Write a program that reads a list of words. Then, the program outputs those words and their frequencies. Ex: If the input is: hey hi Mark hi mark

Answer:

input process and output hehe

Answer:

please mark me brainlist

Explanation:

This algorithm works for n number of strings in python3

Input:

83217

8213897

683147

Output:

837

from itertools import product

import pdb

import numpy as np

def neigh(index):

N = len(index)

for ri in product((0, -1), repeat=N):

if not all(i == 0 for i in ri):

yield tuple(i + i_rel for i, i_rel in zip(index, ri))

def longestCommonSubSequenceOfN(sqs):

numberOfSequences = len(sqs); # to know number of sequences

lengths = np.array([len(sequence) for sequence in sqs]); # to know length of each sequences placed in # array

incrLengths = lengths + 1; # here we are taking no .of sequences +1

lengths = tuple(lengths); # making lengths into tuple to make it mutable

inverseDistances = np.zeros(incrLengths);

ranges = [tuple(range(1, length+1)) for length in lengths[::-1]]; # finding ranges from 1 to each lengths

for tupleIndex in product(*ranges):

tupleIndex = tupleIndex[::-1];

neighborIndexes = list(neigh(tupleIndex)); # finding neighbours for each tupled index value and # store them in list

operationsWithMisMatch = np.array([]); # creating array which are miss matched

for neighborIndex in neighborIndexes:

operationsWithMisMatch = np.append(operationsWithMisMatch, inverseDistances[neighborIndex]);

#appending newly created array with operations miss match and inverseDistances

operationsWithMatch = np.copy(operationsWithMisMatch);

# copying newly generated missmatch indexs

operationsWithMatch[-1] = operationsWithMatch[-1] + 1;

# incrementing last indexed value

chars = [sqs[i][neighborIndexes[-1][i]] for i in range(numberOfSequences)];

# finding a string(chars) with neighbour indexes and checking with other sequences

if(all(elem == chars[0] for elem in chars)):

inverseDistances[tupleIndex] = max(operationsWithMatch);

else:

inverseDistances[tupleIndex] = max(operationsWithMisMatch);

subString = ""; # resulted string

mainTupleIndex = lengths; # copying lengths list to mainTupleIndex

while(all(ind > 0 for ind in mainTupleIndex)):

neighborsIndexes = list(neigh(mainTupleIndex));

#generating neighbour indexes with main tuple index in form of list

anyOperation = False;

for tupleIndex in neighborsIndexes:

current = inverseDistances[mainTupleIndex];

if(current == inverseDistances[tupleIndex]): # comparing indexes in main tuple index and inverse #distance tuple index

mainTupleIndex = tupleIndex;

anyOperation = True;

break;

if(not anyOperation): # if anyoperation is False then we are generating sunString

subString += str(sqs[0][mainTupleIndex[0] - 1]);

mainTupleIndex = neighborsIndexes[-1];

return subString[::-1]; # reversing resulted string

sequences = ["83217", "8213897", "683147"]

print(longestCommonSubSequenceOfN(sequences)); #837

Answer:

G-code and C++ can be used

Answer:

The description of the given question is summarized below.

Explanation:

Answer:

x = 1

y = 1

Explanation:

The apply method has the axis argument which enables it to use the applied function either across the rows or columns, by passing the value 1 to the axis argument, the mean of at each index is calculated, (across the column) such that the length of the AVG column is equal to the lengtb of the original dataframe.

The drop method is used in pandas to remove row or column entry from a dataframe. To remove columns from a data table, the value 1 is passed to the axis argument of the drop method. Hence, passing 1 to the axis argument removes all 6 columns leaving only the AVG column in result_df.

Explanation:

hope it helps you

pls mark this ans brainlist ans

The importance of planning a web page according to the question is provided below.

A well-designed company's website may contribute to making even your potential consumers a favorable immediate impression.

Learn more about the web page here:

https://brainly.com/question/9060926

Fasilitas untuk pengaturan batas kertas pada Microsoft Word adalah

B.View

Office 92 sering disebut juga dengan

A.Office 3.0

Answer:

Explanation:

Click the File tab.

Click Print, or press the control p keyboard command.

On the Print screen, select the printer and other settings.

Click Print.

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: 155 kHz.

Given the following data:

Note: μs represents microseconds.

Conversion:

1 μs = [tex]1[/tex] × [tex]10^{-6}[/tex] seconds

645 μs = [tex]645[/tex] × [tex]10^{-6}[/tex] seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

[tex]Frequency = \frac{1}{Period}[/tex]

Substituting the value into the formula, we have;

[tex]Frequency = \frac{1}{645\; * \;10^{-6}}[/tex]

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

Conversion:

1 hertz = 0.001 kilohertz

1550.3876 hertz = X kilohertz

Cross-multiplying, we have;

X = [tex]0.001[/tex] × [tex]1550.39[/tex]

X = 155039 kHz

To 3 significant figures;

Frequency = 155 kHz

Find more information: https://brainly.com/question/23460034

Answer:

CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator.

Explanation:

There are six basic components of a microcomputer which includes CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator. CPU is the central processing unit which is considered as the brain of the computer. It is the part of a computer that executes instructions. Data memory is the place where data is stored that is present in the CPU.

Explanation:

anytime software and business come together there is an inherent conflict between get it done fast and do a good job

Answer:

The pivot is selected randomly in quick sort.

Answer:

Code:-

#include <iostream>

using namespace std;

int main()

{

   // take array size from user

   int n;

   cout << "Enter array size:";

   cin >> n;

   // Declare array size with user given input

   int a[n];

   // take array elements from user & store it in array

   cout << "Enter array elements:";

   for(int i=0 ; i < n ; i++){

       cin >> a[i];

   }

   /* ----- Solution Starts ----- */

   // i & j for checking disarray & count is for counting no. of disarray's

   int i=1, j=0, count=0;

   for(int k=0; k < n ; k++){

       if(a[i] > a[j]){

           // if disarray found then increament count by 1

               count++;

               }

               // increament i & j also to check for further disarray's

               i++;

       j++;

       }

       // Print the disarray count

   cout << "Pairs of disarray in given array:" << count;

   /* ----- Solution Ends ----- */

   return 0;

}

Output:-

Answer:

The statement is:

For number = 0 to 5

Explanation:

Given

The incomplete pseudocode

Required

The loop statement to complete the pseudocode

To loop from 0 to 5, we make use of:

For number = 0 to 5

Where:

number is the integer variable declared on line 1

So, the complete pseudocode is:

Declare Integer number

For number = 0 to 5

Display number

End For

Answer:

Error reports

Explanation:

Following are the steps of the polynomial-time algorithm:

In a minimum amount of time, this algorithm will determine the best strategy to supply all shops.

Learn more:

polynomial-time algorithm: brainly.com/question/20261998

Answer:

use loop

for(int i =10;i>2; i--)

{

System.out.println(i+"\n")

}

Clarissa should modify the file /root/.profile.

Runtime environment variables

Therefore, in the context, Clarissa wishes to modify the run time environment variable which can be used for all the new logins and also for the new instances for the BASH shell. So for this, Clarissa should modify the /root/.profile file command.

Learn More :

https://brainly.in/question/10061342

Following are the description of the wrong choice:

Therefore, the "/root/.profile" file should be changed by Clarissa.

Learn More :  

https://brainly.in/question/6708999

Answer:

phone grows everyday 82 percent

Explanation:

Answer:

i dont know

Explanation:

Answer:

To manage a modern IT environment characterized by hybrid complexity and exponential data growth — and to make that same IT a driver of growth and innovation for the business — you need to build intelligence into every layer of your infrastructure.

Change management plays a major role in transforming a client  business into a data-driven, intelligent enterprise in: data culture and literacy.

Data culture and literacy refer to all the processes involved in analyzing and understanding data within the framework of an organization.

The employees within such organizations are trained to read and understand data. It becomes a part of the organization's culture.

So data culture and literacy should be used when trying to transform a client  business into a data-driven, intelligent enterprise.

Learn more about data culture here:

https://brainly.com/question/21810261

Judging from it's prevalence and popularity, there will be a long way to go until people start to lose interest with expressing themselves online. So no, social media will not lose its relevance, but maybe when technology is dead, then it will.

Answer:

Coding is simply how we communicate with computers. Code tells a computer what actions to take, and writing code is like creating a set of instructions

Explanation:

Computer coding empowers kids to not only consume digital media and technology, but to create it. Instead of simply playing videogame or envision what their own website, or app might look like and they'll have the outlet for the expression

Answer:

the answer is priming read

Explanation:

hope it helps u

Answer:

#include <iostream>

using namespace std;

struct entry

{

int number;

entry* next;

};

void orderedInsert(entry** head_ref,entry* new_node);

void init_node(entry *head,int n)

{

head->number = n;

head->next =NULL;

}

void insert(struct entry **head, int n)

{

entry *nNode = new entry;

nNode->number = n;

nNode->next = *head;

*head = nNode;

}

entry *searchNode(entry *head, int n)

{

entry *curr = head;

while(curr)

{

if(curr->number == n)

return curr;

curr = curr->next;

}

}

bool delNode(entry **head, entry *ptrDel)

{

entry *curr = *head;

if(ptrDel == *head)

{

*head = curr->next;

delete ptrDel;

return true;

}

while(curr)

{

if(curr->next == ptrDel)

{

curr->next = ptrDel->next;

delete ptrDel;

return true;

}

curr = curr->next;

}

return false;

}

void display(struct entry *head)

{

entry *list = head;

while(list!=NULL)

{

cout << list->number << " ";

list = list->next;

}

cout << endl;

cout << endl;

}

//Define the function to sort the list.

void insertionSort(struct entry **h_ref)

{

// Initialize the list

struct entry *ordered = NULL;

// Insert node to sorted list.

struct entry *current = *h_ref;

while (current != NULL)

{

struct entry *next = current->next;

// insert current in the ordered list

orderedInsert(&ordered, current);

// Update current

current = next;

}

// Update the list.

*h_ref = ordered;

}

//Define the function to insert and traverse the ordered list

void orderedInsert(struct entry** h_ref, struct entry* n_node)

{

struct entry* current;

/* Check for the head end */

if (*h_ref == NULL || (*h_ref)->number >= n_node->number)

{

n_node->next = *h_ref;

*h_ref = n_node;

}

else

{

//search the node before insertion

current = *h_ref;

while (current->next!=NULL &&

current->next->number < n_node->number)

{

current = current->next;

}

//Adjust the next node.

n_node->next = current->next;

current->next = n_node;

}

}

int main()

{

//Define the structure and variables.

char ch;int i=0;

entry *newHead;

entry *head = new entry;

entry *ptr;

entry *ptrDelete;

//Use do while loop to countinue in program.

do

{

//Define the variables

int n;

int s;

int item;

char choice;

//Accept the user choice

cout<<"Enter your choice:"<<endl;

cout<<"a. Add a number"<<endl

<<"b. Delete a number"<<endl

<<"c. Search for a number"<<endl

<<"d. Display the whole list of numbers"<<endl;

cin>>choice;

//Check the choice.

switch(choice)

{

//Insert an item in the list.

case 'a' :

// cin>>item;

cout<<"Enter the element:"<<endl;

cin>>item;

//To insert the first element

if(i==0)

init_node(head,item);

//To insert remaining element.

else

{

ptr = searchNode(head,item);

//Check for Duplicate data item.

if(ptr==NULL)

{

insert(&head,item);

}

else

{

cout<<"Duplicate data items not allowed";

cout<<endl<<"EnterAgain"<<endl;

cin>>item;

insert(&head,item);

}

}

insertionSort(&head);

i=i+1;

break;

//Delete the item from the list

case 'b' :

int numDel;

cout<<"Enter the number to be deleted :"<<endl;

cin>>numDel;

//Locate the node.

ptrDelete = searchNode(head,numDel);

if(ptrDelete==NULL)

cout<<"Element not found";

else

{

if(delNode(&head,ptrDelete))

cout << "Node "<< numDel << " deleted!\n";

}

break;

//Serach the item in the list.

case 'c' :

cout<<"Enter the element to be searched :";

cout<<endl;

cin>>s;

ptr = searchNode(head,s);

if(ptr==NULL)

cout<<"Element not found";

else

cout<<"Element found";

break;

//Display the list.

case 'd' :

display(head);

break;

default :

cout << "Invalid choice" << endl;

break;

}

//Ask user to run the program again

cout<<endl<<"Enter y to countinue: ";

cin>>ch;

}while(ch=='y'||ch=='Y');

return 0;

}

output:

An IS manager can keep up with the endless demand for more software to support new information systems by thinking outside the box.

To think outside the box, the IS manager should try the following strategies:

Thus, the IS manager must realize that there are always solutions to every software problem outside the mainstream box.

Learn more about information systems here: https://brainly.com/question/1521627

Answer:

Explanation:

Usually, applications would have the capability of using either one of these options. But for the sake of the question here are some that usually prefer one method over the other.

Any program that targets an API usually uses Sequential access. This is because API's contain all of the data as objects. Therefore, you need to access that object and sequentially navigate that object to the desired information in order to access the data required.

A music application would have access to an entire folder of music. If the user chooses to set the application to randomly play music from that folder, then the application will use a Random Access method to randomly choose the music file to load every time that a song finishes.