Which of the following functions is graphed below?
(picture included)

Answer:9*y or 9y

Step-by-step explanation:

Answer:

Step-by-step explanation:

$13.1

Step-by-step explanation:

Right, okay, so this is a bit of a weird one. Let's go step by step.

"Today, 6 friends went out for lunch." = The number 6 is gonna be in our equation somewhere.

"Their total bill was $27.60" = so is the number 27.6

"They decided to split the bill equally" = 27.6 "split equally" (aka divided by) 6 friends is 4.6

"each paid with a $10 bill" = This is where it gets a lil weird. So, if they divided the bill among them, none of their amounts are gonna be anywhere near ten dollars. This is one of those questions that wouldn't really happen in real life. People would probably use fives instead, but whatever. So a number we'll be using for something is 10.

"How much money will each person get back?" = So we have to find the amount they all paid (10) minus the amount each one had to pay (4.6).

To put it all into a full equation...

10 - ( 27.6 / 6 )

Divide.

10 - 4.6

Subtract.

5.4

Put back into money form.

$5.40

Answer:

Each person will get back $5.40.

Answer:

if each paid a $10 bill, in total they paid $60 (cuz 10 x 6)

60 - 27.60 = 32.4

32.4/6 = 5.4 (divide the change between 6 people)

Each person will get $5.40 back.

hope it helps :)

Answer:

d=2

Step-by-step explanation:

We are given equation:

sqrt(4y-3)=d-y

Squaring both sides gives:

4y-3=(d-y)^2

Applying the identity (x+y)^2=x^2+2xy+y^2 on right:

4y-3=d^2-2dy+y^2

Now let's y=7:

4(7)-3=d^2-2d(7)+(7)^2

Simplify:

25=d^2-14d+49

Subtract 25 on both sides:

0=d^2-14d+24

Factor left:

0=(d-12)(d-2) since -2+-12=-14 and -2(-12)=24

This gives d=12 or d=2.

The d that makes d-y or I mean d-7 negative will give us y=7 as extraneous

Since 2-7 is -5, then d=2 is what we are looking for.

Check:

sqrt(4y-3)=d-y

Set d=2: sqrt(4y-3)=2-y

Now solve for y:

Square both sides: 4y-3=4-4y+y^2

Subtract 4y and 3 on both sides: 0=7-8y+y^2

Reorder right side: 0=y^2-8y+7

Factor: 0=(y-7)(y-1) since -7+-1=-8 and -7(-1)=7

This gives y=7 or y=1.

Plugging in y=7 for a check to this equation gives:

sqrt(4×7-3)=2-7

Sqrt(25)=-5

5=-5 which is not true which is what we wanted

Answer:

98 is the answer

Step-by-step explanation:

you add 8 each time

Answer:

a₁₃ = 98

Step-by-step explanation:

The nth term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = a₂ - a₁ = 10 - 2 = 8 , then

a₁₃ = 2 + (12 × 8) = 2 + 96 = 98

Answer:

Step-by-step explanation:

We know, for square

[tex](side)^2=(Area)\\=>X^2=8\\[/tex]

∴[tex]X=2\sqrt{2}[/tex] unit

[tex]Now, Side=3X[/tex]

[tex]Then,Area=(3X)^2=(3*2\sqrt{2} )^2=(6\sqrt{2} )^2=72 sq. unit[/tex]

hope you have understood this...

pls mark my answer as the brainliest

The area of square of side 3X is 72 square unit.

The square is a 4 sided figure, each side of the square is equal and make a right angle.

The area of square having sided a unit can be given by a² square unit.

Given that,

Area of square having side X is 8.

Since, formula for area of square having side X is X².

Implies that,

X² = 8

X = 2√2

The area of square having side 3X
side =3 × 2√2

side = 6√2

The area of square = (6√2)²

                                = 36 x 2

                                = 72

The area of square is 72 square unit.

To know more about Square on:

https://brainly.com/question/28776767

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Answer:

Vc. Tính giai cấp

Step-by-step explanation:

let other one be (x,y)

We know midpoint formula

[tex]\boxed{\sf (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)}[/tex]

[tex]\\ \sf\longmapsto (6,-4)=\left(\dfrac{13+x}{2},\dfrac{-2+y}{2}\right)[/tex]

[tex]\\ \sf\longmapsto \dfrac{13+x}{2}=6[/tex]

[tex]\\ \sf\longmapsto 13+x=12[/tex]

[tex]\\ \sf\longmapsto x=12-13[/tex]

[tex]\\ \sf\longmapsto x=-1[/tex]

And

[tex]\\ \sf\longmapsto \dfrac{-2+y}{2}=-4[/tex]

[tex]\\ \sf\longmapsto -2+y=-8[/tex]

[tex]\\ \sf\longmapsto y=-8+2[/tex]

[tex]\\ \sf\longmapsto y=-6[/tex]

Answer:

(- 1, - 6 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] ) ← midpoint formula

Use this formula on the endpoints and equate to the coordinates of the midpoint.

let the other endpoint = (x, y) , then

[tex]\frac{13+x}{2}[/tex] = 6 ( multiply both sides by 2 )

13 + x = 12 ( subtract 13 from both sides )

x = - 1

[tex]\frac{-2+y}{2}[/tex] = - 4 ( multiply both sides by 2 )

- 2 + y = - 8 ( add 2 to both sides )

y = - 6

The coordinates of the other endpoint are (- 1, - 6 )

Answer:

x= -1

Step-by-step explanation:

Since x= 5 is a vertical line, the unknown line would also be a vertical line with an equation of x=___ as they are parallel to each other.

Given that the line passes through (-1, 2), the equation of the line is x= -1.

Parallel lines have the same slope and will never meet.

Answer:

5  [tex]\frac{3}{4}[/tex]    

Step-by-step explanation:

2 [tex]\frac{1}{2}[/tex] + 3 [tex]\frac{1}{4}[/tex]

= (2 + 3) + [tex]\frac{1}{2} + \frac{1}{4}[/tex]    Here we add the two whole numbers first

= 5 +  [tex]\frac{1}{2} + \frac{1}{4}[/tex]

= 5 + [tex]\frac{2}{4} +\frac{1}{4}[/tex]      Here you bring the two fractions to a common denominator     and to to this you find the highest common factor of the denominators.

= 5 + [tex]\frac{3}{4}[/tex]       Here we added 1/4 and 2/4

= 5  [tex]\frac{3}{4}[/tex]    This is the answer simply add 5 and 3/4

HOPE THIS HELPED

Answer:

Step-by-step explanation:

Your answer is 5 3/4

Answer:

12

Step-by-step explanation:

Hello!

First of all you have to understand the order of operations.

PEMDAS

Parenthesis, Exponent, Multiplication/Divison, Addition, Subtraction.

From this you can see that we first have to deal with the exponent, then multiplication, then the addition.

So we get 2+9-(-1)

The 9 is from -3^2

2+9+1

11+1

12.

Hope this helps!

Answer:

75 and 75

Step-by-step explanation:

Answer:

Hello,

Step-by-step explanation:

2 solutions:

Using Pythagorean triplet

[tex]\\ \sf\longmapsto AB^2=AC^2-BC^2[/tex]

[tex]\\ \sf\longmapsto AB^2=4^2-3^2[/tex]

[tex]\\ \sf\longmapsto AB^2=16-9[/tex]

[tex]\\ \sf\longmapsto AB^2=7[/tex]

[tex]\\ \sf\longmapsto AB=\sqrt{7}[/tex]

[tex]\\ \sf\longmapsto Velocity=\dfrac{Displacement}{Time}[/tex]

[tex]\\ \sf\longmapsto Velocity=\dfrac{\sqrt{7}}{35}[/tex]

[tex]\\ \sf\longmapsto Velocity=\dfrac{2.6}{35}[/tex]

[tex]\\ \sf\longmapsto Velocity=0.07m/s[/tex]

Answer:

ln(x) = 1/x... It's a basic rule of Calculus.

Answer:

10 Km/h

Step-by-step explanation:

Let the speed of the container ship be y

The speed of the aircraft = y + 5

Next, we shall determine the time taken by the aircraft to travel 450 Km. This can be obtained as follow:

Speed of aircraft (Sₐ) = y + 5

Distance travelled (dₐ) = 450 Km

Time for aircraft (tₐ) =?

Speed = distance / time

Sₐ = dₐ / tₐ

y + 5 = 450 / tₐ

Cross multiply

(y + 5) × tₐ = 450

Divide both side by (y + 5)

tₐ = 450 / (y + 5)

Finally, we shall determine the speed of the carrier. This can be obtained as follow:

Speed of container ship (S꜀) = y

Distance travelled (d꜀) = 300 Km

Time for container ship (t꜀) = Time for aircraft (tₐ)

Time for aircraft (tₐ) = 450 / (y + 5)

t꜀ = tₐ

t꜀ = 450 / (y + 5)

Speed = distance / time

S꜀ = d꜀ / t꜀

y = 300 ÷ 450 / (y + 5)

y = 300 × (y + 5) / 450

y = (300y + 1500) / 450

Cross multiply

450y = 300y + 1500

Collect like terms

450y – 300y = 1500

150y = 1500

Divide both side by 150

y = 1500 / 150

y = 10 Km/h

Thus, the speed of the container ship is 10 Km/h.

Answer:

3 chocolate bars, and 2 graham crackers

Someone forgot the marshmallows...... :P

Step-by-step explanation:

Chocolate bars = 8 pack

Graham Crackers = 12pack

To have no crackers or chocolate left over, we need to find LCM

Factors of 8:

8, 16, 24, 32, 40, 48, 56, 72....

Factors of 12:

12, 24, 36, 48, 60, 72

The smallest LCM is 24

Chocolate bars:

24/8 = 3

Graham Crackers:

24/12 = 2

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

3 packs of chocolate and 2 packs of crackers

Step-by-step explanation:

the lowest common multiple of 8 and 12 is 24. We can determine this by prime factorization:

Prime factors of 8: 2 x 2 x 2

Prime factors of 12: 2 x 2 x 3

multipyling the bottom rungs of our factor tree we get: 2 x 2 x 2 x 3 = 24.

If you need me to draw the factor tree, just ask.

Answer:

-5

Step-by-step explanation:

Answer:

D. All three chose a valid first step toward solving the equation.

Step-by-step explanation:

Aaron, Blaine, and Cruz are solving the equation 4/7 (7 − n) = −1. Aaron started his solution by multiplying both sides of the equation by 7/4 . Blaine started by using the distributive property to multiply 4/7 by both 7 and −n. Cruz started by dividing both sides of the equation by 4/7 .

Which of the following is true?

A. Blaine and Cruz made an error in picking their first steps.

B. Cruz made an error in picking his first step.

C. All three made an error because the right side equals -1.

D. All three chose a valid first step toward solving the equation.

Given:

4/7(7 - n) = -1

Aaron:

4/7(7 - n) = -1

Multiple both sides by 7/4

4/7(7 - n) * 7/4 = -1 * 7/4

7 - n = -7/4

- n = -7/4 - 7

- n = (-7-28)/4

- n = -35/4

n = 35/4

Blaine:

4/7(7 - n) = -1

4/7(7 - n) × 7 = -1 × 7

4(7 - n) = -7

28 - 4n = -7

-4n = -7 - 28

- 4n = - 35

n = -35/-4

n = 35/4

Cruz:

4/7(7 - n) = -1

Divide both sides by 4/7

4/7(7 - n) ÷ 4/7 = -1 ÷ 4/7

4/7(7 - n) × 7/4 = -1 × 7/4

7 - n = -7/4

- n = (-7-28)/4

- n = -35/4

n = 35/4

D. All three chose a valid first step toward solving the equation.

Answer:

D-All three chose a valid first step toward solving the equation.

Step-by-step explanation:

Hope I Helped

Refer the attached image for the answer

HOPE SO IT HELPS YOU

Step-by-step explanation:

here u have answer of your question dear

Answer: width:60.2 cm

Length: 64.2 cm

Step-by-step explanation:

Given

The area of the rectangle is [tex]3990\ cm^2[/tex]

Width of the rectangle is [tex]x\ cm[/tex]

Length of the rectangle is [tex]x+4\ cm[/tex]

Area of the rectangle is the product of length and width

[tex]\therefore 3990=(x+4)x\\\Rightarrow 3990=x^2+4x\\\Rightarrow x^2+4x-3990=0\\\Rightarrow x=60.198\ or\ -65.198\ cm\\\text{Neglecting negative term}\\\Rightarrow x=60.198\approx 60.2\ cm[/tex]

Width of the rectangle is [tex]60.2\ cm[/tex]

Length of the rectangle is [tex]60.2+4=64.2\ cm[/tex]

Answer:

19 sin + 20 cosec

explanation

9 sin A + 10 sinA + 33 -13 cosecA

19 sin + 20 cosec

Answer:

1.5 per hour

Step-by-step explanation:

Answer:

y = 1/2x + 5/2

Step-by-step explanation:

y = 1/2x + b

5 = 1/2(5) + b

5 = 5/2 + b

5/2 = b

Answer: A

Step-by-step explanation: A function is when every domain (x value) corresponds to one range (y value) so that it passes the vertical line test

Answer:

28

Step-by-step explanation:

Subtract highest number from lowest.

92-64 = 28

Answer:

Step-by-step explanation:

Solve for a:

Answer:

Each of the 4 sectors have an area:

Find the area:

Outer perimeter of the frame:

Answer:

[tex] \rm\cos({600}^{ \circ} ) =-1/2 [/tex]

Step-by-step explanation:

we would like to solve the following using double-angle formula:

[tex] \displaystyle \cos( {600}^{ \circ} ) [/tex]

there're 4 double Angle formulas of cos function which are given by:

[tex] \displaystyle \cos(2 \theta) = \begin{cases} i)\cos^{2} ( \theta) - { \sin}^{2}( \theta) \\ii) 2 { \cos}^{2}( \theta) - 1 \\iii) 1 - { \sin}^{2} \theta \\ iv)\dfrac{1 - { \tan}^{2} \theta}{1 + { \tan}^{2} \theta } \end{cases}[/tex]

since the question doesn't allude which one we need to utilize utilize so I would like to apply the second one, therefore

step-1: assign variables

to do so rewrite the given function:

[tex] \displaystyle \cos( {2(300)}^{ \circ} ) [/tex]

so,

Step-2: substitute:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \cos ^{2} {300}^{ \circ} - 1[/tex]

recall unit circle thus cos300 is ½:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \left( \dfrac{1}{2} \right)^2 - 1[/tex]

simplify square:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2\cdot \dfrac{1}{4} - 1[/tex]

reduce fraction:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = \dfrac{1}{2} - 1[/tex]

simplify substraction and hence,

[tex] \rm\cos({600}^{ \circ} ) = \boxed{-\frac{1}{2}}[/tex]