Which algebraic expression is equivalent to this expression?
6(22 - 12) + 63
Help me please!!

Answer:

x = 4, -6

Step-by-step explanation:

x = 4, -6

Answer:

Part A: f(x) = 1.50x/g(x) = 0.01(3)^x-1

Part B: Option A:  $9 

Part C: Option B:  $1,771.47

Part D: The eighth bushel picked is when the exponential function exceeds the linear function.

Step-by-step explanation:

Part A: Write a function to model each option.

Option A:  f(x) = 1.50x, where x is the number of bushels of apples picked

Option B: g(x) = 0.01(3)^x-1, where x is the number of bushels of apples picked.

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Part B: If Rachel picks six bushels of apples, which option should she choose?  

Option A:  $9    Option B:  $2.43   

Option A is better since what the number is would be higher.

1.50x6 = 9. If I were to do the same for option b, option a would end up higher.

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Part C: If Rachel picks twelve bushels of apples, which option should she choose?  

Option A:  $18 Option B:  $1,771.47

After calculating both of them by multiplying by 12 for each, option B ends up to be much better.

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Part D: How many bushels of apples does Lucy pick to make option B better for her than option A?

The eighth bushel picked is when the exponential function exceeds the linear function.

Answer:

no its not since some dots are above each other and fail the vertical line test

Hope This Helps!!!

Answer:

no the x value repeat

Step-by-step explanation:

Answer:

82.5 miles in 1 1/2 hours

Step-by-step explanation:

Using the information the question gives us we can find the appropriate answer to this question by dividing the miles per hour by two, and then add that number to the additional miles per hour.

55 miles = one hour

2 hours = 110 miles

1 1/2 hours = 55 ÷ 2 = 27.5

55 + 27.5 = 82.5 miles

82.5 miles

Hope this helps

Answer:

70.2

Step-by-step explanation:

28.08 / 0.4 = 70.2

Answer:

How to factor out a polynomial with a 3rd degree-• well here is a For example, let G(x) = 7x³ – 125. Then factoring this third degree polynomial relieve on a differences of cubes as follows: (2x – 5) (4x² + 20x + 25), where ²x is the cube-root of 8x³ and 5 is the cube-root of 1256

Answer:

long division is probably the simplest method of finding out the factors

Step-by-step explanation:

For example,  let G(x) = 8x³ – 125. Then factoring this third degree polynomial relies on a difference of cubes as follows: (2x – 5) (4x² + 10x + 25), where 2x is the cube-root of 8x³ and 5 is the cube-root of 125. Because 4x² + 10x + 25 is prime, you are done factoring.

Answer:

2, -6

Step-by-step explanation:

x^2 + 4x - 12

A = 1

B = 4

C = -12

i used the "X" method to solve for the solutions. i think it's easier than using the quadratic formula but it doesn't always work

for the "X" method you have to multiply your A value and your C value together so 1 x (-12) = -12. that is going to be the top part of the X

the bottom part of the x will be your B value which is 4

we have to find multiples of -12 that will also add to 4

so -2 and 6 multiply to -12 but also add to 4 so we know these numbers will work

i added added two drawings to show how i found the solutions using the "X" method and the quadratic formula

Answer:

6 dollars and 4 cents

Step-by-step explanation:

if there is any doubt leave a comment

Step-by-step explanation:

figure B is a scaled copy of figure B

by scale factor : 1/2

Step-by-step explanation:

We need to break up the given expression into two separate fractions so that when they are added together, we will get the original expression.

Note that the denominator is made up of two factors, [tex](2x - 1)[/tex] and [tex](x^2 + 1).[/tex] But note that the 2nd factor is a 2nd order polynomial so as a rule, the numerator of the fraction containing this factor must be an (n - 1)-order polynomial, where n is the order. With that in mind, we can write the general form of the partial fractions as follows:

[tex]\dfrac{x + 7}{(2x - 1)(x^2 + 1)} = \dfrac{Ax + B}{x^2 + 1} + \dfrac{C}{2x - 1}[/tex]

[tex]\:\:\:\:=\dfrac{2Ax^2 + Bx - Ax - B + Cx^2 + C}{(2x - 1)(x^2 + 1)}[/tex]

Here, we combined the two fractions to form the equation above. Next, we compare the numerators on either side. Note that we satisfy the equality if we impose the following conditions:

[tex]2A + C = 0\:\:\:\:\:\:\:\:\:\:\:\:\:\:(1)[/tex]

[tex]2B - \:A = 1\:\:\:\:\:\:\:\:\:\:\:\:\:\:(2)[/tex]

[tex]-B + C = 7\:\:\:\:\:\:\:\:\:\:\:\:\:\:(3)[/tex]

To find the values of the constants A, B and C, we need to solve this system of equations. We start by multiplying Eqn(3) by 2 and then adding it to Eqn(2) to get

[tex]-A + 2C = 15\:\:\:\:\:\:\:\:\:\:\:\:\:\:(4)[/tex]

Then, multiply Eqn(1) by -2 to get

[tex]-4A - 2C = 0\:\:\:\:\:\:\:\:\:\:\:\:\:\:(5)[/tex]

Add Eqn(4) to Eqn(5) and we will get

[tex]-5A = 15 \Rightarrow A = -3[/tex]

Now that we know the value of A, we can use this in Eqn(2) to get

[tex]2B - (-3) = 1 \Rightarrow B = -1[/tex]

Next, to solve for C, we use the value of A in Eqn(1) to get

[tex]2(-3) + C = 0 \Rightarrow C = 6[/tex]

Therefore, the given expression can be written as

[tex]\dfrac{x + 7}{(2x - 1)(x^2 + 1)} = \dfrac{6}{2x - 1} + \left(\dfrac{-3x - 1}{x^2 + 1}\right)[/tex]

As a check, let's combine the two fractions together:

[tex]\dfrac{x + 7}{(2x - 1)(x^2 + 1)} = \dfrac{6}{2x - 1} + \left(\dfrac{-3x - 1}{x^2 + 1}\right)[/tex]

[tex]= \dfrac{6x^2 + 6 - 6x^2 - 2x + 3x + 1}{(2x - 1)(x^2 + 1)}[/tex]

[tex]= \dfrac{x + 7}{(2x - 1)(x^2 + 1)}[/tex]

As expected, we got the original expression.

Answer:

[tex]\huge\boxed{C)\ -\dfrac{1}{5}}[/tex]

Step-by-step explanation:

The reciprocal of 5: [tex]\dfrac{1}{5}[/tex]

The negative reciprocal of 5: [tex]-\dfrac{1}{5}[/tex]

Answer:

No, it is not a linear function, rather a rational function

Step-by-step explanation:

Because the term on the left-hand side contains both x and y, then neither variable varies directly with the other, hence, it's a rational function:

2yx=4

yx=2

y=2/x

Answer:

8.7

Step-by-step explanation:

8.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.7

Answer:

we need 6 cups of cranberry juice for 12 gallons of punch

Answer:

8/64 = 0.125 = 12.5%

Step-by-step explanation:

8/64 = 0.125 = 12.5%

Answer:

x2 the left side and x3 the right side of the equation

Answer:

X = -2

First you cross multiply, and then you expand to get 15x+6

after that its basic algebra with adding/subtracting from each side, simplifying, and then divide both sides by -13.

Answer:

ayo i think is ufo trying to communicate hey alien we come in peace

Step-by-step explanation:

[tex]\cos \theta(\tan \theta + \cot \theta)\\\\=\cos \theta \tan \theta + \cos \theta \cot \theta \\\\=\cos \theta \left (\dfrac{\sin \theta}{\cos \theta} \right)+ \cos \theta \left(\dfrac{\cos \theta}{\sin \theta} \right)\\\\\\=\sin \theta + \dfrac{\cos^2 \theta}{\sin \theta}\\\\=\dfrac{\sin^2 \theta + \cos^2 \theta}{\sin \theta}\\\\=\dfrac 1{\sin \theta}\\\\=\csc \theta[/tex]

Answer:

y = 8x + 12

Step-by-step explanation:

y = (2x + 3)4

Distribute the 4 to the 2x  and 3

y = 8x + 12

^ Expanded form

Answer:

58%

Step-by-step explanation:

Answer:

3000

Step-by-step explanation:

Answer:

300

Step-by-3step explanation:

Enter a problem...

Calculus Examples

Popular Problems Calculus Find the Domain and Range f(x)=5x-3

f

(

x

)

=

5

x

−

3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

x

|

x

∈

R

}

The range is the set of all valid

y

values. Use the graph to find the range.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

y

|

y

∈

R

}

Determine the domain and range.

Domain:

(

−

∞

,

∞

)

,

{

x

|

x

∈

R

}

Range:

(

−

∞

,

∞

)

,

{

y

|

y

∈

R

}

Answer:

if its me then i will bye the store. but the answer is 50%

Step-by-step explanation:

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$2000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ t=years\dotfill &4 \end{cases} \\\\\\ A=2000e^{0.08\cdot 4}\implies A=2000e^{0.32}\implies \boxed{A\approx 2754.26}[/tex]

Answer:

p ≥ 1,000,000,000

Step-by-step explanation:

since it says "at-least" that is implying that, that is the estimate and there is most likely more people and it is not exactly 1,000,000,000 so we need to use ≥ to show that it could be greater than or equal to 1,000,000,000.

Answer:

Step-by-step explanation:

a) The height of the springboard above the water should be h(0) : Read, the height at t = 0

h(0) = -5(0) + 10(0) + 3

h(0) = 0 + 0 + 3

h(0) = 3

a) 3 meters

b)  The time it takes the diver to hit water should be, the positive 0 solution for t.  Remember, in a quadratic equation,  there are two values for t where a parabola crosses the horizontal axis, which in this case would be t.  Just by looking at the function, h(t) = -5t2 + 10t + 3 , one should be able to see that it cannot be factored easily, so it requires the Quadratic Formula to find the zeros ; x = -b ±√(b2-4ac)  / 2a

Substitute t for x, and use the coefficients for a, b, c:

t  =  (-10 ± √((102 - 4(-5)(3)))/2(-5)

t = (-10 ±√(100 + 60))/-10

t = (-10 ±√160)/-10) ; Now factor the 160 to simplify:

t = (-10 ±√(10*16))/-10

t = (-10 ±4√10)/-10 ; Factor out leading coefficient of -2 from the numerator:

t = -2(5 ± 2√10)/-10

t = (5 ± 2√10)/5

Using a calculator to find the zeros, and disregarding the negative zero (because t starts at 0):

t ≈ 2.265

b) approx. 2.265 seconds for diver to hit water.

c) To find this, set the function equal to 3 to find what other value for t would be equal to 3 (we know one is 0).

-5tt + 10t + 3 = 3

-5t2 + 10t = 0 ; factor out t

t(-5t + 10) = 0

We know t = 0:

We also know that -5t + 10 = 0

-5t = -10

t = 2

c) 2 seconds. This is the time that diver would equal height of t=0 which is where he started, and where he equals the height of the springboard.

d and e) The peak of the dive (parabola), is determined using the formula h = -b/2a (Derived from the Quadratic Formula) to find the y value (in this case, the h value, answering e) and then using that result in the function to find the x value (in this case, the t value answering d) of the point where the parabola (dive path) reaches a maximum(height), or minimum(in upward opening parabolas).

h = -10/2(-5)

h = -10/-10

h = 1

h(1) = -5(1)2 + 10(1) + 3

h(1) = -5 + 10 + 3

h(1) = 8

d) At t = 1 second, diver will have reached peak of dive.

e) At t = 1 second, diver will have reached a maximum height of 8 meters.

Answer:

D) The number that is 5 to the right of -6 on the number line

Hope this helps :)

Answer:

Step-by-step explanation:

2/3 - 1/2 ?=?

4/6 - 3/6 = 1/6 ft more

Answer:

(1+y)^(3/2)-3(1+y)^(1/2)=(1+x)^(3/2)-3(1+x)^(1/2)+c

Step-by-step explanation:

This is separable.

Multiply x dx on both sides and divide both sides by (1+y)^(1/2) to obtain:

y/(1+y)^(1/2)=(1+x)^(-1/2) x dx

Using law of exponents to get rid of negative exponent by finding reciprocal:

y/(1+y)^(1/2)=x/(1+x)^(1/2) dx

Let u=(1+y)^(1/2).

Then u^2=1+y.

Differentiate: 2 u du=dy

[Let v=(1+x)^(1/2).]

Plug in our substitution:

(u^2-1) 2u du/u=(v^2-1) 2v dv/v

Simplify:

(u^2-1) 2 du=(v^2-1) 2 dv

Integrate both sides:

(u^3/3-u) 2+L=(v^3/3-v) 2+K

Divide both sides by 2:

u^3/3-u +L/2=v^3/3-v+K/2

K/2-L/2 is just a constant value C:

u^3/3-u=v^3/3-v+C

Use substitution again to put back in terms of x and y:

((1+y)^(1/2))^3/3-(1+y)^(1/2)=((1+x)^(1/2))^3/3-(1+x)^(1/2)+C

Simplify the exponent part a bit:

(1+y)^(3/2)/3-(1+y)^(1/2)=(1+x)^(3/2)/3-(1+x)^(1/2)+C

I don't like the division by 3 so multiply both sides by 3:

(1+y)^(3/2)-3(1+y)^(1/2)=(1+x)^(3/2)-3(1+x)^(1/2)+3C

3C is still just an unknown constant, c.

(1+y)^(3/2)-3(1+y)^(1/2)=(1+x)^(3/2)-3(1+x)^(1/2)+c