Answer:
[tex](f+g)(1)=0[/tex]
Step-by-step explanation:
We are given that:
[tex]\displaystyle f=\left\{(-2, -5), (3, -1), (1, -1)\right\}\text{ and } \\ \\ g = \left\{(1, 1), (-1, -2), (-4, 1), (-3, -1)\right\}[/tex]
And we want to find the value of (f + g)(1).
Recall that this is equivalent to:
[tex]=f(1)+g(1)[/tex]
According to the set, f(1) = -1 and g(1) = 1. Hence:
[tex]=(-1)+(1)=0[/tex]
josh is standing on the top of a building that is 425 feet tall. He throws a penny up into the air with an initial of 32 ft/sec. How long does it take for the penny to hit the ground?
Y = -4.9x^2 + 32x + 425
A. 10 seconds
B. 6.25
C. 400
D. 0 seconds
Answer:
A
Step-by-step explanation:
cause it will be more faster just because it is in a solid phase or it is solid
The time taken to hit the ground is 6.25 sec.(Option B)
How to calculate time?
It is given that penny follows the trajectory:
[tex]y = -4.9x^2 + 32x + 425[/tex]
Differentiating it we get:
[tex]\dfrac{dy}{dx} =-9.8x+32[/tex]
At y=425, it is obvious that x=0
So dy/dx at x=0 is 32.
Now the vertical component of the velocity is 32sinФ (where Ф is the angle at which penny is thrown).
Ф[tex]=\tan^{-1}(32)[/tex]
Vertical component=[tex]32*\sin(\tan^{-1}(32))[/tex]=31.98 ft/sec
Now applying the equation of motion: acceleration=-32ft/sec^(2)
u=31.98ft/sec s=-425 t=?
[tex]s=ut+\frac{1}{2} at^{2}[/tex]
[tex]-425=31.98t-16t^2[/tex]
[tex]16t^2-31.98t-425=0[/tex]
Solving the quadratic equation we get:
t=6.249 sec≅6.25 sec
Therefore, the time taken is 6.25 sec.
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The area of a segment of a circle is the area of the corresponding sector of the circle _____ the area of the corresponding triangle.
Answer:
The area of a segment of a circle is the area of the corresponding sector of the circle minus the area of the corresponding triangle.
Step-by-step explanation:
We know area of segment of a circle is the area of the corresponding sector of the circle minus the area of the corresponding triangle.
What is the circumference, in inches, of the front tire of Susan’s bike?
Answer:
The bike will travel approximately 1,272 inches or 106 feet.
Step-by-step explanation:
The diameter of a circle (wheel) can be used to find the circumference, which is the total perimeter around the wheel. The formula used to find circumference is: C = dπ, where 'd' is the diameter and π = 3.14. In this case C = 27 x 3.14 ≈ 84.78 inches. Since this measurement represents the perimeter of wheel, we would need to multiply this number by 15 in order to find the total distance after 15 complete rotations of the wheel: 84.78 x 15 ≈ 1,272 inches. 1,272 inches is a large measurement, so we can easily convert this to feet by dividing by the number of inches per foot, or 12: 1272/12 = 106 feet.
Hope this answer helps you :)
Have a great day
Mark brainliest
Monique made several batches of soup for a potluck supper. Each batch required Three-fourths of a pound of potatoes, and she used a total of 6 and one-half pounds of potatoes. How many batches of soup did Monique make?
Which division and multiplication problems could represent this scenario? Check all the apply.
Answer:
Number of batches of soup = 8 2/3 batches
Step-by-step explanation:
Each batch of soup = 3/4 pounds of potatoes
Total pounds of potatoes available = 6 1/2 pounds
How many batches of soup did Monique make?
Number of batches of soup = Total pounds of potatoes available / Each batch of soup
= 6 1/2 pounds ÷ 3/4 pounds
= 13/2 ÷ 3/4
= 13/2 × 4/3
= (13 * 4) / (2 * 3)
= 52/6
= 8 4/6
= 8 2/3
Number of batches of soup = 8 2/3 batches
Answer:
B 13/2 divided by 3/4
E 13/2 (4/3)
-4 = -2/u solve for U
PLSSSS HELP ME I NWWD THIS OR ELSE I FAIL
Answer:
-4= -2/u
or, -4u= -2
or, u= -2/-4
u=1/2
Identify the type of function represented by f(x)=4 x 2^x
Answer:
exponential growth
Step-by-step explanation:
f(x) is in the form a* b^x
where a is the initial value and b is the growth/ decay factor
since b > 1 it is growth
This is the exponential form of a function
We have exponential growth
The following formula gives the area A of a trapezoid, where b and c are the bases of the trapezoid and h
is the height:
A=
(6+c)h
Rearrange the formula to highlight the height.
h
Answer:
[tex]h = \frac{2A}{b + c}[/tex]
Step-by-step explanation:
Given
[tex]A = \frac{1}{2}(b + c)h[/tex]
Required
Solve for h
We have:
[tex]A = \frac{1}{2}(b + c)h[/tex]
Multiply sides by 2
[tex]2A = (b + c)h[/tex]
Make h the subject
[tex]h = \frac{2A}{b + c}[/tex]
I need help please. The question is already there. Tysm. 20 points.
Answer:
$109 and 35%
Step-by-step explanation:
49.05 is the sale price and the discount is 55%. What’s the original price?
price/ 1- discount
49.05/ 1 - 0.55
49.05/ 0.45
109
for the other part
to find the discount subtract final price from original price
94 - 61.10 = 32.9
Which would be 35% in percent form.
Find the missing side. Round it to the nearest tenth
Here is a list of fractions 18/45 14/30 10/25 8/20 16/40 one of these fractions are not equivalent to 2/5 write down this fractions
Answer:
14/30Step-by-step explanation:
How to simplify: • divide both numerator and denominator by their GCF.18/45= 18 ÷ 9 / 45 ÷ 9= 2/514/30= 14 ÷ 2 / 30 ÷ 2= 7/1510/25= 10 ÷ 5 / 25 ÷ 5= 2/58/20= 8 ÷ 4 / 20 ÷ 4= 2/516/40= 16 ÷ 8 / 40 ÷ 8= 2/5[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
[tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex] in the list of fractions [tex]\frac{18}{45}, \frac{14}{30} , \frac{x}{y} \frac{10}{25}, \frac{8}{20}, \frac{16}{40}[/tex].
Equivalent FractionsEquivalent fractions represent the same value even though they look different.
How to determine the Equivalent fractions?We know we can find an equivalent fraction of a given fraction by or dividing both the numerator and denominator of the given fraction with the same number (maybe LCM or HCF of the numerator or denominator).
[tex]\frac{18}{45}=\frac{18/9}{45/9}=\frac{2}{5}[/tex] (since [tex]9[/tex] is HCF of [tex]18, 45[/tex])
[tex]\frac{14}{30}=\frac{14/2}{30/2}=\frac{7}{15}[/tex] (since [tex]2[/tex] is HCF of [tex]7, 15[/tex])
[tex]\frac{10}{25} =\frac{10/5}{25/5} =\frac{2}{5}[/tex] (since [tex]5[/tex] is HCF of [tex]10, 25[/tex])
[tex]\frac{8}{20} =\frac{8/4}{20/4} =\frac{2}{5}[/tex] (since [tex]4[/tex] is HCF of [tex]8, 20[/tex])
[tex]\frac{16}{40} =\frac{16/8}{40/8} =\frac{2}{5}[/tex] (since [tex]8[/tex] is HCF of [tex]16, 40[/tex])
Thus, [tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex].
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Find the difference quotient for f(x) = x2 + 4.
I am trying to simplify a difference quotient with the form
f(x+h)−f(h)/h
if f(x)=2/x2 I have attempted to cancel out the denominator of the numerator by the least common denominator method. I know that I can solve this using implicit differentiation, but am trying to use the difference quotient to get the partial derivative
Here is my work so far:
f(x+h)−f(x)(h)
=f(2/(x+h)2)−f(2/x2)h
=(2/(x+h)2)−(2/x2)h
here I multiply by the LCD
=(2(x2)−2(x+h)2)/(x2(x+h)2)h
Here I expand out the top and cancel out 2x2
=(2x2−(2x2+4xh+2h2))/(x2(x+h)2)h
=−(4xh+2h2)/(x2(x+h)2))h
Here I think I should multiply by 1/h to get rid of the h on the bottom
I end up with:
=4xh+2h2hx2(x+h)2
factor out an h
=−4x+2hx2(x+h)2
please please please help asap
Answer:
1,3,5
Step-by-step explanation:
81 is a perfect square so it can be written as an integer
11.8 is rational because it can be written as a fraction (107/9)
sqrt(6) isn't a perfect square so it is irrational
3/7 is a fraction so it is rational
8.57 is a terminating decimal so it is rational
What is the quotient?
(-3)
(-3)²
O-9
1
o
1
9
100
O 9
Answer:
(-3)
Step-by-step explanation:
follow me if you want
grafique la recta que pasa por el punto (-2,4) y tiene pendiente m= -2/3
2 square5 + 5 square5
Answer:
=2^5+5^5
=32+3125
=3157
Can someone help me on this please
Answer:
x=0,1,±2
Step-by-step explanation:
x^3(x^2-5)=-4x
x^2(x^2-5)=-4
Take x^2=a, we have
a*(a-5)=-4, a^2-5a+4=0, (a-1)(a-4)=0, a=1,4
x^2=0, 1, 4. x=0,1,±2
Answer:
x = 1 and x = 2
Step-by-step explanation:
[tex] {x}^{5} - 5 {x}^{3} = - 4x \\ {x}^{4} - 5 {x}^{2} + 4 = 0 \\ ( {x}^{2} - 4)( {x}^{2} - 1)=0[/tex]
x² = 4 or x² = 1
x = ±√4 = -2 or 2x = ±√1 = -1 or 1Since x > 0, the negative integers are rejected and the solutions to this equations are x = 1 and x = 2
YOU HAVE A GARDEN HOSE AND A 0.5 LITER CONTAINER AND A 0.3 LITER CONTAINER. YOU NEED TO MEASURE OUT 0.1 LITER OF WATER. HOW DO YOU DO IT
Answer:
Fill up the .3 container and then pour it into the .5
fill up the .3 again and fill up the .5 ... if all is poured in the .5 will overflow over the top.
stop when the .5 is totally full... only .3 will fit... the liquid left in the .3 will be .1
Step-by-step explanation:
A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of of Rs. 20 per metre leaving a space 3m wide for a gate on one side?
The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
$\sf\underline\bold{Answer:}$
$\sf\small\underline{\underline{Area\: planted\: by\: the\: gardener : 1452.36m^2}}$$\sf\small\underline{\underline{The\:cost\:of\:fencing\:the\:park:Rs.4940}}$$\space$
$\sf\underline\bold{Step-by-Step:}$
$\space$
$\sf\bold{Given(In \:the\:Q):}$
Sides of the triangular park are 120m,80m and 50m.$\space$
$\sf\bold{To \: find:}$
How much area of the park does she need to plant?The cost of fencing the park ?$\space$
$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$
$\space$
$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$
$\space$
Use heron's formula to find the area of the triangle.
$\space$
$\mapsto$ $\sf\small{Heron's\:formula=}$
[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]
$\sf{Where\:s=semi\:perimeter}$$\sf{a,b,c\: = side\:of\:the\:∆}$$\sf\small{Here\:a=120,b=80 \:and\: c=50}$$\space$
$\sf\bold{Now,find\:semi\:parameter:-}$
$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$
$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$
$\space$
$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$
$\sf{Area\:of\:the\:∆:-}$
$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]
$\space$
$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$
$\space$
$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$
$\space$
$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$
______________________________
$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$
$\sf{Cost\:of\:fencing-}$
$\sf{Rate = Rs.20 per \:meter}$ $\sf{Left\:space=3m}$$\space$
$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$
$\sf{= 250-3=247m.}$$\space$
So,total cost of fencing at the rate of Rs.20 per m:-
$\sf\underline\bold\purple{=247\times20=4940}$___________________________________
what is percent of a number
Step-by-step explanation:
a fraction of a number out of 100%
Answer and step-by-step explanation:
Percent (%) means per 100
A percentage is a number or ratio expressed as a fraction of 100
Example 50% of 8 = 8*50/100 = 4
what is the degree of the polynomial below
Answer:
d
Step-by-step explanation:
trust me gang
Answer:
the degree is the value of the highest exponent... 4x^3 the exponent is a three
answer "D"
Step-by-step explanation:
graph shown here is the graph of which of the following rational
functions?
Answer:
B) f(x) = 1/x-1
Step-by-step explanation:
You can type it into desmos graphing calculator- hope this helps
Option (B) is correct.
What is a graphing function?"Graphing functions is drawing the curve that represents the function on the coordinate plane. If a curve (graph) represents a function, then every point on the curve satisfies the function equation"
For the given graph,
The functions are
(A) [tex]f(x)=\frac{1}{x}[/tex]
(B) [tex]f(x)=\frac{1}{x-1}[/tex]
(C) [tex]f(x)=\frac{1}{x+1}[/tex]
Plot all these functions in the graph. We can obtain the graph as shown for option (B).
Hence we can conclude that option (B) is correct.
Learn more about graphing functions here
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What is the distance from point N to LM in the figure below?
Answer:
It is 7.5
Step-by-step explanation:
PLS HELP ME!!- What is the total cost for 4.6 pounds of blackberry jam and 1.6 pounds of blueberry jam? boysenberry jam $5/1b blackberry jam $5/1b raspberry jam $7/1b apple butter $3/1b marmalade $3/1b blueberry jam $8/1b Submit I don't kn
Answer:
total blackberry: $23
total blueberry: $12.80
total: $35.80
Step-by-step explanation:
the blackberry jam is $5/lb
therefore, 4.6 pounds of it -
5 x 4.6
=23
the blueberry jam is $8/lb
using the same method we do
8 x 1.6
=12.8
adding the two totals -
23 + 12.8 = 35.8
in other words, the two jams will be $35.80
Select the best answer to describe the parabola
Positive parabola that has a minimum.
It’s positive if it opens upward, negative if it opens downward. It has a minimum if it opens upward, and maximum when it opens downward.
May somebody help with this and show how you solved these 4 problems??
Answer:
x=27
y=25
c=12
n=70
Step-by-step explanation:
a- x-10=17
isolate the x by adding 10 to both sides
x=27
b- y+7=32
isolate the y by subtracting 7 from both sides
y=25
c- 4c=48
isolate c by dividing both sides by 4
c=12
d- n/5=14
isolate the n by multiplying both sides by 5
n=70
Answer:
a) [tex]x-10=17[/tex]
Add 10 to both sides:-
[tex]x-10+10=17+10[/tex][tex]x=27[/tex]----------
b) [tex]y+7=32[/tex]
Subtract 7 from both sides
[tex]y+7-7=32-7[/tex][tex]y=25[/tex]------------
c) [tex]4c=48[/tex]
Divide both sides by 4
[tex]\frac{4c}{4}=\frac{48}{4}[/tex][tex]c=12[/tex]------------
d) [tex]\frac{n}{5}=14[/tex]
Multiply both sides by 5
[tex]\frac{5n}{5}=14\cdot \:5[/tex][tex]n=70[/tex]OAmalOHopeO
(3[tex]\sqrt{7} \\[/tex]+7[tex]\sqrt{3}[/tex])/[tex]\sqrt{21}[/tex]
Answer:
sqrt(3) + sqrt(7)
Step-by-step explanation:
3*sqrt(7) / sqrt(21) = 3/sqrt(3)
If you rationalize the denominator, you get 3*sqrt(3)/3. The threes cancel
You are left with sqrt(3)
7sqrt(3)/sqrt(21) = 7 / sqrt(7)
If you rationalize the denominator, you get
7 sqrt(7)/ 7 = sqrt(7)
The 7s have been canceled out
The answer is
sqrt(3) + sqrt(7)
For the function F defined by F(x)=x2−2x+4, find F(|−4|).
A. 8
B. 4
C. 12
D. 28
Answer:
12
Step-by-step explanation:
F(x)=x^2−2x+4
Let x = |-4| = 4
F(|-4|)=4^2−2(4)+4
= 16 -8+4
= 8+4
= 12
Carl has 9/1 cup of jelly worms and a recipe that calls for 1/2 cup of jelly worms. How many batches of Carls recipe can he make?
Answer:
hey sol, ok so im guessing you have to either divide or multiply, im stuck on this problem to lol
Step-by-step explanation:
Find the measure of the indicated angle to the nearest degree 36
Answer:
47°
Step-by-step explanation:
cos ? = 36/53
? = arccos (36/53)
? = 47 (rounded to the nearest degree)
Answered by GAUTHMATH
What is the area of a circle with a diameter of 20 inches if
[tex]\pi[/tex]
=3.1415
$\sf\underline\bold\blue{Information\:given\:in\:the\:question:}$
π =[tex]\sf{ 3.1415}[/tex]$\sf{Diameter = 20inches}$$\space$
$\sf\underline\bold\blue{What\:we\:have\:to\:find?}$
$\sf{Area\:of\:the\:circle.}$$\space$
$\sf\underline\bold\blue{Answer:}$
$\sf\small{Area\:of\:the\:circle\:is : 314.15}$$\space$
$\sf\underline\bold\blue{Calculations:}$
Here we have the value of the circle's diameter that is 20inches. So, first we have to calculate the radius of the circle using the formula :
$\mapsto$ $\sf\bold{Radius=}$ $\sf\dfrac{Diameter}{2}$
$\space$
$\sf\underline\bold\blue{Calculating\:the\:required\:values:}$
$\mapsto$ $\sf\bold{Radius=}$ $\sf\dfrac{20}{2}$
$\sf{Convert \: to \: the\:lowest\:term(Divide),}$
$\mapsto$ $\sf\underline\bold{Radius=10}$
☆Now we know the value of the radius . So now let's calculate the area of the circle.
$\space$
$\sf\bold{Area\:of\:circle:}$ π$\sf{ r \: ^{2} }$
$\sf\bold{Evaluating \: the\:required\:values:}$
$\sf\bold{Area\:of\:circle=3.1415(10)^2}$
$\space$
$\sf\bold{Area\:of\:the\:circle=3.1415\times10\times10}$
$\sf\bold{Now,}$
$\sf\bold{Area\:of\:the\:circle:3.1415\times100}$
$\space$
$\sf\underline\bold\green{Thus,Area\:of\:the\:circle\: is \: 314.15}$
____________________________
