Answer:
Answered below
Explanation:
//Print name and ID
Scanner x = new Scanner(System.in);
System.out.print("Enter name");
String name = x.nextline();
Scanner y = new Scanner(System.in);
System.out.print("Enter ID");
int id = y.nextline();
System.out.println(name, id);
Scanner w = new Scanner(System.in);
System.out.print("enter weight");
double weight = w.nextline();
Scanner h = new Scanner(System.in);
System.out.print("enter height: ");
double height = h.nextline();
int i = 0;
while( I < 2){
if ( !isDigit(weight) && !isDigit(height){
Scanner w = new Scanner(System.in);
System.out.print("enter weight:);
weight = w.nextline();
Scanner h = new Scanner(System.in);
System.out.print("enter height");
height = h.nextline();
}else{
break;
double BMI = weight / ( height **2)
System.out.print(BMI)}
I++
}
let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest values that m could have
Answer:
Explanation:
From the given information:
[tex]a_{n-1} , a_{n-2}...a_o[/tex] in binary is:
[tex]a_{n-1}\times 2^{n-1} + a_{n-2}}\times 2^{n-2}+ ...+a_o[/tex]
So, the largest number posses all [tex]a_{n-1} , a_{n-2}...a_o[/tex] nonzero, however, the smallest number has [tex]a_{n-2} , a_{n-3}...a_o[/tex] all zero.
∴
The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times
i.e.
[tex](11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}[/tex]
[tex]= \dfrac{1(2^n-1)}{2-1}[/tex]
[tex]\mathbf{=2^n -1}[/tex]
[tex](1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}[/tex]
[tex]\mathbf {= 2 ^{n-1}}[/tex]
Hence, the smallest value is [tex]\mathbf{2^{n-1}}[/tex] and the largest value is [tex]\mathbf{2^{n}-1}[/tex]
Help need right now pls
Read the following Python code:
yards - 26
hexadecimalYards = hex (yards)
print (hexadecimalYards)
Which of the following is the correct output? (5 points)
A. 0b1a
B. 0d1a
C. 0h1a
D. 0x1a
Answer:
d. 0x1a
Explanation:
A structure that organizes data in a list that is commonly 1-dimensional or 2-
dimensional
Linear Section
Constant
No answertet provided
It intro technology
Answer:
An array.
Explanation:
An array can be defined as a structure that organizes data in a list that is commonly 1-dimensional or 2-dimensional.
Simply stated, an array refers to a set of memory locations (data structure) that comprises of a group of elements with each memory location sharing the same name. Therefore, the elements contained in array are all of the same data type e.g strings or integers.
Basically, in computer programming, arrays are typically used by software developers to organize data, in order to search or sort them.
Binary search is an efficient algorithm used to find an item from a sorted list of items by using the run-time complexity of Ο(log n), where n is total number of elements. Binary search applies the principles of divide and conquer.
In order to do a binary search on an array, the array must first be sorted in an ascending order.
Hence, array elements are mainly stored in contiguous memory locations on computer.
5. All sites are required to have the following reference materials available for use at VITA/TCE sites in paper or electronic format: Publication 17, Publication 4012, Volunteer Tax Alerts (VTA), and Quality Site Requirement Alerts (QSRA). AARP Foundation Tax Aide uses CyberTax Alerts in lieu of VTAs and QSRAs. What other publication must be available at each site and contains information about the new security requirements at sites
Answer:
Publication 5140.
Explanation:
The acronym VITA stands for Volunteer Income Tax Assistance and TCE stands for Tax Counseling for the Elderly. VITA/TCE is a certification gotten from the Internal Revenue Service in which the holders of such certification are trained on how to help people that have disabilities or that their incomes earners that are low. These volunteers help these set of people to prepare for their tax return.
In order to make the volunteers to be able to perform their work with high accuracy, the Department of Treasury, Internal Revenue Service gave out some aids for Quality Site. One of the aids which is the one contains information about the new security requirements at sites is given in the Publication 5140.
Given that the variable named Boy = "Joey" and the variable named Age = 6, create statements that will output the following message:
Congratulations, Joey! Today you are 6 years old.
First, write one statement that will use a variable named Message to store the message. (You will need to concatenate all of the strings and variables together into the one variable named Message. If you don't know what that means, read the section in Chapter 1 about concatenation.)
Then write a second statement that will simply output the Message variable.
Answer:
isn't it already showing it if not put text box
Explanation:
Implement the method countInitial which accepts as parameters an ArrayList of Strings and a letter, stored in a String. (Precondition: the String letter has only one character. You do not need to check for this.) The method should return the number of Strings in the input ArrayList that start with the given letter. Your implementation should ignore the case of the Strings in the ArrayList. Hint - the algorithm to implement this method is just a modified version of the linear search algorithm. Use the runner class to test your method but do not add a main method to your U7_L4_Activity_One.java file or your code will not be scored correctly.
Answer:
Answered below
Explanation:
//Program is implemented in Java
public int countInitials(ArrayList<string> words, char letter){
int count = 0;
int i;
for(i = 0; i < words.length; i++){
if ( words[i][0]) == letter){
count++
}
}
return count;
}
//Test class
Class Test{
public static void main (String args[]){
ArrayList<string> words = new ArrayList<string>()
words.add("boy");
words.add("bell");
words.add("cat");
char letter = 'y';
int numWords = countInitials ( words, letter);
System.out.print(numWords);
}
}
Approximately how many numeric IP addresses are possible with IPv4?
4 billon
Answer:
4,294,967,296 (~4.3B)
Explanation:
IPv4 uses 32-bits for representing addresses, thus you can have 2^32 total combinations.
