Which one will it be

Answer:

the particles vibrate inside the tyre

Explanation:

as the car moves kinetic energy is transfered in the tyres which causes the particles to vibrate inside the tyre so the kinetic store is. transferred into thermal

Answer:

pretty sure its A

Explanation:

please give brainliest if i'm correct

Answer:

A.

Explanation:

I have done this and that was correct

hope this helps

Answer:

D1

Explanation:

Higher diffusion constants mean that the substance diffuses more in a given time. Because D1>D2, D1 should diffuse more.

Explanation:

2 one is kinametics

please check attachment

Kinematics is the branch of classical mechanics that describes the motion of points, objects and systems of groups of objects, without reference to the causes of motion (i.e., forces ). The study of kinematics is often referred to as the “geometry of motion.”

Answer:

d.it is used in electronic devices

Answer:

The magnitude of the force exerted on the ball by the racquet is 94.73 N.

Explanation:

The force exerted on the ball is the following:

[tex] F = ma [/tex]

Where:

m: is the mass of the ball = 59 g

a: is the acceleration

The acceleration of the ball can be found with the following kinematic equation:

[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]

Where:

d: is the distance = 0.36 m

[tex]v_{f}[/tex]: is the final speed = 34 m/s

[tex]v_{0}[/tex]: is the initial speed = 0 (it start from rest)

Hence, the acceleration is:

[tex] a = \frac{v_{f}^{2}}{2d} = \frac{(34 m/s)^{2}}{2*0.36 m} = 1605.6 m/s^{2 [/tex]

Finally, the force is:

[tex] F = ma = 59 \cdot 10^{-3} kg*1605.6 m/s^{2} = 94.73 N [/tex]    

Therefore, the magnitude of the force exerted on the ball by the racquet is 94.73 N.                                

I hope it helps you!                                                              

Explanation:

the efficiency of a machine can be increased by reducing the friction

please mark the brainliest

Answer:

8.37 Joules

Explanation:

The amount of energy that a substance, such as animal tissue or rubber can take and yet return to its original condition is known as resilience. When we stress such a substance and then let it restore to its previous state, we are referring to the substance to maintain its elastic area of the stress-strain curve.

From the given information:

the resilence is 0.93

The amount of work done during stretching of the tendon = 9.00 J

Thus,

the work done when relaxing = 0.93 × 9.00 J

= 8.37 Joules

Explanation:

the unit of area is called a derived unit because it is made of two fundamental unit metre and metre.

Answer:

1.2 x 10^-12

Explanation:

3/2.5 x 10^-6/10^6

1.2 x 10^-6 x 10^-6

1.2 x 10^-12

Answer:

cause they give u milk

Explanation:

Answer:

Cows are important as they provide humans many things for survival. They provide milk, meat, and leather, all of these are important resources.

Answer:

I = 2/5 M R^2 for solid sphere

IA = 2/5 M R^2

IB = 2/5 M (2 R)^2

IB / IA = 4

a. Sphere A has 1/4 the inertia of sphere B.

Answer:

[tex]K.E = 163 J[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=4.1kg[/tex]

Height [tex]h=4m[/tex]

Speed [tex]V=1m/s[/tex]

Angle [tex]\theta= 2 \textdegree[/tex]

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore

 [tex]K.E=mgH + 0.5mV^2[/tex]

 [tex]K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5[/tex]

 [tex]K.E = 163 J[/tex]

Answer:

In "Young Goodman Brown," Hawthorne reveals his feelings about his Puritan ancestors when the dark man reveals that he helped Brown's forebears persecute others.

Explanation:

hey mate i know it is right so don't worry this is the correct

Answer:

In "Young Goodman Brown," Hawthorne reveals his feelings about his Puritan ancestors when the dark man reveals that he helped Brown's forebears persecute others. so that means the answer is D.

Explanation:

A. brown strives to resist his dark mission

B. faith expresses her anxieties about young brown's departure

C. brown discovers his catechism teacher is on speaking terms with the devil

D. the dark man reveals that he helped brown's forebears persecute others(correct answer)

Answer:

Temperatures on Earth are ideal for water to exist in solid, liquid, and gaseous forms.

Earth's gravity holds the water vapor in Earth's atmosphere close to its surface.

Answer: a and c

Explanation:

from plato

Answer:

Por lo tanto, la presión del ozono es:

[tex]P=0.011\: atm[/tex]  

Explanation:

Podemos usar la ecuacion de los gases ideales;

[tex]PV=nRT[/tex] (1)

Tenemos:

El volumen V = 224 dm³ = 224 L

La temperatura T = 51.09 C = 324.09 K

La masa es m = 4.561 kg

Lo necesitamos ahora es calvular n que es el numero de moles;

recordemos que el peso molecular del ozono M = 48 g/mol.

[tex]n=\frac{m}{M}=\frac{4.561}{48}=0.095\: mol[/tex]

Finalmente, usando la ecuacion 1 despejamos la presion P

[tex]P=\frac{nRT}{V}[/tex]

[tex]P=\frac{0.095*0.082*324.09}{224}[/tex]  

Por lo tanto, la presion del ozono es:

[tex]P=0.011\: atm[/tex]  

Espero te haya ayudado!

Answer:

Initially...

Object A is at rest(v=0)

With Mass =8kg

Object B moving at 10ms- and Mass of 16kg.

Now After collision(Elastic)... B Came to rest...Meaning its final vel =0

But its mass remains the same

What velocity would A be moving with?

From Conversation of Momentum

M'U' + M"U"= M'V' + M"V"

8(0) + (16)(10) = 8V' + 16(0)

0 + 160 = 8V' + 0

8V'= 160

V'= 160/8

V'=20ms-¹.

A would be Moving at 20ms-¹ after collision.

MAnswer:

Explanation:

Answer:

400

Explanation:

Answer:

the speed is 2

Explanation:

speed= distance/ time

speed= 50/25

= 2

hope this helps!

1 kilo = 1000 gms

Therefore, 5 kilo = 5000 gms

Answer:

this is my answer in the first question...

Fuel your body for everyday performance

To help your muscles recover and to replace their glycogen stores, eat a meal that contains both carbohydrates and protein within two hours of your exercise session if possible. Good post-workout food choices include: Yogurt and fruit. Peanut butter sandwich

my family motivated me to achieve it because they support me and my self also because if i did not do my best i would not achieve it

Answer:

yes the answer is D as the two people if we calculate

Answer:

A

Explanation:

correct on A P E X

Answer:

the required speed with which the missile move relative to the Earth is -0.727c

Explanation:

Given the data in the question;

relative velocity relation;

u' = u-v / 1 - [tex]\frac{uv}{c^2}[/tex]

so let V[tex]_B[/tex] represent the velocity as seen by an external reference frame; u=V[tex]_B[/tex]

and let V[tex]_A[/tex] represent the speed of the secondary reference frame; v=V[tex]_A[/tex]

hence, u' is the speed of B as seen by A

so

u' = V[tex]_B[/tex]-V[tex]_A[/tex] / 1 - [tex]\frac{V_BV_A}{c^2}[/tex]

now, given that; V[tex]_A[/tex] = 0.9c  and V[tex]_B[/tex]  = 0.5c

we substitute

u' = ( 0.5c - 0.9c ) / 1 - [tex]\frac{(0.5c)(0.9c)}{c^2}[/tex]

u' = ( 0.5c - 0.9c ) / 1 - [tex]\frac{c^2(0.5)(0.9)}{c^2}[/tex]

u' = ( 0.5c - 0.9c ) / 1 - (0.5 × 0.9)

u' = ( -0.4c ) / 1 - 0.45

u' = -0.4c / 0.55

u' = -0.727c

Therefore, the required speed with which the missile move relative to the Earth is -0.727c

Answer:

Explanation:

When an object's speed increases at a constant rate, we say it has constant/uniform acceleration.

Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Explanation:

Given: Mass = 5 kg

Spring constant = 6 N/m

Formula used to calculate period is as follows.

[tex]T = 2 \pi \sqrt\frac{m}{k}[/tex]

where,

T = period

m = mass

k = spring constant

Substitute the values into above formula as follows.

[tex]T = 2 \pi \sqrt\frac{m}{k}\\= 2 \times 3.14 \times \sqrt\frac{5}{6}\\= 5.73 s[/tex]

Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Answer:

The new angular velocity of the merry-go-round is 18.388 revolutions per minute.

Explanation:

The merry-go-round can be represented by a solid disk, whereas the three children can be considered as particles. Since there is no external force acting on the system, we can apply the principle of angular momentum conservation:

[tex]\left(\frac{1}{2}\cdot M + m_{1}+m_{2} + m_{3} \right)\cdot R^{2}\cdot \dot n_{o} = \left(\frac{1}{2}\cdot M + m_{1} + m_{3})\cdot R^{2}\cdot \dot n_{f}[/tex] (1)

Where:

[tex]M[/tex] - Mass of the merry-go-round, in kilograms.

[tex]m_{1}[/tex], [tex]m_{2}[/tex], [tex]m_{3}[/tex] - Masses of the three children, in kilograms.

[tex]R[/tex] - Radius of the merry-go-round/Distance of the children with respect to the center of the merry-go-round, in meters.

[tex]\dot n_{o}[/tex], [tex]\dot n_{f}[/tex] - Initial and final angular speed, in revolutions per minute.

If we know that [tex]M = 182\,kg[/tex], [tex]m_{1} = 17.4\,kg[/tex], [tex]m_{2} = 28.5\,kg[/tex], [tex]m_{3} = 32.8\,kg[/tex], [tex]R = 1.60\,m[/tex] and [tex]\dot n_{o} = 15.3\,\frac{rev}{min}[/tex], then the final angular speed of the system is:

[tex]\dot n_{f} = \dot n_{o}\cdot \left(\frac{\frac{1}{2}\cdot M + m_{1} + m_{2} + m_{3} }{\frac{1}{2}\cdot M + m_{1} + m_{3} } \right)[/tex]

[tex]\dot n_{f} = \left(15.3\,\frac{rev}{min} \right)\cdot \left[\frac{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg +28.5\,kg + 32.8\,kg }{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg + 32.8\,kg } \right][/tex]

[tex]\dot n_{f} = 18.388\,\frac{rev}{min}[/tex]

The new angular velocity of the merry-go-round is 18.388 revolutions per minute.

The area around a magnet in which it's magnetic force can ne experienced.

➛ Magnetic field has both magnitude and direction.

➛ Magnetic field can be described with help of a magnetic compass.

➛ It's SI unit is Tesla( T ) .

Explanation:

An area around a magnet or materials that behave like a magnet, where there is a force that will attract some metals towards it.

[tex] \: [/tex]