Why is conical flask used in the freezing point of naphthalene activity?

Pick one below.

A Conical flask is used to hold the boiling tube

B Napthalene is poisonous and needs to be contained

C Freezing point can only be determined inside the conical flash

D To ensure the cooling process is not affected by surrounding temperature​

Answers

Answer 1

Answer:

D. To ensure the cooling process is not affected by surrounding temperature

Explanation:

The conical flask acts as a temperature jacket.

Answer 2

The conical flask is used in freezing point of the naphthalene activity because to ensure the cooling process is not affected by surrounding temperature.

What is the use of conical flask ?

In the freezing point determination of naphthalene, a conical flask is used to hold the naphthalene sample and a thermometer. The conical shape of the flask allows for efficient stirring of the naphthalene as it is heated and cooled, ensuring that the temperature is evenly distributed throughout the sample.

The conical flask is also used to protect the naphthalene sample from any external temperature fluctuations that could affect the cooling process. By placing the flask in an ice bath, the cooling process can be closely monitored and controlled, allowing for accurate determination of the freezing point.

Therefore, the primary reason why a conical flask is used in the freezing point determination of naphthalene is to ensure that the cooling process is not affected by surrounding temperature.

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Related Questions

I need help!!!! please

Answers

6.94 is much more closet to 7.016, so Li 7 is more abundant

Give the relation of energy (E) and frequency (v) as given by Planck. Calculate the frequency and energy of a photon of radiation having wavelength 3000°A.
Pls answer correctly,need it urgently...

Answers

Solution:-1

[tex]\\ \sf\longmapsto E=hv[/tex]

E denotes to Energy h denotes to planks constantv denotes to frequency.

Solution:-2

Wavelength=3000Å

[tex]\boxed{\sf \lambda=\dfrac{c}{v}}[/tex]

[tex]\\ \sf\longmapsto v=\dfrac{c}{\lambda}[/tex]

[tex]\\ \sf\longmapsto v=\dfrac{3\times 10^8m/s}{3000\times 10^{-10}m}[/tex]

[tex]\\ \sf\longmapsto v=0.001\times 10^{18}s^{-1}[/tex]

[tex]\\ \sf\longmapsto v=1.0\times 10^{15}s^{-1}[/tex]

Now

[tex]\\ \sf\longmapsto E=hv[/tex]

[tex]\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 1.0\times 10^{15}s^{-1}[/tex]

[tex]\\ \sf\longmapsto E=6.6\times 10^{-19}J[/tex]

A piece of sodium metal can be described as?

Answers

it can be described as a pure metal

hii pls help me to balance the equation and state the symbols thanksss​

Answers

Answer:

I hope that the link above will be helpful

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

[tex]\boxed{\pmb{\green{\sf{2Mg +H_{2}SO_{4}\dashrightarrow H _{2}+Mg_{2}SO_{4}}}}}[/tex]

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

in h-atom if x is radius of first bohrs orbit de broglie wavelength of an atom in 3rd orbit is a.3πx b.6πx c.9x/2 d.x/2
please I need complete explanation fast ​

Answers

Answer:

can you type question properly.

A chemist determines by measurements that 0.0550 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.

Be sure your answer has the correct number of significant digits.

Answers

The mass of nitrogen gas that participated in the chemical reaction is 1.54g

HOW TO CALCULATE MASS OF AN ELEMENT:

Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;

mass (M) = molar mass (MM) × number of moles (n)

According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.

The molecular mass of nitrogen gas (N2) = 14.01(2)

= 28.02g/mol

Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:

Mass (g) = 0.0550 mol × 28.02 g/mol

Mass = 1.5411

Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g

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can you solve question 5 and 6 only​

Answers

Answer:

oil floats on water because it is heavier than water

Salt is no longer visible after stirring as salt dissolves in water

by filtration

At the beginning of the reaction: N2 + 3H2 -> 2NH there is 1 mol of N. and 3 moles of H, and at the end of it is present a mixture formed by 2.5 moles in total, what is the performance for the reaction?
5.- Al comenzar la reacción: N2+ 3H2 -> 2NH existe 1 mol de N. y 3 moles de H, y al finalizarla está presente una mezcla formada por 2,5 moles en total, ¿cuál es el rendimiento para la reacción? ​

Answers

Answer:

75%

Explanation:

call realistic moles of N2 in the reaction is a

moles of H2 :3a

moles of NH3: 2a

the moles of residual N2 after reaction: 1-a

the moles of residual H2 after react: 3- 3a

the moles of mixture: 2a+1-a+3-3a=2.5

-> a=0.75

H=0.75/1=75%

what is the reactant(s) in the chemical equation below

3CO(g) + Fe2O3(s) 2Fe(s) + 3CO2(g)

Answers

Answer:

the reactants are carbon dioxide ,iron, oxygen

What is the AHsol for LiF → Lit + F-? The lattice energy is -1,036 kJ/
mol, the enthalpy of hydration for Lit is -499
kJ/mol, and the enthalpy of hydration for F-is-431 kJ/mol. Use A Hooi = -A Hat + AHhydr.
0-968 kJ/mol
-106 kJ/mol
106 kJ/mol
1,966 kJ/
mol

Answers

The heat of hydration is defined as the heat absorbed or evolved when one mole of a substance undergoes hydration. The heat of solution is the enthalpy change associated with he dissolution of a solute. The lattice energy is the heat. Lattice energy is the energy released when the components of the lattice are brought together from infinity.

Hence the heat of solution for LiF → Li^+ + F- is -1966  kJ/mol

Given that;

Heat of hydration = ΔH solution – ΔH lattice energy

Where,

ΔH solution  = Heat of the solution

ΔH lattice energy = Lattice energy of the solution

The heat of solution or enthalpy of dissolution is defined as the enthalpy change associated with the dissolution of a solute in a solvent

From the formula above;

ΔH solution = Heat of hydration + ΔH lattice energy

Heat of hydration = [(-431) + (-499)] = -930 kJ/mol

ΔH solution = (-930) + (-1,036) = -1966  kJ/mol

Hence the heat of solution for LiF → Li^+ + F- is -1966  kJ/mol

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1. Mg + HCl  … + ….
2. NaOH + HNO3  … + ….
3. KOH + CuCl2  … + ….
4. Na2SO4 + BaCl2  … + ….
5. HCl + FeO à … + …

Answers

Explanation:

The answer is mentioned above.

Hope it helps.

Unknown # 29

Flame Test Color: Green
Addition of HCl(aq): Bubbles
Addition of HCl(aq) and BaCl2(aq): NR (No Reaction)
Addition of HNO3(aq) and AgNO3(aq): White precipitate

What is the unknown ionic compound molecular formula?

Answers

Answer:

I think it's a sulphate ion, because when you add hydrochloric acid to it it produces bubbles and when you add barium chloride it then produces a white precipitate.its formula is SO4

I hope this helps

what do y’all do when y’all brainly says “locked” and won’t show anymore answers !???

Answers

Answer:

Create a new account as the thing you're experiencing now is due to the fact that Brainly had blocked your account.

2(3a-3)-2(a-2)=3
thank you ​

Answers

Answer:

6a - 6 - 2a + 4 = 3

4a - 2 = 3

4a = 3 + 2

4a = 5

a = 5/4

hope that helps ✌

what is second explain it briefly​

Answers

Explanation:

it is that when an object is moving 25 m per sec to calculate its time we can simply divide 1.5 by 25 and multiply by 1

9. During an experiment the students prepared three mixtures A)Starch in water B) Sodium chloride solution C) Tincture of Iodine. i) Students observed a visible beam of light through mixture A. Why? ii) Tincture of lodTe did not show Tyndall effect. Explain reason. ill) How can you relate particle size to Tyndall effect?​

Answers

Answer:

See explanation

Explanation:

Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.

In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.

Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.

El hipoclorito de sodio (NaClO), es vendido en una solución clara de ligero color verde-amarillento y un olor característico que se conoce con el nombre genérico Límpido, con una concentración del 6%. Pero para la desinfección de superficies el Límpido, debe ser diluido al 0,5%. Cuánto Límpido debemos sacar del recipiente para obtener 200 ml de una solución al 0,5%.

Answers

Respuesta:

16,7 mL

Explicación:

Paso 1: Información provista

Concentración inicial (C₁): 6%Volumen inicial (V₁): ?Concentración final (C₂): 0,5%Volumen final (V₂): 200 mL

Paso 2: Calcular el volumen de la solución concentrada

Queremos preparar una solución diluida de hipoclorito de sodio a partir de una concentrada. Podemos calcular el volumen inicial que debemos tomar usando la regla de dilución.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0,5% × 200 mL / 6% = 16,7 mL

How many grams of liquid water are produced when 60 grams of ice melt?

Answers

Answer: 60 Grams of water are produced, because you can't get more than the amount that was in the original ice cube

Explanation:

What exactly is a proton? Is it a member of the periodic table?

Answers

The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon atom, no matter how many neutrons may be present).

Liquids which do not wer the glass surface form a convex meniscus.True or false​

Answers

Answer:

true is your answer

Explanation:

hope it helps

what is the material used to make plaster of paris?​

Answers

Answer:

gypsum

Explanation:

gypsum is used to make plaster of Paris

Answer:

Simple squamous epithelium

This type of epithelia lines the inner surface of all blood vessels (endothelium), forms the wall of alveolar sacs in the lung and lines the body cavities (mesothelium). The primary function of simple squamous epithelia is to facilitate diffusion of gases and small molecules.

Explanation:

isme talk kro

Which of the following is NOT a physical property?
Viscosity
Reactivity
Malleability
Density

Answers

Answer:

reactivity is NOT a physical property

5+64
this is TOTALLY SOOOO hard so help me
^thats what she said

Answers

Answer:

69

Explanation:

I thought that I answer is correct

Answer:

The answer is 69

Explanation:

Because if you add one its 66, and so on, hope this helps! but if you add five it will be 69, if you need help with easy equations let me know

If the temperature of a reversible reaction in dynamic equilibrium decreases, how will the equilibrium change?

A. It will shift towards the endothermic reaction.
B. It will not change.
C. It will shift towards the products.
D. It will shift towards the exothermic reaction.

Answers

Answer:

D. It will shift towards the exothermic reaction.

Explanation:

I forgot to add the answers i had to my question (While a balloon is being filled, if the temperature of the air in the balloon increases, what happens to it’s volume)
A) It stays the same
B) It deflates
C) It decreases
D) It increases

Answers

The correct answer is D ... and if the answer was added to the word "explode" .. it would have been more correct .

Calculate K for 2CO2(g) ⇔ 2CO(g) + O2(g)
given that the equilibrium concentrations of carbon monoxide, oxygen and carbon dioxide are 2.0 x 10-6 M, 1.0 x 10-6 M, and 0.25 M respectively.

Answers

Explanation:

here's the answer to your question

water and development are substitute of one another.
explanation with it, please

Answers

Fawn spends hours each week managing employee shifts and schedules, time she should be spending on other restaurant operations. What can she do? O a) Start leaving more time in her week for scheduling-related tasks b) Write everything down in a weekly planner O c) Consider online inventory management software O d) Consider online scheduling software

The reactivity of elements can be predicted based on the position of an element in the periodic table. Based on the periodic table, which of the following elements would be expected to be the most reactive?

Iodine (I)
Iodine (I)

Chlorine (Cl)
Chlorine (Cl)

Fluorine (F)
Fluorine (F)

Bromine (Br)

Answers

Answer:

Chlorine (Cl) is most reactive out the the listed elements.

Answer:

iodine

Explanation:

It is the most reactive on the periodic table.

A compound was found to contain 90.6% lead (Pb) and 9.4% oxygen. What is the empirical formula for this compound?

Answers

Answer:

the answer is 47.9 and ik because I just had that question

The empirical formula of the compound is O₄Pb₃.

What is the empirical formula?

An Empirical system is the chemical system of a compound that offers the proportions of the elements gifted within the compound however not the real numbers or arrangement of atoms. This would be the lowest complete variety ratio of the elements within the compound.

Amount of lead (Pb) = 90.6%

⇒and amount of oxygen = 9.4%

taking the whole number ratio

o = 4

Pb = 3

∴ ⇒O: Pb=4:3

O4Pb3 answer.

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3g of clean mg ribbon and 8g of clean copper metal was burnt separately in equal volume of air and both mass reacted completely with air state and explain where they was greater change in mass??​

Answers

Answer:

gshshs

Explanation:

bshsjskskehhshs

The copper metal is heated in the air.  The magnesium ribbon emits a brilliant light and magnesium oxide, which is white. When oxygen is passed over copper (in the presence of heat), an oxidation reaction occurs, resulting in the formation of black copper oxide. The greater change in mass observed when they start to burned.

What is copper metal ?

Copper is a mineral and an element that is essential to our daily lives. It is a significant industrial metal due to its high ductility, malleability, thermal and electrical conductivity, and corrosion resistance. It is a necessary nutrient in our diet.

Metals are a class of materials that have high electrical and thermal conductivity, as well as malleability, ductility, and high light reflection. Copper (Cu), aluminium (Al), and other metals are examples.

The combustion of magnesium ribbon is a combined reaction. This is due to the fact that magnesium reacts with oxygen to form the single product magnesium oxide. When magnesium ribbon is burned in air, it reacts with the oxygen in the air to form magnesium oxide.

Thus, 3g of clean mg ribbon and 8g of clean copper metal were burnt separately in equal volume of air and both mass reacted completely with air the greater change in mass observed when they start to burned.

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