Which of the following shows the proper Order of a food chain?

Answer:

43.96

Step-by-step explanation:

ok so you use the formula: A= 3.14•r•2 next you plug in your values a=3.14•7•2 3.14•7= 28.98•2=43.96

Answer:

43.96

im dying on the question before that one it says "What issues are you having when it comes to area and circumference" you typed nothing really and here you are asking us whats the circles area lol

Step-by-step explanation:

Answer:

133 Students

Step-by-step explanation:

Let the number of student in a van=v

Let the number of student in a bus=b

The senior class at Snellville rented and filled 12 vans and 14 buses with 796 students.

Therefore: 12v+14b=796

General High rented and filled 14 vans and 12 buses with 738 students.

Therefore: 14v+12b=738

We solve the two resulting equations simultaneously

12v+14b=796

14v+12b=738

Multiply equation 1 by 12 and equation 2 by 14 to eliminate b

144v+168b=9552

196v+168b=10332

Subtract

-52v=-780

Divide both sides by -52

v=15

We substitute v=15 to obtain b in any of the equations

12v+14b=796

12(15)+14b=796

14b=796-180

14b=616

Divide both sides by 14

b=44

Therefore a bus contains 44 Students and a Van contains 15 students.

Number of Students who would fill 2 buses and 3 vans

=2b+3v

=2(44)+3(15)

=133 Students

Answer:

13

Step-by-step explanation:

It should just be 104 divided by 8 which equals=13

Answer

the answer is -56

Step-by-step explanation:

Answer:

a) Null hypothesis:[tex]\mu \leq 120[/tex]  

Alternative hypothesis:[tex]\mu > 120[/tex]  

b) [tex]t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236[/tex]  

The degrees of freedom are given by:

[tex] df = n-1 = 80-1=79[/tex]

The p value for this case taking in count the alternative hypothesis would be:

[tex]p_v =P(t_{79}>2.236)=0.0141[/tex]  

Step-by-step explanation:

Information given

[tex]\bar X=130[/tex] represent the sample mean for the amount spent each shopper

[tex]s=40[/tex] represent the sample standard deviation

[tex]n=80[/tex] sample size  

[tex]\mu_o =120[/tex] represent the value to verify

t would represent the statistic    

[tex]p_v[/tex] represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 120[/tex]  

Alternative hypothesis:[tex]\mu > 120[/tex]  

The statistic for this case would be given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)  

Replacing the info given we got:

[tex]t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236[/tex]  

The degrees of freedom are given by:

[tex] df = n-1 = 80-1=79[/tex]

The p value for this case taking in count the alternative hypothesis would be:

[tex]p_v =P(t_{79}>2.236)=0.0141[/tex]  

Answer:

1 seconds after being thrown, the stone reaches its max height

Step-by-step explanation:

Answer:1 Seconds Is wrong the correct answer is 2

Step-by-step explanation:

Khan said so

PLEASE LIKE AND RATE IF YOU GOT YOUR QUESTION RIGHT!!!

Answer:

35%

Step-by-step explanation:

The total number of cinema seats can seat 280 people. Since 98 people take up 98 seats of the cinema, they are taking up 98 cinema seats out of the 280 cinema seats originally available.

As a fraction this would be written as  [tex]\frac{98}{280}[/tex] .

What you want to do is then divide 98 by 280 or 98/280, to get 0.35.

To get the percentage of seats filled, you must multiply the decimal you get by 100.

So it should look like this and your result should be 35%.

[tex]\frac{98}{280} = 0.35 *100=35[/tex]%

Answer:

[2,3)

Step-by-step explanation:

[0,1), [0,1),[0,1),[0,1)

[1,2), [1,2),[1,2),[1,2),[1,2),[1,2),[1,2),[1,2)

[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3)

[3,4),[3,4),[3,4),[3,4),[3,4),[3,4),[3,4)

Answer:

0.09

because I multiplied...

Answer:

0.09

Step-by-step explanation:

36/ 10 x 25/ 1000 = 18/ 5 x 1/40 = 9/100 = 0.09

Answer:

$353.28

Step-by-step explanation:

Answer:

7cm²

Step-by-step explanation:

Answer:

You don't need experiments to ask people questions

Answer:

The mean will increase, after the outlier is removed.

Answer:

vertex is: (4,-9)

y intercept= (0,7)

roots= (1,0) and (7,0)

Step-by-step explanation:

so we can use factoring to solve this quadratic equation real quick:

x^2-7x-1x+7

x(x-7)

-1(x-7)

(x-1)(x-7)=0

x-1=0

x=1

x-7=0

x=7

(1,0) and (7,0) are the roots

axis of symmetry: 8/2=4

substitute axsis of symmetry in equation to get vertex:

4^2-8(4)+7

16-32+7

-16+7=-9

vertex is: (4,-9)

y intercept= (0,7)

roots= (1,0) and (7,0)

Hope this helps

Answer:

Jumbo burger with fried is 75%

chicken with salad is 65%

Step-by-step explanation:

you first split the burger and sides. You add up the sides to find the salad. Then add up the sides and burgers

Answer:

What is the probability that he order a Jumbo Burger with Regular Fries or a Chicken Sandwich with a Salad? Make an area or tree diagram to help with the problem.

Answer to question: 20% for Jumbo Burger with Regular Fries and 10.5% for Chicken Sandwich with a Salad.

Step-by-step explanation:

You are going to find the probability that he order a Jumbo Burger with Regular Fries or a Chicken Sandwhich with a Salad by using a area model or a tree diagram. Although you ddin't ask me to solve it, I'm gonna help you with it anyways.

Sandwhiches:

50% - Jumbo Burger (JB)

30% - Chicken Sandwich (CS)

20% - Regular Burger (RB)

Sides:

40% - Curly Fries (CF)

35% - Salad (S)

25% - Regular Fries (RF)

Acronyms

Jumbo Burger (JB) + Curly Fries (CF) = JBCF

Jumbo Burger (JB) + Salad (S) = JBS

Jumbo Burger (JB) + Regular Fries (RF) = JBRF

Chicken Sandwich (CS) + Curly Fries (CF) = CSCF

Chicken Sandwich (CS) + Salad (S) = CSS

Chicken Sandwich (CS) + Regular Fries (RF) = CSRF

Regular Burger (RB) + Curly Fries (CF) = RBCF

Regular Burger (RB) + Salad (S) = RBS

Regular Burger (RB) + Regular Fries (RF) = RBRF

Probability of combinations:

JBCF = 0.5 x 0.4 = 0.20

JBS = 0.5 x 0.35 = 17.5

JBRF = 0.5 x 0.25 = 12.5

CSCF = 0.3 x 0.4 = 12

CSS = 0.3 x 0.35 = 10.5

CSRF = 0.3 x 0.25 = 7.5

RBCF = 0.2 x 0.4 = 8

RBS = 0.2 x 0.35 = 7

RBRF = 0.2 x 0.25 = 5

Your tree diagram should look something like this:

         CF(40%)- outcome - JBCF (20%)

          /  

(50%)JB ---  S(35%)-  outcome - JBS (17.5%)

           \            

           RF(25%)-  outcome - JBRF (12.5%)

         CF(40%)- outcome - CSCF (12%)

          /

(30%)CS ---  S(35%)- outcome - CSS (10.5%)

            \

            RF(25%)- outcome - CSRF (7.5%)

           CF(40%)- outcome - RBCF (8%)

           /

(20%)RB ---  S(35%)- outcome - RBS (7%)

          \

          RF(25%)- outcome - RBRF (5%)

Hope this helps because this took forever :D

Answer:

y = 3x-6

Step-by-step explanation:

y = 3x−5

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

m =3

Parallel lines have the same slope

We have the slope m=3 and a point (2,0)

y = mx+b

y = 3x+b

Substituting the point into the equation to solve for b

0 = 3(2)+b

0 = 6+b

b = -6

y = 3x-6

Answer:

y = 3x - 6

Step-by-step explanation:

Parallel lines have the same slope,

So m = 3

y - 0 = 3(x - 2)

y = 3x - 6

Answer:

25%

Step-by-step explanation:

Answer:

Step-by-step explanation:

To determine the PMF of the points that the team receive, we must determine the probabilities of winning each of the games.

Consider the firt game. We know that the probability of not losing is 0.4. Since the team can either lose the game or not, we have that the probability of losing it is 0.6. We are told that given that the team does not lose, the probability of winning or having a tie is the same. Recall that, given events A, B, the conditional probability P(A|B) (which means probability of A given B) is given as

[tex]P(A|B) = \frac{P(A\cap B)}{P(B)}[/tex]

in our case, we have that B:= not losing the game. Consider A:= To win the game, C:= To tie the game. We know that P(A|B)=P(C|B). When the team doesn't lose, then the team either ties or wins, this means that

[tex]P(A|B)+P(C|B) = 1[/tex]

So we get that P(A|B) = P(C|B) = 1/2. Let us find P(A)

[tex]P(A|B) = \frac{P(A\cap B)}{P(B)} = \frac{P(A)}{P(B)}=\frac{1}{2}[/tex]

Then [tex]P(A) = \frac{P(B)}{2} = 0.2[/tex]. By an analogous calculation we have that P(A) = P(C) = 0.2.

We will define the following events: [tex]W_i[/tex] is the event that the team wins the game i, [tex]T_i[/tex] is the event that the team ties the game i and [tex]L_i[/tex] is the event that the team loses the game i. In this notation, we have that

[tex]P(W_1) = P(T_1) = 0.2, P(L_1) = 0.6[/tex]

By reasoning the same way for the second game, we can calculate that

[tex]P(W_2)=P(T_2)=0.35, P(L_2) = 0.3[/tex]

To calculate the PMF we must check all the possible outcomes of the results of both games. Since we can either win (W), tie(T) or lose(L) a game, we will express the outcome as follows TW(3) means that the team ties  the first game and wins the second one, for a total of points. In this way, the possible outcomes are

WW(4), WT(3), WL(2), TW(3), TT(2), TL(1), LW(2), LT(1), LL(0)

We see that the number of possible points are 0,1,2,3,4. Let X be the number of points, to get the pmf of X is to give the probability P(X=k) for k=0,1,2,3,4 explicitly. Note that since each game is independent of each other, to get the probability of one of the outcomes it suffices to multiply the probability of each event. For example we have that [tex]P(WW) = P(W_1)\cdotP(W_2) = 0.07[/tex]

Then, the pmf is given by

[tex]P(X=0) = P(LL) = 0.18[/tex]

[tex]P(X=1)=P(LT)+P(TL) = 0.27[/tex]

[tex]P(X=2)=P(LW)+P(TT)+P(WL) = 0.34[/tex]

[tex]P(X=3)=P(WT)+P(TW) = 0.14[/tex]

[tex]P(X=4)=P(WW)= 0.07[/tex]

Answer:

Step-by-step explanation:

350-75%=87.5\\so 350-87.5\\=262.5\\$262.5 dolla profit\\

answer would be A because it u factor it out you will get your initial equation

Answer:

Which expression is equivalent to 3 over 175

I would say try - C or D

I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.

We have to turn K into the limits of integration on our integrals.

Clearly 0 is the lower limit for all three of x, y and z.

Now we have to incorporate

x+y+z ≤ 1

Let's do the outer integral over x.  It can go the full range from 0 to 1 without violating the constraint.  So the upper limit on the outer integral is 1.

Next integral is over y.  y ≤ 1-x-z.   We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y.  So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.

Similarly the inner integral goes from z=0 to z=1-x-y

We've transformed our integral into the more tractable

[tex]\displaystyle \int_0^1 \int_0^{1-x} \int _0^{1-x-y} (x^2-z^2)dz \; dy \; dx[/tex]

For the inner integral we get to treat x like a constant.

[tex]\displaystyle \int _0^{1-x-y} (x^2-z^2)dz = (x^2z - z^3/3)\bigg|_{z=0}^{z= 1-x-y}=x^2(1-x-y) - (1-x-y)^3/3[/tex]

Let's expand that as a polynomial in y for the next integration,

[tex]= y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3[/tex]

The middle integration is

[tex]\displaystyle \int_0^{1-x} ( y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3)dy[/tex]

[tex]= y^4/12 + (x-1)y^3/3+ (2x+1)y^2/2- (2x^3+1)y/3 \bigg|_{y=0}^{y=1-x} [/tex]

[tex]= (1-x)^4/12 + (x-1)(1-x)^3/3+ (2x+1)(1-x)^2/2- (2x^3+1)(1-x)/3[/tex]

Expanding, that's

[tex]=\frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1)[/tex]

so our outer integral is

[tex]\displaystyle \int_0^1 \frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1) dx[/tex]

That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).

[tex]= (5/5 + 16/4 - 36/3 + 16/2 - 1)/12[/tex]

[tex]=0[/tex]

That's a surprise. You might want to check it.

Answer: 0

Answer:

Start with making them equal.

1/8 --> 3/24

1/8 --> 3/24

1/3 --> 8/24

Now order them.

1/8, 1/8, 1/3.

Hope this helps ;)

Answer:

The attendance was 198 children, 90 students and 99 adults.

Step-by-step explanation:

We define:

c: children attendance

s: students attendance

a: adult attendance

The equation that describes the total ticket sales is:

[tex]5c+7s+12a=2808[/tex]

We also know that the children attendance doubles the adult attendance:

[tex]c=2a[/tex]

The third equation is the seating capacity, which we assume is full:

[tex]c+s+a=387[/tex]

We start by replacing variables in two of the equations:

[tex]c=2a\\\\s=387-c-a=387-2a-a=387-3a[/tex]

Then, we solve the remaining equation for a:

[tex]5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99[/tex]

Then, we solve for the other two equations:

[tex]c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90[/tex]

The attendance was 198 children, 90 students and 99 adults.

Answer:

  c.  y = 3.25^x

Step-by-step explanation:

At x=1, the value of y is slightly more than 3, so the base must be more than 3. The appropriate choice is ...

  y = 3.25^x

Answer:

A. n = -2

Step-by-step explanation:

A. n = -2

4(-2) + 9 = 1

-8 + 9 = 1

1 = 1

The value of n for which the statement of equation 4n + 9 = 1 holds true is n = -2.

Given an equation:

4n + 9 = 1

There are some given options for the value of n.

It is required to find the value of n, where the statement is true.

A) When n = -2:

4n + 9 = 4(-2) + 9

          = 1

B) When n = 2:

4n + 9 = 4(2) + 9

          = 17

C) When n = 3:

4n + 9 = 4(3) + 9

          = 21

D) When n = 4:

4n + 9 = 4(4) + 9

          = 25

Hence the true statement is when n = -2.

Learn more about Equations here :

https://brainly.com/question/29657988

#SPJ2

[tex]\text{Solve for y:}\\\\2y+2=\frac{3y}{2}\\\\\text{Multiply both sides by 2 to cancel the denominator}\\\\4y+4=3y\\\\\text{Subtract 3y from both sides}\\\\y+4=0\\\\\text{Subtract 4 from both sides}\\\\\boxed{y=-4}[/tex]

Answer:-4

Step-by-step explanation:

2y+2=3y/2

Cross multiply

2(2y+2)=3y

Open bracket

4y+4=3y

Collect like terms

4y-3y=-4

y=-4

Answer: C electricity

Step-by-step explanation:

It is

Answer:

A. associative property of addition

Step-by-step explanation:

Associative because you can add or multiply those regardless of how the numbers are grouped.

I hope this helped and have a good rest of your day!

Answer:

Associative Property of Addition

Step-by-step explanation:

This property states that the sum of 3 or more numbers stays the same, no matter how they are grouped.

Hope this helped. Have an awesome day!