:

(5x + 4)(x - 3)

Step-by-step explanation:

Hello!

Factor:

Think: What two numbers add up to -11 but multiply to (5)(-12)?

Answer: -15 and 4

Continue:

The factored expression is (5x + 4)(x - 3)

Answer:

0.00065104166

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

8 inches

Step-by-step explanation:

A rhombus is a four sides quadrilateral with the four sides equal in length

A rhombus has 4 equal sides and the diagonal bisect at right angles

Adjacent sides = 9/2 = 4.5

we are to determine the value of the hypotenuse given the adjacent side and angle (108/2) = 54

Cos 54 = adjacent / hypotenuse

0.58778 = 4.5 / hypotenuse

hypotenuse = 4.5 / 0.58778

=7.6559

= 8 inches

Answer:

Step-by-step explanation:

this may or may not be right but I tried my best

Answer:

I am not sure on the answer but i think its $9,000

Step-by-step explanation:

11,000x0.20=2,200

2,200+11,000=13,200

22,200-13,200=9,000

which would mean she got $9,000 from commissions.

if you did 100,000x0.03=3,000

9,000/3,000= 3

so she would have had 3 commissions worth over 100,000

Answer:

[tex]n=35[/tex]

Step-by-step explanation:

From the question we are told that:

Standard Deviation [tex]\sigma=4min[/tex]

Let

[tex]CI=95\%[/tex]

Since

Significance level [tex]\alpha[/tex]

[tex]\alpha =1-CI[/tex]

[tex]\alpha =1-0.95[/tex]

Therefore

[tex]Z_{\alpha/2}=Z_{0.025[/tex]

[tex]Z_{\alpha/2}}=1.96[/tex]

Generally the equation for Sample size is mathematically given by

[tex]n = (Z_{\alpha/2}* \frac{\sigma}{E})^2[/tex]

[tex]n= \frac{1.96 * 3}{1}^2[/tex]

[tex]n=35[/tex]

Answer:

5.41 m

Step-by-step explanation:

First, let's find a side length by taking the square root of the area.

117/64 ^ 1/2 = 1.352...

Next, we need to multiply by 4.

1.352... x 4 = 5.408...

= approximately 5.41

Answer: C. 6x+18

Step-by-step explanation:

Use the distributive property

First multiply 6 times x which is 6x

Then multiply 6 times 3 which is 18

Keep the sign the same

Therefore, this should give you 6x+18

Answer:

[tex]4 \sqrt{122} \sqrt{12} \\ (4 \times 2) \times ( \sqrt{12} \times \sqrt{12} ) \\ (4 \times 2) \times 12 \\ 8 \times 12 \\ 96[/tex]

Answer:

535 students passed and 107 students failed

Step-by-step explanation:

Create a system of equations where p is the number of students who passed and f is the number of students who failed:

p + f = 642

p = 5f

Solve by substitution by plugging in 5f as p into the first equation, then solving for f:

p + f = 642

5f + f = 642

6f = 642

f = 107

So, 107 students failed.

Find how many students passed by multiplying this by 5:

107(5)

= 535

535 students passed and 107 students failed.

Answer:

a) -8x³+x²+6x

d) 16x²-9

Step-by-step explanation:

a) -2x(x+4x²)+3(x²+2x)

Expand each bracket:

-2x(x+4x²)

As the -2x is on the outside of the bracket, you have to times everything inside the bracket by -2x.

-2x times x equals -2x²

-2x times 4x² equals -8x³

Then we expand the other bracket:

3(x²+2x)

3 times x² equals 3x²

3 times 2x equals 6x

We then put all of it together:

-2x²-8x³+3x²+6x

Collect like terms:

-8x³+x²+6x

b) (4x-3)(4x+3)

We will use the FOIL method:

F-First

O-outer

I-Inner

L-Last

Times the first two terms in each bracket:

4x times 4x equals 16x²

Times the outer terms in the bracket:

4x times 3 equals 12x

Times the inside terms in the bracket:

-3 times 4x equals -12x

Times the last terms in the bracket:

-3 times 3 equals -9

Put it together:

16x²+12x-12x-9

The 12x and -12x cancel out to leave 16x²-9

Hope this helps :)

We know at centroid medians bisect each other in the ratio 2:1.

[tex]\\ \sf\longmapsto TY=2x[/tex]

[tex]\\ \sf\longmapsto 2x=30[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{30}{2}[/tex]

[tex]\\ \sf\longmapsto x=15[/tex]

Answer:

A

Step-by-step explanation:

On the median TW the distance from the vertex to the centroid is twice the distance from the centroid to the midpoint , then

YW = [tex]\frac{1}{2}[/tex] × TY = [tex]\frac{1}{2}[/tex] × 30 = 15

Answer:

A, B, C

Step-by-step explanation:

none of the 4 options changes the shape.

but D changes the size.

C is the only one that also maintains the orientation of the triangle - it only shifts its position.

A and B maintain size and shape, but they do change its orientation.