Which equation is equivalent to
1
3
= 27X+22
O 3*-3-3x+2
O 3* = 33x+6
O 3-* - 33x+2
O 3-* = 33x+6

Answer:

The required length of AB is 7.28 units.

Answer:

$5,340

Step-by-step explanation:

Given :

Making a probability distribution :

X : ___12000 ____0 _____-6200

P(X) __ 0.6 _____ 0.1 _____ 0.3

Tge expected value of the purchase si equal to the expected value or average, E(X) :

E(X) = ΣX*p(X)

E(X) = (12000 * 0.6) + (0 * 0.1) + (-6200 * 0.3)

E(X) = 7200 + 0 - 1860

E(X) = $5,340

Answer:

The right answer is the 2nd one

hope it will help :)

The given sum is option B. 2xy√y + 2xy²√x.

Expressions are mathematical statements which consist of two or more terms and terms are connected to each other using mathematical operators like addition, multiplication, subtraction and so on.

Given expression of sum is,

√(x²y³) + 2√(x³y⁴) + xy √y

We have to find the sum.

√(x²y³) = √x² √y³ = x√y³ = x√(y²)√y = xy√y

Now,

2√(x³y⁴) = 2[√x² √x √(y²)²] = 2x√x y² = 2xy²√x

Substituting these,

√(x²y³) + 2√(x³y⁴) + xy √y = xy√y + 2xy²√x + xy √y

                                          = 2xy√y + 2xy²√x

Hence the equivalent sum is 2xy√y + 2xy²√x.

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Answer:

   10·2^-8 grams

Step-by-step explanation:

The each day, the initial amount for that day is multiplied by 1/2. After 8 days, the initial amount has been multiplied by (1/2)^8, where the exponent of 8 signifies that (1/2) is a factor 8 times in the product.

After n days, the quantity remaining is ...

  q(n) = 10·(1/2)^n = 10·2^(-n)

after 8 days the remaining amount is ...

  q(8) = 10·2^-8 . . . grams

No piece of information is supplied to choose from ; However, the requirements for the test statistic of the hypothesis in question is given below.

Answer:

Kindly check explanation

Step-by-step explanation:

The hypothesis in the question above which is to be tested is a one sample proportion test ;

The test statistic formula for a one sample proportion test is given as :

Test statistic = (Phat - P) / √[P(1 - P) / n] ;

Where;

Phat = sample proportion

P = population proportion

n = sample size

Sample proportion = x / n ;

Therefore, once the parameters (Sample proportion, population proportion and sample size are given) then obtaining the test statistic is possible.

[tex] \begin{cases} \\ \large\bf{\green{ \implies}} \tt \: - \: \frac{1}{2} \: m \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - \frac{1 \: m}{2} \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 9 \: \times \: 2 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 18 \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{ \cancel- 18}{ \cancel - 1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{18}{1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: 18 \: \\ \end{cases}[/tex]

Answer:

I don't knowledge bro sorry

Answer:

(a) You will get ten

Step-by-step explanation:

single cell = 3 min

30 min = ?

30 divided by 10 = 3

Have a good day!

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Answer:

  10

Step-by-step explanation:

The sum of terms of an arithmetic series is ...

  Sn = (2a +d(n -1))·n/2 = (2an +dn^2 -dn)/2

For the series with first term 2 and common difference 3, the sum is 155 for n terms, where ...

  155 = (3n^2 +n(2·2 -3))/2

Multiplying by 2, we have ...

  3n^2 +n -310 = 0 . . . . . arranged in standard form

Using the quadratic formula, the positive solution is ...

  n = (-1 +√(1 -4(3)(-310)))/(2(3)) = (-1 +√3721)/6 = (61 -1)/6 = 10

10 terms of the series will have a sum of 155.

Step-by-step explanation:

[tex]\displaystyle \ \Large \boldsymbol{} S_n=\frac{2a_1+d(n-1)}{2} \cdot n =155 \\\\ \frac{4+3(n-1)}{2} \cdot n =155 \\\\\\ 4n+3n^2-3n=310 \\\\ 3n^2+n-310=0 \\\\D=1+3720=3721=61^2\\\\n_1=\frac{61-1}{6} =\boxed{10} \\\\\\n_2=\frac{-61-1}{3} \ \ \o[/tex]

Step-by-step explanation:

ccxiddidificifificici i i ivi i i i i i i i iivvii iix9difi

Answer:

Because it is not an equation.

Step-by-step explanation:

[tex] log(x) \times log(2) \\ = log(x + 2) [/tex]

x = 4

Every step shown. Once you become used to doing this you will almost be able to do the basic one's in your head without writing much down.

Explanation:

Let the unknown value be  

x

Converting the words into numbers:

First part: "15 times a certain number"  → 15 x

Second part: "plus 5 times the same number" → 15 x + 5 x

The last part: " is 80" ->  15x + 5 x = 80

We are counting  x ' s . 15 of them plus another 5 of them gives a total of 20.

So 15 x + 5 x = 20 x = 80

Divide both sides by 20

20 x ÷ 20 = 80÷ 20

20/20x=80/20

x=4

Let the number be x

ATQ

[tex]\\ \sf\longmapsto 15x+5x=80[/tex]

[tex]\\ \sf\longmapsto (15+5)x=80[/tex]

[tex]\\ \sf\longmapsto 20x=80[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{80}{20}[/tex]

[tex]\\ \sf\longmapsto x=4[/tex]

Answer:

-3x + 5

Step-by-step explanation:

like terms are the ones that have x and the ones that don't.

hope this makes sense

Answer:

-3x + 5

Step-by-step explanation:

2x - 3 - 5x + 8 can also be written as 2x - 5x - 3 + 8

→ Using the rewritten method collect the x terms

-3x - 3 + 8

→ Now collect the integers

-3x + 5

Answer:

1 kilometer in 1 hour

Step-by-step explanation:

unit rate is km(kilometer) per hour(hr)

1/3 km = 1/3 hr

multiply both sides by 3

1 km in 1 hour

Answer:

x=-17/5

Step-by-step explanation:

–5(–2x – 5) – 2 – 1= -12

+10x+25-2-1=-12

10x+22=-12

10x=-12-22

10x=-34

x=-34/10

x=-17/5

Step-by-step explanation:

Open the brackets

10x +25 -2 - 1= -12

Collect the like terms

10x = -12-25+2+1

10x = -34

Divide both sides by 10

Therefore,x = -34/10 = -3.4

Answer:

6/15.

14/42.

Step-by-step explanation:

2/5 = 6/x

Cross multiply:

2x = 5*6

x = 15

Similarly:

10/30 = 14/x

10x = 30*14

x = 420/10

x = 42.

Answer:

f(7)=109

Step-by-step explanation:

Since f(a)=7 then you just imput 7 on each x like this f(7)=8+13(7)+10= 109

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Answer:

  (f•g)(x) = -16x^3 +10x^2 -14x

Step-by-step explanation:

  (f•g)(x) = f(x)•g(x) = (-2x)(8x^2 -5x +7)

Use the distributive property:

  (f•g)(x) = -16x^3 +10x^2 -14x

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Answer:

Step-by-step explanation:

Let x represent the amount invested at 9%. Then the difference in interest amounts is ...

  (9%)x -(5%)(26876 -x) = 720.78 . . . . . assuming a 1-year investment

  0.14x -1343.80 = 720.78 . . . . . . . . . simplify

  0.14x = 2064.58 . . . . . . . . . . . . . . add 1343.80

  x = 14,747 . . . . . . . . . . . . . . . . divide by 0.14

$14,747 is invested at 9%; $12,129 is invested at 5%.

Answer:

$11.25

Step-by-step explanation:

Total money given to the taxi driver=36+25% of 36=45

Each person will pay (45/4)=11.25

Answer:

Step-by-step explanation:

189² = 215² + 123² - 2(215)(123)cos x°

35,721 = 46,225 + 15,129 - 52,890 cos x°

35,721 = 61,354 - 52,890 cos x°

52,890 (cos x° ) = 25,633

cos x° = 25,633 ÷ 52,890 ≈ 0.4846

x° ≈ 61.01°

Answer:

Its the 3 one

Step-by-step explanation:

Option C

Customers will think she is very busy

A messy desk indicates that the person is very busy.

Must click thanks and mark brainliest

Answer:

–81

Step-by-step explanation:

Step-by-step explanation:

hi

what is your question?

Step-by-step explanation:

please tell full questions

Answer:

option A

Step-by-step explanation:

wx and zy making 90 angle with each other therefore they are perpendicular.

wx and ab making 0 angle with each other therefore they are parallel

First, write out the equation in slope intercept form.

-3y= -2x+6

y= 2/3x -2

The slope of the equation is 2/3, m.

Substitute the slope and coordinate into y=mx+b. Since it’s parallel, the slope remains the same.

6= 2/3(2)+b

6= 4/3+b

14/3=b

y= 2/3x + 14/3

Answer:

D. 11

Step-by-step explanation:

First apply the secant-secant theorem to find the value of x.

Thus,

VU(TU + VU) = VW(BW + VW) (secant-secant theorem)

Substitute

(7)(x + 4 + 7) = (9)(-2 + x + 9)

7(x + 11) = 9(7 + x)

7x + 77 = 63 + 9x

Collect like terms

7x - 9x = 63 - 77

-2x = -14

Divide both sides by -2

x = 7

✔️Find TU

TU = x + 4

Substitute get value of x

TU = 7 + 4 = 11

Answer:

11

Step-by-step explanation:

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Answer:

  A.  96

Step-by-step explanation:

The surface area is the sum of the areas of the two triangular bases and the areas of the three rectangular lateral faces.

  A = 2(1/2)bh + PH

where b is the base of the triangle, h is its height, P is the perimeter of the triangle, and H is the height of the prism.

  A = (3 cm)(4 cm) +(3 +4 +5 cm)(7 cm) = 12 cm² +84 cm²

  A = 96 cm²

The surface area of the triangular prism is 96 square cm.

Hence the area of the second rhombus is 45 square meters

The area of a rhombus is expressed as

A = base * height

For the rhombus with an area of 5 square meters and a side length of 3 meters

Height = Area/length

Height = 5/3 metres

Since the length of a similar rhombus is 9meters, the scale factor will be expressed as;

k = ratio of the lengths = 9/3

k = 3

Height of the second rhombus = 3 * height of the first rhombus

Height of the second rhombus = 3 * 5/3

Height of the second rhombus = 5 meters

Area of the second rhombus = length * height

Area of the second rhombus = 5 * 9

Area of the second rhombus = 45 square meters

Hence the area of the second rhombus is 45 square meters

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The correct option is option B;

(B) 45 square meters

The known parameters in the question are;

The area of the rhombus, A₁ = 5 m²

The length of one of the sides of the rhombus, a = 3 m

The length of a side in a similar rhombus, b = 9 m

The unknown parameter;

The area of the second rhombus

Strategy or method;

We have that two shapes are similar if their corresponding sides are proportional

From the above statement we get that the ratio of the areas of the two shapes is equal to the square of the ratio of the lengths of the corresponding sides of the two shapes of follows;

[tex]\begin{array}{ccc}Length \ Ratio&&Area \ Ratio\\\dfrac{a}{b} &&\left (\dfrac{a}{b} \right)^2 \\&&\end{array}[/tex]

Let the area of the second rhombus be A₂, we get;

[tex]Area \ ratio = \dfrac{A_1}{A_2} = \left( \dfrac{a}{b} \right)^2[/tex]

Where;

a = 3 m, b = 9 m, and A₁ = 5 m², we get;

[tex]Area \ ratio = \dfrac{5 \ m^2}{A_2} = \left( \dfrac{3 \, m}{9 \, m} \right)^2 = \dfrac{1}{9}[/tex]

Therefore;

9 × 5 m² = A₂ × 1

A₂ = 45 m²

The area of the second rhombus, A₂ = 5 m².

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