Answer: [tex]6+\dfrac{14}{p}[/tex] .
Step-by-step explanation:
To find : The expression is equivalent to the product of [tex]p+\dfrac73\text{ and }\dfrac6p[/tex], where p ≠0.
Product of [tex]p+\dfrac73\text{ and }\dfrac6p[/tex] = [tex](p+\dfrac73)\times\dfrac6p[/tex]
Using distributive property: [tex](b+c)a= ba+ca[/tex]
[tex](p+\dfrac73)\times\dfrac6p=p\times\dfrac6p+\dfrac73\times\dfrac6p\\\\= 6+\dfrac{7}{1}\times\dfrac2p\\\\=6+\dfrac{14}{p}[/tex]
Hence, the required expression is [tex]6+\dfrac{14}{p}[/tex] .
Answer:
B!!!
Step-by-step explanation:
Multiply then divide every number by 2 to simplify.
What is equivalent to 9 3/4?
The answer is supposedly is 3 square root 3, but how is that the answer? can someone tell me the steps?
Step-by-step explanation:
We need to say that [tex]9^{3/4}[/tex] is equivalent to what.
We know that, (3)² = 9
So,
[tex]9^{3/4}=((3)^2)^{3/4}\\\\=3^{3/2}[/tex]
We can write [tex]3^{3/2} =3\times 3^{1/2}[/tex]
And [tex]3^{1/2}=\sqrt{3}[/tex]
So,
[tex]3\times 3^{1/2}=3\sqrt{3}[/tex]
So, [tex]9^{3/4}[/tex] is equivalent to [tex]3\sqrt{3}[/tex].
Hence, this is the required solution.
plz help ASAP! thank u
Answer: Choice B)
The relation is a function because there are no vertical lines that can be drawn on the graph that pass through more than one point.
This graph passes the vertical line test. Any input (x) leads to one and only one output (y). An example of a graph failing the vertical line test would be a graph that is a sideways parabola.
PLEASE ANSWER QUICKLY ASAP
ANSWER QUESTION A AND B
Answer:
a) [tex]a+b+c=\begin{pmatrix}-2\\-3\end{pmatrix}[/tex]
b) (i) [tex]a+2c=\begin{pmatrix}-4\\2\end{pmatrix}[/tex]
(ii) [tex]k=2[/tex]
Step-by-step explanation:
It is given that,
[tex]a=\begin{pmatrix}4\\-10\end{pmatrix},b=\begin{pmatrix}-2\\1\end{pmatrix},c=\begin{pmatrix}-4\\6\end{pmatrix}[/tex]
a)
We need to find the value of a+b+c.
[tex]a+b+c=\begin{pmatrix}4\\-10\end{pmatrix}+\begin{pmatrix}-2\\1\end{pmatrix}+\begin{pmatrix}-4\\6\end{pmatrix}[/tex]
[tex]a+b+c=\begin{pmatrix}4+(-2)+(-4)\\-10+1+6\end{pmatrix}[/tex]
[tex]a+b+c=\begin{pmatrix}-2\\-3\end{pmatrix}[/tex]
b)
(i) We need to find the value of a+2c.
[tex]a+2c=\begin{pmatrix}4\\-10\end{pmatrix}+2\begin{pmatrix}-4\\6\end{pmatrix}[/tex]
[tex]a+2c=\begin{pmatrix}4\\-10\end{pmatrix}+\begin{pmatrix}-8\\12\end{pmatrix}[/tex]
[tex]a+2c=\begin{pmatrix}4+(-8)\\-10+12\end{pmatrix}[/tex]
[tex]a+2c=\begin{pmatrix}-4\\2\end{pmatrix}[/tex]
(ii) It is given that a+2c=kb, where k is an integer. We need to find the value of k.
[tex]a+2c=k\begin{pmatrix}-2\\1\end{pmatrix}[/tex]
[tex]\begin{pmatrix}-4\\2\end{pmatrix}=\begin{pmatrix}-2k\\k\end{pmatrix}[/tex]
On comparing both sides, we get
[tex]k=2[/tex]
The function gx) = x^2is transformed to obtain function hr.
h(x) = g(x-3).
Which statement describes how the graph of h is different from the graph of g?
A. The graph of his the graph of g vertically shifted down 3 units.
B. The graph of his the graph of ghorizontally shifted left 3 units.
C. The graph of h is the graph of g vertically shifted up 3 units.
D. The graph of h is the graph of g horizontally shifted right 3 units.
the graph will shift 3 units to the right
Which of the following functions has a vertical asymptote at x = 2, a horizontal
asymptote at f(x) = 1, and a root at x = -1?
A.f(x) = 2 + 1
B.f(x) = x 2 + 1
c.f(x) = x 2 - 1
D.f(x) == +1
Answer:
First, an asymptote means that the function "tends to go" to a value, bt actually never reaches it.
The functions here are:
A.f(x) = 2 + 1
B.f(x) = x^2 + 1
c.f(x) = x^2 - 1
D.f(x) == +1
The functions are really poorly written, but i will try to answer this.
first:
"a root at x = -1"
Means that f(-1) = 0,
The only function that is zero when x = -1, is the option c.
f(-1) = (-1)^2 - 1 = 1 - 1 = 0.
Now, if we want to have a vertical asymptote at x = 2, then we should have a function like:
[tex]f(x) = \frac{something}{x - 2}[/tex]
So we want to have a quotient, where the denominator is equal to zero when x = 2, this will lead to a vertical asymptote.
I can not see this in the options provided, so i guess that the functions are just not well written.
For a horizontal asymptote, we have something like:
[tex]f(x) = \frac{something}{x} + 1[/tex]
So as x starts to grow, the first term in the function will start to decrease, until it becomes really close to zero (but is never equal to zero) so in that case we have an horizontal asymptote to f(x) = 1.
2. The ratio of
the profit, cost of
materials and labour
in the production of
an article is 5:7:13
respectively. If the
cost of materials is Le
840 more than that of
labour, find the total
cost of producing the
article
Answer:
3500Step-by-step explanation:
Given the ratio of the profit, cost of materials and labour in the production of
an article to be 5:7:13 respectively, total ratio = 5+7+13 = 25
If the cost of labour is x, the cost of material will be 840+x (since the cost of materials is Le 840 more than that of labour) .
Let the total cost of producing the article be y.
Cost of labour = 13/25 * y = x
Cost of labour = 13y/25 = x.................... 1
Cost of material = 7/25*y = 840+x
Cost of material = 7y/25 = 840+x ..................... 2
From 1, 13y = 25x
x = 13y/25 ................... 3
Substituting equation 3 into 2:
7y/25 = 840+x
7y/25 = 840+13y/25
collect the like terms:
7y/25 - 13y/25 = 840
-6y/25 = 840
-6y = 25*840
y = 25*840/6
y = 3,500
Hence the total cost of producing the article is 3500
Match each quadratic equation with its solution set.
Answer:
2x²-32 ⇒ x²=16⇒ (-4,4)
4x²-100 ⇒x²=25 ⇒(-5,5)
x²-55=9 ⇒x²=64 ⇒(-8,8)
x²-140=-19 ⇒x²=121 ⇒(-11,11)
2x²-18=0 ⇒x²=9 ⇒(-3,3)
Answer:
2x^2-32 = 0 ===> (-4,4)4x^2 -100=0 ===> (-5,5)x^2 -55=9 ==>(-8, 8)x^2-140= -19 ===>(-11 ,11)Step-by-step explanation: Further explanation
[tex]2x^2-32=0\\\\\mathrm{Add\:}32\mathrm{\:to\:both\:sides}\\\\2x^2-32+32=0+32\\\\2x^2=32\\\\\frac{2x^2}{2}=\frac{32}{2}\\\\\mathrm{For\:}x^2=f\left(a\right)\\\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{16},\:x=-\sqrt{16}\\\\x=\sqrt{16},\:x=-\sqrt{16}\\x=4,\:x=-4[/tex]
[tex]4x^2-100=0\\\mathrm{Add\:}100\mathrm{\:to\:both\:sides}\\4x^2-100+100=0+100\\4x^2=100\\\frac{4x^2}{4}=\frac{100}{4}\\x^2=25\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{25},\:x=-\sqrt{25}\\\\x=5,\:x=-5[/tex]
[tex]x^2-140=-19\\x^2-140+140=-19+140\\x^2=121\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{121},\:x=-\sqrt{121}\\x=11,\:x=-11[/tex]
[tex]x^2-55=9\\x^2-55+55=9+55\\x^2=64\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{64},\:x=-\sqrt{64}\\x=8,\:x=-8\\[/tex]
[tex]2x^2-18=0\\2x^2-18+18=0+18\\2x^2=18\\\frac{2x^2}{2}=\frac{18}{2}\\x^2=9\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{9},\:x=-\sqrt{9}\\x=3,\:x=-3[/tex]
The size of a television screen is given as 95 cm, correct to the nearest 5 cm.
Write down the upper bound of the size of the television screen.
Answer:
U B = 100.5
Step-by-step explanation:
the upper bound of the size of the television screen= 95.5 since it is corrected to the nearest 5 then the U B =100.5 cm
The upper bound of the size of the television screen is 100.5 cm
The conversion of the size of the television screen to the nearest 5cm from the initial size of 95 cm is = 100 cm.
Now, the upper bound of the size of the television screen which is 100 is can be determined by the addition of a half value to 100 cm:
i.e.
= (1/2) + 100 cm
= 0.5 + 100 cm
= 100.5 cm
Therefore, we can conclude that the upper bound of the size of the television screen is 100.5 cm
Learn more about nearest value here:
https://brainly.com/question/16382026?referrer=searchResults
What x value solves the equation? 3x – 5 = 1 x =
Answer:
x = 2
Step-by-step explanation:
3x - 5 = 1
Adding 5 to both sides gives us:
3x - 5 + 5 = 1 + 5
3x = 6
Dividing the equation by 3 gives us:
3x / 3 = 6 / 3
x = 2
Answer:
x = 2 Hfizfifsits96eotst9s
two similar cups are 3 cm and 5 cm deep if the larger cup
s hold 675 cm cube of water what is the volume of the smaller one
Answer:
145.8
Step-by-step explanation:
l.s.f for the two is 3:5
volume scale factor will be 3³:5³ which us 27:125
so 27×675 / 125
= 145.8
Can you help Jorge organize the results into a two-way frequency table?
Answer:
See Explanation
Step-by-step explanation:
Given
Students = 24
Musical Instrument and Sport = 6
Neither = 3
Sport = 14
Required
Complete the two-way frequency table
-------------------------------------------------------- Plays sport || Does not play sport
Plays a musical instrument ---------------------6--------------------------------------
Does not play a musical instrument -------------------------------------3-----------
Total ---------------------------------------------------- 14 ---------------------------------------
To solve this, we'll make use of the following naming rules
A represent students that plays musical instrument; A = 6
B represent students that do not play musical instrument
C represent students that plays sport
D represent students that do not play sport; D = 3
Considering the first column [Plays a sport] and taking note of the naming rules;
[tex]A + B = 14[/tex]
Substitute 6 for A
[tex]6 + B = 14[/tex]
Solve for B
[tex]B = 14 - 6[/tex]
[tex]B = 8[/tex]
Also, given that there are 24 students in the class and 14 of them play sport; this implies that 10 do not play sport
Considering the second column [Does not play a sport]
[tex]C + D = 10[/tex]
Substitute 3 for D
[tex]C + 3 = 10[/tex]
Solve for C
[tex]C = 10 - 3[/tex]
[tex]C = 7[/tex]
Hence, the complete table is:
-------------------------------------------------------- Plays sport || Does not play sport
Plays a musical instrument ---------------------6--------------------------7----------
Does not play a musical instrument ---------8--------------------------3---------
Total ---------------------------------------------------- 14 -----------------------10---------
Points C and D are on a number line (not shown).
The coordinate of point C is -16 and the coordi-
nate of point D is 14. Point E is a point on line
segment CD. If the distance from point E to point C
is 1
4
the distance from point E to point D, what is
the coordinate of point E?
Answer:
17
Step-by-step explanation:
Find an equation for the nth term of the arithmetic sequence. 9, 11, 13, 15, ...
Answer:
2n+7
Step-by-step explanation:
First lets find the common difference which is 2, now we can use this formula to find the nth term.
an = a1 + (n - 1 ) d
an= 9+(n-1)2
=9+2n-2
=2n+7
To check let's insert n=5, 2(5)=10+7=17.
15+2=17!
There were 96 people in a queue to get into a fun fair. There were at least
4 children between any 2 adults.
What was the largest possible number of adults in the queue?
Answer:
32 adulta
Step-by-step explanation:
96÷6 = 16 number of families
now we need to see how many adults there are in 16 families.
and the number is 32 adults.
Answer:
32 adults.
Step-by-step explanation:
At the very least, there are 4 children for every 2 adults. That means that, at the very least, there are 6 people in one group to get into the fun fair.
96 / 6 = 16
So, there are 16 groups trying to get into the fun fair, with 2 adults in each group. 2 * 16 = 32 adults are in the queue.
Hope this helps!
What is the image of (4,-7) after a reflection over the line y=x
Answer:
(-4,7)
Step-by-step explanation:
solved by graphing
A researcher obtained M = 27 for a sample of n = 36 scores selected from a population with µ = 30 and σ = 18. This sample mean corresponds to a z-score of z = –1.00.
Answer:
True
Step-by-step explanation:
Given that:
M = 27, sample of n = 36 scores, µ = 30 and σ = 18.
The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the z score is positive, the raw score is greater than the mean and if the z score is negative the raw score is less than the mean. The z score is given as:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Given that M = 27, this means that x = 27. Therefore:
[tex]z=\frac{x-\mu}{\sigma}\\\\for \ a\ sample\ size(n):z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\z=\frac{27-30}{18/\sqrt{36} } =\frac{-3}{3}=-1[/tex]
This sample mean corresponds to a z-score of z = –1.00.
24.
What is the slope of a line through (-3, 4) and
(5, 6)?
PLEASE help if you can!!
Answer:
slope = 2 : 8 or 1:4
Step-by-step explanation:
a(-3, 4)
b(5, 6)
slope = rise / run
slope (6-4, 3+5))
slope = 2 : 8 or 1:4
Answer:
Slope =¼
Step-by-step explanation:
[tex](-3, 4) \: (5, 6) \\ x _{1} = - 3 , y_1 = 4 \\ x_2 = 5 \\ y_2 = 6[/tex]
[tex]m = \frac{y_2 - y_1}{x_2 - x_1} \\ m = \frac{6 - 4}{5 - ( - 3)} \\ m = \frac{2}{8} = \frac{1}{4} [/tex]
Please answer this in two minutes
Answer:
x = 16
Step-by-step explanation:
The figure shown shows an inscribed angle F and central angle E. Both angles intercept the same arc.
Therefore, angle E is twice the measure of angle F, according to the central angle theorem of a circle.
Thus,
m<E = 2 * m<F
(x + 94)° = 2(55)
We can find the value of x with this equation.
x + 94 = 110
Subtract 94 from both sides
x = 110 - 94
x = 16
the area of a square poster is 27 in.2. Find the length of one side of the poster to the nearest tenth of an inc
Answer:
5.2 inches
Step-by-step explanation:
Let a be the side of the square poster.
The area of it is:
● A = a^2
● 27 = a^2
● a = √27
● a = √(9×3)
● a = 3√3
● a = 5.19
Round it to the nearest tenth
● a = 5.2 inches
The length of one side of the poster is approximately 5 inches rounded to nearest tenth.
What is rounding of numbers ?We round numbers because they are easy to deal with and they also retain their value to that place they have been rounded.
According to the given question the area of a square poster is 27inch².
We have to determine the length of one side of the poster.
We know area of a square is (side)².
∴ (side)² = 27.
side = [tex]\sqrt{27}[/tex].
We know [tex]\sqrt{25}[/tex] is 5 and [tex]\sqrt{36}[/tex] is 6 so [tex]\sqrt{27}[/tex] will lie between 5 and 8 and much closer to 5.
learn more about rounding of numbers here :
https://brainly.com/question/15235224
#SPJ2
PLEASE help me with this question. This is really URGENT
Answer:
$6291.70
Step-by-step explanation:
You have the equation and a value to solve for. So, plug this in to get m = 2500 + 0.05(75,834) = 2500 + 3791.70 = $6291.70.
in the expretion7to the third power-4*3+8 the firstt operation is
Answer:
7³
Step-by-step explanation:
Using PEMDAS, we see that E (which stands for exponents) comes before M (which stands for multiplication) and A (which stands for addition) so the first operation you should do is 7³.
-4(2x-3) simplified
Answer:
-8x + 12
Step-by-step explanation:
Distribute -4 to the parentheses:
-4(2x - 3)
-4(2x) = -8x
-4(-3) = 12
-8x + 12
Answer:
-8x +12
Step-by-step explanation:
-4(2x-3)
Distribute
-4* 2x -4 *-3
-8x +12
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days and a standard deviation of days. (a) What is the minimum pregnancy length that can be in the top % of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom % of pregnancy lengths? (a) The minimum pregnancy length is 280 days.
Answer:
(a) 283 days
(b) 248 days
Step-by-step explanation:
The complete question is:
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?
Solution:
The random variable X can be defined as the pregnancy length in days.
Then, from the provided information [tex]X\sim N(\mu=268, \sigma^{2}=12^{2})[/tex].
(a)
The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:
P (X > x) = 0.11
⇒ P (Z > z) = 0.11
⇒ z = 1.23
Compute the value of x as follows:
[tex]z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283[/tex]
Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.
(b)
The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:
P (X < x) = 0.05
⇒ P (Z < z) = 0.05
⇒ z = -1.645
Compute the value of x as follows:
[tex]z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248[/tex]
Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.
What is the divisor of 5.2 and 0.052
Answer:
5.2/0.052 is 100, and 100 is 10^2, so the missing divisor is 10^2
Answer:
100
Step-by-step explanation:
5.2/x = 0.052
Since the decimal place moves 2 places to the left from 5.2 to 0.052, the divisor is 100.
5.2/100 = 0.052
-3x+2y=6 Find the intercepts. Show your work.
Answer:
The x-intercept is (-2,0)
The y-intercept is (0,3)
Step-by-step explanation:
An x-intercept is the point when the graph crosses the x-axis. In other words, the y-coordinate of the x-intercept is 0 (since it lays on the x-axis). In other words, to solve for the x-intercept(s), plug in 0 for y and solve for x:
[tex]-3x+2y=6\\-3x+2(0)=6\\-3x=6\\x=-2[/tex]
So, the x-intercept is (-2,0).
Likewise, the y-intercept is the point when the graph crosses the y-axis. Because it's on the y-axis, the x-coordinate value would be 0. Thus, to find the y-intercept, plug in 0 for x and solve for y:
[tex]-3x+2y=6\\-3(0)+2y=6\\2y=6\\y=3[/tex]
Thus, the y-intercept is (0,3).
Which number is closest to O on the number line?
-0.26
0.3
0.275
-0.51
Answer:
-.26
Step-by-step explanation:
If you take the absolute value (indicates how far a number-negative/positive- is from 0) of each number u listed you will find that .26 is the smallest number,thus smallest number.
Answer:
-.26 is closest to 0 on the number line.
Step-by-step explanation:
To find distance we use absolute value to find the smallest absolute value.
The absolute value of each number is as follows
-0.26 (0.26)
0.3 (0.3)
0.275 (0.275)
-0.51 (0.51)
In order from least to greatest we have
.26, .275, .3, .51
Therefore -.26 is closest to 0 on the number line.
Good luck!!
plz help me asap!!!!!
What is the equation of the linear function represented by the table?
x
y
–5
14
–2
11
1
8
4
5
y = negative x + 9
y = negative x + 13
y = x + 13
y = x + 9
Answer:
It would be y = -x + 9
Step-by-step explanation:
Answer:
Y=-x+9
Step-by-step explanation:
two inches is approximately
Answer:
5.08 cm
Step-by-step explanation: You dont have the choices for answers.
2inches is also 1/6 of a foot, etc
i’m pretty bad at math
Answer:
2m - 3
Step-by-step explanation:
We know that Jim ran m miles. Twice that amount is simply 2 times that, or 2 * m which simplifies to 2m. 3 miles fewer means that we have to subtract 3 from that quantity, so the answer is 2m - 3.
Answer:
2m - 3
Step-by-step explanation:
Distance ran by Jim = m
Twice as far as Jim : 2 * m = 2m
3 miles fewer than '2m' = 2m - 3
Distance ran by Kelly = 2m - 3
When a fish is selected at random from a tank, the probability that it has a green tail is 0.36, the probability that it has red fins is 0.59, and the probability that it has both a green tail and red fins is 0.21. What is the probability that the selected fish will not have a red fin or a green tail?
Answer: 0.26
Step-by-step explanation:
As per given , we have
P(green tail) = 0.36
P(red fins) = 0.59
P(both a green tail and red fins ) = 0.21
Now, P(Neither red fin nor green tail )= 1 - P(either red fin or green tail )
[P(neither A nor B)= 1- P(either A or B)]
= 1-(P(green tail) +P(red fins)+P(both a green tail and red fins ))
[P(A or B)= P(A)+P(B)-P(A and B)]
= 1- (0.36+0.59-0.21)
= 1-(0.74)
= 0.26
Hence, the probability that the selected fish will not have a red fin or a green tail = 0.26
