Which is not an equation of the line that passes through the points (1, 1) and (5,5)?

Which Is Not An Equation Of The Line That Passes Through The Points (1, 1) And (5,5)?

Answers

Answer 1

Answer:

x - y = 0

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - 1 / 5 - 1

4/4

= 1

y = 1x + b

5 = 1(5) + b

5 = 5 + b

0 = b


Related Questions

Rectangle ABCD is similar to rectangle JKLM. AB = 12, BC = 8, CD = 12, DA = 8, and JK = 15. What is the scale factor from JKLM to ABCD? Reduce all answers.

Answers

Answer:

4/5 or 0.8

Step-by-step explanation:

this problem description is not very precise. it leaves out the definition what corners or sides of JKLM correspond to corners and sides of ABCD.

I assume J and K correlate to A and B, and JK is a long side of JKLM.

so, we are going from JKLM to ABCD.

that means we are going from larger to smaller (as JK = 15 and therefore larger than AB = 12).

what is the scale factor to go from 15 to 12 ?

15 × x = 12

x = 12/15 = 4/5 or 0.8

Find the value of x in Circle O.

Answers

Answer:

x=8

Step-by-step explanation:

x^2+15^2=17^2, x=sqrt(64)=8

For what values of k does the equation (2k + 1)x^2 + 2x = 10x – 6 have two
real and equal roots?

Answers

The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]

In this question, we use the concept of the solution of a quadratic equation to solve it, considering that a quadratic equation in the format:

[tex]ax^2 + bx + c = 0[/tex]

has two equal solutions if [tex]\Delta = b^2 - 4ac[/tex] is 0.

------------------------------------

In this question:

The equation is:

[tex](2k+1)x^2 + 2x = 10x - 6[/tex]

Placing in the correct format:

[tex](2k+1)x^2 + 2x - 10x + 6 = 0[/tex]

[tex](2k+1)x^2 - 8x + 6 = 0[/tex]

Thus, the coefficients are: [tex]a = 2k + 1, b = -8, c = 6[/tex]

------------------------------------

Delta:

We want it to be positive, so:

[tex]\Delta = b^2 - 4ac[/tex]

[tex]\Delta = 0[/tex]

[tex]b^2 - 4ac = 0[/tex]

[tex](-8)^2 - 4(2k+1)(6) = 0[/tex]

[tex]64 - 48k - 24 = 0[/tex]

[tex]-48k + 40 = 0[/tex]

[tex]-48k = -40[/tex]

[tex]48k = 40[/tex]

[tex]k = \frac{40}{48}[/tex]

[tex]k = \frac{5}{6}[/tex]

The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]

A similar question is found at https://brainly.com/question/12144265

common ratio of the geometric sequence 6,42,294

Answers

9514 1404 393

Answer:

  7

Step-by-step explanation:

If there is a common ratio, it can be found by finding the ratio of any two adjacent terms:

  42/6 = 7

The common ratio is 7.

If a translation of (x,y) (x+6,y-10) is applied to figure ABCD, what are the coordinates of D?

Answers

Image of figure ABCD is missing and so i have attached it.

Answer:

D_new = (-1, - 12)

Step-by-step explanation:

From the figure attached, the current coordinates of D are; (-5, -2)

Now, we are told the figure undergoes a translation of (x,y) (x+6,y-10)

Thus, this means we add 6 to the x value and subtract 10 from the y-value.

Thus, new coordinate of D is;

> (-5 + 6, -2 - 10)

> (-1, - 12)

Answer:

1, -12

Step-by-step explanation:

D = -5, -2

|

-5 + 6 = 1

|

-10 and -2 is -12

1, -12

did it on edge, got it right.

Câu 2. Cho hình thang cân ABCD (AB // CD, AB CD). Gọi O là giao điểm của AD và BC, E là giao điểm của AC và BD. Chứng minh rằng: | a) Tam giác AOB cân ở O.
b) Các tam giác ABD và BAC bằng nhau. C) EC = ED
d) OE là trung trực của AB và CD.

Answers

Answer:

Step-by-step explanation:

instructions find the value of x​

Answers

Answer:

Given two equal chords. Since the line from the centre is always equal, thus the lines that bisect the two chords are also equal. X=5

Trevor spent $27 and now has no money left. He had $___ before his purchase. He had $__before his purchase

Answers

Answer:

27

Step-by-step explanation:

Ive never really understood 8th-9th grade volume, could use some help

Answers

The answer is B

Eplanation:

V = pi * r² * (h/3)

Then from here you just make h the subject of the formula:

h = (V * 3)/(pi * r²)

h = (393*3)/[3.14* (10/2)²]

h = 15.01910828 ft

which is rounded to 15 ft...B

:)

Use the points slope formula..

Answers

Answer:

y = -5/14 -13/7

Step-by-step explanation:

First find the slope

m = (y2-y1)/(x2-x1)

m = (1 - -4)/(-8 - 6)

    = (1+4)/(-8-6)

   = 5/-14

   =-5/14

Point slope form is

y-y1 = m(x-x1)

y - -4 = -5/14(x-6)

y+4 = -5/14(x-6)

We want the equation in slope intercept form y = mx+b

Distribute

y+4 = -5/14x + 15/7

Subtract 4 from each side

y+4 -4= -5/14x + 15/7-4

y = -5/14x +15/7 - 28/7

y = -5/14 -13/7

Find the volume of each figure. Round your answers to the nearest tenth, if necessary​

Answers

Answer:

1.92

hopefully this answer can help you to answer the next question.

Simplify this expression.






I need u again pls

Answers

Answer:

The answer is the Second Option

Step-by-step explanation:

Answer:

the second one sqrt(10) + sqrt(15) -sqrt(14) - sqrt(21)

Step-by-step explanation:

HELPPPP
You invest $2700 in an account at 1.5% per year simple interest. The equation
that represents this scenario is:
A(n) = 2700 + (n - 1)(0.015. 2700)
How much will you have in the account in year 5? Round your answer to the
nearest dollar.

Answers

Second option. 1.5% of 2,700 is 40.5. Multiply that by 5 and you get 202.5 add that to 2,700 and you get 2,902.5. Round that and you get 2,903. Hence, the second option is correct.

Samantha has $35 in her savings account. At the end of each week, she will add $20 to the account. Which equation describes the total "S", in dollars, that Samantha will have in her account at the end of the week? * 1 point S = 15w S= 55w S = 20 + 35w S = 35 + 20w

Answers

Answer:

S = 35 + 20w

Step-by-step explanation:

Amount Samantha has in her account = $35

Additional savings per week = $20

Let

S =Totai savings in Samantha's account at the end of the week

w = number of weeks

The equation:

Totai savings in Samantha's account at the end of the week = Amount Samantha has in her account + (Additional savings per week * number of weeks)

S = 35 + 20w

Answer:

s=35+20w

Step-by-step explanation:

please help me to solve this

Answers

Answer:

Step-by-step explanation:

a) 3x^2

b) (512)^-2/3=2^n

1/64=2^n

n=-6

The first one Is 3x^2

Solve the following, where 0° < θ < 360°.
If cos θ=2/3 and tan θ<0
Find θ.

Answers

Answer:

The angle θ = 312°.

Step-by-step explanation:

0° < θ < 360°

If cos θ = 2/3 and tan θ < 0

As cos θ is positive and tan θ is negative so the angle is in fourth quadrant.

cos θ = 2/3

θ = 312°

a. IfA= {a, b} and B = {p, q, r}, find A x B and B x A using tree diagram.​

Answers

Answer:

Step-by-step explanation:

Can you help please answer will give Max points

Answers

Answer: 256/9 or 28 and 4/9

Answer:

28 4/9

Step-by-step explanation:

5 1/3 times 5 1/3

The question is "find the lowest common multiple of 4 and 6"
with step by step explaination

Answers

Answer:

12

Step-by-step explanation:

4s multiples:

4,8,12,16,20,24

6s multiples:

6,12,18,24,30,36

lowest number that is a common multiple between both 4 and 6:

12

Answer: 2

Step-by-step explanation:

There is a $30 fee to rent a tool from the local hardware store plus $6 per day. If Joe rents a jackhammer for 5 days, what is his total bill? The correct function for this situation is f(x) = 30x + 6.
O False
O True

Answers

The answer is false because the 30 and 6 would be in each other’s place

Decide !!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

[tex]\displaystyle [CQF]=5[/tex]

Step-by-step explanation:

Note that [tex][n][/tex] refers to the area of some polygon [tex]n[/tex].

Diagonal [tex]\overline{AC}[/tex] forms two triangles, [tex]\triangle ABC[/tex] and [tex]\triangle ADC[/tex]. Both of these triangles have an equal area, and since the area of parallelogram [tex]ABCD[/tex] is given as [tex]210[/tex], each triangle must have an area of [tex]105[/tex].

Furthermore, [tex]\triangle ADC[/tex] is broken up into two smaller triangles, [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex]. We're given that [tex]\frac{DF}{FC}=2[/tex]. Since [tex]DF[/tex] and [tex]FC[/tex] represent bases of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] respectively and both triangles extend to point [tex]A[/tex], both triangles must have the same height and hence the ratio of the areas of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] must be [tex]2:1[/tex] (recall [tex]A=\frac{1}{2}bh[/tex]).

Therefore, the area of each of these triangles is:

[tex][ACF]+[ADF]=105,\\[][ACF]+2[ACF]=105,\\3[ACF]=105,\\[][ACF]=35 \implies [ADF]=70[/tex]

With the same concept, the ratio of the areas of [tex]\triangle AQE[/tex] and [tex]\triangle DQE[/tex] must be [tex]2:1[/tex] respectively, from [tex]\frac{AE}{ED}=2[/tex], and the ratio of the areas of [tex]\triangle DQF[/tex] and [tex]\triangle CQF[/tex] is also [tex]2:1[/tex], from [tex]\frac{DF}{FC}=2[/tex].

Let [tex][DQE]=y[/tex] and [tex][CQF]=x[/tex] (refer to the picture attached). We have the following system of equations:

[tex]\displaystyle \begin{cases}2y+y+2x=70,\\y+2x+x=35\end{cases}[/tex]

Combine like terms:

[tex]\displaystyle \begin{cases}3y+2x=70,\\y+3x=35\end{cases}[/tex]

Multiply the second equation by [tex]-3[/tex], then add both equations:

[tex]\displaystyle \begin{cases}3y+2x=70,\\-3y-9x=-105\end{cases}\\\\\rightarrow 3y-3y+2x-9x=70-105,\\-7x=-35,\\x=[CQF]=\frac{-35}{-7}=\boxed{5}[/tex]

If someone could help that would really be great. Thank you.!

Answers

x=45 degrees
the angles should add up to 180 degrees in a triangle, so if you do 180-105-30, you end up with 45 (hope that helps)

The length, breadth and thickness of a brick is 18 cm, 8 cm, and 5 cm respectively. Find the area of the widest part of the brick. Also find the volume of the brick.​

Answers

Answer:

area = 8 × 18 = 144 cm^2

volume 8×18×5 = 720cm^3

Match the range of the function f(x) = x2 + 2x − 1 to its domain.
2 -2 3 -3
2 --
14 --
7 --
-1 --

Answers

Answer: (2,7) (-2,-9) (3,11) (-3,-13)

Step-by-step explanation:

(2)(2)+(2)(2)-1 = 7

(2) (-2)+(2)(-2)-1 = -9

(3)(2)+(2)(3)-1 = 11

(-3)(2)+(2)(-3)-1 = -13

Please help me
A person starts walking from home and walks: 6 miles East 6 miles Southeast 3 miles South 5 miles Southwest 2 miles East This person has walked a total of 22Correct miles Find the total displacement vector for this walk: If this person walked straight home, they'd have to walk miles

Answers

Answer:

1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)

2) The number of miles they'd have to walk is approximately 13.856 miles

Step-by-step explanation:

1) The distance, direction, and location of the path of the walk the person takes,  are listed as follows;

Start location, (0, 0)

6 miles East walk to location, (6, 0)

6 miles Southeast to location, (6 + 3·√2, -3·√2)

3 miles South to location, (6 + 3·√2, -3·√2 - 3)

5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)

2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)

(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)

Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)

The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)

d =  (16 + √2)/2)·i - (6+11·√2)/2)·j

2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;

[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]

Therefore;

If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]

Evan is on holidays in Beijing, China. He took a taxi from the airport to his hotel. It cost him 375 Chinese yuan. He went $15 AUD over his travel budget on the taxi ride. How much Chinese yuan does Evan get for every Australian dollar if he budgeted $60 for the taxi ride?


Answers

This question is solved using proportions, and doing this, it is found that Evan gets 5 Chinese yuans for every Australian dollar.

-----------------------------------------

Evan budgeted $60 for the taxi ride.He went $15 over, thus, the taxi ride cost $75.In Chinese yuans, the cost was 375.

-----------------------------------------

75 dollars are worth 375 yuans. How much yuans is a dollar worth?

1 dollar - x yuans

75 dollars - 375 yuans

Applying cross multiplication:

[tex]75x = 375[/tex]

[tex]x = \frac{375}{75}[/tex]

[tex]x = 5[/tex]

Evan gets 5 Chinese yuans for every Australian dollar.

A similar question is given at https://brainly.com/question/23352001

Which pair of polygons is congruent?

Answers

Answer:

C

Step-by-step explanation:

Polygon 3 and 5 are congruent cause they have the same length of side

[100 Points]
SHOW YOUR WORK, PLEASE!

Answers

Answer:

691 251/256

Step-by-step explanation:

So basically exponents is how much time you time the same number

First on the top is 2 exponent 4. that is 2x2x2x2=16

Second is 3 exponent 3. 3x3x3=27

Third is 9 exponent 7. 9x9x9x9x9x9x9=4782969

Fourth is 4 exponent 6. 4x4x4x4x4x4=4096.

All together is 16/27x4782969/4096=691 251/256

What is the factored form of the expression 3x^2 + 6x – 24

Answers

Answer:

(3)(x + 4)(x-2)

Step-by-step explanation:

3x^2 + 6x – 24

3(x^2 + 2x - 8)

(3)(x + 4)(x-2)

Answer:

3(x - 2)(x + 4).

Step-by-step explanation:

3x^2 + 6x – 24

= 3(x^2 + 2x - 8)

= 3(x - 2)(x + 4).

find the distance of gap d

Answers

Answer:

[tex]\displaystyle d \approx 15.8768[/tex]

Step-by-step explanation:

We want to find the distance of d or AB.

From the right triangle with a 35° angle, we know that:

[tex]\displaystyle \tan 35^\circ = \frac{50}{PB}[/tex]

And from the right triangle with a 42° angle, we know that:

[tex]\displaystyle \tan 42^\circ = \frac{50}{PA}[/tex]

AB is PA subtracted from PB. Thus:

[tex]\displaystyle d = AB = PB - PA[/tex]

From the first two equations, solve for PB and PA:

[tex]\displaystyle \frac{1}{\tan 35^\circ } = \frac{PB}{50} \Rightarrow PB = \frac{50}{\tan 35^\circ}[/tex]

And:

[tex]\displaystyle \frac{1}{\tan 42^\circ } = \frac{PA}{50} \Rightarrow PA = \frac{50}{\tan 42^\circ}[/tex]

Therefore:

[tex]\displaystyle d = AB = \frac{50}{\tan 35^\circ} - \frac{50}{\tan 42^\circ}[/tex]

Using a calculator:

[tex]\displaystyle d= AB \approx 15.8768[/tex]

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