which researcher discovered the principles of classical conditioning?

Answer:

The correct answer is "glass".

Explanation:

A room with a smooth and hard surface like the glass is likely to produce an echo because when sound waves hit such surfaces, they bounce back and forth, creating echoes. Soft and porous materials like carpet, dirt, or foam absorb sound waves, reducing the reflection and producing less echo. Therefore, the answer is glass.

All but  option A: the plant is exposed to light condition must be present for the Calvin cycle reactions to occur.

The Calvin cycle is the biochemical process that takes place in the chloroplasts of plants, in which carbon dioxide is fixed into glucose molecules. This process involves several enzymes and molecules, but the energy needed to power the process comes from ATP and NADPH, which are produced during the light-dependent reactions that take place in the thylakoid membranes of the chloroplasts.

Therefore, light is required for the Calvin cycle to occur since it is the source of the energy that drives the reaction. However, all parts of the plant do not need to be exposed to light for the Calvin cycle to occur. Only the chloroplasts, which are found in the mesophyll cells of the plant, need to be exposed to light for photosynthesis to occur.

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See full question below

all but which condition must be present for the calvin cycle reactions to occur?

The plant is exposed to light

water is not involved in any of the reactions

light energy is converted into chemical energy

provide the electrons needed to reduce NADP

The sample size with some specified width error by reducing the confidence level to 80% is 3 times the original sample size and the width error which have been scaled in size compared to the original width error is by a factor of 10.

When reducing the confidence level to 80% and the original width (error) E by a third, the new sample size will be 3 times the original size. To calculate this, use the formula n = (zα/2 / E)² × σ2.

If the original confidence level was 95%, then the original zα/2 = 1.96. If the new confidence level is 80%, then the new zα/2 = 1.282.

The original error was E, and the new error is 1/3 E. By substituting these values into the formula, we get n = (1.282 / (1/3 E))² × σ2. This simplifies to n = 3 × (1.96 / E)² × σ2, which is 3 times the original sample size.

If the original confidence level was 95%, then the original zα/2 = 1.96.

If the new confidence level is 85%, then the new zα/2 = 1.44.

The original error was E, and the new error is 10E.

By substituting these values into the formula, we get n = (1.44 / (10E))² × σ2.

This simplifies to n = (1.96 / E)² × σ2, which is 10 times the original sample size.

Therefore, the width (error) will have scaled in size by a factor of 10 compared to the original width (error) E.

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We cannot determine the value of interference with the given information.

The interference can be determined using the following formula:

interference = (observed double crossover rate - expected double crossover rate) ÷ (1 - expected double crossover rate).

The expected double crossover rate can be calculated using the formula:

expected double crossover rate = (distance AB × distance BC) ÷ total distance (AB + BC + AC).

Given:

Distance between A and B is 10mu;

Distance between B and C is 15mu;

Observed double crossover rate is 0.25%.

Therefore,

Distance AB = 10mu;

Distance BC = 15mu;

Total distance = AB + BC + AC

Expected double crossover rate = (10 × 15) ÷ (10 + 15 + AC)

expected double crossover rate = 150 ÷ (AC + 25)

The observed double crossover rate is 0.25%.

Therefore, the observed double crossover rate = 0.25% = 0.0025.

Interference = (observed double crossover rate - expected double crossover rate) ÷ (1 - expected double crossover rate)=

[0.0025 - (150 / (AC + 25))] ÷ [1 - (150 / (AC + 25))]

what is the interference if: distance between a and b is 10mu distance between b and c is 15mu observed double crossover rate is: 0.25%

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Galileo famously observed that objects of different masses fall to Earth at the same rate, regardless of their mass. This observation led him to conclude that gravity was a universal force of attraction between any two objects with mass.

Galileo Galilei was an Italian astronomer, physicist, and mathematician who contributed greatly to the development of modern science. His contributions to physics include the creation of the scientific method and his work on the principles of motion and gravity.

Galileo was one of the first scientists to study gravity. He observed that objects of different weights would fall at the same rate when dropped from the same height. This led him to conclude that gravity is a constant force that acts upon all objects equally, regardless of their weight or composition.

Galileo's work on gravity laid the foundation for the later development of Sir Isaac Newton's theory of gravity. Newton built on Galileo's findings and formulated the law of universal gravitation, which states that every object in the universe attracts every other object with a force that is proportional to their masses and inversely proportional to the square of the distance between them.

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Potential Energy of Object W, X, Y and Z are 0 J, 7.84 J, 15.7J and 23.5J, for better understand we have to know the meaning of potential energy.

Potential energy in physics is the energy that an item retains as a result of its location in relation to other objects, internal tensions, electric charge, or other elements. Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.

Potential Energy of an Object = m * g * h

Where, m = mass,

g = gravity, and

h = height

Potential Energy of Object W = 2 * 9.8 * 0

= 0 J

Potential Energy of Object X = 2 * 9.8 * 0.4

= 7.84 J

Potential Energy of Object Y = 2 * 9.8 * 0.8

= 15.68 J

≈ 15.7 J

Potential Energy of Object Z = 2 * 9.8 * 1.2

= 23.5 J

Therefore, Potential Energy of Object W, X, Y and Z are 0 J, 7.84 J, 15.7 J and 23.5 J.

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When 872.0 kJ of thermal energy are injected, the temperature of the 25 kg of water in the car's cooling system changes by 35.0 degrees Celsius.

Water's specific heat capacity (J/(gK), or 4,180 J/ (kgK). Thus, we can use the following formula to get the temperature change:

Q = mcΔT

where Q is the extra thermal energy (872 000 J), m the water mass (25 kg), c the water's specific heat capacity (4,180 J/(kg*K)), and T the temperature change.

When we solve for T, we get:

The equation T = Q/(mc) Equals 872,000 J/(25 kg * 4,180 J/(kgK)) = 35.0 °C.

When 872.0 kJ of thermal energy are injected, the temperature of the 25 kg of water in the car's cooling system changes by 35.0 degrees Celsius.

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When a star depletes its core supply of hydrogen and enters the red giant stage, helium dominates in the core, and hydrogen dominates in the atmosphere.

Let's discuss this in detail. Star depletes its core supply of hydrogenWhen a star exhausts its core supply of hydrogen, it begins to convert helium into carbon and oxygen in its core. This process leads to the formation of a heavier core which contracts and increases in temperature. As a result, the temperature of the core increases to the point where it can initiate helium fusion, producing carbon and oxygen. At the same time, the outer shell of the star cools and expands. Dominates in the core and dominates in the atmosphere in the core of a red giant star, helium dominates since this is where helium fusion occurs. The star's atmosphere is, on the other hand, dominated by hydrogen because it is cooler and less dense than the core. The helium-burning phase is shorter than the hydrogen-burning phase in a star's life cycle. When a star enters the red giant phase, it indicates that the core of the star has depleted its hydrogen and is now converting helium to heavier elements. This stage will not last long as the core will continue to contract and heat up, resulting in the production of heavier elements.

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The volume of the solid obtained by rotating the region in the first quadrant bounded by the curves x = 0, y = 1, x = y^7 about the line y = 1 is 0.

To determine the volume of the solid obtained by rotating the region in the first quadrant bounded by the curves x = 0, y = 1, x = y^7 about the line y = 1, we need to use a specific integral formula.

The volume of the solid is calculated by multiplying the area of the cross-section of the solid, which is perpendicular to the axis of rotation, with the distance traveled by the center of mass of the cross-section. And, when this product is summed up across the length of the solid, we get the volume of the solid.

To solve the given problem, the area of the cross-section of the solid is [tex]\pi (r)^2[/tex], where r is the distance from the line y = 1 to the curve [tex]x = y^7[/tex]. Since the cross-section is a circle, we know the area of the cross-section can be represented by the equation of a circle with radius r, which is [tex]\pi (r)^2[/tex].

To find the value of r, we will equate  [tex]x = y^7[/tex] to the line y = 1. By solving for y, we get: [tex]y = 1^{1/7} = 1[/tex].

Hence, r = 1 - 1 = 0.

We can now compute the volume of the solid using the integral formula:

[tex]V =\int_0^1 \pi (r)^2 dy\\V = \int_0^1 \pi (0)^2 dy\\V = \int_0^1 0 dy\\V = 0[/tex]

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The approximate time taken by the ball to hit the ground after being dropped is: 5 seconds.

The velocity at which the ball hits the ground is approximately 49.05 m/s, and it moves in the downward direction (negative velocity).

A ball is dropped from rest from a tower and strikes the ground 122.5 m below.

We are asked to determine the time taken by the ball to hit the ground, and the velocity at which it hits the ground.

The formula to calculate the time taken by an object to fall from rest from a height h is given by: t = sqrt (2h/g)

Here, h = 122.5m; g = 9.81m/s² (acceleration due to gravity)

Using the given formula, t = sqrt (2h/g) = sqrt (2 × 122.5 / 9.81)≈ 5 seconds

We know that, `v = g.t`

Since the ball was dropped from rest, its initial velocity is 0.

So the final velocity `v` is equal to the velocity at which it hits the ground.

Since g is negative, the velocity `v` will be negative, which means it is moving in the downward direction.

Using `g = 9.81 m/s²`,`t = 5 seconds`, we have = g.t = 9.81 × 5 = 49.05 m/s

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A baseball is hit almost straight up into the air with a speed, the greater the ball's potential energy will be upon launch, resulting in a greater maximum height.

(a) The time it takes to reach the maximum height. (b) The duration of the flight can be calculated using the following formula:(c) The launch angle, initial speed, and launch height are all variables that influence how high and far the ball flies. The higher the launch angle, the higher the ball's height; the higher the initial velocity, the higher and farther the ball will travel; and the greater the launch height, the greater the ball's potential energy will be upon launch, resulting in a greater maximum height.

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The statement the construction of psychological profiles is a process of mapping the characteristics of offenders of previously solved crimes and applying them to offenders of unsolved ones is TRUE.

Psychological profiling is a technique used by law enforcement agencies to identify the characteristics of an offender based on their behavior patterns, motives, and other psychological traits. It is a process of creating a psychological profile of an offender by analyzing the crime scene, victimology, and other evidence related to the crime.

This profile is then compared with the profiles of previously solved crimes to identify potential suspects or patterns that can be used to solve unsolved crimes. The process involves mapping the characteristics of offenders of previously solved crimes and applying them to offenders of unsolved ones.

The psychological profile is based on the assumption that an offender's behavior is consistent across different crimes and that it reflects their personality traits and motivations. This technique has been used successfully in many high-profile cases and has helped law enforcement agencies to identify and apprehend serial offenders.

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Answer:

Explanation:

a) The mass of the cube can be calculated using the equation Mass = Volume x Density. The volume of the cube can be calculated as (5.00×10 cm)^3 = 125 cm³. Substituting this volume into the equation gives Mass = 125 cm³ x 7.86 g/cm³ = 983.5 g.

b) The number of iron atoms in the cube can be calculated using Avogadro's number (6.02 x 10^23 atoms/mol). The number of moles can be calculated using the molar mass of iron, 55.9 g/mol. Thus, the number of moles can be calculated as 983.5 g / 55.9 g/mol = 17.61 moles. Multiplying this by Avogadro's number gives the number of iron atoms in the cube as 1.07 x 10^24 atoms.

The final velocity of the plane after a missile of mass 1.20 102 kg is fired from the plane  is 0.255 m/s.

To find the final velocity of the plane when a missile of mass 1.20 x 10² kg is fired from a plane of mass 4.80 x 10³ kg initially moving at a speed of 3.25 x 10² m/s, and the speed of the missile relative to the plane is 1.06 x 10³ m/s, we can use the conservation of momentum.The initial momentum of the system is given by:

m1v1 + m2v2 = (m1 + m2)vf

where m1 = mass of missile, m2 = mass of the plane, v1 = velocity of the missile, v2 = velocity of the plane, and vf = final velocity of the system

Substituting the given values, we get:(1.20 x 10² kg) (1.06 x 10³ m/s) + (4.80 x 10³ kg) (3.25 x 10² m/s) = (1.20 x 10² kg + 4.80 x 10³ kg) vf

Simplifying, we get:1284 = (5.04 x 10³ kg) vf

Therefore, vf = 1284 / (5.04 x 10³ kg) = 0.255 m/s. So, the final velocity of the plane is 0.255 m/s.

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The range of frequencies on the electromagnetic spectrum is known as the electromagnetic spectrum.

The spectrum ranges from radio waves, microwaves, infrared waves, visible light, ultraviolet rays, x-rays, and gamma rays. Each type of wave has a specific frequency range, ranging from hertz (Hz) to exahertz (EHz). The lowest frequency waves, such as radio waves, range from 3 kHz to 300 GHz, while the highest frequency waves, such as gamma rays, range from 300 GHz to 3 EHz.
The electromagnetic spectrum is divided into several sections, including radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, x-rays, and gamma rays. Each type of wave has its own properties and uses in different applications. Radio waves are used for communication, microwaves are used in satellite communication and imaging, infrared radiation is used in medical imaging, visible light is used to see our environment, ultraviolet radiation is used in sun protection and sterilization, x-rays are used in medical imaging and treatment, and gamma rays are used in medical treatment and research.

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The major types of stress are shear, Tension, and Compression. Therefore option D is correct.

Stress refers to the internal forces acting on a material, causing it to deform or change shape. Different types of stress can act on a material, and they are characterized by the way in which the forces are applied.

1. Shear stress: Shear stress occurs when two forces act parallel to each other but in opposite directions, causing the material to deform by sliding or shearing.

2. Tension stress: Tension stress occurs when forces are applied to pull a material apart. It leads to elongation or stretching of the material.

3. Compression stress: Compression stress occurs when forces are applied to squeeze or compress a material.

Therefore, the correct answer is D. Shear, Tension, and Compression, as these three options represent distinct types of stress commonly encountered in materials and structures.

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The major types of stress are Shear, Tension and Compression.  The correct option is D.

Thus, Shear stress, tension stress, and compression stress are the three main forms of stress.

Shear stress is a condition when forces acting in opposite directions and parallel to a surface cause the material to deform by sliding or shearing. It is connected to the propensity for one layer of material to slide or move in relation to another layer.

Tension stress, sometimes referred to as tensile stress, is the strain that develops when a material is subjected to pulling or stretching forces that are applied in opposition to one another, causing the material to elongate. The material tends to be pulled apart by tension stress.

Thus, The major types of stress are Shear, Tension and Compression.  The correct option is D.  

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In the context of the motor control process related to the speed-accuracy trade-off, the initiation phase of movement includes the beginning of limb movement in the direction of a target.

Motor control is the ability to regulate and coordinate motor skills to achieve a desired outcome. The central nervous system (CNS) is in charge of regulating these skills. The CNS is divided into two parts: the peripheral nervous system (PNS) and the central nervous system (CNS). Motor skills are regulated by both parts of the nervous system. The CNS, on the other hand, is more involved in higher-level motor control.

A motor control system can be divided into three stages: planning, initiation, and execution. When the central nervous system processes the desired movement, it activates the motor program in the initiation stage, which produces the motor command sent to the muscles. Movement is initiated by the initiation stage. Following that, the movement is executed to meet the task's requirements. The motor program adjusts movement by making corrections based on previous trials and feedback. Therefore, the initiation phase is critical in the context of the motor control process related to the speed-accuracy trade-off.

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Coordinate , A - the height of the stone when it hits the water. A slingshot sends a stone vertically upward from a height of 20 feet above a pool of water.

The coordinate A represents the height of the stone when it hits the water. When the stone hits the water, its height above the water surface is zero.

So, we can set the expression for the stone's height equal to zero and solve for t to find the time when the stone hits the water. The height of the stone when it is launched is given as 20 feet, which is a fixed value in this problem.

The time when the stone is launched is also a fixed value, which is zero. The maximum height of the stone is the highest point the stone reaches above its initial height of 20 feet. The time when the stone reaches its maximum height is the time at which the vertical velocity of the stone becomes zero.

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The fluid force on one side of the 5ft by 5ft plate lying flat on its 5ft by 5ft face, we can use the equation F = ρghA and the F = 1,945,000 N.

Since the plate is at the bottom of the pool and the pool is filled with water to a depth of 8ft, h = 8ft and the area of the plate A = 5ft × 5ft = 25ft².

There F is the fluid force, ρ is the density of the fluid, g is the acceleration due to gravity, h is the depth of the fluid, and A is the area of the plate.

Therefore, the fluid force on one side of the plate is:

F = ρghA = 1000kg/m³ × 9.81m/s² × 8ft × 25ft² = 1,945,000 N.

To calculate the fluid force on one side of the plate resting vertically on a 5 ft edge, we can use the same equation as above but with an area equal to the length of the plate multiplied by the depth of the pool (8ft):

F = ρghA = 1000kg/m³ × 9.81m/s² × 8ft × 5ft = 392,000 N.

To calculate the fluid force on one side of the plate resting on a 5ft edge and tilted at 45 degrees to the bottom of the pool, we can use the same equation as above but with an area equal to the length of the plate multiplied by the depth of the pool multiplied by the cosine of the angle of the plate:

F = ρghA = 1000kg/m³ × 9.81m/s² × 8ft × 5ft × cos(45) = 283,200 N.

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Because we measured the altitude from the Earth's centre, which is below the surface, the outcome is negative. As a result, the observatory is located 6.37 km below sea level.

Most importantly, placing an observatory on a mountainside means that there is less air to look through, improving the quality of the "seeing". Moreover, there is less air above you on a mountainside to absorb starlight.

The following is the equation for gravitational acceleration at a distance from the Earth's centre:

g = G M / r²

Given that the observatory is located r kilometres above the Earth's surface, we have:

g = G M / (r + Rearth)²

where Rearth is the Earth's radius. The observatory's altitude, h, can be calculated using the following formula:

gsealevel - g = 0.0055 m/s²

G M / (r + Rearth)² - G M / Rearth² = 0.0055 m/s²

G M (1/Rearth² - 1/(r + Rearth)²) = 0.0055 m/s²

r + Rearth = sqrt(G M / (0.0055 m/s² Rearth²) + Rearth²)

r = sqrt(G M / (0.0055 m/s² Rearth²) + Rearth²) - Rearth

Plugging in the values for G, M, and Rearth, we get:

r = sqrt((6.6743 × 10⁻¹¹ m³ kg⁻¹ s⁻²) × (5.9722 × 10²⁴ kg) / (0.0055 m/s² × (6.37 × 10⁶ m)²) + (6.37 × 10⁶ m)) - 6.37 × 10⁶ m

r = 2859.9 m

Therefore, the altitude of the observatory is:

h = r - Rearth = 2859.9 m - 6.37 × 10⁶ m = -6.37 × 10⁶ m + 2859.9 m

h = -6.367 × 10⁶ m

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Hominin remains have been found at sites throughout Africa, Europe, and Asia. Below are five of these fossil sites and their main finds. The correct order of the given hominin fossil sites from oldest to youngest is Omo kibish, Klasies river, Herto, and Tianyuan cave.

Omo kibish is incomplete fossil skull (oldest)The oldest fossil site on the list is Omo kibish in Ethiopia, which is dated to around 195,000 years ago. The site has a partial skull, lower jawbone, and a few other fragments of the skull. Klasies river is fragmentary hominin remains Klasies river Mouth in South Africa is dated back to around 120,000 years ago. The site contains human fossils along with the remains of other animals.

Herto is a skull intermediate between H. heidelbergensis and modern H. sapiens, Herto Bouri in Ethiopia, dated to around 160,000 years ago. The site contains 3 complete hominid skulls which were much more modern than expected for their age. The skulls were similar to Homo sapiens, but with some differences. Tianyuan cave is modern human maniple and femur (youngest). Tianyuan cave in China, dated to around 40,000 years ago, contains one of the earliest modern human fossils. A complete set of human teeth and bones from a foot, leg, and hand were found at this site.

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The average arterial pressure in your hands when they are held at your side is 47.5 mmHg.

The average arterial pressure in your hands when they are held at your side can be determined using the hydrostatic pressure formula, which is a function of height, gravity, and density. When the hands are held at the side, they are 60 cm below the heart, which means they are at a distance of 0.6 m.

The hydrostatic pressure formula is given by

P = ρgh

Where,

P is the pressure, ρ is the density, g is the acceleration due to gravity, and h is the height. We can assume that the density of blood is constant, and we can take the value of g to be 9.81 m/s², the standard acceleration due to gravity.

Therefore, the pressure at the heart is 100 mmHg, or 100/760 = 0.131 atm. The pressure in the hands can be calculated as follows:

P = ρghP = (1.06 × 10³ kg/m³) × (9.81 m/s²) × (0.6 m)

P = 6.26 × 10³ N/m²

P = 6.26 × 10³ Pa

P = 47.5 mmHg

Therefore, the average arterial pressure in the hands when they are held at the side is 47.5 mmHg.

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The fluid movement in a lava lamp is caused by the heat generated from the lamp's light bulb, which causes the wax or oil to rise and fall.

A lava lamp contains two fluids of different densities that do not mix. The fluids heat up as a result of the lamp's light bulb, causing them to expand and become less dense. The wax or oil floats up when it becomes less dense than the fluid that surrounds it, creating a globe at the top of the lamp.

The fluid is then cooled by the environment and becomes more dense, causing the wax to sink back to the bottom. This constant motion cycle creates the flowing effect seen in a lava lamp.

The heat from the light bulb causes the fluid to expand, and as it does, it becomes less dense than the surrounding fluid, causing it to float. When the fluid cools, it becomes denser and settles back down to the bottom. This cyclic motion creates the soothing flow of a lava lamp.

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Answer:

Light energy

Explanation:

When an electron releases or absorbs energy, it goes into an "exited state" which means it goes into a lower or higher energy level respectively. This will radiate light energy.

One of the methods which will not reduce reactivity of observation is telling the person you are observing his/her behaviour. Correct option is B.

A practical, utilitarian approach, behavioral observation focuses on the plainly discernible ways in which the client engages with his or her surroundings. Behavioural observation can be used as a standalone technique or casually as a component of an interview, a test, or both.

Waiting until the subjects of the observation are used to the observer is one method to reduce reactivity. Another option is to have the observer document the actions without the subjects being aware of the observation.

The act of observation modifies in some manner the situation in which a participant is being observed. Within an experimental setting, reactivity is viewed as a threat to internal validity because the change in behaviour is not due to the experimental manipulation. Best choice is B.

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If stars A and B are both main-sequence stars and star A has a greater fusion rate than star B, the following statements hold:

A. Star A must be more luminous than star B.

C. Star A must be more massive than star B.

This is due to the direct relationship between a main-sequence star's brightness and mass and the rate of fusion in that star. A higher fusion rate, therefore, suggests a higher brightness and mass.

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Yes, it is possible for an object to be moving with a constant velocity even when force is exerted on the object. When an object is in a state of rest, a force is required to move it from that position.

Newton’s second law states that the acceleration of an object is directly proportional to the force exerted on it and inversely proportional to its mass. Thus, a larger force results in a greater acceleration of the object. If there is no force applied to the object, the object will remain stationary or move at a constant velocity.

However, if there is a force applied to the object, it will accelerate. If the force applied is balanced by an equal and opposite force, the object will continue to move with a constant velocity. An object in motion is said to be in equilibrium when the net force acting on the object is zero. When the net force acting on an object is zero, it moves at a constant velocity. Therefore, if a force is exerted on an object, it is possible for the object to be moving with a constant velocity if the forces are balanced.

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The factor that does not determine how much gravitational potential energy is in an object-earth system is the object's mass.

An object-earth system is a system in which an object interacts with the earth by exerting a force of attraction. The object's energy is derived from the work done by gravitational forces when the object is moved away from the earth's surface.

An object in an object-earth system's gravitational potential energy is the work done by gravitational forces on the object when it is moved from a lower position to a higher one in the object-earth system. The factor that does not determine how much gravitational potential energy is in an object-earth system is the object's mass. The gravitational potential energy of an object in the earth-object system is determined by the distance between the object and the earth's surface. The gravitational potential energy of an object increases as the distance between it and the earth's surface increases.

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a)  The net Work done is zero. b) The work done on the block by the applied force F as the block moves a distance L is -41.2 J. c) The work done on the block by the applied force F as the block moves a distance L is 41.2 J.

Given:

Weight of the block (w) = 25.0 N

Distance moved by the block (d) = 3.40 m

The angle of the inclined plane (θ) = 29.0°

a) we know that from the work-energy theorem,

W = change in kinetic energy

But since speed is constant which means no change in KE, hence the net Work done is zero.

b) W = -mgy

W = -25 × (3.10 × sin29°)

W = -41.2 J

Therefore, the work done on the block by the force of gravity is -41.2 J.

c) The work done on the block by the applied force F as the block moves a distance L = 3.10m up the incline is,

W = Fd

W = 12.1 × 3.1

W = 41.2 J

Therefore, the work done on the block by the applied force F as the block moves a distance L is 41.2 J.

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