Write a program that first reads in the name of an input file and then reads the input file using the file.readlines() method. The input file contains an unsorted list of number of seasons followed by the corresponding TV show. Your program should put the contents of the input file into a dictionary where the number of seasons are the keys, and a list of TV shows are the values (since multiple shows could have the same number of seasons).
Sort the dictionary by key (least to greatest) and output the results to a file named output_keys.txt, separating multiple TV shows associated with the same key with a semicolon (;). Next, sort the dictionary by values (alphabetical order), and output the results to a file named output_titles.txt.
Ex: If the input is:
file1.txt
and the contents of file1.txt are:
20
Gunsmoke
30
The Simpsons
10
Will & Grace
14
Dallas
20
Law & Order
12
Murder, She Wrote
the file output_keys.txt should contain:
10: Will & Grace
12: Murder, She Wrote
14: Dallas
20: Gunsmoke; Law & Order
30: The Simpsons
and the file output_titles.txt should contain:
Dallas
Gunsmoke
Law & Order
Murder, She Wrote
The Simpsons
Will & Grace
Note: There is a newline at the end of each output file, and file1.txt is available to download.
currently, my code is:
def readFile(filename):
dict = {}
with open(filename, 'r') as infile:
lines = infile.readlines()
for index in range(0, len(lines) - 1, 2):
if lines[index].strip()=='':continue
count = int(lines[index].strip())
name = lines[index + 1].strip()
if count in dict.keys():
name_list = dict.get(count)
name_list.append(name)
name_list.sort()
else:
dict[count] = [name]
return dict
def output_keys(dict, filename):
with open(filename,'w+') as outfile:
for key in sorted(dict.keys()):
outfile.write('{}: {}\n'.format(key,';'.join(dict.get(key))))
print('{}: {}\n'.format(key,';'.join(dict.get(key))))
def output_titles(dict, filename):
titles = []
for title in dict.values():
titles.extend(title)
with open(filename,'w+') as outfile:
for title in sorted(titles):
outfile.write('{}\n'.format(title))
print(title)
def main():
filename = input()
dict = readFile(filename)
if dict is None:
print('Error: Invalid file name provided: {}'.format(filename))
return
output_filename_1 ='output_keys.txt'
output_filename_2 ='output_titles.txt'
output_keys(dict,output_filename_1)
print()
output_titles(dict,output_filename_2)
main()
The problem is that when I go to submit and the input changes, my output differs.
Output differs. See highlights below. Special character legend Input file2.txt Your output 7: Lux Video Theatre; Medium; Rules of Engagement 8: Barney Miller;Castle; Mama 10: Friends; Modern Family; Smallville;Will & Grace 11: Cheers;The Jeffersons 12: Murder, She Wrote;NYPD Blue 14: Bonanza;Dallas 15: ER 20: Gunsmoke; Law & Order; Law & Order: Special Victims Unit 30: The Simpsons Expected output 7: Rules of Engagement; Medium; Lux Video Theatre 8: Mama; Barney Miller; Castle 10: Will & Grace; Smallville; Modern Family; Friends 11: Cheers; The Jeffersons 12: Murder, She Wrote; NYPD Blue 14: Dallas; Bonanza 15: ER 20: Gunsmoke; Law & Order; Law & Order: Special Victims Unit 30: The Simpsons

Answer:

false

Explanation:

function should contain more codes

Answer and Explanation:

Deadlock occurs when two operating systems on the same computer are hindering each other's execution, getting blocked, waiting for each one to run first. This can happen when a preemption has not occurred, when a mutual exclusion has occurred, or when one of the systems causes the other to not execute.

File manager is software that allows a computer user to create directories and organize files inside and outside of them.

Process is the term used to determine the functioning of computer software. When a software is started, it uses its own programming code to perform a specific activity.

Multiprogramming is the term used for the moment when an operating system allows the user to run more than one software at the same time. For this to happen, the computer needs to have a high processing capacity, to handle the effort of running several software simultaneously.

Software Classification is the process that determines the composition and different aspects that make up a software. In this way, it is possible to understand the usefulness and programming of this software.

Virtual memory is the use of secondary memory for caching. This allows the user to share files more securely and quickly, in addition to alleviating the problems that limited memory presents.

Answer:

True

Explanation:

Multimedia is used in many fields. It is basically the ability to express something in many different ways. This allows you to more easily demonstrate a product, idea, or even a theory. Since this can be through art, video, presentation, text, live, etc. It allows you to find the best format for the specific product or idea that you are trying to present to a group of viewers. That is why it is an effective tool for various fields since it can just as easily help a company sell a product as well as help a teacher express a mathematical concept.

Answer:

Print.. is your answer...

Answer:

c. DX=FFFFh, AX=80C0h

Explanation:

CWD instruction set all bits in DX register with same sign as in AX register. The effect is to create a 32 bit sign result. This will have same integer value as of 16 bit.

Answer:

Saved In order to be used as a primary key, which of these characteristics must an attribute possess with respect to a single instance of the entity:

There must be a maximum of one attribute instance.

There must be many instances of the attribute.

There must be at most one entity instance that each attribute instance describes.

There must be at least one instance of the attribute.

A singular attribute is also known as a unique attribute. True

Saved Relationship names and types of relationship maxima or minima that each could have are listed below. True

Explanation:

Answer:

1 is the answer because ur trying to trick us

Explanation:

[tex] \sf\underline{ Photography} \:  is \: the \: way \: / \: process \: / \: art \\ \sf \: of \: taking \: beautiful \: pictures \\ \sf \: usually \: of \: amazing \: sceneries \: (it \: can \: be \: of \: other \: \\ \sf things \: as \: well) \: for \: visual \: pleasure. \: The \: attached \: picture \\ \sf \: is \: an \: example \: for \: a \: good \\ \sf\: type \: of \: photography. \: A \: person \: who \: practices \: the \: \\\sf art \: of \: photography \: is \: known \: as \: a \: \underline{ photographer}.[/tex]

Answer:

(i) C is increased (S, B same)

Explanation:

Cache are items which are stored in the computer at a hidden place. These are sometimes unwanted and they may hinder the speed and performance of the device. They exist to bridge speed gap.

Answer:

semicolon is the answer

Answer:

Python only running exception block when try block fails

Explanation:

i do cyber security and i was learning this in high school

In Python, try and except statements are used to catch and manage exceptions. Statements that can generate exceptions were placed within the try clause, while statements that handle the exception are put within the except clause.

Therefore, the answer is "try block fails ".

Learn more:

brainly.com/question/19154398

Answer:

Test if L(M1-2) is empty.

Construct FA M2-1 from M1 and M2 which recognizes the language L(>M2) - L(>M1).

COMMENT: note we use the algorithm that is instrumental in proving that regular languages are closed with respect to the set difference operator.

Test if L(M2-1) is empty.

Answer yes if and only if both answers were yes.

Explanation:

An algorithm must be guaranteed to halt after a finite number of steps.

Each step of the algorithm must be well specified (deterministic rather than non-deterministic).

Three basic problems:

Given an FA M and an input x, does M accept x?

Is x in L(M)

Given an FA M, is there a string that it accepts?

Is L(M) the empty set?

Given an FA M, is L(M) finite?

Algorithm for determining if M accepts x.

Simply execute M on x.

Output yes if we end up at an accepting state.

This algorithm clearly halts after a finite number of steps, and it is well specified.

This algorithm is also clearly correct.

Testing if L(M) is empty.

Incorrect "Algorithm"

Simulate M on all strings x.

Output yes if and only if all strings are rejected.

The "algorithm" is well specified, and it is also clearly correct.

However, this is not an algorithm because there are an infinite number of strings to simulate M on, and thus it is not guaranteed to halt in a finite amount of time.

COMMENT: Note we use the algorithm for the first problem as a subroutine; you must think in this fashion to solve the problems we will ask.

Correct Algorithm

Simulate M on all strings of length between 0 and n-1 where M has n states.

Output no if and only if all strings are rejected.

Otherwise output yes.

This algorithm clearly halts after a finite number of steps, and it is well specified.

The correctness of the algorithm follows from the fact that if M accepts any strings, it must accept one of length at most n-1.

Suppose this is not true; that is, L(M) is not empty but the shortest string accepted by M has a length of at least n.

Let x be the shortest string accepted by M where |x| > n-1.

Using the Pumping Lemma, we know that there must be a "loop" in x which can be pumped 0 times to create a shorter string in L.

This is a contradiction and the result follows.

COMMENT: There are more efficient algorithms, but we won't get into that.

Testing if L(M) is finite

Incorrect "Algorithm"

Simulate M on all strings x.

Output yes if and only if there are a finite number of yes answers.

This "algorithm" is well specified and correct.

However, this is not an algorithm because there are an infinite number of strings to simulate M on, and thus it is not guaranteed to halt in a finite amount of time.

COMMENT: Note we again use the algorithm for the first problem as a subroutine.

Correct Algorithm

Simulate M on all strings of length between n and 2n-1 where M has n states.

Output yes if and only if no string is accepted.

Otherwise output no.

This algorithm clearly halts after a finite number of steps, and it is well specified.

The correctness of the algorithm follows from the fact that if M accepts an infinite number of strings, it must accept one of length between n and 2n-1.

This builds on the idea that if M accepts an infinite number of strings, there must be a "loop" that can be pumped.

This loop must have length at most n.

When we pump it 0 times, we have a string of length less than n.

When we pump it once, we increase the length of the string by at most n so we cannot exceed 2n-1. The problem is we might not exceed n-1 yet.

The key is we can keep pumping it and at some point, its length must exceed n-1, and in the step it does, it cannot jump past 2n-1 since the size of the loop is at most n.

 This proof is not totally correct, but it captures the key idea.

COMMENT: There again are more efficient algorithms, but we won't get into that.

   Other problems we can solve using these basic algorithms (and other algorithms we've seen earlier this chapter) as subroutines.

       COMMENT: many of these algorithms depend on your understanding of basic set operations such as set complement, set difference, set union, etc.

Given a regular expression r, is Lr finite?

Convert r to an equivalent FA M.

COMMENT: note we use the two algorithms for converting a regular expression to an NFA and then an NFA to an FA.

Test if L(M) is finite.

Output the answer to the above test.

Given two FAs M1 and M2, is L(M1) = L(M2)?

Construct FA M1-2 from M1 and M2 which recognizes the language L(>M1) - L(>M2).

COMMENT: note we use the algorithm that is instrumental in proving that regular languages are closed with respect to the set difference operator.

Test if L(M1-2) is empty.

Construct FA M2-1 from M1 and M2 which recognizes the language L(>M2) - L(>M1).

COMMENT: note we use the algorithm that is instrumental in proving that regular languages are closed with respect to the set difference operator.

Test if L(M2-1) is empty.

Answer yes if and only if both answers were yes.

Explanation:

The file named as A10.java has been attached to this response. It contains the source code for the exercises. The source code contains comments explaining important parts of the code.

A few things to note;

i. To add an item to an arraylist, the add() method is used. For example to add an integer 7 to the arraylist named intList, simply write;

intList.add(7);

ii. To add an item to a hashmap, the put() method is used. The put method receives two parameters which are the key and value respectively. The key is a form of identifier used to store or retrieve a particular value in a hashmap. To store an integer 8 with a key of 5 in a hashmap named intMap, for example, simply write;

intMap.put(5,8);

Solution :

App.java:  

import Controller.Controller;

import Model.Model;

import View.View;  

public class App

{  

public static void main(String[] args) // Main method

{  

Model model = new Model(); // Creates model object.    

View view = new View(); // Creates view object.    

Controller controller = new Controller(view, model); // Creates controller object that accepts view and model objects.    

}

}  

[tex]\text{Controller.java:}[/tex]  

package Controller;  

[tex]\text{impor}t \text{ Model.Model;}[/tex]

import View.View;  

[tex]\text{public class Controller}[/tex]

{

Model model; // Model object    

View view; // View object

public Controller(View v, Model m) // Method that imports both model and view classes as objects.

{

model = m;    

view = v;  

//view.basicDisplay(model.getData()); // basicDisplay method from View class prints FootballPlayer objects as Strings from Model class.  

view.basicDisplay(model.getMembers().get(1).getAttributeName(3));    

view.basicDisplay(model.getMembers().get(1).getAttribute(3));    

view.basicDisplay(model.getMembers().get(1).getAttributeNames());    

view.basicDisplay(model.getMembers().get(1).getAttributes());    

view.basicDisplay("size of names=" + model.getMembers().get(1).getAttributeNames().size());    

view.basicDisplay("size of attributes=" + model.getMembers().get(1).getAttributes().size());

}  

}  

FootballPlayer.java:

package Model;  

import java.util.ArrayList;  

public class FootballPlayer extends Person implements TableMember { // Used "extends" keyword to inherit attributes from superclass Person, while using "implements" to implement methods from TableMember interface.    

private int number; // Creating private attribute for int number.    

private String position; // Creating private attribute for String position.  

public FootballPlayer(String name, int feet, int inches, int weight, String hometown, String highSchool, int number, String position) // Full parameter constructor for FootballPlayer object (using "super" keyword to incorporate attributes from superclass).

{

super(name, feet, inches, weight, hometown, highSchool); // Used super keyword to include attributes from superclass.  

this.number = number; // Value assigned from getNumber method to private number instance variable for FootballPlayer object.  

this.position = position; // Value assigned from getPosition method to private position instance variable for FootballPlayer object.    

}  

public FootballPlayer() // No parameter constructor for FootballPlayer object.

{

this.number = 0; // Default value assigned to private number instance variable under no parameter constructor for FootballPlayer object.    

this.position = "N/A"; // Default value assigned to private position instance variable under no parameter constructor for FootballPlayer object.    

}  

Override

public String getAttribute(int n) // getAttribute method that is implemented from interface.

{

switch (n) { // Switch statement for each attribute from each FootballPlayer object. Including two local attributes, denoted by this. While the others are denoted by "super".

case 0:

return String.valueOf(this.number); // Use of the dot operator allowed me to discover String.valueOf method to output int attributes as a string.

case 1:

return this.position;

case 2:

return super.getName();

case 3:

return super.getHeight().toString();

case 4:

return String.valueOf(super.getWeight());

case 5:

return super.getHometown();

case 6:

return super.getHighSchool();

default:

return ("invalid input parameter");

}

}  

Override

public ArrayList<String> getAttributes() // getAttributes ArrayList method that is implemented from interface.

{

ArrayList<String> getAttributes = new ArrayList<>();    

for(int i = 0; i <= 6; i++){ // For loop to add each attribute to the getAttributes ArrayList from getAttributes method.    

getAttributes.add(getAttribute(i));    

}    

return getAttributes;

}  

Override

public String getAttributeName(int n) // getAttributeName method implemented from interface.

{

switch (n) { // Switch statement for the name of each attribute from each FootballPlayer object.

case 0:

return "number";

case 1:

return "position";

case 2:

return "name";

case 3:

return "height";

case 4:

return "weight";

case 5:

return "hometown";

case 6:

return "highSchool";

default:

return ("invalid input parameter");

}  

}  

Answer:

The function of the suites application is to create presentations and perform numerical calculations.

Explanation:

Answer:

Access includes a Navigation Control that makes it easy to switch between various forms and reports in your database. A navigation form is simply a form that contains a Navigation Control. Navigation forms are a great addition to any desktop database.

Explanation:

yes

Answer:

answer c

Explanation:

correct answer on edge

For learning HTML we recommend a simple text editor like Notepad (PC) or TextEdit (Mac).

mark me brainliestt :))

Answer:

If you want to use HTML editor in windows, you can use notepad. And if you want to use HTML editor on your phone than you need to install any editor on your phone.

Explanation:

If you want to use another app than notepad in pc, laptop, mac, OS or Linux, you can download a editor known as Visual Studio Code. If you want to do another language you can also do it in it. You can do all programming languages in it.

Answer:

d. call WriteInt

Explanation:

Required

Instruction to write to decimal integer

Of the 4 instructions, the call WriteInt instruction is used write to a decimal integer.

This is so, because the WriteInt instruction writes a signed decimal integer to standard output.

This implies that the output will have a sign (positive or negative) and the output will start from a digit other than 0 (i.e. no leading zero)

Answer:

adress: 10101100.00010000.1 0000000.00000000

netmask: 11111111.11111111.1 0000000.00000000

Network:   172.16.128.0/17       10101100.00010000.1 0000000.00000000 (Class B)

Explanation:

ex: 10 -> 00001010

200 ->11001000

Answer:

Below is the required JAVA Code:

Explanation:

public static int largestDigit(int n) {

   if (n < 0) {

       return largestDigit(-1 * n);

   } else if (n == 0) {

       return 0;

   } else {

       int digit = n % 10;

       int maxDigit = largestDigit(n / 10);

       if (digit > maxDigit)

           maxDigit = digit;

       return maxDigit;

   }

}

\color{red}Method\;tested\;in\;a\;complete\;java\;program\;if\;you\;are\;interested.

public class LargestDigitRecursive {

   public static int largestDigit(int n) {

       if (n < 0) {

           return largestDigit(-1 * n);

       } else if (n == 0) {

           return 0;

       } else {

           int digit = n % 10;

           int maxDigit = largestDigit(n / 10);

           if (digit > maxDigit)

               maxDigit = digit;

           return maxDigit;

       }

   }

   public static void main(String[] args) {

       System.out.println(largestDigit(14263203));

       System.out.println(largestDigit(845));

       System.out.println(largestDigit(52649));

       System.out.println(largestDigit(3));

       System.out.println(largestDigit(0));

       System.out.println(largestDigit(-573026));

       System.out.println(largestDigit(-2));

   }

}

OUTPUT:

6

8

9

3

0

7

2

answer:

yes....................

Answer:

bcoz of corona all churches and temples are closed and pilgrimage are cancelled

Answer:

A lower bound on the optimal integer value.

Explanation:

The question is poorly typed.  The original question requires the optimal solution of the objective function of a minimization problem

I will answer this question base on the above illustration.

When an objective function is to be minimized, it means that the objective function will take the feasible solution with the least value.

The least value are often referred to as the lower bound.

Answer:

Acronis True Image is the one I would recommend out of these mentioned online backup services.

Explanation:

The evaluations and reviews of each of the online backup services are as follows:

a. iDrive

For this, we have:

Speed = 60% - fair

Security = 100% - excellent

Privacy = 88% - very good

Features = 95% - excellent

Pricing = 85% - Very good

Because of its various features, pricing, and usability, IDrive reviews suggest that it is a very efficient online backup solution. However, there have been complaints concerning its speed and the fact that there are no monthly plans available.

b. Carbonite

For this, we have:

Speed = 60% - fair

Security = 100% - excellent

Privacy = 87% - very good

Pricing = 85% - very good

File backup and restoration = 75% - good

Carbonite reviews reveal that it is simple to use and provides limitless backup for one device. The main drawback is that it has extremely poor backup speeds.

c. Acronis True Image

This is fast, simple and intuitive

It has complete control over the backup updates, including how and when they occur.

It is not expensive.

Acrnonis True image is a powerful backup storage service. It enables data and file backup and restoration from USB drives.

Many reviewers of Acrnonis True image have stated that they have had no issues with its service, that it is worth purchasing, and that there are no concerns.

d. Backblaze

For this, we have:

Speed = 75% - good

Security = 75% - good

Privacy = 70% - decent

Pricing = 100% - excellent

Support = 95% - excellent

Features = 65% - decent

File back-up and restoration = 70% - decent

Backblaze is one of the most popular internet backup services. This storage service, however, does not allow for ustomization.

Recommendation

Acronis True Image is the one I would recommend out of these mentioned online backup services. This is due to the fact that it delivers a large amount of accurate and high-quality data storage. It is quick, simple and intuitive, which is what most people care about. Furthermore, reviewers have stated that this service is quite effective and that there have been very few issues with it. The other services demonstrate that their services have flaws, such as lack of customization and slowness.

Answer:

Explanation:

The following code is written in Java. In order to code this efficiently, I created a class for the trafficLights. The class contains the currentLight, and the streetType as variables and contains a constructore, getter and setter methods, and a method to turn to the next light in the sequence. Then I created 4 objects of TrafficLights for the highways and the streets.

class Brainly {

   public static void main(String[] args) {

       TrafficLights highwaySouth = new TrafficLights("Highway", "green");

       TrafficLights highwayNorth = new TrafficLights("Highway", "green");

       TrafficLights streetEast = new TrafficLights("Street", "yellow");

       TrafficLights streetWest = new TrafficLights("Street", "red");

   }

}

class TrafficLights {

   String streetType, currentLight;

   public TrafficLights(String streetType, String currentLight) {

       this.streetType = streetType;

       this.currentLight = currentLight;

   }

   public void nextLight() {

       if (this.currentLight == "green") {

           this.currentLight = "yellow";

       } else if (this.currentLight == "yellow") {

           this.currentLight = "red";

       } else {

           this.currentLight = "green";

       }

   }

   public String getStreetType() {

       return streetType;

   }

   public void setStreetType(String streetType) {

       this.streetType = streetType;

   }

   public String getCurrentLight() {

       return currentLight;

   }

   public void setCurrentLight(String currentLight) {

       this.currentLight = currentLight;

   }

}

Answer:

d. you can determine the average age of emoji users based on emoji use.

Explanation:

The infographic displays 100 most common emoji used in text messaging. This information can be used to determine percentages of text message which contains particular emoji. This details can not determine the age of emoji user based in emoji use.