Why is a chemical equilibrium described as dynamic?

Answer:

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Answer:

A) number of electrons

Explanation:

A calcium atom has 20 electrons while a calcium ion has 18 electrons since it loses 2 electrons to form a stable octet structure. The formula of a calcium ion is Ca2+.

The number of protons does not change, neither do the number of neutrons. Atomic number is the proton number which is equals to the number of protons, hence B and C is wrong. Mass number is the number of protons and neutrons. Hence it doesnt change too and D is wrong.

Only the number of electrons change when an atom forms an ion.

Answer:

D working alone

Explanation:

Working alone is the only option that could potentially be a safety hazard; if you have no one watching your back, errors could occur, like dropping glass or burning your hand, and no one is around to help you.

Choices A, B, and C are not correct because those are all good safety standards.

Answer:

D.

Explanation:

It would not be gain because it would say +6 instead of -2. Having a -2 charge means it wants to loose 2 electrons so it can form a full shell of 8 electrons. It wants to be inert (stable).

- Hope that helps! Please let me know if you need further explanation.

Answer:

Before submerged 150ml

After submerged: 180ml

rock volume: [tex]180 - 150 = 30[/tex]

formula for density:

[tex] \frac{mass}{volume} = 5.38 [/tex]

[tex] \frac{175}{30} = 5.38 [/tex]

THE ANSWER IS b

prettty sure this is wrong but eh :/ probably correct

Answer:

120 g SO3

Explanation:

128 g SO2  -> 160 g SO3

 96 g SO2  -> x

x= (96 g SO2 * 160 g SO3)/128 g SO2

x= 120 g SO3

The mass of sulfur trioxide, SO₃, formed is 120 g

The balanced equation for the reaction is given below:

Next, we shall determine the mass of SO₂ that reacted and the mass of SO₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of SO₂ = 32 + (16×2)

= 32 + 32

= 64 g /mol

Mass of SO₂ from the balanced equation = 2 × 64 = 128 g

Molar mass of SO₃ = 32 + (16×3)

= 32 + 48

= 80 g /mol

Mass of SO₃ from the balanced equation = 2 × 80 = 160 g

Thus,

From the balanced equation above,

128 g of SO₂ reacted to produce 160 g of SO₃.

Finally, we shall determine the mass of SO₃ by the reaction of 96 g of SO₂. This can be obtained as follow:

From the balanced equation above,

128 g of SO₂ reacted to produce 160 g of SO₃.

Therefore, 96 g of SO₂ will react to produce = [tex]\frac{96 X 160}{128}\\\\[/tex] = 120 g of SO₃.

Therefore, the mass of SO₃ formed is 120 g

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Answer:

when heat gets transferred through electromagnetic waves that move through

space

Explanation:

Radiation refers to the movement of energy through space without a material medium of propagation.

Electromagnetic waves have the ability to travel through space without a material medium for propagation. For instance, the rays from the sun reach us on earth without any intervening medium. Heat from a furnace can affect an object some distance away from the furnace without an intervening medium.

These are all examples of radiation. Energy is propagated through space without the intervention of any material medium.

Answer: c

Explanation: an xray wave does have a higher frequency than an infrared wave.

Answer:

Explanation:c

Answer:

By using the speed of sound in water

Explanation:

(Which is about 1500 m/s in sea depending on the sea water density )

Answer: 26.1 C

Explanation: Trust me

Answer:26.1

Explanation:

I did the ck12

Answer:

1. sublimation

2.melting

3.melting  

4.sublimation

Explanation:

melting is a process when solid changes to liquid

Sublimation is the transition of a substance directly from the solid to the gas state, without passing through the liquid state.

Answer:

ionic

Explanation:

Answer:

b

Explanation:

it is right

Answer:

Approximately [tex]-74.8\; \rm kJ \cdot mol^{-1}[/tex].

Explanation:

Number the three reactions with known enthalpy changes:

[tex]\begin{aligned}& {\rm C\; (s) + O_2\; (g) \to CO_2\; (g)} & \quad \Delta H = -393.5\; \rm kJ\cdot mol^{-1}& \quad (1) \\ & {\rm H_2\; (2) + \frac{1}{2} O_2\; (g) \to H_2O\; (l)} & \quad \Delta H = -285.8\; \rm kJ\cdot mol^{-1} & \quad (2) \\ & {\rm CH_4\; (g) + 2\; O_2\; (g) \to CO_2\; (g) + 2\; H_2O\; (l)} & \quad \Delta H = -890.3\; \rm kJ\cdot mol^{-1} & \quad (3)\end{aligned}[/tex].

The goal is to find a way to combine these three reactions to obtain: [tex]\rm C\; (s) + 2\; H_2\; (g) \to CH_4\; (g)[/tex].

Assume that the three known reactions are combined in this way:

[tex]a \times (1) + b \times (2) + c \times (3)[/tex].

That corresponds to:

[tex]\begin{aligned} & a\; \mathrm{C\; (s)} + \left(a + \frac{1}{2}\, b + c\right) \; \mathrm{O_2\; (g)} + b\; \mathrm{H_2\; (g)} + c\; \mathrm{CH_4\; (g)} \\ & \to (a + c)\; \mathrm{CO_2\; (g)} + (b+ 2\,c )\; \mathrm{H_2O\; (l)}\end{aligned}[/tex].

Compare the coefficients of this reaction with that of the desired reaction:

[tex]\rm C\; (s) + 2\; H_2\; (g) \to CH_4\; (g)[/tex].

Note that some species (e.g., [tex]\rm CH_4\; (g)[/tex]) appeared on the wrong side of the equation. Their desired coefficient should be the opposite of their true coefficient. For example, the coefficient of [tex]\rm CH_4\; (g)[/tex] is supposed to be [tex]1[/tex]. However, because it appeared on the wrong side of the equation, its desired coefficient would be [tex]-1[/tex].

The coefficients of species that are not in the desired equation should be zero.

[tex]\begin{array}{|c|c|c|}\cline{1-3}\text{Species} & \text{Coefficient}& \text{Desired Coefficient} \\ \cline{1-3} \mathrm{C\; (s)}} & a & 1 \\ \cline{1-3} \mathrm{O_2\; (g)} & a + (1/2)\, b + c & 0 \\ \cline{1-3} \mathrm{H_2\; (g)} & b & 2 \\ \cline{1-3}\mathrm{CH_4\; (g)} & c & -1\\ \cline{1-3} \mathrm{CO_2\; (g)} & a + c & 0 \\ \cline{1-3} \mathrm{H_2O\; (l)} & b + 2\, c & 0\\ \cline{1-3}\end{array}[/tex].

Solve for [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex]:

In other words, the desired equation is equal to [tex]1 \times (1) + 2 \times (2) - 1 \times (3)[/tex].

By Hess's Law, the enthalpy of the desired equation will be:

[tex]\begin{aligned}& 1\times \Delta H (1) + 2 \times \Delta H (2) - 1\times \Delta H(3) \\ &\approx -393.5 + 2 * (-285.8) - (-890.3) \\ &= -74.8\; \rm kJ \cdot mol^{-1} \end{aligned}[/tex].

Answer:

Photo chemical is caused by the chemical reaction of light. It's initiated by the absorption of energy in the form of light.

Explanation:

When the picture is developed, the thiosulfate dissolved the silver bromide that had been exposed to light more easily than the one that had been kept in the dark,

Answer:it is D

Explanation: it is only one that makes sense

The molarity of a KCl solution if 37.3 g of KCl are dissolved in water to give a final solution volume of 500 ml is 1 M.

Molarity of a given solution is known as the total number of moles of solute per litre of the solution.  A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.

Molarity = (No. of moles of solute ÷ Volume of solution in liters)

The unit of molarity is mol L⁻¹.

Molarity is temperature dependent because as temperature changes, volume of the solution also changes.

Given, Mass of KCl = 37.3 g

Molar mass of KCl = 74.5 g/mol

Volume of solution = 500ml = 0.5 L

No. of moles = Mass / Molar mass = 0.5

Molarity = 0.5/0.5 = 1 M

Therefore, The molarity of a KCl solution if 37.3 g of KCl are dissolved in water to give a final solution volume of 500 ml is 1 M.

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Answer:

[tex]\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}[/tex]

Explanation:

The unbalanced nuclear equation is

[tex]\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, ?[/tex]

Let's write the question mark as a nuclear symbol.

[tex]\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{Z}^{A}\text{X}[/tex]

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

60 = 0 + A, so A = 60 - 0 = 60, and

27 = -1 + Z, so Z  = 27 + 1 = 28

Your nuclear equation becomes

[tex]\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{28}^{60}\text{X}[/tex]

Element 28 is nickel, so the balanced nuclear equation is

[tex]\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}[/tex]

Winds are always named from the direction it blows from

Uneven heating of Earth's surface,in turn,causes differences in air pressure at various locations. Heated air rises,creating an area of low pressure beneath. Cooler air descends, creating an area of high pressure

Answer:

The planets themselves are composed of several trillions or quadrillions or more atoms. As far as hard science is concerned, it would be really hard to picture them as electrons. Conclusion: It can be said with a great accuracy that our planets are NOT huge electrons.

Rutherford's experiments showed that the mass of atoms was mostly concentrated in a very small region, with charge equal to the atomic number- the nucleus. He absolutely did not show, nor is it true, that electrons orbit the nucleus as if they were planets. That was a guess people made in trying to figure out how to picture the atom.

(Hope this helps) Sky

Answer:

a. 0.0855 M

b. 0.153 M

c. 0.0351 M

d. 0.0901 M

Explanation:

a.

Molar mass NaCL= 23.0 +35.5 = 58.5 g/mol

10.0 g* 1 mol/58.5 g = 10.0/58.5 mol

(10.0/58.5) mol/2L = 0.0855 mol/L = 0.0855 M

b.

Molar mass (C12H22O11) =342.3 g/mol

52.5 g*1mol/342.3 g = 52.5/342.3 mol=0.153 mol

0.153 mol/1L = 0.153 M

c.

Molar mass (Al2(SO4)3) =342.2 g/mol

120g* 1 mol/342.2 g =0.351 mol

0.351 mol/10.0L = 0.0351 mol/L = 0.0351 M

d.

Molar mass (C8H10N4O2) = 194.2 g/mol

1.75 g*1mol/194.2 g = 0.00901 mol

0.00901 mol/0.100 L =0.0901 M

Answer:

Magnets stick to the fridge door because, underneath the paint, the door is made of steel. Magnets are attracted to certain metals, and if the attraction is strong enough they can hold on even when upside down. ... This means that a magnet will always be attracted to the door. But an iron nail does not have any magnetic properties. So it doesnt get attracted.

Hope this helps, Pls mark as Brainliest!!

A small magnet will stick to a refrigerator door, but a nail will not stick

because magnets attract certain types of metals.

Magnets have a strong magnetic field which is why it attracts metals such

as iron and steel. The refrigerator must have been made with iron or steel

which was why the magnet stuck to it.

Metals such as aluminium and copper aren't attracted by magnets which is

why the nails weren't attracted as a result of it being made with metals which magnets don't attract.

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Answer:

1 quart of lemonade will be in the first cup

Explanation:

1/4th of a gallon is a quart

Answer: The air pressure at the top of the mountain is 96.9 kPa

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.

[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.

We are given:

[tex]P_1=99.5kPa\\V_1=22.3L\\P_2=?\\V_2=22.9L[/tex]

Putting values in above equation, we get:

[tex]99.5\times 22.3L=P_2\times 22.9L\\\\P_2=96.9kPa[/tex]

Thus the air pressure at the top of the mountain is 96.9 kPa

Answer:

The answer is NaOH

Explanation:

Strong bases are characterized by the fact that they dissociate completely in an aqueous solution. In this case, sodium hydroxide, NaOH, is classified as a strong base because it dissociates completely in an aqueous solution to form sodium cations, Na+, and hydroxide anions, OH−. Also, it is strong because it totally breaks in its ion. And the base which breaks totally in its atom called the strong base and which doesn't it that is a weak base.

Answer:

NaOH

Explanation:

Got it right in the test. Please mark as brainliest

Answer: Pounds per Cubic inch(lb/in3)

Answer:

natural selection

Explanation:

it is a biological selection of genes, whether dominant or negative.