Which law is stated below?
All forces exist in action-reaction pairs.
A. Newton's third law
B. Newton's first law
C. Newton's second law
D. The law of inertia

Answers

Answer 1
That would be a, newton’s third law
Answer 2

Answer:

Maybe the answer is Newton's third law


Related Questions

Alexis is a scientist who is studying solid-state physics. Which activity would she most likely do as a part of this research? O identifying the optimal vessel for containing carbon dioxide O studying the atomic structure of solid carbon dioxide O determining the effect of pressure on the volume of carbon dioxide O observing the natural state of carbon dioxide​

Answers

Answer:

pretty sure its studying the atomic structure of a solid carbon dioxide. so c

Explanation:

Answer:

B. Studying the atomic structure of solid carbon dioxide

Explanation:

This is known as crystallography, the study of the arrangement of atoms in a solid, and it is a popular branch of solid-state physics.

Hope this helps :)

CAN SOMEONE PLS HELP ME ILL GIVE YOU BRAINLIEST!!!!

A 7000 N braking force is used to slow a car down. The car was traveling at 25 m/s before the
brakes were applied and was traveling at 5 m/s after 6 seconds. What is the mass of the car? (ANS:
2100 kg)

Answers

Answer:

the answer is already there lol

Explanation:

Answer:

answer is there you can see from there lol

Explanation:

how do icebergs form

Answers

Answer:

They break off large ice sheets found at the North and South poles.

Answer:

The answer is D

Explanation:

They break off large ice sheets found at the poles.

A 0.2 kg block sliding on a horizontal table slows down from 25 m/s to 20 m/s. How much energy does the block lose due to friction?

Answers

Answer:

the kinetic energy lost due to friction is 22.5 J

Explanation:

Given;

mass of the block, m = 0.2 kg

initial velocity of the block, u = 25 m/s

final velocity of the block, v = 20 m/s

The kinetic energy lost due to friction is calculated as;

[tex]\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 - \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J[/tex]

Therefore, the kinetic energy lost due to friction is 22.5 J

Answer:

22.5 J

Explanation:

It loses the difference in kinetic energy between the starting and ending speeds and that is (1/2)(M)(V1)^2 - (1/2)(M)(V2)^2 = (1/2)(M)((V1)^2 -(V2)^2) = (1/2)(0.2 kg)((25)^2 - (20)^2) = 22.5 Joules.

A rock from the top of a hill is falling from rest.

Object name?
Starting energy form?
Conversion?
Final energy form?
Non usable form of energy?

Answers

Object name:- Rock

Starting energy:- Kinetic energy

Conversion:- Potential to kinetic energy

Final energy form:- Potential energy

Non usable form if energy:- Nil [ As it has potential & kinetic both]

A first aid provider is trained to do the following except:
A) diagnose the victims condition
B) recognize, asses and prioritize the need for first aid
C) seek professional medical assistance when necessary
D) provide appropriate first aid care

Answers

A.
They’re supposed to help the person and cannot diagnose them as that is the job of a doctor

Courtney wants to practice doing science. Which example best illustrates her
using inquiry?
A. Courtney decides to drop several different objects off her
apartment's porch to see which falls the fastest.
B. Courtney pays close attention in her physical science class to see
if her teacher explains the speed of falling objects.
C. Courtney reads about the history of the study of gravity and learns
about why scientists first studied falling objects.
D. Courtney finds a calculation that explains the speed of falling
objects. She tries to understand the calculation by writing it down.

Answers

Answer:

A

Explanation:

because she wants to practice science and A is the practical option.

A steel railroad track has a length of 79 when the temperature is 2◦C. What is the increase in the length of the rail on a hot day when the temperature is 35◦C? The linear expansion coefficient of steel is 11 × 10−6 (◦C)−1.

Answers

Answer:

We know that the length is 79 (there are no units of length in the question, so i will leave it as it is written, without units) when the temperature is 2°C.

We want to find the increase in length when the temperature is 35°C, knowing that the linear expansion coefficient is 11*10^(-6) °C^-1

The change in length is just given by the equation:

[tex]\Delta L = \alpha*L_0* (T_1 - T_0)[/tex]

where:

α = 11*10^(-6) °C^-1

T₀ is the initial temperature, so T₀ = 2°C

T₁ is the final temperature, so T₁ = 35°C

L₀ is the initial length, so L₀ = 79

Replacing these in the equation we get:

ΔL = ( 11*10^(-6) °C^-1)*79*(35°C - 2°C)

     = 0.28677

So the length of the railroad will increase by 0.28677  

when two capacitors are connected in series, the effective capacitance is 2.4muF and when connected in parallel, the effective capacitance is 10muF. calculate the individual capacitances.​

Answers

Answer:

let one capacitor be x and other be y

[tex]in \: parallel \: connection : \\ \frac{x + y}{xy} = 10 \times {10}^{ - 6} - - - (a) \\ in \: series \: connection : \\ x + y = 2.4 \times {10}^{ - 6} - - - (b) \\ in \: (a) : \\ \frac{2.4 \times {10}^{ - 6} }{xy} = 10 \times {10}^{ - 6} \\ xy = 0.24 - - - (c) \\ from \: (b) : \\ y = (2.4 \times {10}^{ - 6} ) - x \\ \therefore \: in \: (c) : \\ x(2.4 \times {10}^{ - 6} - x) = 0.24 \\ 2.4 \times {10}^{ - 6} x - {x}^{2} = 0.24 \\ {x}^{2} - 2.4 \times {10}^{ - 6} x - 0.24 = 0 \\ x = 0.5 \\ 0.5y = 0.24 \\ y = 0.48 \\ { \boxed{ C _{1} = 0.5 \: farads}} \\ { \boxed{C _{2} = 0.48 \: farads}}[/tex]

Can someone help me :)

Answers

Answer:

undergone a chemical change

Explanation:

Answer:

undergone a chemical change

Some people can roll the tongue into a tube shape, while others cannot. Practicing is not likely to help because tongue-rolling is an inherited trait. The allele for rolling the tongue (R) is dominant to the allele for not being able to roll the tongue (r). Look at the Punnett square. It shows a cross between two parents with at least one R allele. Drag each option to its spot to correctly finish the Punnett square.

Answers

Hope this helps you.

Do only number 3 and thank

Answers

Charge = 0.2 Ah is the correct answer...

HELP ME ILL MARK U THE BRAINLIEST
the crane takes 2.5s to raise the box 3.0 m. Calculate the power output of the crane

Answers

Answer:

Power = 1800 W

Explanation:

Power = work / time

Power = 4500 / 2.5

Power = 1800 W

50N force accelerated a body at a rateof 8 metres per second square. Calculate the mass of the body​

Answers

Answer:

m=6.25kg

Explanation:

Force= mass × acceleration

50=m×8

make m subject of the formula...

m=50/8

m=6.25kg

Answer:

[tex]\boxed {\boxed {\sf 6.25 \ kilograms}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F= m \times a[/tex]

We know the force is 50 Newtons and the acceleration is 8 meters per second squared. Let's convert the units to make the problem and unit cancellation easier.

1 Newton is equal to 1 kilogram meter per square second (1 kg*m/s²), so the force of 50 N is equal to 50 kg*m/s².

Now we know 2 values:

F= 50 kg*m/s²a= 8 m/s²

Substitute the values into the formula.

[tex]50 \ kg *m/s^2= m \times 8 \ m/s^2[/tex]

Since we are solving for the mass, we must isolate the variable, m. It is being multiplied by 8 meters per square second and the inverse of multiplication is division. Divide both sides by 8 m/s².

[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= \frac{m \times 8 \ m/s^2}{8 \ m/s^2}[/tex]

[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= m[/tex]

The units of meters per square second (m/s²) cancel.

[tex]\frac {50 \ kg }{8 }=m[/tex]

[tex]6.25 \ kg =m[/tex]

The mass is 6.25 kilograms.

Determine the force exerted by two particles that have a charge of +0.35 Coulombs each and are 1 meter apart

Answers

The electric force between two charges is:

F = (9 x 10⁹) Q₁ Q₂ / D²

F is the force, in Newtons

Q₁ and Q₂ are the two charges, in Coulombs

D is the distance between them, in meters

For these two particles:

F = (9 x 10⁹) (0.35) (0.35) / (1)²

F = (9 x 0.35 x 0.35 x 10⁹) / (1)

F = 1.10 x 10⁹  Newtons

Thatsa lotta force . . . like 124 thousand tons !

The reason it's so big is because the charges in this question are so big ... 0.35 Coulombs each.  1 Coulomb is a huge amount of charge.

Each of the particles feels the same force, pushing it away from the other particle.  (The electric force between two charges is always the same in both directions, just like the gravitational force between two masses.)

Acc. to columb's law;

F = k × Q1Q2/r²

Clearly, from the question you have:

Charge on both particles = +0.35 columbsDistance between them = 1 meter = 1 × 10-¹ Å

Now just put them up in the formula:

F = k × Q1Q2/r²

F = 9 × 10⁹ × 0.35 × 0.35/1 × 10-¹⁰

F = 9 × 10⁹ × 35 × 35/ 10-¹⁰ × 100 × 100

F = 9 × 10⁹ × 35 × 35/ 10-¹⁰ × 10⁴

F = 9 × 10⁹ × 35 × 35/ 10-⁶

F = 9 × 10⁹+⁶ × 1225

F = 11025 × 10¹⁵

The diameter of a copper wire is thought to be approximately 0.3mm. Which instrument should be used to obtain a more accurate measurement of the diameter of the wire? A measuring tape B metre rule C micrometer D ruler 2

Answers

Answer:

C

Explanation:

The correct answer should be the micrometer.

The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.

In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.

The correct option is C.

can someone please help me with this question... thank u ❤️​

Answers

Answer:

Which of the following... : constant velocity horizontal motion

A ball is thrown at certain... : 0 m/s

Craig is modeling the discovery of electromagnetism. Which procedure should he use?

A. moving a magnet into a coil of wire in a closed circuit
B. moving a magnet into a coil of wire in an open circuit
C. bringing a compass near a wire that has no electric current
D. bringing a compass near a wire that has an electric current

Answers

Answer:

A

Explanation:

moving a magnet into a coil of wire in a closed circuit

Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism. Option A is correct.

What is electromagnetism ?

The physical interplay of electric charges, magnetic moments, and the electromagnetic field is known as electromagnetism.

The electromagnetic field can be static, moving slowly, or forming waves.

Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism.

Hence, option A is correct.

To learn more about the electromagnetism, refer to the link;

https://brainly.com/question/3427992

#SPJ2

as light passes from water into air it has a refracted angle of 35 degrees. calculate the incident angle of the light.

Answers

I think it’s 44 but I’m not sure

The length of an aluminium rod is 1m and the speed of sound along the rod is 5000 m per second .Find the values of f1 ad f2

Answers

Answer:

i. 2.5 kHz ii. 5 kHz

Explanation:

The frequency of the wave in the rod is given by f = nv/2L where n = harmonic, v = speed of sound in rod = 5000 m/s and L = length of rod = 1 m

i. f1

For f1, n = 1

f1 = 1 × v/2L

= v/2L

Substituting the values of the variables into the equation, we have

= 5000 m/s ÷ (2 × 1 m)

= 5000 m/s ÷ 2 m

= 2500 /s

= 2500 Hz

= 2.5 kHz

ii. f2

For f2, n = 2

f2 = 2 × v/2L

= v/L

Substituting the values of the variables into the equation, we have

= 5000 m/s ÷ 1 m  

= 5000 /s

= 5000 Hz

= 5 kHz

If the satellite weighs 1000g, orbits the Earth at an energy of 9.8 × 10 ^ 9j, what is the speed of the satellite?

Answers

Answer:

1.4×10⁵ m/s

Explanation:

Applying,

K = mv²/2............. Equation 1

Where K = Energy of the satellite, m = mass of the satellite, v = speed of the satellite.

make v the subject of the equation

v = √(2K/m)............ Equation 2

From the question,

Given: K = 9.8×10⁹ J, m = 1000 g = 1 kg

Substitute these values into equation 2

v = √(2×9.8×10⁹/1)

v = √(1.96×10¹⁰)

v = 1.4×10⁵ m/s

A certain AM radio wave has a frequency of 24Hz. Given that radio waves travel at 3 m/s, what is the wavelength of this radio wave?

Answers

Answer:

Wavelength of AM radio wave = 0.125 meter

Explanation:

Given:

Frequency of AM radio wave = 24 Hz

Velocity of AM radio wave = 3 m/s

Find:

Wavelength of AM radio wave

Computation:

Wavelength = Velocity / Frequency

Wavelength of AM radio wave = Velocity of AM radio wave / Frequency of AM radio wave

Wavelength of AM radio wave = 3 / 24

Wavelength of AM radio wave = 0.125 meter

A person weighs 60 kg. The area under the foot of the person is 150 cm2. Find the pressure exerted on the ground by the person.

Answers

Answer:

Pressure = 39200 N/m²

Explanation:

Given the following data;

Mass = 60 kg

Area = 150 cm²

Conversion:

1 centimeter square = 0.0001 meter square

150 centimeter square = 150 * 0.0001 = 0.015 m²

To find the pressure exerted on the ground by the person;

Mathematically, pressure is given by the formula;

[tex] Pressure = \frac {Force}{area} [/tex]

First of all, we would determine the force exerted by the person.

Force = mass * acceleration due to gravity.

We know that acceleration due to gravity is equal to 9.8 m/s².

Substituting into the formula, we have;

Force = 60 * 9.8

Force = 588 Newton

Next, find the pressure;

[tex] Pressure = \frac {Force}{area} [/tex]

Substituting into the formula, we have;

[tex] Pressure = \frac {588}{0.015} [/tex]

Pressure = 39200 N/m²

Mrs. Botts applies brakes on a car help it to decelerate at the rate of -0.80m/s2. What distance is required to stop the car when it is moving 17 m/s.

Answers

Answer:

Explanation:

vf=0

vi = 17

a = -0.8

Δx = ?

vf^2 = vi^2 + 2 a Δx

Δx = (vf^2 - vi^2) / 2a

Δx = (0-17^2) / 2 (-0.8)

Δx = 180.625 m

Your friends sit in a sled in the snow. If you apply a force of 95N to them they have an acceleration of 0.8 m/s2. What is their mass

Answers

there mass would be 83.33

define pressure snd state its SI units to​

Answers

Answer:

Pressure (P) is the amount of force applied perpendicular to the surface of an object per unit area. The SI unit of pressure is the pascal (Pa), which is equivalent to N/[tex]m^{2}[/tex] (newtons per meter squared).

Describe how a wind turbine generates energy.

Answers

The wind Wind turbines work on a simple principle: instead of using electricity to make wind—like a fan—wind turbines use wind to make electricity. Wind turns the propeller-like blades of a turbine around a rotor, which spins a generator, which creates electricity.

Pls help it’s really late <3

Answers

Answer:

22.4%

Explanation:

The plane is 300000 kg

It is 11000 meters about the earth's surface.

g = 9.81

PE = mgh

PE = 300000 * 9.81 * 11000

PE = 3.24* 10^10

The Kinetic Energy

KE = 1/2  m * v^2

m = 300000

v = 250 m/s

KE = 1/2 300000 * (250 m/s)^2

KE = 9.375 * 10^9

Total Energy = 3.24 * 10^10 + 9.375 * 10^9

Total Energy = 4.17 * 10^10

9.375 * 10^9

===========    * 100 % = 22.44 %

4.17 * 10^10

Explique cómo es que las estrellas emiten una radiación, específicamente qué es lo que sucede a nivel atómico

Answers

Answer:

Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella

A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella

Explanation:

Calculate the force that is applied on this 0.25 kg ball, as it goes down to hit the ground.
(given gravity= 9.8 m/s2).

Answers

Answer:

F = 2.45 N

Explanation:

m = 0.25 kg

a = 9.8 m/s^2

F = ma

F = (0.25)(9.8)

F = 2.45 N

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