Find the length of the third side. If necessary, round to the nearest tenth. 16 12
Answer:
20
Step-by-step explanation:
Use the Pythagorean theorem. a^2+b^2=c^2
12^2+16^2=c^2
144+256=c^2
400=c^2
20=c
Hi can someone help me with these 3 questions. Thanks :)
Answer:
a) 45° cause tan = sin/cos and sin 45 and cos 45 both give square root 2/2
b) 120°
c) sin = -1/2 = -30° or 330° both are same
Use the trig circle which i have included in the answer to better understand trig angles
hope that answers your question
I want to let you know that each angle has sets of coordinates the left number is cos and right is sin. Ex) sin of 30 is 1/2 and cos of 30 is square root 3/2 In case you dont fully understand dont hesitate to comment.
good luck!!
Can someone please help me with writing a flowchart proof?
The two triangles are equivalent triangles
Flowchart proofs are organized with boxes and arrows.
The statements given are written in the box and the reason of that statement is written just below the box.
Every statement if flowchart proof complements other statement.
The correct answer is
∠AZ = ∠BX
The two triangles are equivalent triangles.
Learn more at https://brainly.com/question/24319270
What type of angle is angle R?
A. obtuse
B. right
C. straight
D. acute
Answer:
A. Obtuse
Step-by-step explanation:
Angle R is greater than 90°.
Answer:
Obtuse
Step-by-step explanation:
We know this because the angle is larger than 90 degrees which is also known as an obtuse :)
Instructions: Find the missing side. Round your answer to the nearest tenth
Answer:
x≈64.3
Step-by-step explanation:
since we already know the measures of 2 of the 3 angles in the triangle, we can find the 3rd angle:
180°-90°-25°=65°
now, we can use the law of sines to find the missing side:
sin25°/30=sin65°/x
x sin25°=30sin65°
x=(30sin65°/sin25°)
x≈64.33520762
rounded to the nearest 10th:
x≈64.3
help me I’m bad with this stuff
Answer:
(4x10^1)(2x10^4)
=40^1 × 20^4
=800^5
Answer:
8 x 10^5
Step-by-step explanation:
We can start by grouping the powers of ten together and the other numbers together, as you can move numbers around when multiplying:
4 x 2 x 10^1 x 10^4
4 multiplied by 2 is 8, so we can put that in:
8 x 10^1 x 10^4
Next, using the product rule, 10^1 x 10^4 would be ten to the power of the sum of the two exponents, or 10^(4 + 1), which is 10^5.
We will be left with
8 x 10^5
This is in scientific notation, so no further modification is needed.
Un grupo de estudiantes se junta a celebrar el termino del semestre, para lo que acuerdan preoarar un curanto. Reunen todos los ingredientes y los ponen en una olla y le aplican fuego hasta que esta alcanza una temperatura de 175°C. En este momento retiran la olla del fuego y queda expuesta a la temperatura ambiental, que es de 12°C
Answer:
El problema esta incompleto, pero es facil ver que se desea estudiar el enfriamiento de la olla.
Sabemos que la ecuación de enfriamiento de Newton es:
[tex]T (t) = T_s + (T_0 - T_s)*e^{-k*t}[/tex]
Donde t es el tiempo.
[tex]T_s[/tex] es la temperatura del ambiente, en este caso es 12°C
[tex]T_0[/tex] es la temperatura inicial del objeto, en este caso 175°C
k es una constante, que es lo que usualmente se pide obtener en este tipo de problemas.
Reemplazando esos valores en nuestra ecuación obtenemos:
[tex]T(t) = 12 + (175 - 12)*e^{-k*t}\\\\T(t) = 12 + (163)*e^{-k*t}[/tex]
Ahora se nos dice:
"Luego de 10 minutos, la temperatura de la olla será de 100°C"
(estos valores no son necesariamente los del problema, son unos valores genéricos para poder mostrar como se resuelve este tipo de ejercicio)
Entonces, T(10 min) = 100°C
Reemplazando eso en nuestra ecación, obtenemos:
[tex]T(10 min) = 100 = 12 + (163)*e^{-k*10min}[/tex]
Ahora podemos despejar el valor de k resolviendo la ecuación de arriba.
[tex]100 - 12 = (163)*e^{-k*10min}\\\\88 = (163)*e^{-k*10min}\\\\88/163 = e^{{-k*10min}[/tex]
Ahora podemos recordar que:
ln(e^x) = x
Entonces aplicando el logaritmo natural a ambos lados, obtenemos:
[tex]ln(88/163) = ln(e^{-k*10min}) = -k*10min\\\\ln(88/163)/(-10 min) = k = 0.062 min^{-1}[/tex]
Así hemos encontrado el valor de k, y con exactamente el mismo método podríamos encontrar k en cualquier situación de este tipo.
if A is a subset and equal to B then B'-A' is equal to
Answer:
A-B
Step-by-step explanation:
It doesn't say A=B... But just that A is a subset of B.
Anyways, why not try an example to help reveal the answer.
Let the universe set, U, be U={1,2,3,4,5,6}.
Let B={1,2,3,4} and A={1,3,5}
First choice would become A'={2,4,6}
Second choice would become B'={5,6}
Third choice would become A-B={5}
Fourth choice is just { }
B'-A'={5}
The only choice matching is A-B
*Just so you know X-Y is the set of elements contained in X only if they are not also in Y.
Can somebody help me with this problem. And make sure that u can explain how to do it don't just give me the answer.
Answer:
x=50
Step-by-step explanation:
Look at the triangle as a whole. This is a 30-60-90 triangle by speculation. You can see that the hypotenuse is equal to 100. By using sine (you can use cosine as well) , you get the expression, "(sin 30 degrees) = x/100" since sin is the opposite side over the hypotenuse. Do some basic trigonometry to get "1/2 = x/100". By now, you should know that 50/100 is the same as 1/2.
Write this rate as a unit rate 1/7inch 1/14 minute
Answer:
2 inches per minute
Step-by-step explanation:
find the missing length indicated
Answer:
x = 240
Step-by-step explanation:
Apply the leg rule to find the value of x.
Leg rule is given as:
Hypotenuse/leg 1 = leg 1/part 1
Hypotenuse = 400
Leg 1 = x
Part 1 = 144
Plug in the known values into the formula
400/x = x/144
Cross multiply
x*x = 144*400
x² = 57,600
Take the square root of both sides
√x² = √57,600
x = 240
Non right angled triangle
Answer:
18.06
Step-by-step explanation:
law of cos()
b^2 = (16.5)^2 + (17.1)^2 - 2(16.5)(17.1)cos(65)
[tex]\frac{3\sqrt{2}\sqrt{-3135\cos \left(65^{\circ \:}\right)+3137}}{10}\quad \begin{pmatrix}\mathrm{Decimal:}&18.06035\dots \end{pmatrix}[/tex]
Phoebe took a survey of her classmates' favorite sport. The results are in the table below:
What is the relative frequency of survey members who prefer football?
Answer:
.14
Step-by-step explanation:
The relative frequency that favors football is around 0.14, or 14%.
Given that Phoebe took a survey of her classmates' favorite sport.
We need to find the relative frequency of survey members who prefer football,
Preferred sports =
Football baseball basketball tennis others total
4 5 8 7 4 28
To calculate the relative frequency of survey members who prefer football, you need to divide the number of people who prefer football by the total number of survey respondents.
According to the table, the number of people who prefer football is 4, and the total number of respondents is 28.
Relative Frequency = Number of people who prefer football / Total number of respondents
= 4 / 28
≈ 0.14
Therefore, the relative frequency of survey members who prefer football is approximately 0.14 or 14%.
To know about frequency distribution, here
brainly.com/question/1094036
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What is the smallest number, which is neither prime nor a square and that has no prime factor smaller than 100?
Answer:
10403.
Step-by-step explanation:
To find the smallest number that isn't prime and doesn't any factors smaller than 100, we need to multiply the 2 smallest prime numbers greater than 100. The smallest prime number greater than 100 is 101, but we cannot multiply 101 by itself, as the number would become a square. Because of this, we need to multiply 101 by the next smallest prime number, which is 103.
After multiplying 101 by 103, we get 10403.
To check our answer, we can verify each point.
10403 is not prime, as it has 2 factors, 101 and 103.
10403 is not square, as the square root of 10403 is 101.9951.
10403 has 2 factors 101 and 103, both of which are greater than 100.
When a willow tree was planted it was 24 inches tall. Three years later, the tree was 54 inches tall. How many inches per year is the willow tree growing on average?
Answer:
On average 10 inches
Step-by-step explanation:
1st= 24 inches
2nd= 34 inches
3rd= 44 inches
4th= 54 inches
What is the answer in scientific notation?
(5.1 × 106) x (4.3 × 105)
A 0.8 × 106
B 0.8 × 105
C 4.67 × 105
D 4.67 × 106
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\boxed{\star \ (5.1 \times10^6) \times (4.3 \times 10^5)\ \star}[/tex]
[tex]\huge\boxed{10^6}[/tex]
[tex]\huge\boxed{= 10 \times 10 \times10 \times10 \times10 \times 10}[/tex]
[tex]\huge\boxed{= 100\times 100\times100}[/tex]
[tex]\huge\boxed{= 10,000\times100}[/tex]
[tex]\huge\boxed{= \bf 1,000,000}[/tex]
[tex]\huge\boxed{\star\ (5.1 \times 100,000) \times(4.3 \times 10^5)\ \star}[/tex]
[tex]\huge\boxed{10^5}[/tex]
[tex]\huge\boxed{= 10 \times 10 \times10 \times 10 \times 10}[/tex]
[tex]\huge\boxed{= 100\times100\times 10}[/tex]
[tex]\huge\boxed{= 10,000\times10}[/tex]
[tex]\huge\boxed{= \bf 100,000}[/tex]
[tex]\huge\boxed{\star \ (5.1 \times 1,000,000) \times (4.3\times 100,000)\ \star}[/tex]
[tex]\huge\boxed{5.1 \times 1,000,000}[/tex]
[tex]\huge\boxed{= \bf 5,100,000}[/tex]
[tex]\huge\boxed{4.3 \times 100,000}[/tex]
[tex]\huge\boxed{= \bf 430,000}[/tex]
[tex]\huge\boxed{\star\ 5,100,000 \times 430,000\ \star}[/tex]
[tex]\huge\boxed{= \bf 2,193,000,000,000}[/tex]
[tex]\huge\boxed{0.8 \times 10^6}[/tex]
[tex]\huge\boxed{= \bf 800,000}[/tex]
[tex]\huge\boxed{0.8 \times 10^5}[/tex]
[tex]\huge\boxed{= \bf 80,000}[/tex]
[tex]\huge\boxed{4.67\times10^5}[/tex]
[tex]\huge\boxed{= \bf 467,000}[/tex]
[tex]\huge\boxed{4.67 \times 10^6}[/tex]
[tex]\huge\boxed{= \bf 4,670,000}[/tex]
[tex]\huge\boxed{\textsf{Therefore, this makes the answer: \bf NONE}}\\\hug\boxed{\textsf{of the \bf ABOVE}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\huge\boxed{\frak{Amphitrite1040:)}}}[/tex]
Can someone help me on these ones. PLEASE HELP ME !!
[tex]\huge\blue{ANSWER}:—[/tex]
Plz mark me as brainliest as I have solve all the questions for you
Answer:1 : x is 95/3
4 x is -32/10
7 b is 6
10 x is 20/7
13 x is 9/2
Step-by-step explanation:
Jim removed 27 gallons of water from a rainwater storage tank. There are 59 gallons left in the tank. What equation can Jim use to find how much water was in the tank earlier? Use x to represent the amount of water originally in the tank.
Answer: X = 86 gallons
Step-by-step explanation:
X-27=59
X=59+27
Jonathan has a comic book collection.
He tells you he sold half of them, but then bought 9 more new comics.
After this, Jonathan now has 81 comic books. How many comic books did he have before he sold some? a) Let b = the number of Jonathan had before selling some. Write the equation you would use to solve this problem.
Ms. Davis writes an equation on the board.
(-6) + 6 = 0
Which scenario could represent this equation?
There are many answers we could go with here. One such answer could be the following:
You are 6 meters below the ocean surface doing a deep sea dive. This is represented by -6. Then going up 6 meters means you'll add on 6 to say (-6)+6 = 0, showing that you are at the 0 meter height, aka sea level.
---------------------------------
Another possible answer could be this:
You are 6 dollars in debt. Debt is represented with negative numbers. You then somehow get 6 dollars in which you use to pay off that debt. Your balance is now (-6) + 6 = 0 dollars.
---------------------------------
Another possible answer could be this:
Walking to the left is defined as moving in a negative direction. So -6 could mean we've moved 6 feet to the left. On the flip side, +6 means we move 6 feet to the right. The two cancel each other out (-6)+6 = 0 which says at the end of the day, we haven't moved anywhere. In other words, our displacement is 0 feet.
-----------------------------------
I'm sure there are other more creative ways to answer this question, but those three ideas above are good possible starting points.
help me please its confusing neeed help
Answer:
1.94 mm
Step-by-step explanation:
V = pi(r^2)h
V/pi(h) = r^2
r = sqrt(V/pi(h))
r = sqrt(200/pi(17))
r = 1.94 mm
ncert maths class 10 solution 5.1 4
Can you attach a picture to your question?
I would love to help you out.
Answer:
Step-by-step explanation:
NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Ex 5.1
where is question ??
If (8z − 9)(8z + 9) = az2 − b, what is the value of a?
Explanation:
We use the difference of squares rule to say
(m-n)(m+n) = m^2 - n^2
So in this particular case,
(8z-9)(8z+9) = (8z)^2-(9)^2 = 64z^2 - 81
We can see that the 64 matches with the 'a' of the expression az^2-81, which must mean a = 64
Side note: This means b = 81
Answer:
64
Step-by-step explanation:
took the test
really need help to do step by step
Answer:
x/4+10=2
x/4=2-10
x/4=-8
x=-8 x 4
x=-32
Step-by-step explanation:
Helppp and explain pls and ty
The mean score of 7 boys and 16 girls is 49. If the scores of the boys are 42,85,47,29,58,54and 72, find the mean score of the girls
Answer:
[tex]\bar x_{girls} = 46.25[/tex]
Step-by-step explanation:
Given
[tex]Boys = 7\\Girls = 16[/tex]
[tex]\bar x = 49[/tex]
Required
Mean of girls
The mean of the boys and girls is calculated as:
[tex]\bar x = \frac{\sum x}{n}[/tex]
This gives:
[tex]\bar x = \frac{\sum(boys) + \sum(girls)}{boys + girls}[/tex]
So, we have:
[tex]49= \frac{42+85+47+29+58+54+ 72 + \sum(girls)}{7 + 16}[/tex]
[tex]49= \frac{387 + \sum(girls)}{23}[/tex]
Cross multiply
[tex]23 * 49=387 + \sum(girls)[/tex]
[tex]1127=387 + \sum(girls)[/tex]
Subtract by 387
[tex]1127-387 = \sum(girls)[/tex]
[tex]740= \sum(girls)[/tex]
[tex]\sum(girls) = 740[/tex]
The mean of girls is:
[tex]\bar x_{girls} = \frac{\sum(girls)}{girls}[/tex]
[tex]\bar x_{girls} = \frac{740}{16}[/tex]
[tex]\bar x_{girls} = 46.25[/tex]
Need help asap please thank you
Answer:
Option d, ln 54.6 = 4
Step-by-step explanation:
54.6 = e⁴
taking log both side (where base of log is e)
ln 54.6 = log e⁴
or, ln 54.6
or, ln 54.6 = 4×ln e
or, ln 54.6 = 4 (ln e = 1)
Answered by GAUTHMATH
help someone!! which one is it?
Answer:
not great with math but I'm sure it's the second circle
Determine the intercepts of the line.
Y-intercept: (_,_)
X-Intercept: (_,_)
the polygons in each pair are similar. find the scale factor of the smaller figure to larger figure.
Answer:
Scale factor = [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
From the picture given in the question,
If the larger figure is dilated to form the smaller figure,
Scale factor by which a figure is dilated with is determined by the expression,
Scale factor = [tex]\frac{\text{Measure of one side of the smaller figure}}{\text{Measure of the corresponding side of the larger figure}}[/tex]
= [tex]\frac{3}{6}[/tex]
= [tex]\frac{1}{2}[/tex]
