Which integers could you add to −18 to get a sum that is greater than 5?

Answer:

The answer is "[tex]\bold{\$1160}[/tex]"

Step-by-step explanation:

Calculating total paid money:

[tex]= \$4000 \times 101\% \\\\= \$4000 \times \frac{101}{100} \\\\=\$40 \times 101\\\\=\$4040[/tex]

[tex]\text{Total received money = Principle on Maturity + Interest for 5 years}[/tex]

                                   [tex]= \$4000 + \$4000\times 6\% \times 5 \\\\= \$4000 + \$4000\times \frac{6}{100} \times 5 \\\\= \$4000 + \$40 \times 6 \times 5 \\\\= \$4000 + \$40 \times 30 \\\\= \$4000 + \$1200 \\\\= \$5200 \\\\[/tex]

Total earnings over the life of the corporate bond

[tex]= \$5200 - \$4040 \\\\=\$1160[/tex]

[tex]\displaystyle\bf 2^{2x+1}-9\cdot 2^x+4=0 \quad ; \qquad \boxed{ 2^x=t \; ; \; 2^{2x}=t^2} \\\\2t^2-9t+4=0 \\\\D=81-32 =49 \\\\ t_1=\frac{9+7}{4} =4 \\\\ t_2=\frac{9-7}{4} =\frac{1}{2} \\\\1) \ 2^x=4 \Longrightarrow x_1=2 \qquad 2) \ 2^x=2^{-1}\Longrightarrow x_2=-1 \\\\Answer: \boxed{x_1=2 \quad ; \quad x_2=-1}[/tex]

Answer:

25

Step-by-step explanation:

6ab of 2a ÷ 12 × 12ab + 14a - a

= 6ab * 2a ÷ 12 × 12ab + 14a - a

= 12a²b ÷ 144ab + 13a

= 12*a*a*b / 144*a*b + 13*a

= a/12 + 13*a

= 1/12 + 13

= 1/25

Answer:

5

Step-by-step explanation:

You divide the change in the output value by the change in the input value.

  Input: 0 |  4

Output: 1  |  21

20/4= 5

Answer:

12

Step-by-step explanation:

First substitute the equation with the variable replacements given:

-r/9 + 5x <--- Before

-27/9 + 5(3) <--- After

Next Solve the parts of the Equation

-27/9 + 5(3)

-3 + 15 <--- -27 divided by 9 is -3, 5 times 3 is 15.

= 12 <--- 15 - 3 = 12.

I hope this helps!

Answer:

12

Step-by-step explanation:

[tex]-\frac{27}{9}+5(3)[/tex]

- 3 + 15

15 - 3

12

Answer:

3√2

Step-by-step explanation:

* means multiply

-7√2 + 10 √2

take √2 out of the expression

√2 (-7 + 10)

√2 (3)

3√2

Answer:

17.5

Step-by-step explanation:

as the triangles are similar, when oriented in the same direction they have the same angles, and the lengths of all sides of DEF are the lengths of the sides of ABC but multiplied by the same scaling factor f for all sides.

so, we see that

A ~ D

B ~ E

C ~ F

and therefore

AB ~ DE

BC ~ EF

CA ~ FD

that means

DE = AB × f

EF = BC × f

FD = CA × f

we know DE and AB.

so,

4 = 10 × f

f = 4/10 = 2/5

and now we know

EF = 7 = BC × f

BC = 7/f = (7/1) / (2/5) = (5×7)/(2×1) = 35/2 = 17.5

Answer:

17.5

Step-by-step explanation:

Answer:

the answer is 2035.75 cm³

Step-by-step explanation:

comment if you want explanation

Answer:

the answer is D

Step-by-step explanation:

Answer:

11 feet

Step-by-step explanation:

Given,

Area of square ( a^2 ) = 121 ft

To find : Length of each side ( a ) = ?

Formula : -

Area of square = a^2

a^2 = 121

a = √121

a = 11 feet

Answer:

11 ft = side length

Step-by-step explanation:

The area of a square is found by

A = s^2

121 = s^2

Taking the square root of each side

sqrt(121) = sqrt(s^2)

11 = s

Answer:

y=9x^2 + 8

Step-by-step explanation:

using the power rule, we will differentiate each term separately

d/dx of 3x^3 = (3)(3)x^(3-1) = 9x^2

d/dx of 8x = 8x^(1-1) = 8

d/dx of -7 = 0

combining them we get the derivative which is y = 9x^2 + 8

Answer:

9x² + 8

Step-by-step explanation:

The given function to us is ,

[tex]\implies y = 3x {}^{3} + 8x - 7[/tex]

And we need to differentiate the given function with respect to x . Taking the given function and differenciating wrt x , we have

[tex]\implies y = 3x^3 + 8x - 7 [/tex]

Recall that , the derivative of constant is 0 . Therefore ,

[tex]\implies \dfrac{dy }{dx}= \dfrac{d}{dx}(3x^3 + 8x - 7) \\\\\implies\dfrac{dy }{dx}= \dfrac{d}{dx}(3x^3)+\dfrac{d}{dx}(8x) + 0 \\\\\implies\dfrac{dy }{dx}= 3\times 3 . x^{3-1} + 8\times 1 . x^{1-1} \\\\\implies\underline{\underline{\dfrac{dy }{dx}= 9x^2+8}} [/tex]

Hence the derivative of given function is 9x² + 8 .

Answer:

-8z+1

term:2

variable:z

coefficient:-8

constant:1

2

term:1

variable:nil

coefficient:nil

constant:2

y-7.7

term:2

variable:y

coefficient:nil

constant:-7.7

The solution is given below.

A number is a mathematical object used to count, measure, and label. The original examples are the natural numbers 1, 2, 3, 4, and so forth. Numbers can be represented in language with number words.

now, we get,

-8z+1

term:2

variable: z

coefficient:-8

constant:1

again,

2

term:1

variable : nil

coefficient : nil

constant:2

now,

y-7.7

term:2

variable : y

coefficient : nil

constant:-7.7

To learn more on number click:

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Question: Dentify the parts of the following algebraic expression.

-8z + 1

2

y - 7.7

Term:

Variable:

Coefficient:

Constant:

Answer:

(4.5,-6)

Step-by-step explanation:

[tex]2x-3y = 27\\4x+3y = 0[/tex]

6x = 27

x = 27/6=4.5

9-3y = 27

-3y = 18

y = -6

Answer:

ok so first they drove 55 for 3 hours so

55*3=165

and then they drove 45 for 2 hours

45*2=90

165+90=255

so in total they drove 255 miles

Hope This Helps!!!

The solution is : 255 miles total miles did the Ramos family drive.

Speed is measured as distance moved over time. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).

Speed = Distance/ Time.

here, we have,

given that,

The Ramos family drove to their family reunion. Before lunch, they drove at a constant rate of 55 miles per hour for 3 hours. After lunch, they drove at a constant rate of 45 miles per hour for 2 hours.

we get,

Journey before lunch:

Speed = 55 mph

Time = 3 hrs

distance = 55*3 = 165 miles.

Journey after lunch:

Speed = 45 mph

Time = 2 hrs

distance = 45 * 2 = 90 miles

Total miles driven

= distance traveled before lunch + distance traveled after lunch

= 165 miles + 90 miles

= 255 miles

Therefore, the Ramos family drove 255 miles in total.

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Hi there!  

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I believe your answer is:  

(0.286, 5.587)

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Here’s why:  

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Hope this helps you. I apologize if it’s incorrect.  

Answer:

Option (C)

Step-by-step explanation:

Equation of the quadratic function having vertex at (3, 4) and opening upwards,

So the the minimum point of the function is (3, 4).

Therefore, minimum value of the function is 4 at x = 3.

y = (x - h)² + k [Here, (h, k) is the vertex]

g(x) = 2(x - 4)² + 3

Vertex of the parabola is (4, 3).

Since, leading coefficient is positive, parabola will open upwards.

Therefore, vertex will be the minimum point.

Minimum value of the function will be 3 at x = 4.

Minimum value of the function 'f' is greater than the minimum value of the function 'g'.

Option (C) will be the answer.

Answer:

C. The minimum value of f is greater than the minimum value of g.

Step-by-step explanation:

I got a 100% on my test

Answer:  Graph 2

Explanation:

The graph of f(x) = x^2 is a parabola with the vertex at the origin. If we replace every x with x-2, then we shift the xy axis 2 units to the left, giving the illusion the parabola shifts 2 units to the right.

In short, going from y = x^2 to y = (x-2)^2 means we shift the curve 2 units to the right. This is shown in the second graph.

Answer:

cant download send ss

Step-by-step explanation:

Answer:

3 times

Step-by-step explanation:

Step 1: Express the volume of the cup in terms of "r" (radius) and "h" (height)

The formula for the volume of a cone is:

Vcone = 1/3 × h × π × r²

Step 2: Express the volume of the container in terms of "r" and "h"

The formula for the volume of a cylinder is:

Vcylinder = h × π × r²

Step 3: Calculate how many times the volume of the cone is contained in the volume of the cylinder

Vcylinder/Vcone = (h × π × r²) / (1/3 × h × π × r²) = 3

Answer:

[tex]{ \tt{27 = {3}^{3} }} \\ { \tt{}} \sqrt[4]{27} = {27}^{ \frac{1}{4} } \\ { \tt{ = {3}^{3( \frac{1}{4}) } }} \\ = { \tt{ {3}^{ \frac{3}{4} } }} \\ { \boxed{ \bf{a = 3 \: \: and \: \: k = \frac{3}{4} }}}[/tex]

Answer: nose

Step-by-step explanation:

Answer:

D.  I or II only

Step-by-step explanation:

By a small online search, I've found that the equation is:

6x + 7 = 3x - 5

And the options are:

I. Combining the 6x and 3x terms

II. Combining the 7 and 5

III. Dividing both sides of the equation  by 6

A.  I only

B.  II only

C.  III only

D.  I or II only

E.   I or II or III

So, let's solve the equation in such a way that we can prevent the use of fractions:

6x + 7 = 3x - 5

We can use I and II, combining one in each side, so we get (so we use I and II at the same time)

6x - 3x = -5 - 7

solving these, we get:

(6 - 3)*x = -12

3*x = -12

and -12 is divisible by 3, so if we divide in both sides by 3, we get:

x = -12/3 = -4

x = -4

So we avoided working with fractions, and we used I and II.

Then the first step could be either I or II (the order does not matter)

Then the correct option is:

D.  I or II only

Answer:

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.0256} & {0.1536} & {0.3456} & {0.3456} & {0.1296} \ \end{array}[/tex]

Step-by-step explanation:

Given

[tex]p = 60\%[/tex]

[tex]n = 4[/tex]

Required

The distribution of x

The above is an illustration of binomial theorem where:

[tex]P(x) = ^nC_x * p^x *(1 - p)^{n-x}[/tex]

This gives:

[tex]P(x) = ^4C_x * (60\%)^x *(1 - 60\%)^{n-x}[/tex]

Express percentage as decimal

[tex]P(x) = ^4C_x * (0.60)^x *(1 - 0.60)^{n-x}[/tex]

[tex]P(x) = ^4C_x * (0.60)^x *(0.40)^{4-x}[/tex]

When x = 0, we have:

[tex]P(x=0) = ^4C_0 * (0.60)^0 *(0.40)^{4-0}[/tex]

[tex]P(x=0) = 1 * 1 *(0.40)^4[/tex]

[tex]P(x=0) = 0.0256[/tex]

When x = 1

[tex]P(x=1) = ^4C_1 * (0.60)^1 *(0.40)^{4-1}[/tex]

[tex]P(x=1) = 4 * (0.60) *(0.40)^3[/tex]

[tex]P(x=1) = 0.1536[/tex]

When x = 2

[tex]P(x=2) = ^4C_2 * (0.60)^2 *(0.40)^{4-2}[/tex]

[tex]P(x=2) = 6 * (0.60)^2 *(0.40)^2[/tex]

[tex]P(x=2) = 0.3456[/tex]

When x = 3

[tex]P(x=3) = ^4C_3 * (0.60)^3 *(0.40)^{4-3}[/tex]

[tex]P(x=3) = 4 * (0.60)^3 *(0.40)[/tex]

[tex]P(x=3) = 0.3456[/tex]

When x = 4

[tex]P(x=4) = ^4C_4 * (0.60)^4 *(0.40)^{4-4}[/tex]

[tex]P(x=4) = 1 * (0.60)^4 *(0.40)^0[/tex]

[tex]P(x=4) = 0.1296[/tex]

So, the probability distribution is:

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.0256} & {0.1536} & {0.3456} & {0.3456} & {0.1296} \ \end{array}[/tex]

1st option

{(3,0) e (0,9)}; {(2,0) e (0,-4)}; {(1,0) e (0,-5)}

see screenshot

sorry btw, no hablo espanol

Answer:1. = 4x+8  

2. 2a²-a+1

Step-by-step explanation:

1. ((x+2)+3x+6.  2. 2a(a-1)-a+1​

((x+2)+3x+6

= x+2+3x+6

= 4x+8

2a(a-1)-a+1

2a²-2a-a+1

2a²-a+1

Answer:

La ecuación genérica para un círculo centrado en el punto (a, b), de radio R, es:

(x - a)^2 + (x - b)^2 = R^2

Entonces si miramos a nuestra ecuación:

(x + 2)^2 + (y - 3)^2 = 121

Tendremos el centro en:

(-2, 3)

el radio está dado por:

R^2 = 121

R = √121 = 11

La gráfica de esta circunferencia se puede ver en la imagen de abajo.

Answer:

It's C

Step-by-step explanation:

Answer: D. (5, 4)

Step-by-step explanation:

An x-intercept of -1 means the point = (-1, 0)

So find the slope(m) using the formula: [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

[tex](x_{1},y_{1})=(-4,-2)\\(x_{2},y_{2})=(-1,0)\\\\m = \frac{0-(-2)}{-1-(-4)}=\frac{0+2}{4-1}=\frac{2}{3}[/tex]

Now find the y-intercept(b) by substituting a point into the function:

y = mx + b

[tex]y=\frac{2}{3} x+b\\\\0=\frac{2}{3} (-1)+b\\\\0=-\frac{2}{3}+b\\\\b=\frac{2}{3}[/tex]

So now the function is determined as [tex]y=\frac{2}{3} x+\frac{2}{3}=\frac{2}{3}(x+1)[/tex].

Bring each of the coordinates in to see if it fits in:

A. (-6, -5)  [tex]\frac{2}{3}(-6+1)=\frac{2}{3}(-5)=-3.33\neq -5[/tex]

B. (3, 2) [tex]\frac{2}{3}(3+1)=\frac{2}{3}(4)=2.67\neq 2[/tex]

C. (4, 5) [tex]\frac{2}{3}(4+1)=\frac{2}{3}(5)=3.33\neq 5[/tex]

D. (5, 4) [tex]\frac{2}{3}(5+1)=\frac{2}{3}(6)=4[/tex]

Answer:

D(5,4)

Step-by-step explanation:

Took Quiz

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3

Answer:

[tex] \displaystyle( {x}_{1} , y_{1}) =( - 3,4)\\ (x _{2}, y_{2}) = (4, - 3)[/tex]

Step-by-step explanation:

we are given two conditions

let the two integers be x and y respectively according to the first condition

[tex] \displaystyle xy = - 12[/tex]

according to the second condition:

[tex] \displaystyle x + y = 1[/tex]

now notice that we have two variables therefore ended up with a simultaneous equation so to solve the simultaneous equation cancel x from both sides of the second equation which yields:

[tex] \displaystyle y = 1 - x[/tex]

now substitute the got value of y to the first equation which yields:

[tex] \displaystyle x(1 - x) = - 12[/tex]

distribute:

[tex] \displaystyle x- {x}^{2} = - 12[/tex]

add 12 in both sides:

[tex] \displaystyle x- {x}^{2} + 12 = 0[/tex]

rearrange it to standard form:

[tex] \displaystyle - {x}^{2} + x + 12 = 0[/tex]

divide both sides by -1:

[tex] \displaystyle {x}^{2} - x - 12 = 0[/tex]

factor:

[tex] \displaystyle ({x} + 3)(x - 4) = 0[/tex]

by Zero product property we acquire:

[tex] \displaystyle {x} + 3 = 0\\ x - 4= 0[/tex]

solve the equations for x therefore,

[tex] \displaystyle {x}_{1} = - 3\\ x _{2} = 4[/tex]

when x is -3 then y is

[tex] \displaystyle y _{1}= 1 - ( - 3)[/tex]

simplify

[tex] \displaystyle y _{1}= 4[/tex]

when x is 4 y is

[tex] \displaystyle y _{2}= 1 - ( 4)[/tex]

simplify:

[tex] \displaystyle y _{2}= - 3[/tex]

hence,

[tex] \displaystyle( {x}_{1} , y_{1}) =( - 3,4)\\ (x _{2}, y_{2}) = (4, - 3)[/tex]

Answer:

The height of flag pole=8.3m

Step-by-step explanation:

We are given that

Height of boy=1.4 m

[tex]\theta=36^{\circ}[/tex]

Distance of boy from the flag pole=9.5 m

We have to find  the height of the flag pole​.

BCDE is a rectangle

BC=ED=1.4 m

CD=BE=9.5 m

In triangle ABE

[tex]\frac{AB}{BE}=tan36^{\circ}[/tex]

Using the formula

[tex]tan\theta=\frac{Perpendicular\;side}{base}[/tex]

[tex]\frac{AB}{9.5}=tan 36^{\circ}[/tex]

[tex]AB=9.5tan36^{\circ}[/tex]

AB=6.90 m

Height of flag pole=AB+BC=6.90+1.4

Height of flag pole=8.3m