Which of the following is NOT one of the main components of the cell theory?
1.Cells must contain DNA
2.All living things are made of cells
3.cells can only come from other cells
4.Cells are the basic unit of life

Which Of The Following Is NOT One Of The Main Components Of The Cell Theory?1.Cells Must Contain DNA2.All

Answers

Answer 1

Answer:

number 1 so a (=

Step-by-step explanation:

Answer 2
Number 1. “ cells must contain DNA”

Related Questions

Which expression is equivalent to 2x^2 - 2x + 7?

Answers

Answer:

(o,7) vertical intercept

minimum (1/2 , 13/2)

select the equation that represents the function given in the table below:

Please help!

Answers

Answer:

im to lazy to do an equation

Step-by-step explanation:

what is 2/3x + 1/4x= 6 ??????

Answers

Use Cymath to find your answer

Answer:

x=72/11

Step-by-step explanation:

The Reiter family uses three different-sized scoops to serve mashed potatoes : blobs, globs and gobs (these names are so weird aren't they). 2 blobs are equal to 1 glob, and 5 globs equal 3 gobs of mashed potatoes. A bowl holds 12 gobs of potatoes. How many blobs are there in the bowl? RATIO PROBLEM!!! DUH, DUH, DUHHHHHHH.

Answers

Answer: 30 blobs

Step-by-step explanation:

The ratios are:

2 blobs: 1 glob

5 globs: 3 gobs

If the bowl can hold 12 gobs, then we can multiply the 5:3 ratio by 4, to make solving easier. We get the ratio 15:12 and then we need to multiply the 2:1 ratio by 15 to get the answer 30 blobs

can someone help me pleas

Answers

The last choice is the correct answer (-1,-2)

Answer:

(-1,-2)

Step-by-step explanation:

D's original postion/location is at (1,-2)

You basically take the point D and keep your y coordinate, -2, the same /constant and change your x coordinate (flip the sign)

So keeping the y-coordinate constant, -2 changing positive 1 to negative 1

So.. D's location reflected on the y axis is (-1,-2)

*Let's Say: D was reflected on the x-axis you would do the opposite by keeping the x coordinate constant and flipping the y-coordinate sign (to positive)

So...

D's location reflected on the x-axis is (1,2)

Please help. with this question ​

Answers

Answer:

33  36 42 52 92

105

Step-by-step explanation:

If , which equation describes the graphed function? A. y = f(-x) − 3 B. y = -f(x) + 3 C. y = -f(x) – 3 D. y = f(-x) + 3

Answers

Answer:

y=-f(x)-3

Step-by-step explanation:

when f is negative it is reflected over the x-axis and -3 means to translate 3 units down

y = -f(x) – 3 describes the graphed function.

When f is negative it is reflected over the x-axis.

-3 means to translate 3 units down.

How do you identify a function?

By using inspecting the inputs (x-coordinates) and outputs (y-coordinates), you could decide whether or no longer the relation is a function. Keep in mind, that this is a feature each input has only one output.

What are examples of graph functions?

Function Graphs.Linear. Quadratic. Cubic. Square Root. Cube Root. Absolute Value. Reciprocal.

Learn more about graph functions here: https://brainly.com/question/4025726

#SPJ2

Find the slope of two points (1,-5)(10,6)

Answers

Answer:

11/9

Step-by-step explanation:

Answer: 11/9

Step-by-step explanation:

The slope is found by the change in y over the change in x

(6-(-5))/(10-1)

Simplify:

11/9

Donna wants to calculate the height of a tree. She finds the length of the tree's shadow is 25 meters and the angle of elevation from the ground to the top of the tree is 30°. Find the height of the tree to the nearest whole number.

Answers

Answer:55

Step-by-step explanation:

Help me plzzz I don’t understand this

Answers

The correct justification is to multiply each side by -3 where W= -18

Give three examples of equations where the solution will be unique that is only one solution is possible.

Answers

Answer:

5x = 3x

4+8t-y=y-t+8

98/r=34t

Step-by-step explanation:

Josh has been working andsaving money in order to buy a car andtravel the country. According to hiscalculations, it will cost him $1450 amonth for all his expenses. If Josh hassaved up $40,000, and will be purchasinga car for $16,500, at most, how manymonths will he have enough money totravel?

Answers

Answer:

16 months

Step-by-step explanation:

40k-16.5k=23.5k. 23.5k/1450= A little bit more than 16 months.

cuánto es 120 por 12

Answers

Answer:

120 x 12 = 1440

Step-by-step explanation:

Answer:

es 1440

Step-by-step explanation:

solo pones 120

x12

In a recent flu epidemic, the number of flu cases increased by 40% each week. There were 3,000 flu cases during the first week of January. How many more people were affected by the flu during the third week of January than during the first week?​

Answers

Answer:

2880

Step-by-step explanation:

The total number of people affected by flu during  the 2nd and 3rd week of January,  1200 + 1680  = 2880        

Answer

2880

Step-by-step explanation:

Olivia takes a trip to visit her aunt who lives 120 mi. away. Olivia's car can travel 24 miles per gallon of gasoline. If gasoline costs 03 per gallon, how much will Olivia pay for the gasoline for this trip? Show or explain your reasoning.

Answers

Answer:

$15

Step-by-step explanation:

Given that :

Aunt's distance = 120 miles

Miles per gallon of Olivia's car = 24 miles per gallon

Cost of gasoline = 3 per gallon

Cost of gasoline for the trip :

(Aunt's distance / miles per gallon) * cost of gasoline per gallon

(120 miles / 24 miles per gallon) * 3

5 * 3 = $15

Cost of gasoline for the trip = $15

someone please help!! 60 points!!

Answers

Answer:

It C am sure it correct....

Answer:

I think the answer would be C.

Ms. Guthrie spent 80% of her cash on gifts.
What fraction of her cash did she spend on gifts?
She spent type your answer...
of her cash on gift.

Answers

Answer:

She spend (8/10) or (4/5) of her cash on gift.

Step-by-step explanation:

4/5 is simplified.

but not simplified its 8/10

5. Evaluate 13 + 6 + 7 + 4.
b. 29
a. 2184
c. 20
d. 30

Answers

Answer:

D is the answer for the question

Answer:

30/D

Step-by-step explanation:

just add the numbers :)

A water tank fills through two pipes. Water flows in
through one pipe at a rate of 25,000 gallons per hour
and in through the other pipe at a rate of 45,000
gallons per hour. Water leaves the system at a rate of
60,000 gallons per hour.
There are 3 of these tanks, and each tank holds
1 million gallons. Each tank is half full. Water is
entering and leaving a tank at the maximum
amounts. Determine the number of hours, x, it will
take to fill all 3 tanks one at a time.​

Answers

Answer:

130,000

Step-by-step explanation:

Answer:oh hey yulissa ✌️

Step-by-step explanation:

Plz help me get the right answer

Answers

Model H shows 9/10
This is because have of 10 is 5
And you would only fill in half a circle after that

Hope this helps

Answer: Choice H (upper right corner)

====================================================

Explanation:

Refer to the diagram below.

I started with the set of five circles you were given. Then I cut each of them in half. This results in 2*5 = 10 sections (each section is numbered in blue). If you shade 9 of those 10 sections, then you'll represent the fraction 9/10. This is what choice H represents, so that's why it's the answer

9/10 = 0.90 in decimal form

0.90 = 90% in percent form

Another oneeeeeeeeeeeeeeeeee

Answers

Answer:

c

Step-by-step explanation:

pick me as the brainlist

Answer:

B. The student multiplied 380 by [tex]\frac{19}{20}[/tex].

Step-by-step explanation:

In the equation -[tex]\frac{3}{4}[/tex]y - [tex]\frac{1}{5}[/tex]y = 380, we can further evaluate the equation into:

-[tex]\frac{19}{20}[/tex]y = 380

To find y, we need to multiply 380 by the inverse of the fraction on the other side, which is -[tex]\frac{20}{19}[/tex]. However, the students multiplied 380 by [tex]\frac{19}{20}[/tex] to get 361. Thus, this was the mistake.

What is the surface area of a cylinder with a radius of 6 cm and a height of 3 cm?
A.108cm
B.72cm
C.54cm
D.36 cm?

Answers

Step-by-step explanation:

2πr^2h

2*22/7*6*6*3

2*22/7*36*3

2*22/7*108

determine the domain and range for this relationship. Drag the tiles to the correct locations. Not all tiles will be used.
domain:
range:
{4,4.5,5,5.5,6,6.5,7}
(i cant do the less than or equal to sign but its supposed to have the line under it.)
4 0 4 {4,5,6,7}
0 0 {0,1,2,3,4,5,6}

pleaseee help me thanks

Answers

Answer in the picture below!

help please I will give brainiest​

Answers

It should be D

If not I’m sorry

Find f(6); f(n) = 5 – 2n

Answers

Answer:

f(6)=-7

Step-by-step explanation:

Just plug in n=6 into the function:

f(n)=5-2n

f(6)=5-2(6)

f(6)=5-12

f(6)=-7

Therefore, the correct answer is f(6)=-7

Answer:

the answer is g=−12+ 30/n

Step-by-step explanation:

Who's is the faster runner? Raj can run 1 1/3 laps in 1/4 of an hour. Yvonne can run 4 1/2 laps in 7/8 of an hour.

Answers

raj can run faster than yvonne
Raj can run faster out of all of them

Integrate the following:
[tex]\displaystyle \int \frac{x^2}{x^2+x+3}\, dx[/tex]

Answers

Answer:

[tex]\int {\frac{x^2}{x^2+x+3} } \, dx = - \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} ) - \frac{1}{2}ln|x^2+x+3| +x + C[/tex]

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Completing the SquareRearranging Variables

Algebra II

Long Division

Calculus

U-Substitution[Integration Trick 1] Numerator Split[Integration Trick 2] Completing the SquareIntegration Rule 1: [tex]\int {cf(x)} \, dx = c\int {f(x)} \, dx[/tex]Integration Rule 2: [tex]\int {f(x)+g(x)} \, dx =\int {f(x)} \, dx + \int {g(x)} \, dx[/tex]Integration 1: [tex]\int {\frac{1}{u} } \, du =ln|u| + C[/tex]Integration 2: [tex]\int {\frac{du}{u^2+a^2} } = \frac{1}{a} arctan(\frac{u}{a} )+C[/tex]Integration 3: [tex]\int {x^n} \, dx = \frac{x^{n+1}}{n+1} +C[/tex]

Step-by-step explanation:

Step 1: Define

[tex]\int {\frac{x^2}{x^2+x+3} } \, dx[/tex]

Step 2: Simplify Function

We do long division to simplify the function inside the function.

See Attachment for Long Division Work.

Once we do long division, our function becomes [tex]1-\frac{x+3}{x^2+x+3}[/tex]

Now we rewrite our Integral: [tex]\int ({1-\frac{x+3}{x^2+x+3} }) \, dx[/tex]

Step 3: Integrate Pt. 1

Distributive Integral [Int Rule 1]:                    [tex]\int {1} \, dx - \int {\frac{x+3}{x^2+x+3} } \, dx[/tex]Integrate 1st Integral [Int 3]:                          [tex]x - \int {\frac{x+3}{x^2+x+3} } \, dx[/tex]

Step 4: Identify Variables Pt.1

Set variables for u-substitution.

u = x² + x + 3

du = (2x + 1)dx

Step 5: Integrate Pt. 2

Rewrite Integral [Int Rule 1]:                                                                [tex]x - \frac{1}{2} \int {\frac{2(x+3)}{x^2+x+3} } \, dx[/tex]Distribute 2 [Alg]:                                                                             [tex]x - \frac{1}{2} \int {\frac{2x+6}{x^2+x+3} } \, dx[/tex]Rewrite Integral [Alg]:                                                                      [tex]x - \frac{1}{2} \int {\frac{2x+1+5}{x^2+x+3} } \, dx[/tex]Rewrite Integral [Int Trick 1]:                                       [tex]x - \frac{1}{2} [\int {\frac{2x+1}{x^2+x+3} } \, dx + \int {\frac{5}{x^2+x+3} } \, dx ][/tex](2nd Int) Complete the Square:                              [tex]x - \frac{1}{2} [\int {\frac{2x+1}{x^2+x+3} } \, dx + \int {\frac{5}{(x+\frac{1}{2})^2 + \frac{11}{4} } } \, dx ][/tex]

Step 6: Identify Variables Pt. 2

Set variables for u-substitution for 2nd integral.

z = x + 1/2

dz = dx

a = √(11/4)

Step 7: Integrate Pt. 3

[Integrate] U-Substitution:                                 [tex]x - \frac{1}{2} [\int {\frac{1}{u} } \, du + \int {\frac{5}{z^2 + (\sqrt{\frac{11}{4}})^2} } \, dz ][/tex]Rewrite Integral [Int Rule 1]:                                     [tex]x - \frac{1}{2} [\int {\frac{1}{u} } \, du + 5\int {\frac{dz}{z^2 + (\sqrt{\frac{11}{4}})^2} } ][/tex]Integrate 1st Integral [Int 1]:                                       [tex]x - \frac{1}{2} [ln|u| + 5\int {\frac{dz}{z^2 + (\sqrt{\frac{11}{4}})^2} } ][/tex]Integrate 2nd Integral [Int 2]:                            [tex]x - \frac{1}{2} [ln|u| + 5(\frac{1}{\sqrt{\frac{11}{4}}}arctan(\frac{z}{\sqrt{\frac{11}{4} } } ) ) ][/tex]Distribute 5 [Alg]:                                                 [tex]x - \frac{1}{2} [ln|u| + \frac{5}{\sqrt{\frac{11}{4}}}arctan(\frac{z}{\sqrt{\frac{11}{4} } } ) ][/tex]Distribute -1/2 [Alg]:                                           [tex]x - \frac{1}{2}ln|u| - \frac{5}{2\sqrt{\frac{11}{4}}}arctan(\frac{z}{\sqrt{\frac{11}{4} } } )[/tex]Rationalize [Alg]:                                                   [tex]x - \frac{1}{2}ln|u| - \frac{5\sqrt{11} }{11}arctan(\frac{z}{\sqrt{\frac{11}{4} } } )[/tex]Resubstitute variables [Alg]:                              [tex]x - \frac{1}{2}ln|x^2+x+3| - \frac{5\sqrt{11} }{11}arctan(\frac{x+\frac{1}{2} }{\sqrt{\frac{11}{4} } } )[/tex]Simplify/Rationalize [Alg]:                     [tex]x - \frac{1}{2}ln|x^2+x+3| - \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} )[/tex]Rewrite [Alg]:                                [tex]- \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} ) - \frac{1}{2}ln|x^2+x+3| +x[/tex]Integration Constant:                            [tex]- \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} ) - \frac{1}{2}ln|x^2+x+3| +x + C[/tex]

And we have our final answer! Hope this helped you on your Calculus Journey!

hope this will help you........

can someone please help me factor and write the equations for these two problems ?

Answers

Answer:

Step-by-step explanation:

Asymptotes 3

g(x) = [tex]\frac{3x}{x^2-3x-10}[/tex]

Factors of denominator will be,

x² - 3x - 10 = x² - 5x + 2x - 10

                 = x(x - 5) + 2(x - 5)

                 = (x + 2)(x - 5)

Therefore, factored form of g(x) will be,

g(x) = [tex]\frac{3x}{(x + 2)(x - 5)}[/tex]

Asymptotes 4

h(x) = [tex]\frac{(x-5)}{x^{2} + 14x + 40}[/tex]

      = [tex]\frac{x-5}{x^{2}+10x+4x+40}[/tex]

      = [tex]\frac{x-5}{x(x+10)+4(x+10)}[/tex]

      = [tex]\frac{x-5}{(x+10)(x+4)}[/tex]

Calculati- 2x + 3y – 5x + y

Answers

Answer:

.10

x

2

+

11

x

y

6

y

2

Step-by-step explanation:

The Expression

=

(

2

x

+

3

y

)

(

5

x

2

y

)

=

2

x

(

5

x

2

y

)

+

3

y

(

5

x

2

y

)

=

10

x

2

4

x

y

+

15

x

y

6

y

2

=

10

x

2

+

11

x

y

6

y

2

.

50 points.


Record the simplified expression

Answers

Answer:

-4x+5

Step-by-step explanation:

-(4x-2) change sign of each in parenthesis so they are now -4+2

now you have -4x+2+3 add like terms

now you have -4x+5

Distribute

[tex]\sf \longmapsto−4x+2+3[/tex]

Combine like terms

[tex]\sf \longmapsto−4x+2+3[/tex]

[tex]\sf \longmapsto(−4x)+(2+3)[/tex]

[tex]\sf \longmapsto−4x+5[/tex]

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