Which is equivalent to (-m)4x n2 ?

Answer:

The rotation rule states that rotation 90° counterclockwise means (x, y) = (-y, x)

The new points would be equal to:

Try graphing it to see if the new points make sense(because I'm not too sure :\)

Answer:

so the answer is 0.16339

The question isn't well stated ; If the question intends to ask the meaning of the inequality :

Answer:

Kindly check explanation

Step-by-step explanation:

Given the inequality : y ≥ 3

This inequality statement or expression means that :

y is true for all values beginning from 3 and beyond

That is values from 3 makes the expression a true statement.

Therefore values of y for which the inequality holds or is true are :

(3,....)

Answer:

100

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(-93 - 3)² + [-37 - (-9)]

√(-96)² + (-28)²

√9216 + 784

√10000

= 100

D. 2.3.5 is the correct answer

Answer:  [tex]y=\frac{1}{4}x-7[/tex]

Step-by-step explanation:

The perpendicular slope of the line(m) = [tex]-\frac{1}{m}[/tex]:

The function formula is y = mx + b, where the y-intercept(b) is found by substituting in the values of a point on the line ⇒ (4, -6):

[tex]y=\frac{1}{4}x+b\\-6=\frac{1}{4}(4)+b\\-6=1+b\\b=-6-1=-7[/tex]

So the perpendicular equation is [tex]y=\frac{1}{4}x-7[/tex].

Answer:

z (min)  =  2079

L = 26     D =  39.6    S  =  16.5

Step-by-step explanation:

L  numbers of hours assigned to Lisa

D numbers of hours assigned to David

S numbers of hours assigned to Sara

Objective Function to minimize:

z = 30*L  +  25*D  +  18*S

Constraints:

Total time available

L  +  D  +  S  ≤ 110

Lisa experience

L  ≥  0.4 *  ( L + D )  then    L ≥ 0.4*L  +  0.4*D

0.6*L - 0.4*D ≥ 0

To provide designing experience to Sara

S ≥ 0.15*110        then     S ≥ 16.5

Time for Sara

S  ≤ 0.25 * ( L + D )     S ≤ 0.25*L  +  0.25*D   or    -0.25*L - 0.25*D + S ≤0

Availability of Lisa

L ≤ 50

The Model is:

z = 30*L  +  25*D  +  18*S  to minimize

Subject to:

L  +  D  +  S  ≤ 110

0.6*L - 0.4*D ≥ 0

S ≥  16.5

-0.25*L - 0.25*D + S ≤0

L ≤ 50

L ≥   0  ;   D  ≥  0  , S  ≥  0

After  6  iterations  optimal ( minimum ) solution is:

z (min)  =  2079

L = 26     D =  39.6    S  =  16.5

The formula that can be used to determine the number of hours each graphic designer should be assigned to the project to minimize the total cost is z = 30L + 25D + 18S and the minimum z is 2079.

Given :

The formula that can be used to determine the number of hours each graphic designer should be assigned to the project to minimize the total cost is given by:

z = 30L + 25D + 18S

The constraints are given by:

1) L + D + S [tex]\leq[/tex] 110

2) L [tex]\geq[/tex] 0.4(L + D)  

   L [tex]\geq[/tex] 0.4L + 0.4D

   0.6L - 0.4D [tex]\geq[/tex] 0

3) S [tex]\geq[/tex] 0.15(110)

   S [tex]\geq[/tex] 16.5

Now, to minimize 'z' then use:

[tex]\rm -0.25L-0.25D+S\leq 0[/tex]

L [tex]\leq[/tex] 50

L [tex]\geq[/tex] 0, D [tex]\geq[/tex] 0, S [tex]\geq[/tex] 0

Now, the minimum z is given by:

z = 2079

L = 26,  D = 39.6,  S = 16.5

For more information, refer to the link given below:

https://brainly.com/question/23017717

Answer:

50.24 or 50.272

Step-by-step explanation:

Square radius and then times by 3.14 or 3.142

4^2*3.14 = 50.24

4^2*3.142 = 50.272

Answer:

3/2 + 7

Step-by-step explanation:

Answer:

A. d

Step-by-step explanation:

If you find the 3rd square root or whatever its called, and multiply it by itself again 3 times, You end up with d again.

Answer:

fgvilgiuhuikj

Step-by-step explanation:??????????????

Answer:

B

Step-by-step explanation:

(6)^1/2 × (8)^1/2

6^1/2 × 2 (2)^1/2

4 (3)^1/2

Answer:

Slope = [tex]\frac{4}{3}[/tex]

Equation of the line → [tex]y=\frac{4}{3}x[/tex]

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = [tex]\frac{4-0}{3-0}[/tex]

m = [tex]\frac{4}{3}[/tex]

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

[tex]y=\frac{4}{3}x[/tex]

Answer:

[tex] \cos(x) = - \frac{5}{ \sqrt{41} } [/tex]

[tex] \csc(x) = \frac{ \sqrt{41} }{4} [/tex]

[tex] \tan(x) = - \frac{4}{5} [/tex]

Step-by-step explanation:

We know that (-5,4) is the terminal side. This means out legs will measure 5 and 4 if we graph it on a triangle.

We need to find the cos, csc, and tan measure of this point.

We can find cos by using the formula of

[tex] \cos(x) = \frac{adj}{hyp} [/tex]

The adjacent side is -5 and we can find the hypotenuse by doing pythagorean theorem.

[tex] { - 5}^{2} + {4}^{2} = \sqrt{41} [/tex]

So using the info the answer is

[tex] \cos(x) = \frac{ - 5}{ \sqrt{41} } [/tex]

We can find tan but first me must find sin x.

[tex] \sin(x) = \frac{opp}{hyp} [/tex]

[tex] \sin(x) = \frac{4}{ \sqrt{41} } [/tex]

So now we just use this identity,

[tex] \tan(x) = \sin(x) \div \cos(x) [/tex]

[tex] \tan(x) = \frac{ \frac{4}{ \sqrt{41} } }{ \frac{ - 5}{ \sqrt{41} } } = - \frac{4}{5} [/tex]

So tan x=

[tex] - \frac{ 4}{5} [/tex]

We can find csc by taking the reciprocal of sin so the answer is easy which is

[tex] \frac{ \sqrt{41} }{4} [/tex]

Answer:

[tex]A = 200,000(1+.025) ^{t}[/tex]

[tex]A = 200,000(1+.025) ^{10}[/tex]

Step-by-step explanation:

9514 1404 393

Answer:

  372 m²

Step-by-step explanation:

A vertical line down the center of the figure will divide it into two congruent trapezoids, each with bases 13 and 18, and height 12.

The area of one of them is ...

  A = 1/2(b1 +b2)h

So, the area of the two of them together is ...

  A = (2)(1/2)(b1 +b2)h = (b1 +b2)h

  A = (13 m + 18 m)(12 m) = 372 m²

Answer:

The maximum error in calculating the surface area of the box is 72 square centimeters.

Step-by-step explanation:

From Geometry, the surface area of the closed rectangular box ([tex]A_{s}[/tex]), in square centimeters, is represented by the following formula:

[tex]A_{s} = w\cdot l + (w + l)\cdot h[/tex] (1)

Where:

[tex]w[/tex] - Width, in centimeters.

[tex]l[/tex] - Length, in centimeters.

[tex]h[/tex] - Height, in centimeters.

And the maximum error in calculating the surface area ([tex]\Delta A_{s}[/tex]), in square centimeters, is determined by the concept of total differentials, used in Multivariate Calculus:

[tex]\Delta A_{s} = \left(l+h\right)\cdot \Delta w + \left(w+h\right)\cdot \Delta l + (w+l)\cdot \Delta h[/tex] (2)

Where:

[tex]\Delta w[/tex] - Measurement error in width, in centimeters.

[tex]\Delta l[/tex] - Measurement error in length, in centimeters.

[tex]\Delta h[/tex] - Measurement error in height, in centimeters.

If we know that [tex]\Delta w = \Delta h = \Delta l = 0.2\,cm[/tex], [tex]w = 60\,cm[/tex], [tex]l = 50\,cm[/tex] and [tex]h = 70\,cm[/tex], then the maximum error in calculating the surface area is:

[tex]\Delta A_{s} = (120\,cm + 130\,cm + 110\,cm)\cdot (0.2\,cm)[/tex]

[tex]\Delta A_{s} = 72\,cm^{2}[/tex]

The maximum error in calculating the surface area of the box is 72 square centimeters.

Answer:

Volume of composite figure = 44.9 feet³

Step-by-step explanation:

Given:

Height of cylinder = 3.5 feet

Diameter of cylinder = 3.5 feet

Diameter of hemisphere = 3.5 feet

Find:

Volume of composite figure

Computation:

Radius of cylinder and sphere = 3.5/2 = 1.75 feet

Volume of composite figure = Volume of cylinder + Volume of hemisphere

Volume of composite figure = πr²h + (2/3)πr³

Volume of composite figure = (3.14)(1.75)²(3.5) + (2/3)(3.14)(1.75)³

Volume of composite figure = (3.14)(3.0625)(3.5) + (2/3)(3.14)(5.359375)

Volume of composite figure = 33.656875 + 11.2189583

Volume of composite figure = 44.8758

Volume of composite figure = 44.9 feet³

Answer:

2.3 pounds

Step-by-step explanation:

First, the mean is equal to the sum divided by the number of numbers.

There are four packages, so there are four numbers. Let's say the fourth package has a weight of x. We can then write

mean = sum / number of numbers

2.5 = (1.8+3.2+2.7+x)/4

multiply both sides by 4 to remove the denominator

10 = 1.8+3.2+2.7+x

10 = 7.7 + x

subtract 7.7 from both sides to isolate the x

x = 2.3 pounds

Answer:

Huh? is it triangle? and right triangle? if it is its 62^2 = 12^2 + x^2

Step-by-step explanation:

Answer:

(a) Increase the differences between the sample means this will increase the Numerator.

(b) Increase the sample variances will increase the denominator.

Step-by-step explanation:  

F Ratio = Variance between treatments/ Variance within treatments.  

Here,  

(a) Increase the differences between the sample means:  

  - Will increase the Numerator and  

  - Size of the F-ratio would increase  

(b) Increase the sample variances:  

 - Will increase the denominator and  

 - Size of the F Ratio would decrease.

Answer:

A

Step-by-step explanation:

graph is 6 units to the right

if it had been (x+6)^2

it would have been 6 units to left

9514 1404 393

Answer:

  Kim

Step-by-step explanation:

The ratio of Kim's distance to Adrian's distance is ...

  (9/10)/(3/5) = (9/10)/(6/10) = 9/6 = 3/2 = 1.5

__

You need to be very careful with the wording here. Kim ran 1 1/2 times as far as Adrian. That is, she ran Adrian's distance plus 1/2 Adrian's distance.

If we take the wording "1/2 times farther" to mean that 1/2 of Adrian's distance is added to Adrian's distance, then Kim is correct.

_____

In many Algebra problems, you will see the wording "k times farther" to mean the distance is multiplied by k. If that interpretation is used here, neither claim is correct, as Kim's distance is 1 1/2 times farther than Adrian's.

On the other hand, if the value of "k" is expressed as a percentage, the interpretation usually intended is that that percentage of the original distance is added to the original distance. Using this interpretation, Kim's distance is 50% farther than Adrian's. (Note the word "times" is missing here.)

__

Since Adrian ran 1 5/10 the distance Kim ran, Adrian's claim is incorrect regardless of the interpretation. If you require one of the two to be correct, then Kim is.

Answer with Step-by-step explanation:

We are given that

[tex]a+ib=\sqrt{\frac{1+i}{1-i}}[/tex]

We have to prove that

[tex]a^2+b^2=1[/tex]

[tex]a+ib=\sqrt{\frac{(1+i)(1+i)}{(1-i)(1+i)}}[/tex]

Using rationalization property

[tex]a+ib=\sqrt{\frac{(1+i)^2}{(1^2-i^2)}}[/tex]

Using the property

[tex](a+b)(a-b)=a^2-b^2[/tex]

[tex]a+ib=\sqrt{\frac{(1+i)^2}{(1-(-1))}}[/tex]

Using

[tex]i^2=-1[/tex]

[tex]a+ib=\frac{1+i}{\sqrt{2}}[/tex]

[tex]a+ib=\frac{1}{\sqrt{2}}+i\frac{1}{\sqrt{2}}[/tex]

By comparing we get

[tex]a=\frac{1}{\sqrt{2}}, b=\frac{1}{\sqrt{2}}[/tex]

[tex]a^2+b^2=(\frac{1}{\sqrt{2}})^2+(\frac{1}{\sqrt{2}})^2[/tex]

[tex]a^2+b^2=\frac{1}{2}+\frac{1}{2}[/tex]

[tex]a^2+b^2=\frac{1+1}{2}[/tex]

[tex]a^2+b^2=\frac{2}{2}[/tex]

[tex]a^2+b^2=1[/tex]

Hence, proved.

(a) The region Y₁ < 1/2 and Y₂ > 1/4 corresponds to the rectangle,

{(y₁, y₂) : 0 ≤ y₁ < 1/2 and 1/4 < y₂ ≤ 1}

Integrate the joint density over this region:

[tex]P\left(Y_1<\dfrac12,Y_2>\dfrac14\right) = \displaystyle\int_0^{\frac12}\int_{\frac14}^1 (y_1+y_2)\,\mathrm dy_2\,\mathrm dy_1 = \boxed{\dfrac{21}{64}}[/tex]

(b) The line Y₁ + Y₂ = 1 cuts the support in half into a triangular region,

{(y₁, y₂) : 0 ≤ y₁ < 1 and 0 < y₂ ≤ 1 - y₁}

Integrate to get the probability:

[tex]P(Y_1+Y_2\le1) = \displaystyle\int_0^1\int_0^{1-y_1}(y_1+y_2)\,\mathrm dy_2\,\mathrm dy_1 = \boxed{\dfrac13}[/tex]

Y₁ and Y₂ are not independent because

P(Y₁ = y₁, Y₂ = y₂) ≠ P(Y₁ = y₁) P(Y₂ = y₂)

To see this, compute the marginal densities of Y₁ and Y₂.

[tex]P(Y_1=y_1) = \displaystyle\int_0^1 f(y_1,y_2)\,\mathrm dy_2 = \begin{cases}\frac{2y_1+1}2&\text{if }0\le y_1\le1\\0&\text{otherwise}\end{cases}[/tex]

[tex]P(Y_2=y_2) = \displaystyle\int_0^1 f(y_1,y_2)\,\mathrm dy_1 = \begin{cases}\frac{2y_2+1}2&\text{if }0\le y_2\le1\\0&\text{otherwise}\end{cases}[/tex]

[tex]\implies P(Y_1=y_1)P(Y_2=y_2) = \begin{cases}\frac{(2y_1+1)(2y_2_1)}4&\text{if }0\le y_1\le1,0\ley_2\le1\\0&\text{otherwise}\end{cases}[/tex]

but this clearly does not match the joint density.

Answer:

x = -4   or   x = 5

Step-by-step explanation:

To solve the absolute value equation

|X| = k

where X is an expression in x, and k is a non-negative number,

solve the compound equation

X = k or X = -k

Here we have |2 - 4x| = 18

In this problem, the expression, X, is 2 - 4x, and the number, k, is 18.

We set the expression equal to the number, 2 - 4x = 18, and we set the expression equal to the negative of the number, 2 - 4x = -18. Then we solve both equations.

2 - 4x = 18  or  2 - 4x = -18

-4x = 16   or   -4x = -20

x = -4   or   x = 5

Answer:

x = -5 . x= 4

Step-by-step explanation:

because |4| = 4 and |-4| = 4

you can see that TWO inputs can get an output of (lets say) 4

The absolute value function can be seen as a function that ignores negative signs

so to get an OUTPUT of "18" using the absolute value function

there are really two ways of getting there

"2-4x = 18"  AND "2-4x = -18"

if you solve both of those you will find that -5 and 4 will

produce the 18 and -18

Answer: the answer is c

Step-by-step explanation:brainlist [tex]\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right][/tex]

Answer:

Domain: -4 ≤ x ≤ -1

Range: -1 ≤ y ≤ 3

Step-by-step explanation:

Hi there!

The domain is the possible x-values of a function.

The lowest x-value the function contains is -4, and the greatest is -1.

Therefore, the domain is -4 ≤ x ≤ -1.

The range is the possible y-values of a function.

The lowest y-value the function contains is -1, and the greatest is 3.

Therefore the range is -1 ≤ y ≤ 3.

I hope this helps!

Answer:

Step-by-step explanation: