Answer:
B.
Velocity describes how fast something is going, whereas Speed describes how fast something is going and in which direction.
Explanation:
. If the above statement is true, then describe an example of such a motion. ... b. What was the displacement for the entire trip? 0 miles (You finish where you started) ... Speed is a quantity that describes how fast or how slow an object is moving.
Which of the following statements best describes the corn plants below?
Answer:
The Bt gene is inserted into one plant cell by using a bacterial plasmid.
Explanation:
Athlete’s foot is also called...
A.) pedicure sickness Not Quite!
B.) runner’s bacteria Not Quite!
C.) toe virus Not Quite!
D.) tinea pedis
Answer:
Your answer is: D) Tinea Pedis
Explanation:
Hope this helped : )
The time it takes for a dragster to cross the finish line is unknown. The dragster accelerates from rest at 26 m/s2 for a quarter-mile (402 m). What is the final velocity of the dragster?
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
[tex] {v}^{2} - {v(0)}^{2} = 2.a.∆x[/tex]
[tex]v = final \: \: velocity[/tex]
[tex]v(0) = the \: \: velocity \: \: in \: \: the \: \: rest \: \: which \: \: is \: \: zero \\ [/tex]
[tex]a = acceleration[/tex]
[tex]∆x = covered \: \: distance[/tex]
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[tex] {v}^{2} - ({0})^{2} = 2 \times 26 \times 402 [/tex]
[tex] v = \sqrt{2 \times 26 \times 402} [/tex]
[tex]v = \sqrt{20904} [/tex]
[tex]v = 144.58 \: \: \frac{m}{s} [/tex]
Done...
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
While sitting in class, your body exerts a force of 600 N on your chair. How much work do you do?
Answer:
1000 N
Explanation:
Beginning: Identify the above circuits (A and B) as either a series or parallel circuit.
A ball is thrown up into the air with an initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed for the ball to reach its max height.
Answer:
B) t = 1.83 [s]
A) y = 16.51 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} -g*t[/tex]
where:
Vf = final velocity = 0
Vo = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.
A) The maximum height is reached when the final velocity of the ball is zero.
0 = 18 - (9.81*t)
9.81*t = 18
t = 18/9.81
t = 1.83 [s], we found the answer for B.
Now using the following equation.
[tex]y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\[/tex]
where:
y = elevation [m]
Yo = initial elevation = 0
y = 18*(1.83) - 0.5*9.81*(1.83)²
y = 16.51 [m]
Nikolas had an idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard.
Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to produce to propel Nikolas if he wanted to accelerate at a rate of 1.2 m/s2? Round your answer to the nearest whole newton.
60 N
Which of Newton’s laws did Nikolas have to use to calculate this force?
Answer:
I'm terrible at explaining so here's a screenshot, please do not listen to the other answer, it is wrong.
- Ripper
Explanation:
Answer:
C is the correct answer !!!
Explanation:
The lens in the eyepiece of a reflecting telescope breaks. How will this most affect the function of the telescope?
A. Magnified images will appear upside down. B. Magnified images will not be created.
C. Light from distant objects will not be captured.
D. Light rays will not be sent to the eyepiece.
Answer:
B
Magnified images will not be created.
Explanation:
I did it and this was the correct answer
Answer:
B is correct the person above me is also correct. Hope this helps
Explanation:
A man travels 25 kilometers in 15 minutes. A police officer stops him and
writes a ticket for speeding. The posted speed limit is 80 kilometers per
hour. Did the man exceed the posted speed limit?
Answer:
yes
Explanation:
cuz 15x2=30 30x2=60 60=1 hour, and the limited is 80 km per hour
15=25
15x4=60 25x4=100
so yes
he was going 100km per hour
A stunt man launches a car from the edge of a cliff horizontally. If he is launching off a
30-meter high cliff and must hit a mark 268-meters down range, with what speed
must he leave the cliff?
Answer:
All i got to say is that he is dead dead
Explanation:
A dumptruck filled with sand moves 1.8 km/h when it begins to accelerate uniformly at a constant rate. After traveling 4.0 102 m, the truck's speed is 24.0 km/h. What is the magnitude of the truck's acceleration?
The acceleration of the truck is obtained from the calculation done as 0.055 m/s^2.
What is the magnitude of the truck's acceleration?We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.
Initial velocity = 1.8 km/h or 0.5 m/s
Final velocity = 24.0 km/h or 6.67 m/s
Distance covered = 4.0 * 10^2 m
Then;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance covered
a = v^2 - u^2/2s
a = (6.67)^2 - (0.5)^2/2 * 4.0 * 10^2
a = 44.4 - 0.25/800
a = 0.055 m/s^2
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A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete is = 0.02. (a) What is the cart's acceleration if rolling friction is neglected? (b) What is the cart's acceleration if rolling friction is included?
Answer:
(a) 5.62 m/s²
(b) 5.46 m/s²
Explanation:
The given values are:
mass,
m = 50 kg
angle
= 35°
(a)
If friction neglected,
⇒ [tex]F_x=mgSin \theta=ma[/tex]
⇒ [tex]a_x=gSin \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}[/tex]
[tex]=5.62 \ m/s^2[/tex]
(b)
If friction present,
⇒ [tex]F_x=mgCos \theta[/tex]
⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]
⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]
[tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]
[tex]=5.46 \ m/s^2[/tex]
hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest
Answer:
A. Cue, White Ball, Blue Ball
Explanation:
Visualize in which order things are being hit
If your body were a tall building, your skeleton would be
Los satélites de televisión giran alrededor de la Tierra en una órbita de 42370 km de radio. a) ¿Cuánto vale la aceleración de la gravedad en esa órbita? (Resultado: g = 0,22 m/s2 ) b) ¿Cuánto pesará allí un satélite de 1200 kg? (Resultado: P = 264 N) Datos: G = 6,67 10-11 Nm2 /kg masa de la Tierra: 6 1024 kg
Answer:
(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) Un satélite de 1,200 kg pesará allí 264 N.
Explanation:
(a) Cada punto del espacio tiene un valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:
[tex]g=G*\frac{m}{r^{2} }[/tex]
donde m será masa, r la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]
En este caso:
m= 6*10²⁴ kgr=42,370 km= 42,370,000 mReemplazando:
[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]
Resolviendo, obtenes:
g= 0.22 [tex]\frac{m}{s^{2} }[/tex]
La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria. Esto se expresa matemáticamente como:
F= m*a
en donde F es fuerza neta , m la masa y a la aceleración.
El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:
P=m*g
En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].
Reemplazando:
P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]
Resolviendo:
P= 264 N
Un satélite de 1,200 kg pesará allí 264 N.
does anyone know how to do this? the scenario is ""dominique reads that race cars have wide tires because the increased area of contact between the tire and the road results in a stronger force of friction. she hypothesizes that the force of kinetic friction on an object is directly proportional to the area of the object in contact with the surface and wants to test this hypothesis. Dominique and Blake take a long wooden plank and cut the plank into pieces that have different lengths but the same width and height. The students also have access to other equipment commonly available in a school physics lab.
Answer:
Stupid
Explanation:
Because there is never a answer when we are trying to find one
A person travels by car from one city to another. He drives for 30.0 min at 80.0 km/h, 12.0 min at 105 km/h, and 45.0 min at 40.0 km/h, and he spends 15.0 min eating lunch and buying gas. What is the average speed for the trip?
Answer:
53.53 km/h
Explanation:
Given that the person drives for 30.0 min at 80.0 km/h, 12.0 min at 105 km/h, and 45.0 min at 40.0 km/h, and he spends 15.0 min eating lunch and buying gas.
So, the total time to complete the journey is
t=30+12+45+15=102 min
[tex]=\frac{102}{60}=1.7[/tex] hours
As distance=(speed)x(time), so
the distance covered in 30 minutes with a speed of 80 km/h
[tex]d_1=80 \times \frac{30}{60}=40[/tex] km.
The distance covered in 12 minutes with a speed of 105 km/h
[tex]d_2=105 \times \frac{12}{60}=21 km[/tex].
The distance covered in 45 minutes with a speed of 40 km/h
[tex]d_3=40 \times \frac{45}{60}=30 km[/tex].
So, to the total distance covered is
[tex]d=d_1+d_2+d_3[/tex]
[tex]=40+21+30=91 km[/tex]
As the average speed = (Total distance covered)/(Total time taken)
So, the average speed for the whole journey
[tex]=\frac{d}{t}[/tex]
[tex]=\frac{91}{1.7}= 53.53 km/h[/tex].
Hence, the average speed for the trip is 53.53 km/h.
Which is the balanced equation for Sg + O2 → SO2?
OS: + 016 — 8S02
O S₂ + O₂S₃ + O₂
O S8+ O₂S₂O₂
O Sg + 802 8S02
The balanced equation for S(g) + O₂ → SO₂ is as follows: S₈ + 8O₂ → 8SO₂ (option C).
What is a balanced equation?A balanced equation is a chemical equation in which the number of atoms of each element on both sides of the equation are the same.
This means that the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.
Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.
According to this question, sulfur reacts with oxygen gas to produce sulfur dioxide as follows:
S₈ + O₂ → SO₂
The balanced chemical equation is as follows:
S₈ + 8O₂ → 8SO₂
Learn more about balanced equation at: https://brainly.com/question/28294176
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When dribbling you should?
a. Use both feet.
b.Use frequent small touches of the ball.
C.Protect the ball with your body.
D. All of the above.
Which statement is supported by the information in the diagram and table below?
Answer:
a
Explanation:
a
În ce raport de mase trebuie amestecate două cantități din același lichid, având temperaturile t1=10 grade Celsius, respectiv t2=65 grade Celsius, pentru a obține o temperatură de echilibru t=45 grade Celsius?
Răspuns:
7: 4
Explicaţie:
Formula pentru calcularea cantității de căldură absorbită este exprimată ca;
Q = mc∆t
m este masa substanței
c este capacitatea termică specifică
∆t este schimbarea temperaturii
Conform legii calorimetriei, căldura pierdută de substanța rece = căldura câștigată de substanța fierbinte.
Folosind formula
(mc∆t) rece = (mc∆t) fierbinte
McCw∆tc = MhCw∆th
Deoarece au aceeași capacitate de căldură specifică, se vor anula. Ecuația devine;
Mc∆tc = Mh∆th ...... 1
Pentru apa rece;
∆tc = 45 ° C - 10 ° C
∆tc = 35 ° C
Pentru apa fierbinte:
∆th = 65 ° C - 45 ° C
∆th = 20 ° C
Înlocuiți în ecuația 1;
Mc (35) = Mh (20)
35Mc = 20Mh
Luând raportul dintre masa apei reci și cea fierbinte:
Mh / Mc = 35/20
Mh / Mc = 7/4
Prin urmare, lichidul trebuie amestecat împreună în raportul 7: 4
Adhira loves to ride her bike around the neighborhood. She starts riding 1.2 miles at 30° S of E. Then, she rides another 2.0 miles at 20° W of S. Next, she rides 1.6 miles at 30° S of W. And finally, she rides 2.6 miles at 15° W of N. What is her final displacement from her starting point?
Answer:
D = 1.8677 miles , θ = 24.28º at South of West
Explanation:
This is an exercise in adding vectors, the easiest way to solve them is to decompose the vectors and add each component algebraically. Let's use trigonometry
first displacement. d = 1.2 miles to 30º south of East
cos ( 360-30) = cos (-30) = x₁ / d
sin (-30) = y₁ / d
x₁ = d cos (-30)
y₁ = d sin (-30)
x₁ = 1.2 cos (-30) = 1,039 miles
y₁ = 1.2 sin (-30) = -0.6 miles
second shift. d = 2.0 miles to 20º West of South
cos (270-20) = x₂ / d
cos (250) = y₂ / d
x₂ = 2.0 cos 250 = -0.684 miles
y₂ = 2.0 sin250 = -1.879 miles
Third displacement. d = 1.6 miles to 30º South of West
cos (180 + 30) = x₃ / d
sin (210) = y₃ / d
x₃ = 1.6 cos 210 = -1.3856 miles
y₃ = 1.6 sin 210 = -0.8 miles
Fourth displacement. d = 2.6 miles to 15º West of North
cos (90 + 15) = x₄ / d
sin (105) = y₄ / d
x₄ = 2.6 cos 105 = -0.6729 miles
y₄ = 2.6 sin 105 = 2,511 miles
having all the components we add
x-axis (West-East direction)
X = x₁ + x₂ + x₃ + x₄
X = 1.039 -0.684 - 1.3846 - 0.6729
X = -1.7025 miles
Y = y₁ + y₂ + y₃ + y₄
Y = -0.6 -1.879 -0.8 +2.511
Y = -0.768
The modulus of this displacement is we use the Pythagorean theorem
D = √ (X² + Y²)
D = √ (1.7025² + 0.768²)
D = 1.8677 miles
let's use trigonometry to find the direction
tan θ = Y / X
θ = tan⁻¹ Y / x
θ = tan⁻¹ (0.768 / 1.7025)
θ = 24.28º
as the two components are negative this angle is in the third quadrant
therefore in cardinal direction form is
θ = 24.28º at South of West
HELP PLEASE
A load is a device that changes electrical energy into other forms of energy. Which load converts electrical energy into thermal energy by passing an electric current through a high-resistance material?
A.
Hand-powered generator
B.
Toaster
C.
Fan
D.
Electrical drill
Answer:
A toaster because you plug it up for electric energy and heat to toast it
when a car suddenly stops,the objects in the backseat are thrown forward.this is explained by-
A.Newton's first law of motion
B.Newton's second law of motion
C.Newton's third law of motion
D.the universal law of gravitation
Answer:law of interia(1st law)
Explanation:
PLEASE HELP THE question on picture
Vertical:
(20 m/s) sin(25º) ≈ 8.45 m/s
Horizontal:
(20 m/s) cos(25º) ≈ 18.1 m/s
What is one physical benefit that can be obtained from participating in field events?
A) strengthen balance
B) better sleep pattern
C) increase capacity for learning
D) all of the above
Answer:
D
Explanation:
It does all three
Marlene loves astronomy and has enrolled in an online course to learn more about space. The course gives Marlene access to a digital classroom.
What does this enable her to do? Check all that apply.
discuss the solar system with others in the class
attend a field trip to a planetarium at a local college
upload an amateur video of a shooting star
make a presentation about her favorite planet
take notes, tests, and quizzes
watch instructional videos made by a teacher
Answer:
A E and F are the correct answers
Explanation:
Answer:
A E F are correct
Explanation:
What is the speed of a
rocket that travels
8,000m in 13 seconds?
Answer:
speed of rocket=615.38m/s
Explanation:
find acceleration of block and tension in strings if m1 =8kg m2= 4kg and take g=10m/s²
[tex]\sf{m_1}[/tex] = 8kg
[tex]\sf{m_2}[/tex] = 4kg
g = 10m/s²
[tex]\large\bold{\underline{\underline{To \: Find:-}}}[/tex]→Acceleration of block
→Tension in strings
[tex]\large\bold{\underline{\underline{Solution:-}}}[/tex]Let, the two equation will be ,
[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)
[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)
Putting the value of equation no (1) and (2) we get,
[tex]\implies[/tex] 4g = 12a
[tex]\implies[/tex] 4 × 10 = 12a
[tex]\implies[/tex] 40 = 12a
[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]
[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]
Again, we have to putting the value of a in the equation no (2) we get,
[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]
[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]
[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40
[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]
[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N
[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².
And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N
What is the speed of a car that
accelerates at a rate of 10 m/s2 for a
total of 25 seconds?
Answer:
250 m/sExplanation:
The speed of the car can be found by using the formula
v = a × twhere
a is the acceleration
v is the speed
t is the time
From the question we have
v = 10 × 25
We have the final answer as
250 m/sHope this helps you
