Write and algebraic expression:
The tens digit of a number is b and the units digit is twice as big. What is the value of the number in terms of b if the digits are reversed?

Answer:

UV = 10

HG = 25

Step-by-step explanation:

UV = (11+9)/2 = 20/2 = 10

HG = (28+22)/2 = 50/2 = 25

Answer:

Below in bold.

Step-by-step explanation:

First problem:

The length of the mid segment is the mean of the 2 outer segments.

So it is (11+9)/2

= 20/2

= 10.

Second problem:

As above, it is (22+28) / 2

= 50/2

= 25.

Answer:

siis  corretoed

Step-by-step explanation:

Answer:

A(-2,1)》A1(-8, 4)

B(-3,3)》B1(-12,12)

C(-1,3)》C1(-4,12)

HOPE IT HELPS....

Answer:

H^2 = P^2 + B^2

H^2 = ( 3 root 2 )^2 + ( 3 root 2)^2

H^2 = 18 + 18

H^2 = 36

H = 6

Hence , option A is correct

hope that helps ✌

Answer: 1:3

Step-by-step explanation:

The odds are 2/6 because you’re given 2 choices from the 6 side die you can then simplify that fraction to 1:3

Answer:

Step-by-step explanation:

15. = 2.39

and jus use mathaway lma

Answer:

61

Step-by-step explanation:

45/3 = 15

2*8 = 16

15+16-12+42 = 61

Answer:

15 + 16 + 30

and that is in total 61

Step-by-step explanation:

45/3 = 15

2×8 = 16

-12 + 42 = 30

you simplify an expression by calculating the part expressions, to be left only with the main terms and main operations.

The ratio 2:3 means for every 2 inches on the original, the photocopy would be 3 inches.

3/2 = 1.5

The photocopied image is 1.5 times larger than the original.

Side BG on the original is side FG on the copy:

14 x 1.5 = 21 meters

FG = 21 meters

Answer:

FG = 21

Step-by-step explanation:

The ratio is 2:3

2               BC

----- = ----------------

3                FG

2              14

----- = ----------------

3                FG

Using cross products

2FG = 3*14

2FG = 42

Divide by 2

FG = 21

Answer:

5 cm

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

let h be the hypotenuse , then

h² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )

h = [tex]\sqrt{25}[/tex] = 5

Answer:

x < -51/10

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Step-by-step explanation:

Step 1: Define

Identify

-2(5x + 1) > 49

Step 2: Solve for x

Answer:

x < -51/10

Step-by-step explanation:

-10x -2 > 49

-10x > 51

x < -51/10

Answer:

A=29.12ft^2

Step-by-step explanation:

first, find the area of the triangle and semicircle separately, then add them together to find the total area of the figure:

area of a triangle: 1/2bh

1/2(6)(8)=24ft^2

area of a circle: πr^2

(**we're using 3.14 instead of pi, and it's a semicircle)

1/2(3.14)(4)^2

1/2(3.14)(16)

1/2(50.24)

25.12ft^2

total area of the figure:

24+25.12=29.12ft^2

Answer: 49.12 ft²

Step-by-step explanation:

This figure is composed of

First, find the area of the half-circle.

The area of a full circle is π · r², but since it's only half a circle, we divide that by half, resulting in (π · r²)/2

Therefore, the area of the half-circle is:

(3.14 · 4²)/2 = (3.14 · 16)/2 = 50.24/2 = 25.12 ft²

Second, find the area of the right triangle.

The area of a triangle = ½bh.

Therefore, the area of the triangle is:

½ · 6 · 8 = ½ · 48 = 24 ft²

Add the two areas together:

24 + 25.12 = 49.12 ft²

Answer:

[tex]\text{1) }\\\text{Circumference: }24\pi \text{ m}},\\\text{Length of bolded arc: }18\pi \text{ m}\\\\\text{3)}\\\text{Circumference. }4\pi \text{ mi},\\\text{Length of bolded arc: } \frac{3\pi}{2}\text{ mi}[/tex]

Step-by-step explanation:

The circumference of a circle with radius [tex]r[/tex] is given by [tex]C=2\pi r[/tex]. The length of an arc is makes up part of this circumference, and is directly proportion to the central angle of the arc. Since there are 360 degrees in a circle, the length of an arc with central angle [tex]\theta^{\circ}[/tex] is equal to [tex]2\pi r\cdot \frac{\theta}{360}[/tex].

Formulas at a glance:

Question 1:

The radius of the circle is 12 m. Therefore, the circumference is:

[tex]C=2\pi r,\\C=2(\pi)(12)=\boxed{24\pi\text{ m}}[/tex]

The measure of the central angle of the bolded arc is 270 degrees. Therefore, the measure of the bolded arc is equal to:

[tex]\ell_{arc}=24\pi \cdot \frac{270}{360},\\\\\ell_{arc}=24\pi \cdot \frac{3}{4},\\\\\ell_{arc}=\boxed{18\pi\text{ m}}[/tex]

Question 2:

In the circle shown, the radius is marked as 2 miles. Substituting [tex]r=2[/tex] into our circumference formula, we get:

[tex]C=2(\pi)(2),\\C=\boxed{4\pi\text{ mi}}[/tex]

The measure of the central angle of the bolded arc is 135 degrees. Its length must then be:

[tex]\ell_{arc}=4\pi \cdot \frac{135}{360},\\\ell_{arc}=1.5\pi=\boxed{\frac{3\pi}{2}\text{ mi}}[/tex]

Answer:

a polygon has 3 or more sides

Answer:

5 up and 2 to the right

Step-by-step explanation:

The center will be at the same spot as circle D, dilate by 3, then the dilation maps circle C into circle D.

Answer:

the correct answer is option 1.

The correct explanation is: All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.

Those triangles look the same but are different in size.

And in similar triangles,

the corresponding sides are in proportion to each other and the corresponding angles are equal to each other.

In an equilateral triangle, all three sides are congruent, and all three angles are congruent.

Therefore, any equilateral triangle can be transformed into any other equilateral triangle through a combination of translations, rotations, and reflections, without changing the size or shape of the triangle.

Thus, all equilateral triangles are similar, with side lengths in a 1:1 ratio, since they have the same shape but may differ in size.

To learn more about similar triangles;

https://brainly.com/question/14926756

#SPJ7

Answer:

70 cents or 0.70 dollars

Step-by-step explanation:

one dime is 10 cents so if you have 7 than you have 70 cents

Answer:

Step-by-step explanation:

Relation 1 is a function

Relation 2 is not a function

Relation 3 is a function

Realation 4 is not a function

==================================================

Explanation:

The ratio of boys to girls is 3 to 5, which means,

b/g = 3/5

12/g = 3/5 ... plug in b = 12

12*5 = g*3 ... cross multiply

60 = 3g

3g = 60

g = 60/3 .... divide both sides by 3

g = 20 is the number of girls

b+g = 12+20 = 32 total students in the chess club.

Answer:

The Tasty Beans Coffee House being planned for the corner of SE 12th and Main will ruin a perfectly nice neighborhood. Besides the fact that Tasty Beans already has coffee shops all over the city, it will pull business away from local coffee houses that have been here for decades. In addition, there is already a parking problem on that street, and the new business will just add to the congestion. They're planning a drive-up window, too, and that will mean a steady stream of traffic in a very high-volume area. Ask anyone walking down the street, and they'll tell you this is a bad idea. I speak for my whole neighborhood when I say, "Go away, Tasty Beans!"

Step-by-step explanation:

Answer:

Step-by-step explanation:

In order to write the equation of this line, we need to pick 2 points on the graph where the line goes right through the intersection of the grids. Actually, you only need 1 of these, because the line goes through at (0, 15). Another point then can be (6, 6). Locate this point so you know what I means when I say that the line goes right through where the grids intersect at x = 6 and y = 6 (as opposed to somewhere in the middle of one of these grids). Find the slope between these 2 points:

[tex]m=\frac{6-15}{6-0}=-\frac{9}{6}=-\frac{3}{2}[/tex]

Since there's only one choice with that slope, that is the choice you want.

Answer: [tex]864\ m^2,\ 24\ m[/tex]

Step-by-step explanation:

Given

Perimeter of the rhombus is [tex]120\ m[/tex]

Length of one of the diagonal is [tex]d_1=36\ m[/tex]

All the sides of the rhombus are equal

[tex]\Rightarrow 4a=120\\\Rightarrow a=30\ m[/tex]

Area of the rhombus with side and one diagonal is

[tex]\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}[/tex]

Insert the values

[tex]\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2[/tex]

Area with two diagonals length can be given by

[tex]\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m[/tex]

Thus, the area of the rhombus is [tex]864\ m^2[/tex] and the length of the other diagonal is [tex]24\ m[/tex]

Answer:

x>4

Step-by-step explanation:

3/(x-4) >0

Divide each side by 3

3/(x-4) * 1/3 >0*1/3

1/(x-4) >0

We know if 1/(x-4) >0 then x-4 > 0

x-4>0

Add 4 to each side

x-4+4 >0+4

x>4

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

[tex]:\implies{\dfrac{3}{x-4}>0}\\\\:\hookrightarrow{\dfrac{3}{x-4}×\dfrac{1}{3}>0×\dfrac{1}{3}}\\\\:\longrightarrow{x-4>0}\\\\:\implies{x-4+4>0+4}\\\\ :\dashrightarrow{\sf{x>4}}[/tex]

Answer:

Apply the distributive property.

4

x

+

4

⋅

−

3

−

2

(

x

−

1

)

>

0

Multiply

4

by

−

3

.

4

x

−

12

−

2

(

x

−

1

)

>

0

Apply the distributive property.

4

x

−

12

−

2

x

−

2

⋅

−

1

>

0

Multiply

−

2

by

−

1

.

4

x

−

12

−

2

x

+

2

>

0

Given:- 4(x - 3) - 2(x - 1) > 0.

Solving It:-

4(x - 3) - 2(x - 1) > 0

4x - 12 - 2x + 2 > 0

2x -10 > 0

2x > 10

x > 10/2

x > 5

Answer:

5

Step-by-step explanation:

The Fundamental theorem of Algebra states that a polynomial of degree n has n roots, some may be complex.

11[tex]x^{5}[/tex] + 5x - 3 = 0 ← is a polynomial of degree 5

Thus the equation will have 5 roots

The answer is

w + c ≤ 32

w < 11

w - the number of acres of wheat

c - the number of acres of corn

Johanna will plant up to 32 acres on her farm with wheat and corn:

w + c ≤ 32

Fewer than 11 acres will be planted with wheat:

w < 11

The two inequalities are:

w + c ≤ 32

w < 11

Answer:

Hello,

Answer 8a²c(a+3c) =8a³c+24a²c

Step-by-step explanation:

2a²+6ac=2a(a+3c)

4a²c+12ac²=4ac(a+3c)

H.C.F=2a(a+3c)*4ac=8a²c(a+3c)

Answer:

1st expression:2a×a+2×3×a×c

2nd expression:2×2×a×a+2×2×3×a×c×c

here,

2×a×a+2×3×a×c

2a^a+6ac

Answer:

See explanation

Step-by-step explanation:

Given

[tex]Flat = 20[/tex]

[tex]Visit = 5[/tex]

Required

The function to represent x visits

This is calculated as:

[tex]f(x) = Flat + Visit * x[/tex]

So, we have:

[tex]f(x) = 20 + 5 * x[/tex]

[tex]f(x) = 20 + 5x[/tex]

The second question is incomplete; however, I will explain how to calculate the horizontal asymptote of a rational function.

For polynomials with the same degree (i.e. m = n), the horizontal asymptote is calculated by dividing the coefficients of the highest degrees.

e.g.

[tex]f(x) = \frac{6x^2 + 1}{3x^2 + 4}[/tex] ---the degrees of both is 2

So, the horizontal asymptote is:

[tex]y = 6/3[/tex]

[tex]y =2[/tex]

If the numerator has a higher degree, then there is no horizontal asymptote.

If the denominator has a higher degree, then the horizontal asymptote is:

[tex]y = 0[/tex]

Answer:

First one is B, Second is 5

Step-by-step explanation:

got it right on edge

Answer:

i can help you i know this answer

Answer:

[tex]TD \cong GS[/tex]

Step-by-step explanation:

See comment for complete question

Given:

[tex]TM \cong GL[/tex]

[tex]MD \cong LS[/tex]

Required

The information that shows [tex]\triangle MTD \cong \triangle LGS[/tex] by SSS

By SSS implies that, the three sides of both triangles are congruent

Already, we have:

[tex]TM \cong GL[/tex]

[tex]MD \cong LS[/tex]

The third side of [tex]\triangle MTD[/tex] is [tex]TD[/tex]

The third side of [tex]\triangle LGS[/tex] is [tex]GS[/tex]

So, for both to be congruent by SSS, the third sides must be congruent

i.e.

[tex]TD \cong GS[/tex]

Answer:

Step-by-step explanation:

This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.

The table will look like this before we even fill anything in:

            d        =        r        *        t

SUV

sedan

Ok now we start to pick apart the problem. Motion problems are the hardest of all story problems ever. This is because there are about 100 ways a motion problem can be presented. So far what we KNOW for an indisputable fact is that the distance from Georgetown to Greenville is 120 km. So we fill that in, making the table:

             d      =      r      *      t

SUV     120

sedan  120

The next part is derived from the sentence "After an hour, the SUV was 24 km ahead of the sedan." This tells us the rate of the SUV in terms of the sedan. If the SUV is 24 km ahead of the sedan in 1 hour, that tells us that the rate of the sedan is r and the rate of the SUV is r + 24 km/hr. BUT we have other times in this problem, one of them being 25 minutes. We have a problem here because the times either have to be in hours or minutes, but not both. So we will change that rate to km/min. Doing that:

24 [tex]\frac{km}{hr}[/tex] × [tex]\frac{1hr}{60min}=.4\frac{km}{min}[/tex] So now we can fill in the rates in the table:

            d      =      r      *      t

SUV    120    =   r + .4

sedan 120    =     r

They left at the same time, so now the table looks like this:

             d      =      r      *      t

SUV    120     =   r + .4  *      t

sedan  120    =      r      *      t

We will put in the time difference of 25 minutes in just a sec.

If d = rt, then the equation for each row is as follows:

SUV:   120 = (r + .4)t

sedan:   120 = rt

Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.

Solving the first equation for time:

sedan:  [tex]\frac{120}{r}=t[/tex]  That's the easy one. Now the SUV. This is where that time difference of 25 minutes comes in from the last sentence. Let's think about what that sentence means in terms of the times of each of these vehicles. If the sedan arrived 25 minutes after the SUV, then the sedan was driving 25 minutes longer; conversely, if the sedan arrived 25 minutes after the SUV, then the SUV was driving 25 minutes less than the sedan. The latter explanation is the one I used in the equation. Again, if the SUV was driving 25 minutes less than the sedan, and the equations are solved for time, then the equation for the SUV in terms of time is

[tex]\frac{120}{r+.4}=t-25[/tex] and we solve that for t:

[tex]\frac{120}{r+.4}+25=t[/tex]

Again, going off the fact that times they both leave are the same, we set the equations equal to one another and solve for r:

[tex]\frac{120}{r+.4}+25=\frac{120}{r}[/tex]

I began by first multiplying everything through by (r + .4) to get rid of it in the denominator. Doing that:

[tex][r+.4](\frac{120}{r+.4}) +[r+.4](25)=[r+.4](\frac{120}{r})[/tex] which simplifies very nicely to

[tex]120+25(r+.4)=\frac{120}{r}(r+.4)[/tex]  So maybe it's not so nice. Let's keep going:

[tex]120+25r+10=\frac{120r}{r}+\frac{48}{r}[/tex] and keep going some more:

[tex]130+25r=120+\frac{48}{r}[/tex] and now we multiply everything through by r to get rid of THAT denominator:

[tex]r(130)+r(25r)=r(120)+r(\frac{48}{r})[/tex] giving us:

[tex]130r+25r^2=120r+48[/tex] Now we have a second degree polynomial we have to solve by factoring. Get everything on one side and factor using the quadratic formula.

[tex]25r^2+10r-48=0[/tex]

That factors to

r = 1.2 and r = -1.6 and both of those rates are in km/minute. First of all, we cannot have a negative rate (this is not physics where we are dealing with velocity which CAN be negative) so we throw out the -1.6 and convert the rate of 1.2 km/minute back to km/hr:

[tex]1.2\frac{km}{min}[/tex] × [tex]\frac{60min}{1hr}[/tex] and we get

r = 72 km/h, choice B.

Wow...what a pain THAT was, right?!