A and B
I hoped it helped you
please help (picture) 25 points
Answer:
1) perimeter = sum of all the sides = 3y+9+2y+4+y+3+2y+4 = 8y+20
2) P = 4(5x-2) = 20x-8
Find the surface area of the
rectangular prism.
2 cm
6 cm
3 cm
[?] sq cm
Enter
Answer:
72 sq cm
Step-by-step explanation:
Surface area of the cuboid is 2*(lb+bh+lh)=2*(12+18+6)=2*36=72
Answer:
36 sq cm
Step-by-step explanation:
This prism is formed by rectangles, and to find the area of a rectangle you have to multiply its sides. So, to find the surface area, you find the area of each rectangle and after add it all:
3×2 = 6 sq cm, and your have two of this rectangles
6×2 = 12 sq cm, and you also have two of this
3×6 = 18 sq cm, and also have two of this
6 + 12 + 18 = 36 sq cm
— 12 — бр – (-2)
HELP ASAP
Answer:
-10 - 6p
Step-by-step explanation:
-12 - 6р - (-2)
~Combine like terms
-10 - 6p
Best of Luck!
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textsf{-12 - 6p - (-2)}\\\\\huge\text{COMBINE the LIKE TERMS}\\\huge\textsf{\underline{\underline{-12 - (-2)}} + \underline{\underline{\underline{(-6p)}}}}\\\\\\\huge\text{\underline{\underline{-12 - (-2)}}}\\\huge\textsf{= -12 + 2}\\\huge\textsf{= \bf -10}\\\\\\\huge\textsf{-6p \text{does not have any like terms so it}}\\\huge\textsf{stays the same}\\\\\\\huge\textsf{= \bf -6p - 10}\\\\\boxed{\boxed{\huge\text{Answer: \bf -6p - 10}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\boxed{\huge\boxed{\frak{Amphitrite1040:)}}}[/tex]
3000 dollars is invested in a bank account at an interest rate of 7 percent per year, compounded continuously. Meanwhile, 20000 dollars is invested in a bank account at an interest rate of 5 percent compounded annually.
To the nearest year, when will the two accounts have the same balance?
9514 1404 393
Answer:
after 89 years
Step-by-step explanation:
For principal p, interest rate r, and number of years t, the two account balances are ...
a = p·e^(rt) . . . . continuous compounding
a = p(1+r)^t . . . . annual compounding
Using the given values, we have
3000·e^(0.07t) . . . . . compounded continuously
20000·1.05^t . . . . . . compounded annually
We want to find t so these are equal.
3000·e^(0.07t) = 20000·1.05^t
0.15e^(0.07t) = 1.05^t . . . . divide by 20,000
ln(0.15) +0.07t = t·ln(1.05) . . . . take natural logarithms
ln(0.15) = t·(ln(1.05) -0.07) . . . . subtract 0.07t
t = ln(0.15)/(ln(1.05) -0.07) ≈ -1.8971/-0.02121 . . . . . divide by the coefficient of t
t ≈ 89.4 ≈ 89
The two accounts will have the same balance after 89 years.
Blanca runs 8 laps around the track each day to train for an endurance race. She times each lap to practice her pacing for the race. The table shows the lap times, in seconds, for three days of practice.
A 3-column table with 8 rows. The first column is labeled day 1 lap times (seconds) with entries 83, 92, 91, 89, 94, 93, 88, 84. The second column is labeled day 2 lap times (seconds) with entries 87, 90, 92, 91, 92, 95, 90, 85. The third column is labeled day 3 lap times (seconds) with entries 85, 86, 91, 93, 91, 89, 88, 84.
Which histogram represents Blanca’s lap times for the three days of practice?
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 laps.
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 3 laps were 84 to 86 seconds. 3 laps were 86 to 88 seconds. 5 laps were 88 to 90 seconds. 5 laps were 90 to 92 seconds. 3 laps were 92 to 94 seconds. 3 laps were 94 to 96 seconds. 1 lap was 96 to 98 seconds.
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 3 laps were 84 to 86 seconds. 3 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 4 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 1 lap was 96 to 98 laps.
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 3 laps were 92 to 94 seconds. 4 laps were 94 to 96 seconds. 0 laps were 96 to 98 laps.
Answer:
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds
Step-by-step explanation:
The given table is presented as follows;
[tex]\begin{array}{ccc}Day \ 1 \ lap \ times \ (seconds)&Day \ 2 \ lap \ times \ (seconds)&Day \ 3 \ lap \ times \ (seconds)\\83&87&85\\92&90&86\\91&92&91\\89&91&93\\94&92&91\\93&95&89\\88&90&88\\84&85&84\end{array}[/tex]The number of laps in the range 82 to 84 seconds = 1
The number of laps in the range 84 to 86 seconds = 4
The number of laps in the range 86 to 88 seconds = 2
The number of laps in the range 88 to 90 seconds = 4
The number of laps in the range 90 to 92 seconds = 6
The number of laps in the range 92 to 94 seconds = 5
The number of laps in the range 94 to 96 seconds = 2
The number of laps in the range 96 to 98 seconds = 0
Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds
Answer: A.
Step-by-step explanation: On Edge!
Consider the reflection of parallelogram PQRS across the line of reflection wy
Answer:
Consider the reflection of the parallelogram PQRS across the line of reflection wy if RR = 14 Then RZ= If SX=5 then = 5
Step-by-step explanation:
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST!!
Answer:
so the simplest way to find the volume of water is by dividing into different....objects
so when dividing you create a rectangular box that has length of 12 width of 14.5 and height of 5 and another rectangular box with length of 7 (19-12) width of 4 and height of 5
now calculate the volume of each box and add them up
v = length x width x height
box 1 = 12 x 14.5 x 5 = 870 ft^3
box 2 = 7x4x5 = 140
now smash them up together = 870+140=1010ft^3
hope that answers your question
I need help I don't understand this.
9514 1404 393
Answer:
∠4 = 108°
Step-by-step explanation:
Angles 2 and 4 together form a "linear pair". That is, the sum of them is 180°, a "straight angle." They are supplementary.
∠4 = 180° -∠2 = 180° -72°
∠4 = 108°
$60 is shared between Ali, Ben and Carol in the ratio of 5 :3 : Z How much does Ben get?
Answer:
the answer is 100:60:40 hope it helps
Hi, just need help with this graph problem.
Answer:
Domain: (-2, 2]
Range: (-5, 4]
General Formulas and Concepts:
Algebra I
Domain is the set of x-values that can be inputted into function f(x) Range is the set of y-values that are outputted by function f(x)Interval Notation: [Brackets] denote inclusion and (Parenthesis) denote exclusionStep-by-step explanation:
According to the graph, we see that our x values span from -2 to 2. Since -2 is an open dot and 2 is a closed dot, they are exclusive and inclusive, respectively:
(-2, 2] or -2 < x ≤ 2
According to the graph, we see that our y values span from -5 to 4. Since -5 is an open dot and 4 is a closed dot, they are exclusive and inclusive, respectively:
(-5, 4] or -5 < y ≤ 4
Geometry, please answer question ASAP
Answer:
A
Step-by-step explanation:
The inscribed angle IJK is half the measure of its intercepted arc, so
arc IK = 2 × 75° = 150°
The 3 arcs sum to 360° , then
arc IJ = 360° - (150 + 110)° = 360° - 260° = 100° → A
30 points PLEASE HELP!!!!
Find the volume of the pyramid.
76.34 ft3
458.06 ft3
916.11 ft3
305.37 ft3
Answer:
916.11 ft³
Step-by-step explanation:
(9×6)×7.83/2×13/3
= 211.41×13/3
= 916.11 ft³
Answered by GAUTHMATH
Answer:
916.11 ft³
Step-by-step explanation:
40) what is the area of a rectangular porch measuring 8 ft x 12/f
45) Create a stem and leaf plot to represent this set of data.
30, 62, 32, 63, 43, 77, 48, 78, 49, 82, 51, 84, 60,
please make sure to answer both questions
Show that 1.272727... = 1.27 can be expressed in the form , where p and q are integers and q not equal to 0.
Answer:
Hello,
Step-by-step explanation:
[tex]1.272727....=1.\overline{27}\\\\=1+\dfrac{27}{99} \\\\=1+\dfrac{3}{11} \\\\=\dfrac{11+3}{11} \\\\=\dfrac{14}{11} \\[/tex]
One other way:
Let say x=1.272727...
100x=127.272727...
x=1.272727...
99x=126
x=126/99
x=14/11
37. for the graph x= -3
please help
Answer: 0
Step-by-step explanation:
Slope of x = -3 is infinite / undefined (there is infinite/no defined change in y for a given change in x). Remember, line x = -3 slopes straight up.
Perpendicular means at a 'right angle to'.
The only kind of line that is perpendicular to a vertical line is a horizontal line, which is like y = 15 or y = 5 or something. The slope of such lines is always zero, because there is no change in line's rise for a given run.
please
[tex] \sin(120) \\ \tan( \frac{3\pi}{4} ) [/tex]
help me I need help
Answer:
[tex] \sin(120) \\ = \sin(90 + 30) \\ = \cos(30) \\ = \frac{ \sqrt{3} }{2} \\ \\ \tan( \frac{3\pi}{4} ) \\ = \tan(135) \\ = \tan(90 + 45) \\ = - \cot(45) \\ = - 1[/tex]
[tex]\\ \rm\longmapsto sin120[/tex]
[tex]\\ \rm\longmapsto sin(90+30)[/tex]
[tex]\\ \rm\longmapsto cos30[/tex]
[tex]\\ \rm\longmapsto \dfrac{\sqrt{3}}{2}[/tex]
Now
[tex]\\ \rm\longmapsto tan\left(\dfrac{2\pi}{4}\right)[/tex]
[tex]\\ \rm\longmapsto tan135[/tex]
[tex]\\ \rm\longmapsto -1[/tex]
A man was traveling by air is allowed a maximum of 20kg luggages .The man has four bags weighing 3.5kg ,15 kg ,2kg and 1.5kg .Find excess weight of his luggage. 2 . Express the excess weight as a percentage of his maximum weight allowed.
Answer:
See explanation
Step-by-step explanation:
Maximum weight = 20 kg
Bag 1 = 3.5kg
Bag 2 = 15 kg
Bag 3 = 2kg
Bag 4 = 1.5kg
Total weight of bags = 22 kg
Excess weight of his luggage = Total weight of bags - Maximum weight
= 22 kg - 20 kg
= 2 kg
Express the excess weight as a percentage of his maximum weight allowed = excess weight / maximum weight × 100
= 2/20 × 100
= 0.1 × 100
= 10%
Express the excess weight as a percentage of his maximum weight allowed = 10%
please help me its hard
Answer:
1
Step-by-step explanation:
16-9=5t+2t
7=7t
1=t
Answer:
t = 1
Step-by-step explanation:
16 - 2t = 5t + 9
=> 16 - 2t - 9 = 5t
=> 16 - 9 = 5t + 2t
=> 7 = 7t
=> 7/7 = t
=> 1/1 = t
=> 1 = t
(100 PTS!!) Match the following vocabulary
Answer:
Step-by-step explanation:
1. arc length
2. semicircle
3. minor arc
4. arc measure
5. circumference
6. radius
7. diameter
HOPE THIS HELPS
Answer:arc length
2. semicircle
3. minor arc
4. arc measure
5. circumference
6. radius
7. diameter
Step-by-step explanation:
From the Rule y = -4x+1 fill in the following table
Answer:
y: 1, -3, -7, -11, -15
Step-by-step explanation:
Substitute the value of x in the chart for the formula given:
y = -4x + 1
For the first column in the x-row, do the following
y = -4(0) + 1
y = 1
And...
y = -4(1) + 1
y = -3
And so on.
CAN SOMEONE PLS TELL ME DOMAIN AND RANGE
Answers:
Domain is (-4, 3]Range is (-5, 5]=====================================================
Explanation:
The domain is the set of allowed x input values, aka the set of all allowed x coordinates of the points. We see that [tex]-4 < x \le 3[/tex]. It might help to draw vertical lines through the endpoints until you reach the x axis. Note the open hole at x = -4 to indicate we do not include this as part of the domain (hence the lack of "or equal to" for the first inequality sign).
The interval [tex]-4 < x \le 3[/tex] then can be condensed into the shorthand form (-4, 3] which is the domain in interval notation.
It says: x is between -4 and 3. It can't equal -4 but it can equal 3.
So the use of parenthesis versus square brackets tells the reader which endpoint is included or not.
--------------------------------------------------
The range describes all possible y outputs. We see that y = 5 is the largest it gets and y = -5 is the lower bound. It might help to draw horizontal lines through the endpoints until you reach the y axis. The open hole means -5 is not part of the range.
The range as a compound inequality is [tex]-5 < y \le 5[/tex]. This condenses into the shorthand of (-5, 5] which is the range in interval notation.
Verbally, the range is the set of y values such that y is between -5 and 5. It can't equal -5 but it can equal 5.
Answer:
Hello,
Step-by-step explanation:
Domain(f)= ]-4;3]={x€R | -4<x≤3}
Rang(f)=]-5;5]={y€R | -5< y ≤5}
Simplify the expression.
7(5 +t) - 4(t + 4)
7(5 + t) - 4(t + 4) = [
7(5 + t) - 4(t + 4) =
= 35 + 7t - 4t - 16 =
= 7t - 4t + 35 - 16 = 3t + 19
The inequalities x < -5 and -X > -5 are the same.
True
False
QUESTION-:
The inequalities x < -5 and -X > -5 are the same.
True
False
ANSWER-:
FALSE
!! HOPE ITS HELP U !!
X
( = [?]
DK
x Х
А AK
140°
B
HC
Angles are not drawn to scale
Answer:
40 degrees
Step-by-step explanation:
Supplementary angles are a pair of angles that add up to 180 degrees
Since ABD and DBC are supplementary, you can make the equation:
180=140+x
Simplify and you get x=40
[tex]\bf \large \implies \: \: x \: + \: 140 \degree \: = \: 180 \degree[/tex]
[tex]\bf \large \implies \: \: x \: = \: 180 \degree - \: 140 \degree[/tex]
[tex]\bf \large \implies \: \: x \: = \: 40 \degree[/tex]
james cuts 2 of his neighbor's lawn the first is 1000 m long and 100 m wide what is the area
Step-by-step explanation:
The formula for area is l x b. This stands for length and breadth. I can multiply 1000(100) to get 100,000m. The area of the lawn is 100,000 m.
HOPE IT HELPS YOU
MARK ME BRAINLIEST
evaluate each algebraic expression for the given values if the variable
[tex](4d)( - 5d)[/tex]
d= -8
Answer:
1280
Step-by-step explanation:
4d*(-5d)=-20(d)^2, d=-8. - 20*64=1280
Qualitative manpower is the most valuable assets of an organization
Answer:
True
Step-by-step explanation:
Office resources can be defined as all those means, facilities or equipments, including manpower that are utilized in the operation of various office procedures on a daily basis. Thus, office resources comprises means of communication, means of transportation, manpower (workers or employees), furniture, computer, etc.
Basically, the proper and efficient utilization of office resources determine the level of success that would be achieved in any office.
In Business management, office resources are generally grouped into five (5) main categories and these include;
I. Communication.
II. Transportation.
III. Material and office supplies.
IV. Sources of income (finance).
V. Manpower (human resources).
Manpower is also referred to as human resources or office personnels and it can be defined as the total number of people working from the lower hierarchy to top hierarchy of an organization, engaged in various jobs or tasks at different levels.
Basically, manpower is considered to be the most important type of office resources because it is vital for achieving the organizational goal.
This ultimately implies that, the most valuable assets of an organization is its qualitative manpower because it comprises human competence, skills and knowledge.
(
−
2
,
2
)
(−2,2) under a translation is
(
−
3
,
5
)
(−3,5). Find the coordinates of the image of the point
(
−
3
,
1
)
(−3,1) under the same translation.
Answer:
kslskd बोडलालामसूनिविवल
LCM of two even number is 220, find their sum
Answer:
Two consecutive even terms and LCM = 180
Let’s assume the two terms:
1st term : 2x
2nd term : 2x + 2
There is a rule which states that
If ‘a’ and ‘b’ are two numbers, then their product is equal to the product of their LCM and HCF.
i.e,
a∗b=HCF∗LCM - (i)
We can logically say that the HCF of any two consecutive even numbers is always equal to ‘2’ provided that the smallest no. is at least ‘2’.
i.e.,
HCF of ‘2x’ and ‘2x + 2’ is ‘2’ - (ii)
Therefore,
from (i) and (ii),
2x∗(2x+2)= HCF * LCM
2x∗(2x+2)=2∗180
x∗(2x+2)=180
2x2+2x−180=0
Solving the quadratic equation we get,
x=9,−10 (we discard -10 since it is negative)
Therefore, the numbers are
2∗9=18 (1st no.)
2∗9+2=18+2=20 (2nd no.)
Answer : 18,20
Step-by-step explanation:
WILL GIVE BRAINLEST!Two machines are printing shirts. The first machine can produce 2.400 shirts in 150 minutes. The second machine can produce 2.400 shirts in 120minutes. If the two work together, how long will it take them to produce 6,480 shirts? If necessary, round your answer to the nearest whole number.
Step-by-step explanation:
see the answer in attached picture
pls mark me as brainliest pls
Answer:
If two machine works together it takes 180 minute to complete 6480 shirts
Step-by-step explanation:
2400 ÷ 150 = 6
So here,
1st machine produces 20 shirts per minutes
let, x=minutes for shirt's production
Now,
(16+20)x=6480
36x=6480
x=6480/36
Therefor, x=180 minutes