Write an one page paper about a athlete that sacrificed his career during the civil rights movement in America. List: Kareem Abdul Jabber, Jim Brown, Tommie Smith and John Carlos, Bill Russell, Althea Gibson, Arthur Ashe.

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Answer 1

Title: Athletes as Activists: Sacrifices Made During the Civil Rights Movement

Introduction:

The civil rights movement in America was a pivotal period in history, marked by a fervent fight for equality and justice. While numerous activists and leaders emerged during this era, it is important to recognize the significant contributions of athletes who used their platforms to champion social change. This paper aims to shed light on the sacrifices made by prominent athletes, including Kareem Abdul Jabbar, Jim Brown, Tommie Smith and John Carlos, Bill Russell, Althea Gibson, and Arthur Ashe, as they courageously took a stand for civil rights amidst the challenges and opposition they faced.

Kareem Abdul Jabbar:

Kareem Abdul Jabbar, one of the greatest basketball players of all time, made a profound impact on and off the court. Born as Lew Alcindor, he converted to Islam and changed his name as an assertion of his cultural identity. Jabbar actively voiced his support for civil rights, refused to participate in the 1968 Olympics as a protest against racial inequality, and consistently advocated for social justice throughout his career.

Jim Brown:

Jim Brown, a renowned football player, took a principled stand against racial discrimination. Despite facing backlash and criticism, Brown used his influence to speak out against injustice and inequality. He notably organized the Cleveland Summit, bringing together prominent black athletes to address civil rights issues, and became a strong advocate for equality and community empowerment.

Tommie Smith and John Carlos:

Tommie Smith and John Carlos, Olympic sprinters, made an indelible mark on the civil rights movement during the 1968 Olympics. With raised fists covered in black gloves, they stood on the podium during the medal ceremony to symbolize black power and protest racial inequality. Their powerful gesture sparked both admiration and outrage, ultimately leading to significant sacrifices, including the loss of their athletic careers.

Bill Russell:

Bill Russell, a legendary basketball player, faced racism throughout his career and became an instrumental figure in the fight against racial discrimination. Despite experiencing prejudice, Russell maintained his integrity and became a vocal advocate for civil rights. He used his platform to raise awareness, break barriers, and inspire others to challenge systemic racism.

Althea Gibson:

Althea Gibson, a trailblazing tennis player, faced numerous obstacles as she broke racial barriers in a predominantly white sport. Through her talent, perseverance, and courage, Gibson not only achieved remarkable success on the tennis court but also paved the way for future generations of black athletes. Her accomplishments challenged the notion of racial inferiority and contributed to the broader civil rights movement.

Arthur Ashe:

Arthur Ashe, an iconic tennis player, combined his athletic prowess with his dedication to social justice. As the first African American man to win a Grand Slam tournament, Ashe used his platform to advocate for equality and fight against racial discrimination. He dedicated his life to promoting education, civil rights, and HIV/AIDS awareness, leaving a lasting legacy both in and beyond the realm of sports.

Conclusion:

The sacrifices made by athletes during the civil rights movement in America were profound and impactful. Through their courageous actions and unwavering commitment to justice, athletes like Kareem Abdul Jabbar, Jim Brown, Tommie Smith and John Carlos, Bill Russell, Althea Gibson, and Arthur Ashe not only faced personal sacrifices but also played a crucial role in advancing the cause of civil rights. Their contributions remind us that athletes can be more than just sports figures – they can be powerful agents of change, using their platforms to inspire and create a better world for all.

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Related Questions

A letter congratulating a teach on winning a physical ed award

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[Your Name], [Your Address], [City, State, ZIP], [Email Address], [Phone Number], [Date], [Teacher's Name], [School Name], [School Address], [City, State, ZIP], Dear [Teacher's Name]. Wishing you continued success and fulfillment in all your future endeavors. Warmest regards, [Your Name]

Subject: Congratulations on Winning the Physical Education Award I hope this letter finds you in good health and high spirits. I am writing to extend my heartfelt congratulations to you on winning the prestigious Physical Education Award. Your remarkable achievement is a testament to your dedication, passion, and outstanding contributions to the field of physical education. As a teacher, you have consistently demonstrated an unwavering commitment to promoting health and wellness among your students. Your innovative teaching methods, enthusiasm, and ability to inspire have undoubtedly had a profound impact on the lives of countless young individuals. Your remarkable success in receiving this award is well-deserved recognition for your exceptional work and accomplishments. Your ability to create an inclusive and engaging learning environment has not only helped students develop physical skills but has also fostered a sense of teamwork, discipline, and self-confidence among them. Your tireless efforts in organizing various sporting events, implementing effective training programs, and encouraging students to adopt an active lifestyle have significantly contributed to the overall well-being of the school community. Your passion for physical education is evident in the way you go above and beyond to ensure that each student feels valued and motivated to pursue their personal fitness goals. Your dedication and commitment as an educator have not only positively impacted the students but have also served as an inspiration to your colleagues. Your willingness to share your expertise, collaborate with others, and continuously strive for excellence is commendable. Once again, congratulations on this well-deserved recognition. Your hard work and dedication are truly exemplary, and I have no doubt that you will continue to make a significant difference in the lives of your students. May this award serve as a reminder of your accomplishments and as encouragement to pursue your passion for physical education.

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Which events are the craters on the moon evidence of?.

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The craters on the moon are evidence of past collisions with asteroids and meteoroids.

When these objects impact the surface, they release a tremendous amount of energy that melts and vaporizes the impacted material,

which then sprays outwards, forming a crater.

Because the moon has no geological activity to erase the evidence of these impacts, the craters are still visible today.

The size and number of craters on the moon provide scientists with valuable information about the history of the solar system.

The craters on the moon are also important because they help scientists understand the impact history of the Earth.

Since the Earth has an atmosphere and geological activity, the evidence of past impacts is often erased.

However, by studying the craters on the moon, scientists can get an idea of how often large objects impact the Earth and what kind of damage they can cause.

In conclusion, the craters on the moon are evidence of past collisions with asteroids and meteoroids. The size and number of these craters provide valuable information about the history of the solar system. By studying these craters, scientists can gain a better understanding of the impact history of both the moon and the Earth.

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g A 475-gram ball is traveling horizontally at 12.0 m/s to the left when it is suddenly struck horizontally by a bat, causing it to reverse direction and initially travel at 8.50 m/s to the right. If the bat produced an average force of 1275 N on the ball, for how long (in milliseconds) was it in contact with the ball?

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The time (in milliseconds) in which the bullet was in contact with the ball is 7.64 millisecond

How do determine the time in contact?

First, we shall determine the impulse of the sytem. This is shown below:

Mass (m) = 475 g = 475 / 1000 = 0.475 KgInitial velocity = 12 m/sFinal velocity = 8.50 m/sImpulse =?

Impule = m(v + u) (since there is a reverse)

= 0.475 × (8.50 + 12)

= 0.475 × 20.5

= 9.74 Ns

Finally, we shall determine the time. Details below:

Impulse = 9.74 NsForce = 1275 NTime =?

Impulse = force × time

9.74 = 1275 × time

Divide both sides by 1275

Time = 9.74 / 1275

= 7.64×10⁻³ s

Multiply by 1000 to excess in millisecond

= 7.64×10⁻³ × 1000

= 7.64 millisecond

Thus, the time taken is 7.64 millisecond

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Oliver, while visiting a nearby army base, gets to visit the firing range. When he fires the first round his mind turns to physics and he wonders. If the bullet leaves the muzzle of the rifle with a velocity of 600 m/s, and the barrel of the rifle is 0. 9 m long, at what average rate is the bullet accelerated while in the barrel? (20 pts)​

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The average rate at which the bullet is accelerated while in the barrel is 666.67 m/s². The length of the barrel is given as 0.9 m.

To calculate the average rate of acceleration, we can use the formula:

acceleration = (final velocity - initial velocity) / time

In this case, the bullet starts from rest at the beginning of the barrel and exits the muzzle with a velocity of 600 m/s. The length of the barrel is given as 0.9 m.

Since the bullet travels the entire length of the barrel, we can consider the time it takes to exit the muzzle as the time of acceleration. The distance traveled in this time is equal to the length of the barrel.

So, using the equation of motion:

final velocity² = initial velocity² + 2 * acceleration * distance

we can rearrange to solve for acceleration:

acceleration = (final velocity² - initial velocity²) / (2 * distance)

Substituting the given values, we get:

acceleration = (600² - 0²) / (2 * 0.9) = 666.67 m/s²

Therefore, the average rate at which the bullet is accelerated while in the barrel is 666.67 m/s².

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can a magnet be used to convert an unmagnetized piece of magnetic material such as an iron nail, into a magnet

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Yes, a magnet can be used to convert an unmagnetized piece of magnetic material such as an iron nail, into a magnet. When a magnet is brought near an unmagnetized material, the magnetic domains of the material get realigned, and it becomes magnetized. This phenomenon is known as magnetic induction.

However, to make the material permanently magnetic, it has to be magnetized in such a way that all its magnetic domains are aligned in the same direction. This can be done by using a magnetic field to align the domains, and once aligned, the material becomes a permanent magnet.

For example, to make an iron nail a permanent magnet, it can be rubbed against a strong magnet several times in the same direction. This will align the magnetic domains of the iron and make it a magnet.

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_____ is to structuralism as _____ is to functionalism.

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Wilhelm Wundt is to structuralism as William James is to functionalism.

Wilhelm Wundt, a German psychologist, is considered the founder of structuralism. Structuralism focused on the analysis of the basic elements of consciousness and the study of mental structures. On the other hand, William James, an American psychologist, is associated with functionalism. Functionalism emphasized the study of the purpose or function of mental processes and behavior, rather than their individual components. It aimed to understand how the mind and behavior adapt to the environment and fulfill specific functions.

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How many joules of kendrick energy does the car have at point c

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The energy of the car at the point that have been marked C is 290 J option D

Conservation of energy in roller coaster

Roller coasters must adhere to the crucial notion of energy conservation. Roller coasters are built to effectively transform potential energy into kinetic energy and vice versa while making sure that the system's overall energy level stays consistent.

The car has the most potential energy and the least kinetic energy at the top of a roller coaster, which is typically at the top of a hill. The pull of gravity causes potential energy to progressively transform into kinetic energy as the car descends. The car's potential energy diminishes as its speed rises.

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A particle with a charge of 5nC has a distance of 0. 5m away from a charge of 9. 5nC. What is its electric potential energy?

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The electric potential energy of the particle with a charge of 5nC, located 0.5m away from a charge of 9.5nC, is 1.9 J.

To calculate the electric potential energy, we can use the formula:

Electric potential energy = (k * q1 * q2) / r

Where:

k is the electrostatic constant (9 x 10^9 N m^2/C^2),

q1 and q2 are the charges of the two particles (in this case, 5nC and 9.5nC, respectively),

r is the distance between the charges (0.5m).

Substituting the given values into the formula:

Electric potential energy = (9 x 10^9 N m^2/C^2) * (5 x 10^-9 C) * (9.5 x 10^-9 C) / 0.5m

Calculating the expression:

Electric potential energy ≈ 1.9 J

Therefore, the electric potential energy of the particle is approximately 1.9 Joules.

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Why do s cells contain only half the number of chromosomes needed for offspring?

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Somatic cells contain only half the number of chromosomes compared to the cells needed for offspring because they have two sets of chromosomes, while gametes have only one set.

Somatic cells contain only half the number of chromosomes compared to the cells needed for offspring because somatic cells are diploid, meaning they contain two complete sets of chromosomes. In humans, for example, somatic cells have 46 chromosomes organized into 23 pairs. During sexual reproduction, the fusion of two gametes (sperm and egg) occurs. Gametes, also known as sex cells, are haploid cells, meaning they contain only one set of chromosomes. In humans, gametes have 23 chromosomes each. When the sperm and egg fuse during fertilization, their haploid sets of chromosomes combine to form a diploid zygote, which will develop into an offspring. The diploid zygote contains the complete set of chromosomes needed for the development of an individual. The fusion of gametes during fertilization restores the diploid number of chromosomes required for normal development and growth of the offspring.

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Two forces PQ act on a body the maximum and minimum resultant forces that can act on the body are 13N and 7N respectively. What are the magnitude of PQ

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Two forces PQ act on a body the maximum and minimum resultant forces that can act on the body are 13N and 7N respectively. The magnitude of PQ (|P|) = 10 N and (|Q|) is 3 N.

To find the magnitude of the forces PQ, we need to determine the maximum and minimum values for the individual forces.

Let's assume that the forces PQ are represented by vectors P and Q.

The maximum resultant force ([tex]F_m_a_x[/tex]) can be achieved when the forces P and Q are aligned in the same direction. In this case, the maximum resultant force is the sum of the magnitudes of the forces P and Q:

[tex]F_m_a_x[/tex] = |P| + |Q|

Given that [tex]F_m_a_x[/tex] is 13 N, we have:

13 N = |P| + |Q| (1)

Similarly, the minimum resultant force ([tex]F_m_i_n[/tex]) can be achieved when the forces P and Q are aligned in opposite directions. In this case, the minimum resultant force is the difference between the magnitudes of the forces P and Q:

[tex]F_m_i_n[/tex] = |P| - |Q|

Given that [tex]F_m_i_n[/tex] is 7 N, we have:

7 N = |P| - |Q| (2)

Now, we can solve the above two equations simultaneously to find the magnitudes of the forces P and Q.

From equation (1):

|P| = 13 N - |Q|

Substituting this into equation (2):

7 N = 13 N - |Q| - |Q|

Simplifying:

2|Q| = 6 N

|Q| = 3 N

Substituting the value of |Q| back into equation (1):

|P| = 13 N - 3 N

|P| = 10 N

Therefore, the magnitude of force P (|P|) is 10 N, and the magnitude of force Q (|Q|) is 3 N.

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What colour does litmus paper change to when it is dipped in an alkali?

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Litmus paper is a common pH indicator used to determine the acidity or alkalinity of a substance. When litmus paper is dipped in an alkali (a basic or alkaline solution), it changes its color to blue.

Litmus paper contains a mixture of dyes that are sensitive to changes in pH. In acidic solutions, the litmus paper turns red, while in alkaline solutions, it turns blue. This color change occurs due to the chemical reactions between the dyes and the hydrogen ions (H+) or hydroxide ions (OH-) present in the solution. Therefore, if litmus paper is dipped in an alkali, it will show a blue color, indicating the alkalinity of the solution.

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An engineer creates a solid steel for an engine. The part has a volume of 1450 cm3. Steel can be purchased for $0. 35 per kg, and has a density of 7. 95g/cm3. If the engineer makes 350 of these parts, what is the cost of the steel to the nearest dollar

Answers

The cost of the steel for 350 parts, to the nearest dollar, is approximately $1413.

How to find cost?

To find the cost of the steel, calculate the total mass of the steel required for 350 parts and then multiply it by the cost per kilogram.

Given:

Volume of each part = 1450 cm³

Density of steel = 7.95 g/cm³

Number of parts = 350

Cost of steel per kilogram = $0.35

First, calculate the total mass of steel required for 350 parts:

Mass of one part = Volume × Density

Mass of one part = 1450 cm³ × 7.95 g/cm³

Mass of one part = 11527.5 g (or 11.5275 kg)

Total mass of steel for 350 parts = Mass of one part × Number of parts

Total mass of steel for 350 parts = 11.5275 kg × 350

Total mass of steel for 350 parts = 4034.625 kg

Next, calculate the cost of the steel:

Cost of steel = Total mass of steel × Cost per kilogram

Cost of steel = 4034.625 kg × $0.35/kg

Cost of steel ≈ $1412.67

Therefore, the cost of the steel for 350 parts, to the nearest dollar, is approximately $1413.

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Suitable cross section shape of a dam wall diagram

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Trapezoidal shapes are used for dams with a height of 20 to 80 meters. Rectangular shapes are used for dams with a height of more than 80 meters. The cross-sectional shape of a dam wall is an important consideration in the design of a dam as it affects the safety and stability of the dam wall.

The cross-section shape of a dam wall is determined by the hydraulic forces that the dam will experience. The suitable cross-section shape of a dam wall diagram should have a wide base with a gradual reduction in width as it approaches the top. It should be designed in such a way that the dam can withstand the force of water pressure and the load of the content loaded. The width of the base should be at least 2 to 3 times the height of the dam. Additionally, the dam wall should have a curvature at the upstream face that minimizes the water pressure at the base of the wall. The most common types of dam cross-section shapes include triangular, trapezoidal, and rectangular shapes. Triangular shapes are preferred for small dams with a height of less than 20 meters. Trapezoidal shapes are used for dams with a height of 20 to 80 meters. Rectangular shapes are used for dams with a height of more than 80 meters. The cross-sectional shape of a dam wall is an important consideration in the design of a dam as it affects the safety and stability of the dam wall.

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Dolasetron (anzemet) is an antiemetic. The concentration is 20 mg/ml. A nauseous 7 weekold 4 kg pitbull puppy named ""Spot"" needs a dose at 0.6 mg/kg IV. How many mg will ""Spot""be given? How many ml?

Answers

Dolasetron (anzemet) is an antiemetic for a nauseous 7 weekold 4 kg pitbull puppy named "Spot" will be given a dose of 2.4 mg of dolasetron (anzemet).

To calculate the dose of dolasetron for "Spot," we multiply the weight of the puppy (4 kg) by the dose per kilogram (0.6 mg/kg). This gives us 2.4 mg. Therefore, "Spot" will be given a dose of 2.4 mg of dolasetron.

To calculate the volume in milliliters (ml) needed for this dose, we need to consider the concentration of dolasetron, which is 20 mg/ml. Since we have 2.4 mg of dolasetron, we divide this by the concentration to obtain the volume. Therefore, "Spot" will be given a dose of 0.12 ml of dolasetron.

In summary, "Spot" will be given a dose of 2.4 mg and the corresponding volume is 0.12 ml of dolasetron.

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The sun heats land faster than it heats water. As a result, the air above the water is usually cooler than that above land. Many times, early in the morning, the air above the water is very dense and is difficult to see through. What effect is observed from this difference in temperature?.

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The effect that is observed from the difference in temperature is a sea breeze.

A sea breeze is a cooling wind that blows from the sea to the land and results from the difference in temperature between the land and the sea. The sun heats land faster than water, which causes the air above the land to heat up faster than the air above the water, as per the given statement.

As a result, the warm air above the land rises, creating low pressure over the land. On the other hand, the cool air above the sea sinks, creating high pressure over the sea. As a result, the cool air moves from the sea to the land, which is known as a sea breeze.So, the difference in temperature caused by the sun's heating land faster than water leads to the formation of a sea breeze.

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Assuming a constant density, the size of an object scales as its mass raised to what power?.

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Assuming a constant density, the size of an object scales as its mass raised to the power of 1/3 (one-third).

The mass, density, and volume of an object are related by the equation:

ρ = m/Vwhere ρ is the density, m is the mass, and V is the volume.

We can write this equation as

V = m/ρThis equation can be used to find the relationship between the mass and volume of an object of constant density.

Assume that we have two objects of the same material with masses m1 and m2.

We can find the ratio of their volumes by taking the ratio of their masses and density as follows:

V1/V2 = m1/ρ / m2/ρV1/V2 = m1/m2V1/V2 = (m1/m2)^(1/3)

This shows that the ratio of the volumes of two objects with the same density is proportional to the cube root of the ratio of their masses.

This relationship can be expressed as:

V ∝ m^(1/3)

This relationship can also be expressed as the size of an object scales as its mass raised to the power of 1/3.

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Describe a condition in which it would be impossible to


actually measure a displacement. URGENT PLEASE HELPP

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It would be impossible to actually measure a displacement if the initial position and final position of the object is not known.

What is the displacement of an object?

The displacement of an object is defined as the change in the position of the object.

Mathematically, the formula for displacement of an object is given as;

Δx = x₂ - x₁

where;

x₂ is the final position of the objectx₁ is the initial position of the object

So the displacement of an object measures the change in the initial position of the object to the final position of the object.

Thus, it would be impossible to actually measure a displacement if the initial position and final position of the object is not known.

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You have discovered and practiced the memory tools and study skills in this learning path.



Describe one specific tool or skill that has been most valuable for you to learn.


Describe how that specific tool or skill has been valuable.


Your answer should be at least two complete sentences.

Answers

One specific tool or skill that has been most valuable for me to learn is the technique of creating mnemonic devices. Mnemonic devices are memory aids that help me remember and recall information more easily. They involve associating the information I want to remember with vivid and memorable images, patterns, or acronyms.

This tool has been valuable because it has significantly improved my ability to retain and retrieve information. By using mnemonic devices, I can convert complex or abstract concepts into visual or auditory cues that are easier for my brain to process and store. It has helped me remember key facts, formulas, and sequences, making my studying more efficient and effective.

Additionally, mnemonic devices have made learning more engaging and fun, as I get to be creative in constructing mental associations that stick in my memory for a long time.

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A call can supply circuit of 0. 4A and 0. 2A through a 4ohms and 10 ohms resistor respectively what is the internal resistant of the cell

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A call can supply circuit of 0. 4A and 0. 2A through a 4ohms and 10 ohms resistor respectively what is the internal resistant of the cellThe internal resistance of the cell is 3 ohms.

According to Ohm's Law, the current in a circuit can be determined using the equation I = V/R, where I is the current, V is the voltage, and R is the resistance. In this case, we have two resistors connected in parallel. Let's assume the voltage of the cell is V.

For the 4-ohm resistor, the current is given as 0.4A. Using Ohm's Law, we can calculate the voltage across the resistor as V1 = I1 * R1 = 0.4A * 4ohms = 1.6V.

For the 10-ohm resistor, the current is given as 0.2A. Using Ohm's Law, we can calculate the voltage across the resistor as V2 = I2 * R2 = 0.2A * 10ohms = 2V.

Since the resistors are in parallel, the voltage across both resistors is the same, so V1 = V2. This means the internal resistance of the cell can be calculated as V = I * r, where r is the internal resistance. Substituting the values, we have 1.6V = 0.4A * r, which gives us r = 1.6V / 0.4A = 4 ohms.

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Susie estimated that she can run for hours at a steady rate of 8mph. She enters a marathon, a distance of 26miles. How long should it take her to complete the race? Give answers in hours and minutes.

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To determine the time it would take Susie to complete the marathon, we can use the formula: Time = Distance / Speed

Given that the distance of the marathon is 26 miles and Susie's steady rate is 8 mph, we can substitute these values into the formula. Time = 26 miles / 8 mph. To calculate the time, we divide 26 miles by 8 mph: Time = 3.25 hours. Since there are 60 minutes in an hour, we can convert the decimal part of the time to minutes: 0.25 hours * 60 minutes/hour = 15 minutes.  Therefore, it would take Susie approximately 3 hours and 15 minutes to complete the marathon.

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If the surface of a moon is impacted by meteorites at a constant rate, the density, or quantity per unit of area, of impact craters on the moon’s surface will increase over time. How can this information be used to determine the relative age of a moon’s surface?.

Answers

The information about the increasing density of impact craters on a moon's surface over time can be used to determine the relative age of the moon's surface.

This concept is based on the principle of superposition, which states that in undisturbed layers of rock or regolith, the oldest layers are at the bottom, and the youngest layers are at the top. When meteorites impact the surface of the moon, they create craters. Over time, new craters form on top of older craters. Therefore, the density of impact craters on the moon's surface can be an indicator of its relative age. If a specific region of the moon has a high density of impact craters, it suggests that the region is older because it has been exposed to meteorite impacts for a longer time, accumulating more craters.  On the other hand, a region with a lower density of impact craters indicates a relatively younger surface with less time for meteorite impacts to accumulate. By comparing the density of impact craters on different regions of the moon's surface, scientists can make relative age determinations. Areas with higher crater density are considered older, while areas with lower crater density are considered younger. It's important to note that this method of age determination assumes a constant rate of meteorite impacts over time and that there have been no major geological events or processes that could have reset or altered the surface. Additionally, the age determination based on crater density is a relative dating technique and does not provide an exact or absolute age for the moon's surface.

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A 5-kg object is moving to the right at 4 m/s and collides with another object moving to the left at 5 m/s. The objects collide and stick together. After the collision, the combined object:

Answers

After the collision, the two objects stick together and move as one. Their total mass is m1 + m2 = 5 kg + m2.

How to determine the effect of the collision

In this case, we can apply the principle of conservation of linear momentum

The initial momentum of the first object (P1_initial) is given by its mass (m1) times its velocity (v1), which is [tex]5 kg * 4 m/s = 20 kg*m/s.[/tex]

Therefore, the total initial momentum [tex](P_{total_initial}) is P1_{initial} + P2_{initial} = 20 kg*m/s - m2 * 5 m/s.[/tex]

After the collision, the two objects stick together and move as one.

Their total mass is m1 + m2 = 5 kg + m2.

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The distribution of the mass of the milky way galaxy is determined by.

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The distribution of the mass of the Milky Way galaxy is determined by measuring the velocity of objects orbiting around it. This is done through the application of Kepler's laws of planetary motion.

There are several methods used to determine the mass distribution of the Milky Way galaxy. One of the most widely used methods is to measure the velocity of objects orbiting around the center of the galaxy. By applying Kepler's laws of planetary motion, which relate the period and radius of an orbiting object to its mass and the mass of the object it is orbiting, astronomers can infer the mass of the Milky Way and its distribution throughout the galaxy. This method is particularly useful for measuring the mass of dark matter in the galaxy, as dark matter cannot be directly observed but exerts a gravitational force on other objects.Another method used to measure the mass distribution of the Milky Way is to study the motion of stars within the galaxy. By analyzing the velocities and positions of stars, astronomers can infer the mass distribution of the galaxy and the presence of dark matter. This method is useful for studying the distribution of mass in the inner regions of the galaxy, where the velocity of stars is affected by the gravitational pull of the central black hole.The distribution of mass in the Milky Way can also be studied by analyzing the gravitational lensing of distant objects. This occurs when light from a distant object is bent by the gravitational field of a massive object, such as a galaxy or cluster of galaxies. By studying the shape and position of the lensed images, astronomers can infer the mass distribution of the galaxy causing the lensing.

The distribution of the mass of the Milky Way galaxy is determined by several methods, including measuring the velocity of objects orbiting around the galaxy, studying the motion of stars within the galaxy, and analyzing the gravitational lensing of distant objects. These methods allow astronomers to infer the mass of the Milky Way and its distribution throughout the galaxy, including the presence of dark matter.

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In the experiment, we measure the total time for 20 complete revolutions and divide it by 20 to obtain the period of the rotation. why not measure the amount of time for one complete revolution directly and record it as the period of rotation?

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In the experiment, measuring the total time for 20 complete revolutions and dividing it by 20 to obtain the period of rotation is done to reduce errors and improve the accuracy of the measurement.

Measuring the time for one complete revolution directly can be subject to human reaction time and potential errors in starting and stopping the stopwatch precisely at the beginning and end of each revolution. These errors can accumulate and affect the accuracy of the measurement.

By measuring the total time for 20 complete revolutions and then dividing it by 20, we are essentially averaging out these potential errors over multiple revolutions. This helps to minimize the impact of any individual timing error and provides a more reliable and accurate measurement of the period of rotation.

Additionally, by taking multiple measurements (in this case, 20), we increase the sample size and reduce the influence of outliers or irregularities in any individual measurement. This improves the overall precision and reliability of the calculated period.

Therefore, measuring the total time for multiple revolutions and dividing by the number of revolutions allows for a more accurate determination of the period of rotation in the experiment.

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A Projectile , initially 80. 0 m from the ground, has an initial velocity of 50 m/s, +60 degree. A0 where is the projectile when its speed is a minimum? b) where is the projectile when its speed is 10. 0 m/s?

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The projectile is approximately (50 m/s * cos(60 degrees) * 2.81 s) meters horizontally away from the initial point when its speed is 10 m/s.

The projectile is at its minimum speed when it reaches the highest point of its trajectory. At this point, the vertical component of the velocity is zero. Since the initial velocity is given as 50 m/s at an angle of 60 degrees, we can find the vertical component of the velocity using trigonometry:

Vertical component = Initial velocity * sin(angle)

Vertical component = 50 m/s * sin(60 degrees)

Vertical component = 50 m/s * 0.866

Vertical component ≈ 43.3 m/s

The time taken to reach the highest point can be found using the equation of motion:

Final velocity = Initial velocity + (acceleration * time)

0 m/s = 43.3 m/s - (9.8 m/s^2 * t)

Solving for time:

43.3 m/s = 9.8 m/s^2 * t

t ≈ 4.42 seconds

Using the time, we can find the horizontal distance traveled by the projectile:

Horizontal distance = Initial velocity * cos(angle) * time

Horizontal distance = 50 m/s * cos(60 degrees) * 4.42 s

Horizontal distance ≈ 120.2 meters

Therefore, the projectile is at its minimum speed when it is approximately 120.2 meters horizontally away from the initial point.

b) To determine the position of the projectile when its speed is 10 m/s, we need to find the time at which it reaches that speed. Since the speed of the projectile is composed of both horizontal and vertical components, we can calculate the speed using the Pythagorean theorem:

Speed = √(Horizontal component^2 + Vertical component^2)

Since we know the initial velocity and angle, we can calculate the horizontal and vertical components:

Horizontal component = Initial velocity * cos(angle)

Vertical component = Initial velocity * sin(angle)

Now we can solve for the time when the speed is 10 m/s:

10 m/s = √((Horizontal component)^2 + (Vertical component)^2)

10 m/s = √((Initial velocity * cos(angle))^2 + (Initial velocity * sin(angle))^2)

Simplifying the equation and solving for time:

10 m/s = √((50 m/s * cos(60 degrees))^2 + (50 m/s * sin(60 degrees))^2)

10 m/s = √((50 m/s * 0.5)^2 + (50 m/s * 0.866)^2)

Solving for time:

t ≈ 2.81 seconds

Using this time, we can calculate the horizontal distance traveled by the projectile:

Horizontal distance = Initial velocity * cos(angle) * time

Horizontal distance = 50 m/s * cos(60 degrees) * 2.81 s

Therefore, the projectile is approximately (50 m/s * cos(60 degrees) * 2.81 s) meters horizontally away from the initial point when its speed is 10 m/s.

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Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. What is the approximate vertical component of the initial velocity? 0. 5 m/s 0. 87 m/s 12. 5 m/s 21. 7 m/s.

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The approximate vertical component of the initial velocity is `21.7 m/s`. The vertical component of an initial velocity in a projectile motion is given by the equation: `Vy = V₀sin(θ)` where `V₀` is the initial velocity of the projectile, `θ` is the angle at which the projectile was thrown and `Vy` is the vertical component of the initial velocity.

The vertical component of an initial velocity in a projectile motion is given by the equation: `

Vy = V₀sin(θ)`

With the given values `V₀ = 25 m/s` and `θ = 60°`,

The vertical component of the initial velocity is:
Vy = V₀sin(θ)
Vy = (25 m/s) sin(60°)
Vy ≈ 21.7 m/s
Therefore, the approximate vertical component of the initial velocity is `21.7 m/s`.

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If the speed of light in an unknown medium is 1.79x108 m/s, what is the index of refraction for that substance?

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Answer:1.68.

Explanation:The index of refraction of a substance can be calculated using the formula:

index of refraction = speed of light in vacuum / speed of light in the substance

The speed of light in vacuum is 3.00 x 10^8 m/s, and the speed of light in the unknown medium is 1.79 x 10^8 m/s.

index of refraction = 3.00 x 10^8 m/s / 1.79 x 10^8 m/s = 1.68

Therefore, the index of refraction for the unknown substance is 1.68.

geostationary satellite are placed in orbit of radius 4.2*10^4km use this information to deduce of at that height

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To deduce the orbital period of a geostationary satellite at a given height, we can use the formula for the orbital period of a satellite:

T = 2π√(r³/GM),

where T is the orbital period, r is the radius of the orbit, G is the gravitational constant (approximately 6.67430 x 10^(-11) m³/(kg·s²)), and M is the mass of the Earth (approximately 5.972 x 10^24 kg).

First, we need to convert the radius of the orbit from kilometers to meters:

r = 4.2 x 10^4 km * 10^3 m/km = 4.2 x 10^7 m.

Now, we can calculate the orbital period:

T = 2π√((4.2 x 10^7)^3 / (6.67430 x 10^(-11) * 5.972 x 10^24)).

Evaluating this expression, we can find the orbital period of the geostationary satellite at that height.

Please note that the above calculation assumes a circular orbit and neglects the effects of other celestial bodies and atmospheric drag, which could slightly affect the satellite's actual orbital period.

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8. The line is 2 meter long. What is the length of the line in millimeters?

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To convert the length of the line from meters to millimeters, we need to understand the relationship between these two units of measurement.

There are 1,000 millimeters (mm) in one meter (m). This conversion factor allows us to convert a length from meters to millimeters.

In this case, the given length of the line is 2 meters. To find the equivalent length in millimeters, we can multiply the given length by the conversion factor of 1,000.

Length in millimeters = Length in meters × Conversion factor

Length in millimeters = 2 meters × 1,000

Length in millimeters = 2,000 millimeters

Therefore, the length of the line is 2,000 millimeters.

When converting units of length, it is important to remember that millimeters are smaller units than meters. So, when converting from meters to millimeters, the value increases because we are dividing a larger unit into smaller units.

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Veronica’s velocity was measured as 4. 3 m/s. She displaced 20 meters in 4. 7 seconds. Which piece of information is missing for the correct calculation of velocity?

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The missing piece of information required for the correct calculation of velocity is the direction of the displacement.

In order to calculate velocity accurately, we need to have both the displacement and the time. In this scenario, the displacement of 20 meters in 4.7 seconds is provided, but the missing piece of information is the direction of the displacement. Velocity is a vector quantity, which means it includes both magnitude (speed) and direction. To calculate the velocity accurately, we need to know whether Veronica's displacement was in a specific direction (e.g., north, east, etc.) or if it was only given as a magnitude (20 meters) without a direction.

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