Which regular polygon can be used to form a tessellation?


I need help

Answer:

If a square has a side length of 4, then the area is 16.

A = [tex]s^{2}[/tex]    where s = side length.

If a diagonal is drawn to create 2 halves, then the area of each half is 8.

So most likely the answer you are seeking is:  [tex]\frac{1}{2}[/tex] ( 4 · 4 )

Answer:

Step-by-step explanation:

Daniel

Daniel starts with $50 and each week he adds $8. To find out the amount he has in any given week, the following formula would work:

= 50 + 8x

The x is the number of weeks and is multiplied by 8 because the amount of money he has increase by 8 every week.

After 4 weeks he would have:

= 50 + (8 * 4)

= 50 + 32

= $82

Saquon

Applying the same formula:

= 65 + 5x

After 4 weeks:

= 65 + (5 * 4)

= 65 + 20

= $85

Saquon has more money after 4 weeks.

Number of weeks it would take for both of them to have the same amount.

To find this out, equate both formulas and solve for x.

50 + 8x = 65 + 5x

8x - 5x = 65 - 50

3x = 15

x = 15/3

x = 5 weeks

At 5 weeks they will both have:

50 + 8 * 5 = $90

65 + 5 * 5 = $90

Answer:

N/A

Step-by-step explanation:

What's the question to the question?

Answer:

B

Step-by-step explanation:

the graph has been shifted 4 units to left, and 2 units down.

Answer:

Graph shifted down by 2 ... -2

graph slid  4 to the left ... + 4

B is the answer y = |x+4| -2

Step-by-step explanation:

Answer:

I know the answer...

Step-by-step explanation:

but i dont know the question (i also dont know how to comment so i have to do it as an answer)... thanks

Answer:

C

Step-by-step explanation:

You can distribute the values or even plug in x=2 and see which one matches.

the answer is in the picture

Answer: what is the rest of the question?

Step-by-step explanation:

Answer:

g = 1, 3

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

g² - 4g = -3

Step 2: Solve for g

Answer:

This would not be 20

Step-by-step explanation:

This question can be thought as a Pythagoras question.

By subtracting 2cm from both the left side ZW, and the right side YX, you will have a right angled triangle WYX (or ZYX, since after subtracting 2cm Z and W are essentially the same point)

I have attached a crude drawing of what the triangle is looking like, we are looking for the unknown value marked with the ?

Pythagoras states that [tex]a^{2} +b^{2} =c^{2}[/tex]

We are given the lengths 2cm and 20cm, which can be thought of as a (or b) and c. Substitute in the values 2 and 20 and solve for the unknown

Answer:

you have to take away you word they said how many

Answer:

[tex]2 {x}^{2} - 6x - 1 = 0 \\ a = 2 \: \: \: b = - 6 \: \: \: c = - 1 \\ \\ x = \frac{6\binom{ + }{ - } \ \sqrt{ {6}^{2} - 4(2)( - 1)} }{2 \times 2} \\ \\ x = \frac{6 \binom{ + }{ - } \sqrt{44} }{4} \\ x = \frac{6 + \sqrt{44} }{4} \\ \\ or x = \frac{6 - \sqrt{44} }{4} [/tex]

I hope that is useful for you :)

Answer:

Three times a number minus two times a number

3x-2x

=x

Answer:

7.8391

Step-by-step explanation:

Answer:

Step-by-step explanation:

The key to solving this equation is knowing how to "undo" a natural log. Just like square roots are "undone" by squaring, and cubing "undoes" a cubed root, raising a natural log to the base of e, Euler's number, undoes a natural log. Because this is an equation you have to raise both sides of it to the base of e:

[tex]e^{ln(x+3)}=e^5[/tex]

That leaves us on the left with simply

x + 3

On the right we have a constant. e is not a variable, it is a number. You can find its value on your calculator. Solving for x:

[tex]x=e^5-3[/tex] and

[tex]e^5=148.4131591[/tex], so

x = 148.4131591 - 3 and

x = 145.4132, the first choice listed.

Answer:

Graph:

Solution: (1, 1)

Check:

y = -3x +4

1 = -3 +4

1 = 1

y = 3x -2

1 = 3 -2

1 = 1

Answer:

The two numbers are 182 and 210. I hope this will help you.

Answer: 289,952,278

Step-by-step explanation: Big brain

Answer:

C

Step-by-step explanation:

We are given that

[tex]\angle[/tex]DCB and [tex]\angle[/tex]CDA are supplementary.

We have to identify the parallel segments if [tex]\angle[/tex]DCB and [tex]\angle[/tex]CDA are supplementary.

Supplementary angles: If the angles are supplementary then the sum of two angles is 180 degrees.

Therefore,

[tex]\angle DCB+\angle CDA=180^{\circ}[/tex]

Therefore, angle DCB and angle CDA are interior angles .

Because CA is a transversal line and sum of interior angles is 180 degrees.

When the sum of interior angles formed between two lines  and on same side of transversal line is 180  degrees. Then the lines are parallel.

Therefore, angle DCB and angle CDA are formed between line AD and BC.

Hence, AD is parallel to BC.

Option C is correct.

Answer:

c

Step-by-step explanation:

i had the same question

Answer:

11/12 miles Lyon walk.

Step-by-step explanation:

3/4 -> 9/12

1/6 -> 2/12

9 + 2 = 11

The solution is :about  11/12 miles Lyon walk.

Addition is a way of combining things and counting them together as one large group. ... Addition in math is a process of combining two or more numbers.

here, we have,

given that,

Lyon walked 3/4 mile from school to the soccer field.

He then walked 1/6 mile home.

now, we have to find that,

About how many miles did Lyon walk

so, we need to add the both distance

i.e.  3/4 + 1/6

so, we have,

3/4 -> 9/12

1/6 -> 2/12

so, we get,

9 + 2 = 11

i.e. 3/4 + 1/6

= 9/12 + 2/12

=11/12

Hence, about  11/12 miles Lyon walk.

To earn more on addition click:

brainly.com/question/29560851

#SPJ2

Answer:

A, E, F

Step-by-step explanation:

From the angles given, we can infer that ΔPQR is a 30-60-90 special triangle. In a 30-60-90 triangle, the leg opposite the 30 degree angle is 1/2 the hypotenuse and the leg opposite the 60 degree angle is √3 times the one opposite the 30. Using this, we can say:

PR = 1/2 PQ which is just 2 PR = PQ(E)

PR √3 = QR (A)

We can substitute in PR from the first equation to the second to get:

√3/2 PQ = QR(F)

Answer:

2(x - 3)^2 - 25.

Step-by-step explanation:

2x^2-12x-7

= 2(x^2 - 6x) - 7

= 2[(x - 3)^2 - 9] - 7

= 2(x - 3)^2 - 18 - 7

= 2(x - 3)^2 - 25.

9514 1404 393

Answer:

  C.  f^-1(x) = (x +4)^2; x  ≥ -4

Step-by-step explanation:

The range of the given function f(x) is -4 ≤ f(x). This will be the domain of the inverse function.

We find the inverse function by solving ...

  x = f(y)

  x = √y -4

  x +4 = √y

  (x +4)^2 = y

The inverse function is ...

  f^-1(x) = (x +4)^2 . . . for x ≥ -4

Answer:

5/4

Step-by-step explanation:

The area of a rectangle is given by

A = l*w

1/2 = 2/5 * w

Multiply each side by 5/2

5/2 * 1/2 = 2/5 *w * 5/2

5/4 = w

Formula we use,

→ A = l × w

Then the width of the rectangle,

→ A = I × w

→ 1/2 = 2/5 × w

Now multiply each side by 5/2,

→ 1/2 × 5/2 = 2/5 × w × 5/2

→ w = 5/4

Hence, the width is 5/4.

Answer:

2a times the sq root of 2a or 2a (2a)**1/2

Step-by-step explanation:

(8a**3)**1/2 =

((2**2 * 2) (a**2) (a))**1/2 then take out and squares

2a (2a)**1/2

or 2a times the sq root of 2a

Answer:

Step-by-step explanation:

C

Answer:

1372/3 π

that's the volume

Answer:

m∠B = 43°

b = 26.1

c = 38.3

Step-by-step explanation:

By applying triangle sum in the given triangle,

47° + 90° + m∠B = 180°

137° + m∠B = 180°

m∠B = 43°

By applying sine ratio to the angle measuring 47°.

sin(47°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

            = [tex]\frac{28}{c}[/tex]

c = [tex]\frac{28}{\text{sin}(47^{\circ})}[/tex]

c = 38.28

c ≈ 38.3

By applying cosine rule,

cos(47°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

             = [tex]\frac{b}{c}[/tex]

             = [tex]\frac{b}{38.3}[/tex]

b = 38.3[cos(47°)]

b = 26.1

Answer:

Solution given:

we have formula

a²+b²=(a+b)(a-b)

now

4x²-9

(2x)²-3²

using formula

(2x+3)(2x-3)

other expression is 2x-3.

Answer:

( 2x - 3 )

Step-by-step explanation:

4x² - 9 is a perfect square meaning it can be factored into 2 expressions,

( 2x + 3 ) ( 2x - 3 )

Answer:

do you have a pic of it but i think its 15.75

Step-by-step explanation: