Which postulate proves these two
triangles are congruent?
A. HL
B. SSA
C. ASA
D. SAS

Answer:

[tex]y=-\frac{1}{4}x\\[/tex]

Step-by-step explanation:

The slope is calculated by "up ÷ across".

= -1 ÷ 4

= [tex]-\frac{1}{4}[/tex]

The y-intercept is just 0 (because the line meets at the y axis at 0).

So, using [tex]y=mx+b[/tex] (where m = slope and b = y-intercept),

[tex]y=-\frac{1}{4}x+0[/tex]

but the '+0' is unnecessary so we just say [tex]y=-\frac{1}{4}x[/tex]

Answer:

I think that you should take your time and answer, every one can help you

Step-by-step explanation:

Step-by-step explanation:

ok give question and intro new sis

Answer: use distributive property

Step-by-step explanation:

Answer:

7+5=12

Step-by-step explanation:

To calculate the mass number of an atom, you have to add the protons and the neutrons. We have 7 neutrons and 5 protons, so your mass number would be 12. Let me know if you have any further questions. :)

Answer:

use graphs

Step-by-step explanation:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

9514 1404 393

Answer:

  7

Step-by-step explanation:

Of the 9 2-digit numbers ending in 6, only 2 are perfect squares: 16 and 36. The other 7 are not perfect squares.

Answer:

the correct answer is B

Step-by-step explanation:

I got it correct on 2021 edge

Please check the attached image for the steps.

Answer = 11/42 = 0.261

____

RainbowSalt2222 ☔

Answer:

3 ( 917 ) = 3 ( 900 ) + 3 ( 10 ) + 3 ( 7 )

5 ( 209 ) = 5 ( 200 ) + 5 ( 0 ) + 5 ( 9 )

6 ( 347 ) = 6 ( 300 ) + 6 ( 40 ) + 6 ( 7 )

9 ( 821 ) = 9 ( 800 ) + 9 ( 20 ) + 9 ( 1 )

11 ( 142 ) = 11 ( 100 ) + 11 ( 40 ) + 11 ( 2 )

Step-by-step explanation:

Answer:

Hint(look at the first number in each part and math it with the first number in each answer.) For example, 3(937), the distributive property for that one would be 3(900) + 3(30) + 3(7). Then for 5(209) it would be 5(200) + 5(0) + 5(9), then for 6(342), it would be 6(300) + 6(40) + 6(2). Then for 9(821), it would be 9(800) + 9(20) + 9(1), and for the last one it would be 11(143), it would be 11(140) + 11(40) + 11(3). You basically distribute each amount into different place values.

Step-by-step explanation:

Hope it helps. Mark brainiest if it does!

Answer: The answer to this math question about completing the equation in order to calculate the cost of the portable speaker, including the sales tax is $94.34.

Step-by-step explanation: I don't have any step-by-step explanation, I'm sorry about that, but anyway, I hope that my given short answer is very helpful to your own math question about completing the equation in order to calculate the cost of the portable speaker, including the sales tax, please mark me as Brainliest, take care, always be safe, and have a great rest of the day! :D

Sincerely,

Jason Ta,

The Ambitious of The Brainly And The Role of The TDSB And WHCI Student of The High School.

Answer:

£86.50

Step-by-step explanation:

To find how much 10 t-shirts cost we have to find how much they cost individually.

3 T- Shirts / 25.95 = 8.65 which means that each T-Shirt Costs 8.65.

8.65 x 10 T-Shirts = £86.50

Answer:

Rate of change problem:

theres 2 ways but it’s a basically the same thing, if you do these questions enough you’d know right away to find the unit rate of gallon of gasoline To price.

So you can divide.

10 gallons, 23 dollars

23 ÷ 10 = $2.30

$2.30 per gallon of gasoline.

Now we multiply by 15 to find how much will 15 gallons will cost.

2.3*15= $34.5

or you can do it proportionally, this is if you would want to show your work more clearly or just started doing these problems.

So we can make x unknown price.

So we know its 10 gallons for 23 dollars

we want to know how much it would be for 15 gallons

So we can do it like gallon/ price = gallon/ price

ex:

10/23 = 15/x

Make sure it’s lined up correctly

Now just cross multiply and solve for this proportion

10x= 345

now solve

x= 34.5

same answer

Answer:

104

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

-5g -6

Let g= -2

-5 (-2) -6

Multiply

10 -6

4

Answer:

A. 4

Step-by-step explanation:

So, we have an equation with a variable (g), and they've given us the value of g to be -2. All we have to do at this stage is plug in the value of g into the equation.

-5g-6 (g=-2)

-5(-2)-6

10-6=4

Doing the math by plugging in -2, you would get your answer to be 4. Let me know if you see any errors, and if you have any further questions at all.

Answer:

200

Step-by-step explanation:

I think sorry if I am wrong

Answer:

$14.40 is the discount price.

Step-by-step explanation:

0.2 x 18 = 3.6

18 - 3.6 = 14.4

a is right its 58

and in my opinion i think b would be 58*5=290 cents, since nickel is worth 5 cents.

but gotta check other people's answers

∆HFE is similar to ∆HFG and ∆ HEG (they all are right triangles and have the same, shape.)

The given triangle ΔHFE is similar to triangle GFH and triangle GHE.

Similar triangles are two triangles that have the same shape but may differ in size. They have corresponding angles that are congruent and corresponding sides that are proportional.

Here,

Since triangle HFE is similar to triangle GFH,
∠HEF = ∠GHF,
∠FHE = ∠HGF, and ∠HFE = ∠HFG

Similarly

ΔHFE is similar to triangle ΔGHE.

Similar triangles are useful in many areas of mathematics and in the real world, such as in architecture, engineering, and cartography, where they are used to make scale models of buildings and other structures.

Thus, the given triangle ΔHFE is similar to triangle GFH and triangle GHE.

Learn more about similar triangles here:

https://brainly.com/question/12101336
#SPJ2

percent of water is: 32/80*100= 40%

Answer:

-5/6a - 5/8

Step-by-step explanation:

i took the k12 quiz

Answer:

10/5 - 4

Step-by-step explanation:

you have to write down what you understand from the sentence.

First, you read it carefully since it says quotient then you will have to put that first and then subtraction. Normally you would put subtraction in front because the sentence is in that order. But since your dealing with division then the subtraction part would go afer.

10/5 - 4

Answer: uhh i think both are correct since the order of operation states that you must do division over subtraction first, it doesn't matter which position 4 is in, but you must do the division first.

Answer:

uh.. shii i dont know

Step-by-step explanation:

Answer:

2.29883

formula

[tex]c = 2 \times \pi \times r[/tex]

solving for (r) radius

[tex]r = \frac{c}{2\pi} = \frac{14.44}{2 \times \pi} [/tex]

= 2.29883

JK=JH

[tex]\\ \sf\longmapsto 10t=7t+15[/tex]

[tex]\\ \sf\longmapsto 10t-7t=15[/tex]

[tex]\\ \sf\longmapsto 3t=15[/tex]

[tex]\\ \sf\longmapsto t=15/3=5[/tex]

Answer:

C

Step-by-step explanation:

Answer:

5 Motorcycles are used

30÷6= 5

5×5= 25

30-24=5

so the answer is 5

Answer:

5 out of the 30 motorcycles are used

Step-by-step explanation:

First, we should look at what we know. We know that there are 30 motorcycles in total. As a fraction, that'd be 30/30. We also know that of that 30, the equivalent of 5/6 are brand new.

Our next step is to figure out how much 5/6 is out of 30. Since we know that in total there 30/30 motorcycles, we need to convert 5/6 to have a denominator of 30. So what times 6 equals 30.

30 ÷ 6 = ?    opposite of 6 x ? = 30

5                   divide

So now we now that 6 times 5 equals 30. What we do to the denominator we must do to the numerator.

[tex]\frac{5}{6}[/tex] × [tex]\frac{5}{5}[/tex]    

[tex]\frac{25}{30}[/tex]

Now we know that 25 of the 30 motorcycles are new and all we need to do is subtract that 25 from the total 30 to get 5. This tells us that 5 of the total motorcycles are used.

I hope this helped :)

Step-by-step explanation:

[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]

[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

We can write as :

27 = 3 × 3 × 3 = 3³

8 = 2 × 2 × 2 = 2³

243 = 3 × 3 × 3 × 3 × 3 = 3⁵

32 = 2 × 2 × 2 ×2 × 2 = 2⁵

[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now, we can write as :

(3³/2³) = (3/2)³

(3⁵/2⁵) = (3/2)⁵

[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now using law of exponent :

[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]

[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]

Step-by-step explanation:

first find out the area of sector ECF

π(10)² × 40°/360°

=100π×1/9

=100π/9 m²

now find the area of sector DCG

π(2)² × 40°/360°

=4π/9 m²*

so the area of the shaded region would be the big sector minus the small sector

so

100π/9 - 4π/9

=96π/9

=33.5 m² (3sig.fig.)

*Note that 4π/9 DOES NOT equal to 2π/3

4/9 DOES NOT EQUAL TO 2/3

Answer:

3000

Step-by-step explanation: