Which of these groups of values plugged into the TVM Solver of a graphing
calculator will return the same value for PV as the expression
($415)((1 +0.003)24 – 1)?
(0.003)(1 +0.003)24
Answers
The TVM solver is a tool found in graphing calculators, that solve Time
Value of Money problems.
The group of values that will return the same value as the given expression is; D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :ENDReasons:
In the TVM solver, we have;
I = The annual percentage rate
N = n × t
t = The number of years
PV = Present value
PMT = Payment
P/Y = Number of payments per year = n
C/Y = Number of compounding periods per year = n
The formula for monthly payment is presented as follows;
[tex]M = \mathbf{\dfrac{P \cdot \left(\dfrac{r}{n} \right) \cdot \left(1+\dfrac{r}{n} \right)^{n \times t} }{\left(1+\dfrac{r}{n} \right)^{n \times t} - 1}}[/tex]
Which gives;
[tex]P = \mathbf{\displaystyle \frac{M\cdot \left(\left(1+\dfrac{r}{n} \right)^{n \times t} - 1 \right) }{\left(\dfrac{r}{n} \right) \cdot \left(1+\dfrac{r}{n} \right)^{n \times t}}}[/tex]
Therefore, we get;
Where;
M = PMT = -415
P = PV
r = I
P/Y = n = 12
Therefore;
[tex]\displaystyle 0.003 = \frac{I}{12}[/tex]
I = 0.003 × 12 = 0.036 = 3.6%
N = n × t = 24
[tex]P = \displaystyle \frac{(415)\cdot \left(\left(1+\dfrac{I}{12} \right)^{24} - 1 \right) }{\left(\dfrac{I}{12} \right) \cdot \left(1+\dfrac{I}{12} \right)^{24}} = \mathbf{\displaystyle \frac{(415)\cdot \left(\left(1+0.003\right)^{24} - 1 \right) }{\left(0.003\right) \cdot \left(1+0.003 \right)^{24}}} = ?[/tex]
The value of the equation is the present value, PV = ?
When payment are made based on the PV, we have FV = 0
The group of values the same value as the expression[tex]\displaystyle \frac{(\$415)\cdot (1 + 0.003)^{24} - 1}{(0.003) \cdot (1 + 0.003)^{24}}[/tex], when plugged into the TVM solver of a calculator is; D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END
Learn more about Present Value Solver here:
https://brainly.com/question/1759639
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Step-by-step explanation:
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HOPE THIS HELPS :D
The Pythagoras is the sum of the square of two sides equal to the square of the longest side. Then the exact measure of each leg is 9.4 ft.
What is a right-angle triangle?It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.
A right-angle 45-45-90 triangle with the hypotenuse measuring 5√7 feet.
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Let each side length of x ft. Then by the Pythagoras theorem. we have
[tex]\begin{aligned} x^2 + x^2 &= (5\sqrt7)^2\\\\2x^2 &= 25 \times 7\\\\x^2 &= \dfrac{175}{2}\\\\x^2 &= 87.5\\\\x &= 9.354 \approx 9.4 \ \rm ft \end{aligned}[/tex]
More about the right-angle triangle link is given below.
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Step-by-step explanation:
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Answer:
yes its B................
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Step-by-step explanation:
is your answer
Answer:
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Step-by-step explanation:
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Answers
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Answers
Step-by-step explanation:
log (√1000000x)
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expand long ((1000000x)1/2) by moving 1/2
oby moving logarithm.
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Step-by-step explanation:
See the steps below:
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I hope this helps! :)
Answer:
a=5
Step-by-step explanation:
3(a-4)+1=9-a
3a-12+1=9-a
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[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Solution ~
[tex]100 {}^{4} [/tex][tex]100 \times 100 \times 100 \times 100[/tex][tex]100000000[/tex]or it can also be expressed as ~
[tex]10 {}^{8} [/tex]
[tex]1 {0}^{8} \\ \\ hope \: \: it \: \: helps \\ \\ see \: \: the \: \: attachement[/tex]
3
Assume that a randomly selected subject is given a one density test those test scores are normally distributed with a mean of 0 and a standard deviation of 1
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Answer:
See Image below for answer:)
Step-by-step explanation:
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Answers
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Therefore, the height of the cliff is approximately 123.86 m.
A sketch to this question is attached.
Visit: https://brainly.com/question/23497407
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Answers
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____
Hope it helps!
꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂ ❤
Answer:
[tex]\boxed{\boxed{\sf x=2}}[/tex]
Step-by-step explanation:
[tex]\sf 2x+4+8x=24[/tex]
Combine like terms:
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[tex]\sf 10x+4-4=24-4[/tex][tex]\sf 10x=20[/tex]Divide both sides by 10:
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Hello there!
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~Just a determined gal
#CarryOnLearning
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[tex]MysteriousNature :)[/tex]
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Hello, have a great day.
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