One of the methods which will not reduce reactivity of observation is telling the person you are observing his/her behaviour. Correct option is B.
A practical, utilitarian approach, behavioral observation focuses on the plainly discernible ways in which the client engages with his or her surroundings. Behavioural observation can be used as a standalone technique or casually as a component of an interview, a test, or both.
Waiting until the subjects of the observation are used to the observer is one method to reduce reactivity. Another option is to have the observer document the actions without the subjects being aware of the observation.
The act of observation modifies in some manner the situation in which a participant is being observed. Within an experimental setting, reactivity is viewed as a threat to internal validity because the change in behaviour is not due to the experimental manipulation. Best choice is B.
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A 2 kg object is released from rest near the surface of a planet such that its gravitational field is considered to be constant. The mass of the planet is unknown. The
object's speed after falling for 3 sis 75 m/s. Air resistance is considered to be negligible, Calculate the weight of the 2 kg object on the planet of unknown mass.
2N
B
25 N
50N
D
75 N
of the three states of matter, which one has the most kinetic energy?
Of the three states of matter (solid, liquid, and gas), gas has the most kinetic energy. This is because the particles in a gas have the highest average speed compared to the particles in solids and liquids.
In a gas, the particles are in constant motion, colliding with each other and the walls of the container. This motion generates kinetic energy, which is proportional to the speed and mass of the particles. In contrast, solids have the lowest kinetic energy because their particles are tightly packed and have limited movement. The particles in a solid vibrate around a fixed position, and only experience small oscillations. Liquids have an intermediate amount of kinetic energy. The particles in a liquid are less tightly packed than in a solid, and can move more freely, resulting in more kinetic energy. However, liquids have more intermolecular forces between the particles compared to gases, which restricts their movement and reduces their average speed. Therefore, of the three states of matter, gases have the most kinetic energy, followed by liquids and then solids.
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if two identical resistors are connected in series to a battery, does the battery have to supply more power or less power than when only one of the resistors is connected? explain
The battery has to supply more power when two resistors are connected in series than when only one resistor is connected. This is because the power dissipated in a series circuit is equal to the sum of the power dissipated in each resistor.
When two identical resistors are connected in series to a battery, the battery has to supply more power than when only one of the resistors is connected. This is because the resistors offer resistance, which results in the dissipation of energy as heat. The higher the resistance of a resistor, the more power it requires to operate.Resistors consume energy as they offer resistance to the flow of current. The power supplied by the battery is converted to heat energy in the resistor, and the amount of heat energy dissipated is determined by the resistance of the resistor. The greater the resistance of the resistor, the more power it requires to function.
As a result, when two identical resistors are connected in series to a battery, the battery has to supply more power than when only one of the resistors is connected, to produce the same current through the circuit. Therefore, if two resistors of equal value are connected in series, the total power dissipated is twice that of when a single resistor is connected.
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when a 2.75-kg fan, having blades 18.5 cm long, is turned off, its angular speed decreases uniformly from 10.0 rad/s to 6.30 rad/s in 5.00 s. (a) what is the magnitude of the angular acceleration of the fan?
The angular acceleration of the fan is 0.740 rad/s^2,
Angular acceleration which represents the rate at which the angular velocity changes over time. The unit used to measure angular acceleration is radians per square second (rad/s2), according to the International System of Units. The Greek alphabet symbol alpha (α) is used to denote angular acceleration.
To calculate the angular acceleration of the fan, the formula α = Δω/Δt is used. Here, α represents angular acceleration, Δω represents the change in angular speed, and Δt represents the change in time.
In this scenario, Δω is equal to 10.0 - 6.30 = 3.70 rad/s, and Δt is equal to 5.00 s. By substituting these values into the formula, we obtain α = 3.70/5.00 = 0.740 rad/s^2.
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A 2. 00-kg object is attached to an ideal massless horizontal spring of spring constant 100. 0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2. 00-kg object traveling along the x-axis at 3. 00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision? 0. 300 m, 1. 26 s 0. 424 m, 5. 00 s 0. 424 m, 0. 889 s 0. 300 m, 0. 889 s 0. 424 m, 1. 26 s
The correct option is A, the amplitude and period of the oscillations that result from this collision are 0.300 m in 1.26s.
The expression for Period of spring is,
[tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]
Here, m is the mass of the spring and k is the spring constant
Substitute 2 kg
for m
and 100N/m
for k
in equation [tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]
and solve for T .
[tex]T = 2\pi\sqrt{\frac{(2)2 kg}{100 N/m} }[/tex]
T = 1.26s
In physics, amplitude refers to the maximum displacement or distance moved by a wave from its equilibrium or mean position. It is a measure of the intensity or strength of a wave, and it is usually represented as the height of the crest or depth of the trough of the wave.
The amplitude of a wave can be measured in various units, depending on the type of wave and the context in which it is being studied. For example, the amplitude of a sound wave is measured in decibels (dB), while the amplitude of an electromagnetic wave is measured in volts per meter (V/m). Amplitude plays an important role in the behavior of waves. It determines the energy carried by the wave and affects other properties such as frequency, wavelength, and phase.
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Complete Question: -
A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2.00-kg object traveling along the x-axis at 3.00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision
A) 0.300 m, 1.26 s
B) 0.300 m, 0.889 s
C) 0.424 m, 0.889 s
D) 0.424 m, 1.26 s
E) 0.424 m, 5.00 s
you live on an island in the pacific. an earthquake of magnitude 8.5 off the coast of japan, 8000 km away, generates a tsunami with a wavelength of 200 km. the average water depth between your island and japan is 4900 m. if a tsunami warning is issued for your island, how many hours will you have before the waves arrive?
If a tsunami warning is issued for the island, they will have approximately 11.7 hours before the waves arrive.
What is Magnitude?
Magnitude is a measure of the strength or intensity of a physical quantity or phenomenon, such as an earthquake or a sound wave. It is often expressed using a numerical scale, with higher values indicating greater strength or intensity. In the case of earthquakes, magnitude is typically measured using the Richter scale or the moment magnitude scale, which take into account the amplitude of seismic waves and the energy released by the earthquake.
To calculate the time it takes for a tsunami to travel from Japan to the island, we can use the following formula:
t = (2 * pi * d) / g * ln(1 + sqrt(h/d))
where t is the time it takes for the tsunami to travel, d is the average water depth, h is the wave height, and g is the acceleration due to gravity (9.8 m/s^2).
Magnitude of the earthquake: 8.5
Wavelength of the tsunami: 200 km = 200,000 m
Average water depth: 4,900 m
To calculate the wave height, we can use the following formula:
h = (M / 5) * (D / 10)^1/2
where M is the magnitude of the earthquake and D is the distance between the earthquake epicenter and the observation point (in this case, the island). Note that this formula is an approximation and may not be accurate for all cases.
Using the given values, we get:
D = 8,000 km = 8,000,000 m
h = (8.5 / 5) * ((8,000,000 / 10)^1/2) = 2,738.6 m
Substituting these values into the formula for t, we get:
t = (2 * pi * 4,900) / 9.8 * ln(1 + sqrt(2,738.6/4,900)) = 11.7 hours
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A small grinding wheel has a moment of inertia of 4. 0×10−5 kg⋅m2
k
g
⋅
m
2. What net torque must be applied to the wheel for its angular acceleration to be 150 rad/s2
r
a
d
/
s
2
?
A net torque of [tex]6.0×10^−3 N⋅m[/tex] is sufficient to produce the desired angular acceleration of [tex]150 rad/s^2[/tex].
The net torque required to produce an angular acceleration in a rotating object can be calculated using the formula: net torque = moment of inertia × angular acceleration In this case, the moment of inertia of the grinding wheel is given as 4.0×10^−5 kg⋅m^2 and the angular acceleration required is 150 rad/s^2.
Therefore, the net torque required can be calculated as: net torque = [tex](4.0×10^−5 kg⋅m^2) × (150 rad/s^2) = 6.0×10^−3 N⋅m[/tex]To explain this result, we need to understand the relationship between torque and angular acceleration. Torque is the rotational equivalent of force and it is defined as the product of force and the perpendicular distance between the line of action of the force and the axis of rotation.
When a torque is applied to a rotating object, it produces an angular acceleration in the object, which is a measure of how quickly the object's rotational speed changes.
The moment of inertia of an object is a measure of its resistance to changes in its rotational motion. It depends on the object's mass distribution and the distance of each element of mass from the axis of rotation. Objects with larger moments of inertia require more torque to produce a given angular acceleration than objects with smaller moments of inertia.
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In which of the following cases does a car have a negative velocity and a positive acceleration? A car that is traveling in the ................. (A) -x direction at a constant 10 m/s. (B) - direction increasing in speed. (C) +x direction increasing in speed. (D) - direction decreasing in speed. (E) +x direction decreasing in speed.
In the case where the car is traveling in the -x direction and decreasing in speed, it has a negative velocity and a positive acceleration. Therefore, option D is the correct answer. In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration.
Let's discuss the given options one by one:
(A) In this case, the car is traveling in the -x direction at a constant speed. Therefore, it has a negative velocity and zero acceleration. This option is incorrect.
(B) In this case, the car is traveling in the - direction and increasing its speed. Therefore, it has a negative velocity and a positive acceleration. However, the given direction is not specified, and thus this option is not accurate.
(C) In this case, the car is traveling in the +x direction and increasing in speed. Therefore, it has a positive velocity and a positive acceleration. This option is incorrect.
(D) In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration. This option is correct.
(E) In this case, the car is traveling in the +x direction and decreasing in speed. Therefore, it has a positive velocity and a negative acceleration. This option is incorrect.
Therefore, Option D ( - direction decreasing in speed) is correct.
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the end result of a theory that is not verified is
Unproven theories ultimately cannot be regarded as scientific facts or principles and are not generally recognised by the scientific community.
A well-supported explanation of a natural occurrence in science that has passed rigorous examination and is backed by empirical data is referred to as a theory. A hypothesis, however, cannot be regarded as a scientific fact or principle if it is not backed up by empirical data or if it has not undergone extensive testing and verification. The scientific community frequently rejects unproven notions with scant empirical backing and may even label them as pseudoscientific or non-scientific. This is so that scientific theories and findings may be evaluated and verified frequently. Science does this by using evidence-based reasoning and critical thinking. Unproven theories are therefore eventually not regarded as being a part of the corpus of scientific knowledge.
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the maximum energy of photoelectrons from aluminium is 2.3 ev for radiation of 2000 a and 0.90 ev for radiation of 3130 a. use this data to calculate plancks constant and the work function of aluminium
The maximum energy of photoelectrons from aluminium is 2.3 eV for radiation of 2000 Å and 0.90 eV for radiation of 3130 Å.
To calculate Planck's constant and the work function of aluminium, we need to use the equation:
h = E2 - E1/ λ2 - λ1
Where h is Planck's constant, E1 and E2 are the maximum energy of photoelectrons for each wavelength, and λ1 and λ2 are the wavelengths.
Using the given data, we have:
h = (2.3 - 0.90) / (2000 - 3130)
Therefore, h = -1.4 eV / -930 Å, which simplifies to h = 0.0015 eVÅ.
The work function of aluminium is equal to the maximum energy of the photoelectrons for the longest wavelength, in this case, 0.90 eV. Therefore, the work function of aluminium is 0.90 eV.
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Ceteris paribus, which of these events would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall?
• A dcrease investor confidance
• A decrease in cosmetic income and wealth • A strengh of time preference
• A decrease in capital productivity
Ceteris paribus, a decrease in capital productivity is the event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. The correct answer is option C.
Ceteris paribus is a Latin expression that means "all other things being equal." Ceteris paribus is a model in which economists use to analyze the effect of one independent variable on a dependent variable while keeping all other independent variables constant. This implies that only one variable is allowed to change while all other variables are held constant at their current level or position.
Therefore, Ceteris paribus, an increase in investor confidence, an increase in cosmetic income and wealth, and a strength of time preference will not cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. However, a decrease in capital productivity is an event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall.
When capital productivity is low, firms are unable to produce goods and services efficiently, and as a result, the demand for investment falls. When the demand for investment falls, the equilibrium quantity of investment will also decrease, leading to a decrease in the equilibrium interest rate.
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a particle's velocity is described by the function vx=kt2 , where vx is in m/s , t is in s , and k is a constant. the particle's position at t0=0s is x0 = -5.40 m . at t1 = 2.00 s , the particle is at x1 = 5.80 m .
A particle's velocity is described by the function vx=kt2 , where vx is in m/s , t is in s , and k is a constant. The particle's position at t0=0s is x0 = -5.40 m. At t1 = 2.00 s , the particle is at x1 = 5.80 m. The value of k is 2.80 m/s2.
The given equation describes the velocity of a particle in terms of a constant, k, and time, t. The velocity, vx, is given in m/s. The initial position of the particle at t0=0s is x0=-5.40 m, and at t1=2.00 s the particle is at x1=5.80 m. To find the value of the constant k, we can solve the equation for the change in velocity Δvx.
Δvx = vx1 – vx0 = k(t12 – t02)
Δvx = 5.80 – (-5.40) = 11.20 m/s
k = (11.20 m/s) / (2.002 s2) = 2.80 m/s2
Now that we have found the value of the constant k, we can use it to find the velocity of the particle at any time t. For example, at t2=4.00 s the velocity of the particle is vx2=11.20 m/s. This can be calculated using the equation vx2 = k(t22) = 2.80(4.002) = 11.20 m/s.
From the velocity equation, we can also calculate the position of the particle at any time t. The position of the particle at t2=4.00 s is x2= 11.20(4.00) = 44.80 m. We can also calculate the position of the particle at any other time t, by simply substituting in the corresponding value of t into the equation.
In conclusion, the equation vx = kt2 describes the velocity of a particle in terms of a constant, k, and time, t. Using this equation, we can calculate the velocity and position of the particle at any given time.
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Complete Question:
A particle’s velocity is described by the function vx = [tex]kt^2m/s[/tex], where k is a constant and t is in s. The particle’s position at [tex]t_0[/tex] = 0s is [tex]x_0[/tex] = -5.40 m. At [tex]t_1[/tex] = 2.00 s, the particle is at [tex]x_1[/tex] = 5.80 m. Determine the value of the constant k. Be sure to include the proper units
Assume that a drop of mercury is an isolated sphere. What is the capacitance in picofarads of a drop that results when two drops each of radius R = 5.61 mm merge?
The formula C=4R, where is the permittivity of open space, may be used to determine the capacitance of a merged mercury drop, assuming it is an isolated sphere. The capacitance is around 1.68 pF with R = 5.61 mm.
The formula C=4R, where R is the drop's radius and is the permittivity of free space, may be used to determine the capacitance of a merged mercury drop. As the capacitance of an isolated sphere is exactly proportional to its radius, the capacitance produced by the merger of two drops with similar radii is equal to the total of the capacitances of the individual drops. Given that the radius of the combined drop in this instance is R = 5.61 mm, the capacitance can be estimated using the formula C = 4(8.85 x 10-12 F/m) (5.61 x 10-3 m)2, yielding a capacitance of around 1.68 pF.
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for the given input voltage amplitude (200 mvpp), what is the maximum gain that this amplifier will be able to produce? show your calculation below.
The maximum gain of an amplifier that produces an output voltage amplitude of 50 Vpp with an input voltage amplitude of 200 mVpp is 25. The formula to calculate gain is output voltage amplitude divided by input voltage amplitude.
In this case, we are given an input voltage of 200 mVpp, so the maximum gain of this amplifier can be calculated as follows:
Gain = Output Voltage/Input Voltage = Output Voltage/200 mVpp
Therefore, the maximum gain of this amplifier is equal to the output voltage. In other words, the maximum gain of this amplifier is equal to the voltage output of the amplifier.
To calculate the output voltage of the amplifier, we need to know the supply voltage and the resistance of the load. Assuming the supply voltage is 5V and the load resistance is 10k ohms, the output voltage can be calculated as follows:
Output Voltage = Supply Voltage * Load Resistance / (Load Resistance + Output Resistance) = 5V * 10k ohms / (10k ohms + 10k ohms) = 5V
Therefore, the maximum gain of this amplifier is 5V/200 mVpp = 25.
To summarize, the maximum gain of this amplifier is 25, calculated by dividing the output voltage by the input voltage. The output voltage can be calculated by knowing the supply voltage and load resistance.
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This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Pin A, which is attached to link AB, is constrained to move in the circular slot CD. At t=0, the pin starts from rest and moves so that its speed increases at a constant rate of 1.2 in/s2 D 3.5 in. А B Determine the magnitude of its total acceleration when t= 0. The magnitude of its total acceleration is in/s2
The magnitude of the total acceleration of the pin when t=0 is 1.2 in/s^2.
To explain further, the acceleration of the pin is the sum of two components: tangential acceleration and centripetal acceleration. The tangential acceleration is responsible for increasing the speed of the pin, and its magnitude is constant at 1.2 in/s^2.
The centripetal acceleration is due to the circular motion of the pin in the slot CD and is directed towards the center of the circle.
To find the magnitude of the total acceleration at t=0, we need to first find the magnitude of the tangential acceleration and the centripetal acceleration separately. We know that the tangential acceleration is 1.2 in/s^2, and we can use the formula for centripetal acceleration, a_c = v^2/r, where v is the velocity of the pin and r is the radius of the circle. At t=0, the velocity of the pin is zero, and the radius of the circle is 3.5 inches.
Therefore, the centripetal acceleration is also zero.
Since the centripetal acceleration is zero, the magnitude of the total acceleration is equal to the magnitude of the tangential acceleration, which is 1.2 in/s^2.
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Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.20 m high. Assume it starts from rest and rolls without slipping.
Express your answer using three significant figures and include the appropriate units. Thank you!!
The translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.
We can use conservation of energy to solve this problem. The initial energy of the cylinder is all potential energy, and the final energy is all kinetic energy. The potential energy at the bottom of the incline is zero.
The potential energy of the cylinder at the top of the incline is given by:
PE = mgh
where m is the mass of the cylinder, g is the acceleration due to gravity, and h is the height of the incline. Substituting the given values, we get:
PE = (mass of cylinder) x (acceleration due to gravity) x (height of incline) = mgh
The kinetic energy of the cylinder at the bottom of the incline is given by:
KE = (1/2)mv^2
where v is the translational speed of the cylinder at the bottom of the incline.
According to the conservation of energy, the initial potential energy is equal to the final kinetic energy, so we can set these two expressions equal to each other:
mgh = (1/2)mv^2
We can cancel the mass of the cylinder from both sides, and solve for v:
v = sqrt(2gh)
Substituting the given values, we get:
v = sqrt(2 x 9.81 m/s^2 x 7.20 m) ≈ 9.43 m/s
Therefore, the translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.
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A light bulb used in a slide projector draws a current of 6 amperes when operating on 120 volts.. the power consumed by th light bulb in watts is? B.)a light bulb used in a slide projector draws a cuurent of 6 amperes when operating on 120 volts. the resistance of the light bulb in ohms is?
a..05
b.20
c.720
d.none
When a light bulb used in a slide projector draws a current of 6 amperes while operating on 120 volts, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb in ohms is 20. Thus, the correct option is B.
Why the resistance of a light bulb is 20 ohms?When we know that the current drawn by a light bulb is 6 amperes and the voltage applied to it is 120 volts, we can easily calculate the resistance of the light bulb, as follows:
Resistance (R) = Voltage (V) / Current (I)
here, V = 120V and I = 6A
Therefore, the resistance of the light bulb is:
R = V/I = 120/6 = 20 Ohms
The formula used to calculate the power (P) consumed by a light bulb is:
P = V × I
Here, the voltage (V) applied to the light bulb is 120 volts and the current (I) drawn by the light bulb is 6 amperes. So, the power consumed by the light bulb is:
P = 120 × 6 = 720 watts
Hence, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb is 20 ohms.
Therefore, the correct option is B.
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What gauge pressure must a pump produce to pump water from the bottom of Grand Canyon (elevation 730 m) to Indian Gardens (elevation 1370 m)? Express your results in pascals and in atmospheres.
The gauge pressure that a pump must produce to pump the water from the bottom of Grand Canyon to Indian Gardens is about 627080 pascals and 6.17 atm.
What is the gauge pressure?The difference in elevation of the two points = 1370 - 730 = 640m
Density of water, `ρ` = 1000 kg/m³
g = 9.8 m/s²
The gauge pressure must a pump produce to pump water from the bottom of Grand Canyon (elevation 730 m) to Indian Gardens (elevation 1370 m).
Formula used: `P = ρgh`
where, `P` is pressure, `ρ` is density of water, `g` is acceleration due to gravity, `h` is height difference between the two points.
The gauge pressure that must a pump produce to pump water from the bottom of Grand Canyon to Indian Gardens is 627080 Pa and 6.17 atm.
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What allowed the Voyager 2 spacecraft to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's?
1) NASA had developed a new kind of rocket that could propel the craft from planet to planet
2) the four planets were approximately aligned on one side of the Sun and we used the gravity of each planet to speed up the spacecraft to get to the next one in its path
3) the spacecraft stopped off to collect fuel on the satellites of each planet before proceeding to the next one
4) we used laser beams to propel the spacecraft into the outer solar system, where sunlight is dim
5) you can't fool me, no single spacecraft has ever explored four different planets
Answer:
The four planets were approximately aligned on one side of the Sun and we used the gravity of each planet to speed up the spacecraft to get to the next one in its path
Explanation:
All the Options 1, 2, 3, 4 are true about the Voyager 2 spacecraft to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's.
The Voyager 2 spacecraft was able to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's due to the following:
NASA had developed a new kind of rocket that could propel the craft from planet to planet.The four planets were approximately aligned on one side of the Sun and we used the gravity of each planet to speed up the spacecraft to get to the next one in its path.The spacecraft stopped off to collect fuel on the satellites of each planet before proceeding to the next one.We used laser beams to propel the spacecraft into the outer solar system, where sunlight is dim.Learn more about "NASA and spacecraft" at: https://brainly.com/question/16538247
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In outer space will a liquid in a beaker exert a pressure on the bottom or on the sides of a beaker?
Answer:
Yo dude, if you had a beaker of liquid in outer space, it wouldn't push down on the bottom or the sides of the beaker like it would on Earth. In space, there's no gravity to make the liquid settle down, so it forms a round shape because of surface tension. So basically, the liquid would just float around in a ball inside the beaker. If you moved the beaker around, the liquid would just roll around with it like a bouncy ball.
why do nuclear reactors have three separate water loops instead of just a single one that runs from the water source, through the reactor, then back to the cooling tower?
Nuclear reactors have three separate water loops instead of just a single one that runs from the water source, through the reactor, then back to the cooling tower because the water running through the reactor is highly radioactive.
What are nuclear reactors?A nuclear reactor is a device that controls and maintains a sustained nuclear chain reaction for the purpose of generating heat or power, as well as the materials that make up a nuclear reactor.
The water running through the reactor is highly radioactive, which means that it cannot be released into the atmosphere or allowed to come into touch with humans or the environment. As a result, nuclear reactors are designed with three separate water loops.
The first loop circulates ordinary water that passes through the reactor and generates heat. The second loop, which is a separate circuit, brings this water to a steam turbine. The third loop, which is also a closed circuit, recovers the cooling water after it has passed through the turbine and transports it back to the reactor's inlet.In summary, nuclear reactors have three separate water loops instead of a single one that runs from the water source, through the reactor, and back to the cooling tower because the water running through the reactor is highly radioactive.
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1. I’m in the 2nd column, 4th row, and I’m a metal. Who am I? ________________ 2. I’m a very lonely nonmetal. Who am I? ____________ 3. I’m the only metal who is a liquid at room temperature. Who am I? ____________ 4. I’m named after the person who created the 1st Periodic Table. Who am I? ___________ 5. I have 92 protons. Who am I? _____________ 6. I’m the only nonmetal who is a liquid at room temperature. Who am I? ___________ 7. I’m named after a very famous scientist. Who am I? ___________ 8. I have 46 electrons. Who am I? ____________ 9. My atomic mass is 183. 84. Who am I? _____________ 10. My chemical symbol is Ag. Who am I? ________________ 11. I’m the only metalloid in period 3. Who am I? ___________ 12. I’m the only element that is solid and a nonmetal in group 14. Who am I? _____________ 13. I have 5 neutrons. Who am I? ____________ 14. I’m the only gas at room temperature that is in group 16. Who am I? ___________ 15. I have 68 protons. Who am I? __________ 16. What element has the chemical symbol of Ir? ______________ 17. Which element is in group 7 and has 30 neutrons. Who am I? ___________ 18. I’m the only metal in group 15. Who am I? ____________ 19. I have 88 electrons. Who am I? ___________ 20. I’m the only gas at room temperature and in period 5. Who am I? ____________ 21. My symbol is Am. Who am I? ______________ 22. I’m the only nonmetal in period 6. Who am I? ____________ 23. My atomic number is 69. 723. Who am I? _________________ 24. I have 159 neutrons. Who am I? ________________ 25. I’m the only metalloid in group 17. Who am I? ______________ 26. I have 50 electrons. Who am I? __________________ 27. I’m in the 1st group and the 4th period. Who am I? ________________ 28. I’m a metalloid whose symbol is Sb. Who am I? ______________ ©JFlowers2017 Name: ______________________________ Date: ___________Class: ________ Periodic Table Scavenger Hunt Directions: You will use the Periodic Table to answer the questions. 1. I’m in the 17th column, a nonmetal, & a solid at room temperature. Who am I? ________________ 2. I have 79 electrons. Who am I? ____________ 3. I’m the only gas in period 6. Who am I? ____________ 4. My atomic mass is 257. Who am I? ___________ 5. My chemical symbol is Hs. Who am I? _____________ 6. I have 114 neutrons. Who am I? ___________ 7. I’m in the 18th group and 2 nd period. Who am I? ___________ 8. I have 67 protons. Who am I? ____________ 9. I’m a nonmetal who is solid at room temperature & has 2 letters for my symbol. Who am I? _________ 10. I’m in the 1 st group & 7 th period. Who am I? ________________ 11. I’m the only metalloid in group 13. Who am I? ___________ 12. I have 97 electrons. Who am I? _____________ 13. I am the only gas in column 15. Who am I? ____________ 14. My name is similar to Mickey Mouse’s best friend. Who am I? ___________ 15. I’m in group 11 & period 4. Who am I? __________ 16. I have 62 protons. Who am I? ______________ 17. My name fits really well with doctors because they try to do this. Who am I? ___________ 18. My name reminds me of where we all live. Who am I? ____________ 19. I’m the only nonmetal in period 2. Who am I? ___________ 20. My atomic number is 87. 62. Who am I? ____________ 21. My symbol is Mt. Who am I? ______________ 22. I’m in group 17 & the only metalloid. Who am I? ____________ 23. I have 71 electrons. Who am I? _________________ 24. My symbol is Pd. Who am I? ________________ 25. I’m Dorothy’s friend who needed a heart. Who am I? ______________ 26. I have 41 protons. Who am I? __________________ 27. I have 125 neutrons. Who am I? ________________ 28. My name comes from the 8th planet. Who am I? ______________
The Periodic Table of Elements served as the inspiration for this scavenger hunt. The exercise consists of two sets of questions, each of which has 28 questions that must be answered using the Periodic Table.
Students are tasked with identifying elements in the first set of questions using information from their attributes, such as the element's position on the periodic table, atomic mass, or quantity of electrons, protons, or neutrons. The objectives of the questions are to familiarise students with the properties of various elements and the structure of the Periodic Table. The second series of questions is comparable to the first, but more difficult because it asks students to identify components using less obvious cues, like their chemical symbol or a chemical formula. In order to succeed in their future studies of chemistry and other related sciences, students will benefit from being more familiar with the structure of the periodic table and the characteristics of various elements.
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the car passes over the top of a vertical curve at a with a speed of 50 km/hr and then passes through the bottom of a dip at b. the radii of curvature of the road at a and b are both 70 m. find the speed of the car at b if the normal force between the road and the tires at b is twice that at a. the mass center of the car is 1.2 meter from the road.
The speed of the car at b if the normal force between the road and the tires at b is twice that at a is about 44.1 km/h.
What is Speed?Speed of the car at A = 50 km/h
Radius of curvature at A = 70 m
Radius of curvature at B = 70 m
Normal force between the road and the tires at B = 2 × Normal force between the road and the tires at A= 2N
Mass center of the car = 1.2 m
The speed of car at B be v km/h
From the conservation of energy at the point A and B, we get:
1/2 mv² + mgh = 1/2 m(50)² + mg(70 - r)
1/2 mv² + mg(70 + r) = 1/2 m(50²)
1/2 mv² = 1/2 m50² - mg(70 + r) …… equation (1)
From the conservation of energy at point B, we get:
1/2 mv² + mg(2r + 1.2) = 1/2 m(50)² + mg(70 - r)
2× Normal force between the road and the tires at A = Normal force between the road and the tires at B
Normal force between the road and the tires at B = 2 × Normal force between the road and the tires at A
Therefore, mg - 2 × N = mv²/rmg - N = mv²/2r
2mg - 4N = mv²/rmg - 2N = mv²/2r
Subtracting, we get:
N = mg/3
Normal force between the road and the tires at A = mg/3
Normal force between the road and the tires at B = 2mg/3
Normal force between the road and the tires at B = 2(mg/3) = mg/3
From the above equations, we get the value of v. Putting the values, we get:
1/2 mv² = 1/2 m(50)² - mg(70 + r) - mg(2r + 1.2) + mg(70 - r)1/2 v² = 1/2(50)² - g(70 + r) - g(2r + 1.2) + g(70 - r)v = 44.1 km/h
Therefore, the speed of the car at B is 44.1 km/h.
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Review your answer to part c. In addition, reread the portion of your physics text that discusses Newton's third law. Then consider a book on a level table: e. Which force completes the Newton's third law (or action-reaction) force pair with the normal force exerted on the book by the table?
In this case, the normal force exerted by the table on the book is the action force and the reaction force is the force that the book exerts on the table. This force is equal in magnitude to the normal force and acts in the opposite direction.
Newton's third law states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on another object, the second object exerts a force back on the first object that is equal in magnitude and opposite in direction.
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The magnitude of the force between two point charges 1. 0 m
apart is 9 x 10°n. If the distance between them is doubled,
what does the force become?
Force will become 2.25 x 10^N. because, According to Coulomb's Law, the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Thus, if the distance between two point charges is doubled, the force between them will decrease by a factor of 4. This is because the inverse square relationship means that the force decreases rapidly with distance. Therefore, if the force between two point charges is 9 x 10^N when they are 1 meter apart, when the distance is doubled to 2 meters, the force will become 9 x 10^N / 4 = 2.25 x 10^N.
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A spring attached to a mass is at rest in the initial position (not shown). The spring is compressed in position A and is then released, as shown in position B. Which equation describes the conservation of energy in position A?
[tex]E=\frac{1}{2} mv^{2} \\E=mgh\\E=\frac{1}{2} kx^{2} \\E=\frac{1}{2} k2kx^{2}[/tex]
Answer:
Explanation:
The energy conservation is equal to half of the product of the spring constant and the square of displacement of the spring, so option C is correct.
two blocks with masses 4m and 7m are on a collision course with the same initial speeds vi. the block with mass 4m is traveling to the left, and the 7m block is traveling to the right. they undergo a head-on elastic collision and each bounces back, retracing its original path. find the final speeds of the particles. (enter your answers in terms of
The final speeds of the particles expressed in terms of the initial velocity are |v1'| = |v1| = 27/8|vi| and |v2'| = |v2| = 27/14|vi|
The conservation of momentum can be applied. The total momentum of the system before the collision is:
P before = m1v1 + m2v2
where m1 and v1 are the mass and velocity of the 4m block and m2 and v2 are the mass and velocity of the 7m block. Since the two blocks have the same initial speed, the momentum before the collision is:
P before = (4m)(-vi) + (7m)(vi)
P before = 3mvi
After the collision, the two blocks bounce back, so their final velocities are:
v1' = -v1
v2' = -v2
where v1 and v2 are the velocities of the blocks after the collision. Using the conservation of momentum again, the total momentum of the system after the collision is:
Pafter = m1v1' + m2v2'
Pafter = -4mv1 - 7mv2
Pafter = -4m(-v1) - 7m(-v2)
Pafter = 4mv1 + 7mv2
Since the collision is elastic, the total kinetic energy of the system is conserved. Therefore, the kinetic energy before the collision is equal to the kinetic energy after the collision:
Kbefore = Kafter
where Kbefore is the kinetic energy of the system before the collision and Kafter is the kinetic energy of the system after the collision. The kinetic energy can be expressed as:
K = 1/2mv²
Therefore, the total kinetic energy of the system before the collision is:
Kbefore = 1/2(4m)(vi)² + 1/2(7m)(vi)²
Kbefore = 27/2m(vi)²
The total kinetic energy of the system after the collision is:
Kafter = 1/2(4m)(-v1)² + 1/2(7m)(-v2)²
Kafter = 1/2(4m)(v1)² + 1/2(7m)(v2)²
Using the conservation of kinetic energy, Kbefore = Kafter:
27/2m(vi)² = 1/2(4m)(v1)² + 1/2(7m)(v2)²
Simplifying, the final velocities can be expressed in terms of the initial velocity:
v1 = 27/8vi
v2 = 27/14vi
Therefore, the final speeds of the particles are: |v1'| = |v1| = 27/8|vi| and |v2'| = |v2| = 27/14|vi|
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Is an object moving with a constany speed around a circular path veloctiy? why? why not?
Answer: The motion of a body with constant speed in a circular path is said to be accelerated, because it is moving with uniform speed, but not with uniform velocity, as velocity is a vector quantity, it can be represented in magnitude as well the direction.
Explanation:
discuss whether the values found in parts (a) and (b) seem consistent with the fact that tidal effects with earth have caused the moon to rotate with one side always facing earth.
Yes, the values found in parts (a) and (b) are consistent with the fact that tidal effects with earth have caused the moon to rotate with one side always facing earth.
This is because part (a) states that the moon rotates on its axis in the same amount of time it takes to complete one orbit around the Earth, which is a phenomenon known as tidal locking. Part (b) further indicates that the same side of the moon always faces the Earth, further supporting the notion that tidal effects have caused the moon to rotate with one side always facing Earth.
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A car has an intial velocity of 50 km hr after 5 h, its final velocity is 70 km hr. solve for the car acceleration
Answer:
4 km/hr^2
Explanation:
We can use the formula for acceleration:
a = (v_f - v_i) / t
where:
a = acceleration
v_f = final velocity
v_i = initial velocity
t = time taken
Substituting the given values, we get:
a = (70 km/hr - 50 km/hr) / 5 hr
a = 20 km/hr / 5 hr
a = 4 km/hr^2
