Answer:
C. sound energy
Explanation:
hope this helps
Dr. Bishop wants to study how small children respond to scary stimuli. She will explain the procedure to parents and ask them to sign a permission form. She will have 3-5 year old kids individually come into her lab
Each child will be given a teddy bear to cuddle with. She will then stand a couple of feet behind the child as he or she plays and make a very loud scary sound. She will observe and measure the child's responses. The
child will come back in a few days and be given the teddy bear again, she will measure any reactions the child has to the bear.
What might an ethics review committee decide about the proposal?
The proposal is approved, as it meets the ethical guidelines defined by the APA
O The proposal is approved, because there is no deception
The proposal is denied, because participants wil ikely suffer psychological harm.
O The proposal is denied, because participants are not allowed to leave the study
The proposal is denied, because it does not meet confidentiality standards
Answer:
The correct option is;
The proposal is denied, because participants will likely suffer psychological harm
Explanation:
Among the recommendations in the report on ethical research with children, it is suggested that the following should be observed by researchers;
1) Seeking consent should be a continuous process
2) Contemplate payment forms other than money to allow more discretion on child safety
3) Have two way communication with the child
4) Ask for assent of the child participating in the research
The above APA suggestions where not met by the researcher in the study.
Answer:
The proposal is denied, because participants will likely suffer psychological harm.
Explanation:
This proposal would cause psychological harm to its participents.
I also took the test and that was the correct answer.
What form of energy does a block of chocolate have?
Answer:
Chemical Energy
Explanation:
Explain what happens to the sound waves when a singer hits the high pitched notes during the National Anthem. Be sure to use the terms amplitude and frequency in your answer.
Answer: The frequency increases as the pitch increases, and the amplitude increases as the volume increases
Explanation:
Waves have the property of:
v = f*λ
where v is the speed of the wave (which is almost constant for soundwaves, v = 340 m/s)
f is the frequency of the wave, and λ is the wavelength.
Now, we know that when the pitch of a note increases, also does the frequency of the soundwave (so the wave oscillates faster).
Now, we also want to include the amplitude of the soundwave in this.
The amplitude is related to the volume of the soundwave (actually is related to the energy, and as higher is the energy, more "loud" is the sound).
As the high pitch part is usually "louder", we can assume that we have an amplitude increase.
Then the answer would be:
"The frequency increases as the pitch increases, and the amplitude increases as the volume increases"
Which of the following best describes a consumer?
0. a business owner who sells clothes
0. someone who studies economics
O. a farmer who sells his crops
O. a person who buys goods and services
Answer:
a business who buys goods and services
A skydiver falls toward the ground at a constant velocity. Which statement best applies Newton’s laws of motion to explain the skydiver’s motion? An upward force balances the downward force of gravity on the skydiver. The skydiver’s inertia is zero, which no longer allows for acceleration. An unbalanced force pulls the skydiver toward the ground. The mass of the skydiver is so great that there is no acceleration
Answer: A) an upward force balances the downward force of gravity on the skydiver
Explanation: I got it correct on my test on edge
The statement best applies Newton’s laws of motion to explain the skydiver’s motion an upward force balances the downward force of gravity on the skydiver. Thus, option A is correct.
Which statement best applies Newton’s laws of motion?
The statement that best applies Newton’s laws of motion to explain the skydiver’s motion is that an upward force balances the downward force of gravity on the skydiver. Newton's 3rd law often applies to skydiving.
When gravity is not acting upon the skydivers they would continue moving in the direction the vehicle they jumped from was moving. If no air resistance takes place, then the skydivers would still accelerating at 9.8 m/s until they hit the ground.
The skydiver after leaving the aircraft will accelerates downwards due to the force of gravity usually as there is no air resistance acting in the upwards direction, and there is a resultant force acting downwards, the skydiver will accelerates towards the ground.
Therefore, The statement best applies Newton’s laws of motion to explain the skydiver’s motion an upward force balances the downward force of gravity on the skydiver. Thus, option A is correct.
Learn more about skydiver on:
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state three effects of malnutrition in farm animals
Answer:
Cows,Pigs,Chicken. They are always in farm
i) A 100 W and 60 W bulb are joined in series and connected to the mains. Which bulb
will glow brighter? Why?
ii) A 100 W and a 60 W bulb are joined in parallel to the mains. Which bulb will
glow brighter? Why?
Answer:
i) 60 W
ii) 100 W
Explanation:
In each case, the bulb that dissipates the most power is the bulb that glows brighter. Power is voltage times current (P = VI). Using Ohm's law, we can rewrite this as P = I²R or P = V²/R.
Bulbs are rated at a certain power for a certain voltage. P = V²/R, so the bulb with the lower resistance will have the higher power rating. Therefore, the 100 W bulb has a lower resistance than the 60 W bulb.
i) They are in series, so they have the same current. P = I²R, so the bulb with the higher resistance will glow brighter. That's the 60 W bulb.
ii) They are in parallel, so they have the same voltage. P = V²/R, so the bulb with the lower resistance will glow brighter. That's the 100 W bulb.
What is the equation for burning a fossil fuel
Answer:
Fuel + O2 → CO2 + H2O
Explanation:
To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from the pulley, to the velocity the stone would have if falling the same distance while unconnected to the pulley. What is the velocity of an untethered stone after falling 0.337 m from rest
Answer:
The velocity of the stone is 2.57 m/s.
Explanation:
Given that
Height = 0.337 m
We need to calculate the velocity of the stone
Using equation of motion
[tex]v^2-u^2=2gh[/tex]
Where, v = velocity of stone
u = initial velocity
g = acceleration due to gravity
h = height
Put the value into the formula
[tex]v^2-0=2\times9.8\times 0.337[/tex]
[tex]v=\sqrt{2\times9.8\times0.337}[/tex]
[tex]v=2.57\ m/s[/tex]
Hence, The velocity of the stone is 2.57 m/s.
Un pez llamado PARGO ROJO vive a grandes profundidades. Si se pesca, al salir a la superficie puede tomar el aspecto de la foto porque su vejiga natatoria aumenta de volumen al disminuir la presión. La ley que lo explica es...
Answer:
Hay diversas leyes que podemos usar acá.
Acá sabemos que la vejiga aumenta su tamaño al reducir la presión, esto tiene sentido, pues al haber menos presión, hay menos fuerza que comprime la vejiga, lo que le permite aumentar su volumen.
Acá tenemos una relación inversa de la forma: V = K/P
Una relación inversa donde la presión esta en el denominador y K es un termino que no depende ni del volumen ni de la presión.
Entonces, a medida que aumenta P, el denominador aumenta, por lo que el valor del volumen decrece.
Un ejemplo de una ecuación similar es la del gas ideal, por ejemplo, para un gas ideal dentro de un globo de volumen V para una dada presión P:
V = nRT/P
donde n es el numero de moles, R es la constante termodinámica y T es la temperatura, acá podemos ver que esta ecuación tiene la misma forma fundamental que la escrita arriba.
A control clinic offers a program that guarantees a weight loss of up to 0.46 kg in one week. Express the weight loss in a ratio of milligrams per second.
Answer:
0.76 mg/s
Explanation:
0.46 kg/week × (1 week / 7 days) × (1 day / 24 hrs) × (1 hr / 3600 s) × (1000 g/kg) × (1000 mg/g) = 0.76 mg/s
A physical inventory on December 31 shows 3500 units on hand. Bonita sells the units for $15 each. The company has an effective tax rate of 20%. Bonita uses the periodic inventory method. The weighted-average cost per unit is
What two factors determine how much potential energy an object has?
Answer:
The mass of the object and its height in the gravitational field of the Earth.
Explanation:
If we are talking about gravitational potential energy which is defined as:
[tex]U=m\,*\,g\,*\,h[/tex]
being "m" the object's mass, "g" the acceleration due to gravity, and "h" the height at which the object is located relative to the conventionally picked level for zero of potential energy.
As long as the value of "g" is constant, the only two variables that determine the gravitational potential energy are the mass (m) of the object and its relative height (h).
Answer:
The objects weight and height above Earth's surface
Explanation:
K12 :)
Question is on the picture. Answers: A. 0.1 J/g*C B. 0.2 J/g*C C. 0.4 J/g*C D. 4 J/g*C
Answer:
B. 0.2 J/g/°C
Explanation:
The solid phase is the first segment (from 0°C to 50°C).
q = mCΔT
200 J = (20 g) C (50°C)
C = 0.2 J/g/°C
a object 1.5cm high produces a real image 2cm high. placed at a distance of 20cm
from a concave mirror calculate: [a] the position of the image [b] focal lenght of the concave mirror
Answer:
a. 26.7 cm. b. 11.4 cm.
Explanation:
a. We know h'/h = d'/d where h' = image height = + 2 cm (since it is a real image), h = object height = + 1.5 cm, d' = image distance from mirror and d = object distance from mirror = 20 cm
So, from h'/h = d'/d
d = h'd/h
= 2 cm × 20 cm/1.5 cm
= 40/1.5 cm
= 26.67 cm
≅ 26.7 cm
The position of the image is 26.7 cm from the mirror
b. Using the mirror formula
1/d + 1/d' = 1/f where d = object distance from mirror = + 20 cm, d' = image distance from mirror = + 26.7 cm (its positive since its a real image) and f = focal length of mirror.
So, 1/d + 1/d' = 1/f
⇒ f = dd'/(d + d')
= 20 cm × 26.7 cm/(20 cm + 26.7 cm)
= 534/46.7
= 11.43 cm
≅ 11.4 cm
The focal length of the mirror is 11.4 cm
1. Determina el momento que produce una fuerza de 7 N tangente a una rueda de un metro de diámetro, sabiendo que el punto de aplicación es el mismo borde de dicha rueda provocando un impulso en el sentido de las agujas del reloj. Solución:
Answer:
τ= F r into the blade
Explanation:
The moment of a force is defined by
τ = F x r
where the bold indicates vectors
Let us write in the expression in magnitude
τ = F r sin θ
in our case the force is tangent to the wheel therefore the angle between F and the radius is 90º, and the sin 90 = 1
τ= F r
The direction of τ can be used by the rule of the right hand, the fingers curve in the direction of the torque when advancing from the force to the radius and the thumb points in the direction of the torque.
In this case, for a clockwise rotation, the fingers are curved in the direction and the thumb points into the blade, this is the direction of the τ.
TRASLATE
El momento de una fura es definido por
τ = F x r
donde la negrillas indican vectores
Escribamos en ta expresión en magnitud
τ = F r sin θ
en nuestro caso la fuerza es tangente a la rueda por lo tanto el angulo entre F y el radios es 90º, y el sin 90=1
τ = F r
la dirección de tau la podemos usar la regla de la mano derecha, los dedos curva en la dirección del torque al avanzar dese la fuerza al radio y el pulgar apunta en la dirección del torque.
En este caso para un giro en sentido horario los dedos se curvan ente sentido y el pulgar apunta hacia dentro de lla hoja, esta es la dirección del troque
Students are going to conduct an experiment to study the effect of a net force applied to an object on the object’s motion. In each trial of the experiment, the students will apply a net force on the object. They also need to take two other measurements. What are the other quantities they should measure in each trial of the experiment?(1 point) velocity and time mass and acceleration mass and velocity acceleration and time
Answer:
A. velocity and time
Explanation:
A force can be define as an agent which has the capacity to change the state of an object. It can either increase the velocity of a body, change its direction of motion or cause a moving object to come to rest.
From Newton's second law of motion;
F = ma
where F is the force on the object, m is the mass of the object and a is the acceleration of the object. The unit of force is kgm/[tex]s^{2}[/tex] or Newtons.
a = [tex]\frac{change in velocity}{change in time}[/tex]
In the given question, apart from the mass of the object which is constant, the students should take the measurements of the velocity and time in each trial so as to calculate the required acceleration.
Answer:
mass and acceleration!
Explanation:
Because i am in class just like you and got it wrong because i didn't choose my first answer:(
PLEASE ASAP! I SENT A PHOTO CHECK AND TELL!
Answer:
Answer B is the correct answer: "Motion of one projectile as seen from the other is a straight line."
Explanation:
Let's write the equations of motion for each projectile, using that projectile [tex]a[/tex] is launched with velocity [tex]a[/tex] which has components associated with the angle of launching, given in x and y coordinates as: [tex]a_x\,\,and\,\,a_y[/tex].
Similarly, assume that projectile b is launched with velocity [tex]b[/tex] with components due to the launching angle = [tex]b_x\,\,and \,\,b_y[/tex]
then the equations of motion for the two projectiles launched at the same time (t) from the same spot (position that we assume to be at the origin of coordinates to simplify formulas) are:
[tex]x_a=a_x\,t\\y_a= a_y\,t-\frac{1}{2} g\,t^2\\and\\x_b=b_x\,t\\y_b= b_y\,t-\frac{1}{2} g\,t^2[/tex]
therefore, from the frame of reference of projectile "b", the x and y position of projectile "[tex]a[/tex]" would be:
[tex]x_{a\,b}= x_a-x_b= a_x\,t-b_x\,t=(a_x-b_x)\,t[/tex] which is linear in "t"
[tex]y_{a\,\,b}=y_a-y_b= a_y\,t-\frac{1}{2} g\,t^2-\left[ b_y\,t-\frac{1}{2} g\,t^2\right]=(a_y-b_y)\,t[/tex] which is also linear in t.
Therefore the motion of one projectile with reference to the other is a straight line (answer B)
Notice as well that this two projectiles cannot collide because they have been launched together, and supposedly at different speeds and angles. The only way that they can share the same x-coordinate and the same y-coordinate at the same time "t" is if their velocity components are equal, which is not what we are told.
[tex]x_a=x_b\\a_x\,t= b_x\,t\\and\\y_a= y_b\\a_y\,t-\frac{1}{2} g\,t^2= b_y\,t-\frac{1}{2} g\,t^2\\a_y\,t=b_y\,t\\a_y=b_y[/tex]
Astronomers were at first surprised to find complicated molecules in the interstellar medium. They thought ultra-violet light from stars would break apart such molecules. What protects the molecules we observe from being broken apart
Answer:
The dust present in the clouds.
Explanation:
The complicated composition molecules that can be found in space are generally associated with clouds of dust. The significant amount of dust in these clouds provides protection not only for these molecules, but for any body that makes up or is associated with dust clouds.
It is exactly this dust that protects the molecules against the action of ultraviolet rays.
If we removed the producers from this food web, how would it affect the balance of the ecosystem?
In a food web, the removal of any trophic level upsets the balance within the web and can cause its eventual collapse. Because producers capture solar energy and convert it to food energy, their loss would affect every other level of the food web.
Explanation:The removal of the producers would cause the collapse of the entire food web. Primary consumers or herbivores, which feed on producers directly, would die off. The next to be affected would be the secondary consumers or carnivores that eat the primary consumers. Higher level consumers would suffer as organisms from lower trophic levels start to die off. Decomposers would break down the bodies of dead organisms, returning their basic elements and compounds to the environment. However, even these dead organisms would run out and the entire food web would collapse.
Hope you like the answer.
numeria
problems
lifted
Joy
1
لوووو
G. Solue the
following
A load
800 Nis
effort
If
the load is
laced at
a distance
Lo cun from
achat will be the
effort distance ?
Solher load ( l = 8oon
Effort
(e) = 200N
the fularum,
Answer:
[tex] \boxed{40 \: cm}[/tex]Explanation:
Load ( L ) = 800 N
Effort ( E ) = 200 N
Load distance ( LD ) = 10 cm
Effort distance ( ED ) = ?
now, Let's find the effort distance:
[tex] \mathsf{L \times LD = E \times ED}[/tex]
Plug the values
[tex] \mathsf{800 \times 10 = 200 \times ED}[/tex]
Multiply the numbers
[tex] \mathsf{8000 = 200 \: ED}[/tex]
Swipe the sides of the equation
[tex] \mathsf{200 \: ED = 8000}[/tex]
Divide both sides of the equation by 200
[tex] \mathsf{ \frac{200 \: ED }{200} = \frac{8000}{200} }[/tex]
Calculate
[tex] \mathsf{ED \: = \: 40 \: cm}[/tex]
Hope I helped!
Best regards!
The quantum state of a particle can be specified by giving a complete set of quantum numbers (n,l, ml,ms). How many different quantum states are possible if the principal quantum number is n=3?
Explanation:
We need to find the quantum state of a particle can be specified by giving a complete set of quantum numbers (n,l, ml,ms).
We have the principal quantum number, n = 3
The value of l = n-1
l = 0,1,2,3
The value of [tex]m_l[/tex]
[tex]m_l=-l\ \text{to}\ +l\\\\m_l=-3,-2,-1,0,1,2,3[/tex]
The value of [tex]m_s[/tex]
[tex]m_s=\dfrac{-1}{2},\dfrac{+1}{2}[/tex]
Hence, this is the required solution.
A man of mass 75kg stands on a weighing machine in a lift. Determine the reading of the weighing machine when the lift is moving: 1. Upwards with an acceleration of 2m/s² 2. Downwards with a constant velocity of 1.5m/s 3. Downwards with an acceleration of 2.5m/s²
Explanation:
Given that,
Mass of a man, m = 75 kg
(1) We need to find the reading of the weighing machine when the lift is moving upwards with an acceleration of 2 m/s². When the lift is moving upward, reading of the weighing machine is given by :
R = m(g+a)
R = 75 (9.8+2)
R = 885 N
(2) When the lift is moving downwards with a constant velocity of 1.5m/s. It means that the lift is at rest. So, the reading is :
R = mg
R = 75 (9.8)
R = 735 N
(3) When the lift is moving downwards with an acceleration of 2.5 m/s². In this case,
R = m(g-a)
R = 75 (9.8-2.5)
R = 547.5 N
Hence, this is the required solution.
Gravity is affected by the ?
Answer:
Mass and distance
Explanation:
The force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases. Hence, answer is mass and distance
we hammer the broader side of a nail and not its sharp end to put it in wood .why ?
Explanation:
We hammer the broader side of a nail instead of its sharp end to put it in wood. It is a concept based on the pressure exerted.
The force acting per unit area of an object is called pressure exerted. It means that pressure is inversely proportional to the area of cross section i.e. area increases, pressure decreases and vice versa.
The broader side of a nail has more area as compared to the sharp end. It means that the broader side will exert less pressure on them which make it easier for us to fix it into the wood.
An atom of unknown element Z has mass number of 39 and an atomic number of 18. How many protons and how many neutrons are in this atom? Show your work
Answer:
proton:18
neutron:39-18=21
If a body is moving in the horizontal axis with a velocity Vx= 6m/s and in the vertical axis Vy=8m/s What is the angle Theta above the horizontal axis of the velocity of the body V? A. Theta = 45.0 degrees B.Theta = 63.3 degrees C. Theta = 53.1 degrees D. Theta = 43.7 degrees
Answer: C
Explanation: It's a lot of math.
The option that gives the correct value for the angle theta above the horizontal axis of the velocity of the body, v is option C.
C. 53.1°
The given parameters are;
The velocity of the body relative to the horizontal axis, vₓ = 6 m/s
The velocity of the body relative to the vertical axis, [tex]v_y[/tex] = 8 m/s
Required;
The measure of the angle theta above above the horizontal axis of the velocity of the body, v
Solution:
The velocity of the body can be represented vectorially as follows;
v = 6·i + 8·j
The vectoral form gives the legs of the right triangle that has the magnitude and direction as the hypotenuse side
Therefore;
[tex]\theta = arctan \left(\dfrac{8}{6} \right) \approx \underline{53.1^{\circ}}[/tex]
Learn more about the vectors here:
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in this system, potential and kinetic energy are ____ proportional.
Answer:
Inversely proportional
Explanation:
P.E ∞ h
K.E ∞ v
v ∞ 1/h
Therefore
K.E ∞ 1/h
Then
P.E ∞ 1/(K.E)
Answer:
Inversely
Explanation:
If the boy on the bicycle in the preceding problem accelerates from rest to a speed of 10.0 m/s in 10.0 s, the angular acceleration of the tires is:_______
Answer:
The angular acceleration is 3.33 rad/s²
Explanation:
Here is the preceding problem as well as the given problem:
A boy rides his bicycle 2.00 km. The wheels have radius 30.0 cm. What is the total angle the tires rotate through during his trip?
21.
If the boy on the bicycle in the preceding problem accelerates from rest to a speed of 10.0 m/s in 10.0 s, what is the angular acceleration of the tires?
Explanation:
To determine the angular acceleration, we will first find the linear accelerationFrom one of the equations of kinematics for linear motion
v = u + at
Where v is the final speed
u is the initial speed
a is the linear acceleration
and t is time
From the question, the boy starts from rest, hence,
u = 0.0 m/s
v = 10.0 m/s
t = 10.0 s
a = ??
From, v = u + at
a = [tex]\frac{ v - u}{t}[/tex]
a = [tex]\frac{10 - 0}{10}[/tex]
a = 1 m/s²
Now, for the angular acceleration, [tex]\alpha[/tex]
The relationship between linear acceleration, a and angular acceleration, [tex]\alpha[/tex] is
a = [tex]\alpha[/tex]r
where r is radius
From the previous question, r = 30.0cm = 0.3m
From the equation, a = [tex]\alpha[/tex]r
[tex]\alpha[/tex] = a / r
[tex]\alpha[/tex] = 1 / 0.3
[tex]\alpha[/tex] = 3.33 rad/s²
( TRUE false )
1.)manuals are the organic matter.
2.)combine is used for sowing the seeds.
3.) the first agricultural task is sowing of seeds.
4.) many plants are first grown in Kinder Gardens and then sown in fields.
5.) earthworm are farmer friendly.
6.)substance that kills
pests are called weedicides.
7.) animals which provide us both egg and flesh are called milch animals.
8.) Grains should be dried in Sun before storage.
9.)wheat,gram,barley,potato, are kharif crops.
10.) the crops on in June /July and harvested in September/ October are called rabi crops.
plz answerzz fast
Answer:
number 6 is wrong
the answer is pesticides
2.combines are used for harvesting or threshing.so number 2 is wrong
at least you tried
Explanation:
there is no such thing as weedicides
Answer:
1. True
2.True
3.False
4. True
5. True
6.False
7.False
8.True
9.False
10.False
