Write a situation that can be represented by 2x + 6 > 20.

Answer: (3,0) and (-12,0)

Step-by-step explanation:

The x-intercepts of the graph of f(x) = x² + 5x - 36 are (-9,0) and (4,0).

Option B is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

To find the x-intercepts of the function f(x) = x^2 + 5x - 36,

we need to set y = f(x) to 0 and solve for x.

So, we have:

x² + 5x - 36 = 0

We can factor the left side of the equation:

(x + 9)(x - 4) = 0

Using the zero product property, we get:

x + 9 = 0 or x - 4 = 0

Solving for x, we get:

x = -9 or x = 4

Therefore,

The x-intercepts of the graph of f(x) = x² + 5x - 36 are (-9,0) and (4,0).

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Answer:

A. 21°, 69°

Step-by-step explanation:

If you work by process of elimination all you have to do is take 27 away from the bigger degree of the two and see if it is 2x as much as the smaller degree.

Ex.

1. 69°-27°= 42°, which is 2x as many as 21°.

Answer:

x = 5/8

Step-by-step explanation:

x^3 = 125/512

Take the cube root of each side

x^3 ^1/3 = (125/512)^ 1/3

We know (a/b) ^1/3 = a^ 1/3  / b^1/3

x = (125) ^1/3 / (512)^ 1/3

x = 5/8

Answer:

The dimensions are:

l = 2*1.96 = 3.92 yd

h = 5/(1.96)² = 1.30 yd

w = 1.96 yd

Step-by-step explanation:

The volume is given by:

[tex]V=l*w*h[/tex]

Where:

We know that l = 2w, so we have:

[tex]V=2w^{2}*h[/tex]

[tex]10=2w^{2}*h[/tex]

[tex]5=w^{2}*h[/tex] (2)

Now, the surface of this parallelepiped is:

[tex]S=2wh+2lh+lw[/tex]

Using l = 2w:

[tex]S=2wh+4wh+2w^{2}[/tex]

Using (2) we obtain the surface equation in terms of w.

[tex]S=2w\frac{5}{w^{2}}+4w\frac{5}{w^{2}}+2w^{2}[/tex]    

[tex]S=2\frac{5}{w}+4\frac{5}{w}+2w^{2}[/tex]

We need to take the derivative with respect to w to minimize the surface area.

[tex]S=2\frac{5}{w}+4\frac{5}{w}+2w^{2}[/tex]  

[tex]S=\frac{30}{w}+2w^{2}[/tex]

[tex]\frac{dS}{dw}=-\frac{30}{w^{2}}+4w[/tex]

Now, let's equal it to zero.

[tex]0=-\frac{30}{w^{2}}+4w[/tex]  

[tex]\frac{30}{w^{2}}=4w[/tex]              

[tex]w^{3}=\frac{30}{4}[/tex]          

[tex]w=1.96\: yd[/tex]  

So, l = 2*1.96 = 3.92 yd and h = 5/(1.96)² = 1.30 yd

Therefore, the dimensions are:

l = 2*1.96 = 3.92 yd

h = 5/(1.96)² = 1.30 yd

w = 1.96 yd

I hope it helps you!

Answer:

The Answer Is Point B (2,0)

Step-by-step explanation:

Answer:

Step-by-step explanation:

The null and alternative hypothesis are usually used in hypothesis testing to present the claim being tested as give in terms of the mean or proportion :

Given that the mean score of high school students is 10 ; using a sample of 50 students, a mean of 8 was obtained ; we could want to test the claim that the mean score is less than 10.

Here; population mean, μ = 10 ; the claim is now that, μ < 10 based on what was observed about the sample.

H0 : μ = 10

H0 : μ < 10

If we wanted to test If the mean was greater than 10 ; then the sign is reversed

H0 : μ = 10

H0 : μ > 10

If we wanted to test If the score is just different from the mean score stated ; (it may be less than or greater than)

H0 : μ = 10

H0 : μ ≠ 10

Answer:  9 gallons

Work Shown:

(15 gallons)/(10 minutes) = (x gallons)/(6 minutes)

15/10 = x/6

15*6 = 10*x ... cross multiplication

90 = 10x

10x = 90

x = 90/10

x = 9

The camel can drink 9 gallons in 6 minutes. This is assuming that the unit rate is kept the same.

9514 1404 393

Answer:

  27%

Step-by-step explanation:

The price multiplier for the first discount is (1 -55%) = 0.45.

The price multiplier for the second discount is (1 -40%) = 0.60.

Then the price multiplier for the two discounts together is ...

  (0.45)(0.60) = 0.27

You end up paying 27% of the original price.

Answer:

3 planters can be filled, with 288,156 gallons left over.

Step-by-step explanation:

Given that a dump truck with 1500 gallons of soil arrives on campus to fill in the new planters on the quad, and each planter needs 2 cubic yards of soil, to determine how many planters can be filled the following calculation must be performed:

1 cubic yard = 201.974 gallons

2 cubic yards = 403.948 gallons

1500 / 403.948 = X

3.71 = X

1500 - (403.948 x 3) = 288.156

Therefore, 3 planters can be filled, with 288,156 gallons left over.

[tex] \Large \mathbb{SOLUTION:} [/tex]

[tex] \begin{array}{l} \dfrac{1 + \sin 2A}{1 - \sin 2A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{1 + 2\sin A\cos A}{1 - 2\sin A\cos A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \because \sin 2A = 2\sin A\cos A\ (\text{Double Angle Identity}) \\ \\ \text{Divide both numerator and denominator of} \\ \text{LHS by }\cos^2 A. \\ \\ \dfrac{\frac{1 + 2\sin A\cos A}{\cos^2 A}}{\frac{1 - 2\sin A\cos A}{\cos^2 A}} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{\frac{1}{\cos^2 A} + \frac{2\sin A\cos A}{\cos^2 A}}{\frac{1}{\cos^2 A} - \frac{2\sin A\cos A}{\cos^2 A}} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2}\\ \\ \dfrac{\sec^2 A + 2\tan A} {\sec^2 A- 2\tan A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{1 + \tan^2 A + 2\tan A} {1 + \tan^2 A - 2\tan A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \because \sec^2 A = 1 + \tan^2 A\ (\text{Pythagorean Identity}) \\ \\ \text{Rearranging, we get} \\ \\ \dfrac{\tan^2 A + 2\tan A + 1} {\tan^2 A - 2\tan A + 1} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2}\\ \\ \text{LHS} = \text{RHS}_{\boxed{\:}}\end{array} [/tex]

Answer:

It will take them both 24 minutes to mow the lawn if they are working together.

Step-by-step explanation:

Given that Sam can mow a lawn in 40 minutes, and Melissa can mow the same lawn in 80 minutes, to determine how long does it take for both Sam and Melissa to mow the lawn if they are working together, the following calculation must be performed:

1/40 + 1/60 = 1 / X

3X + 2X = 120

X = 120/5

X = 24

Thus, it will take them both 24 minutes to mow the lawn if they are working together.

Answer:

The answer must be between 20 and 5000 characters

Answer:

Cluster

Step-by-step explanation:

When observations from a large population are divided into groups, such that subjects in each of these groups are similar to one another than those in the other groups. These individual groups of observation are called clusters. In the scenario above, the random group of 4 third grade classes selected represent of cluster or group since all the subjects belong to the class grade which is to be measured and all subjects belonging to the selected cluster or group are to be measured.

Answer:

[tex]2 \times 5 = 10 \\ 3 \times 11 = 33 \\ 10 + 33 = 43 \\ 43 {m}^{2} [/tex]

hey please give brainly

Answer:

3

Step-by-step explanation:

common ratio

2.1/0.7=3

6.3/2.1=3

18.9/6.3=3

therefore common ratio is equal to 3

Answer:

14.29%

Step-by-step explanation:

Total observations that had grade D or F: 5

Total observations: 35

[tex]\frac{5}{35} =\frac{1}{7} =.1429[/tex]

Answer:

.14

without rounding it is .1492 , rounded to the nearest hundredth it is .14

Answer:

19.44%

Step-by-step explanation:

28/144 × 100 = 19.44

I hope this helps

19.4 percent of 144 is 28.

The percentage means the required value out of 100.

It is calculated by dividing the required value by the total value and multiplying by 100.

The percentage change is also calculated using the same method.

In percentage change we find the difference between the values given.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

We have,

Percentage= M

Now,

M% of 144 = 28

M/100 x 144 = 28

Solve for M.

(M/100) x 144 = 28

M/100 = 28/144

M = 28/144 x 100

M = 19.44%

Thus,

28 is 19.4 percent of 144.

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The complete question.

28 is what percent of 144.

Answer:

a) 2, 6, 10, 14, 18, 22

b)60, 59, 57, 54, 50, 45

c)240, 120, 60, 30, 15, 7 1/2

Step-by-step explanation:

The answer was already there.

9514 1404 393

Answer:

 14

Step-by-step explanation:

  [tex]7\log_7(49)=7\log_7(7^2)=7\cdot2=\boxed{14}[/tex]

Answer:

The zeroes are -6, 1/2 and 2.

Step-by-step explanation:

f(x) = 2x3 + 7x2 - 28x + 12 = 0

From the first and last coefficient 2 and 12, one guess for a zero is x = 2.

So substituting x = 2:

f(2) = 16+ 28 - 56 + 12 = 0

So x = 2 is a zero and x - 2 is a factor of f(x)

Performing long division:

x - 2)2x3 + 7x2 - 28x + 12( 2x2 + 11x - 6 <------- Quotient

       2x3  - 4x2

                 11x2 - 28x

                 11x2 - 22x

                          - 6x + 12

                           -6x + 12

                            .............

Now we solve

2x2 + 11x - 6 = 0

(2x - 1)(x + 6) = 0

2x - 1 = 0 or x + 6 = 0, so:

x = 1/2,  x = -6.

Answer: -6, 1/2, 2.

Step-by-step explanation:

{(x) = 2x3 + 7x2 - 28x + 12 = 0

From the first and last coefficient 2 and 12, one

guess for a zero is x=2.

So substituting x=2:

{(2) = 16+ 28 - 56 + 12 = 0

So x = 2 is a zero and x - 2 is a factor of f(x)

Performing long division:

X - 2)2x3 + 7x2 - 28x + 12(2x2 + 11x - 6 <

Quotient

Answer:

40

Step-by-step explanation:

(x+2)^5 use binomial theorem :

(a+b)^n = (n choose 0)*a^n*b^0 + (n choose 1)*a^(n-1)*b^1 + (n choose 2)*a^(n-2)*b^2) + ... + (n choose (n-1)*a^1*b^(n-1) + ( n choose n)*a^0*b^n

this seems like a lot but to break it down, notice how the exponent on 'a' decreases as the exponent on 'b' gets bigger.

also, the 'choose' formula is :

(n choose r ) = n!/ (n-r)!r!

now plug in your values

(x+2)^5 =

(5 choose 0)*x^5*2^0 + (5choose 1)*x^4*2^1 + (5 choose 2)*x^3*x^2 + (5 choose 3)*x^2*2^3 + (5 choose 4)*x^1*2^4 + (5 choose 5)*x^0*x^5

we only need the third term so we will solve for this :

(5 choose 2)*x^3*x^2

5 choose 2 = 5!/ (5-2)!2! = 5!/ 3!2! = 10

x^3 * 2^2 = 4x^3

10*4x^3 = 40x^3

Answer:

8/100×500=4000/100=$40

Answer:

desculpa não consigo responder pq esta td inglês ou espanhol prá mim se vc me dizer como posso fazer para voltar a ser português possa te ajudar em algo

Answer:

2.72 [tex]cm^2[/tex]

Step-by-step explanation:

You first find the area of the whole rectangle.

Then you have to find the area of the circle. The area of a circle is [tex]2\pi r[/tex].

The radius is 1 so it will be 2[tex]\pi[/tex].

[tex]\pi[/tex] equals 3.14 so you have to do 3.14*2 that equals 6.28.

Finally subtract 9-6.28=2.72

Answer:

x = 76.9

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side / adj side

tan 70 = x/28

28 tan 70 = x

x=76.92936

Rounding to the nearest tenth

x = 76.9

Answer:

76.9

Step-by-step explanation:

SOH: Sin(θ) = Opposite / Hypotenuse

CAH: Cos(θ) = Adjacent / Hypotenuse

TOA: Tan(θ) = Opposite / Adjacent

Tan 70 = [tex]\frac{x}{28}[/tex]

(28) tan 70 = x

76.929 = x

Area of 1 face of this cube

= s²

Because it is a square.

Answer:

s√2

Step-by-step explanation:

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X=180-57-57=66

Dababy sus

Answer:

The distance between two points (a, b) and (c, d) is given by:

[tex]d = \sqrt{(a - c)^2 + (b - d)^2}[/tex]

So the distance between the point (6, 5) and the line y = 5x - 10 can be thought as the distance between the point (6, 5) and the point (x, 5x - 10)

Where:

(x, 5x - 10) denotes all the points in the line y = 5x – 10

That distance is given by:

[tex]d = \sqrt{(x - 6)^2 + (5x - 10 - 5)^2} = \sqrt{(x - 6)^2 + (5x - 15)^2}[/tex]

Now we want to minimize this.

Because the distance is a positive quantity, we can try to minimize d^2 insted, so we have:

[tex]d^2 = (\sqrt{(x - 6)^2 + (5x - 15)^2})^2 = (x - 6)^2 + (5x - 15)^2}\\\\d^2 = x^2 - 2*x*6 + 36 + 25*x^2 - 2*15*x + (-15)^2\\\\d^2 = 26*x^2 - 42*x + 261[/tex]

Notice that this is a quadratic equation with a positive leading coefficient, which means that the arms of the graph will open upwards, then the minimum will be at the vertex of the parabola.

Remember that for a parabola:

y = a*x^2 + bx + c

the x-value of the vertex is:

x = -b/2a

Then for our parabola:

d^2 = 26*x^2 - 42*x + 261

The vertex is at:

x = -(-42)/(2*26) = 0.808

Then we just need to evaluate the distance equation in that value of x to get the shortest distance:

[tex]d = \sqrt{(0.808 - 6)^2 + (5*0.808 - 15)^2} = 12.129[/tex]

The shortest distance between the point A and the line is 12.129 units.

Answer:

87653210=highest

01235678=least

Answer:

Least number: 10235678

Greatest number: 87653210