Explanation:
the small intestine absorbs most of the nutrients in your food, and your circulatory system passes them on to other parts of your body to store or use. Special cells help absorbed nutrients cross the intestinal lining into your bloodstream.
Calculate the electric potential at point A, the middle of the rectangle, and at point B, the middle of the right-hand side of the rectangle. How would you find the electric potential?
Answer:
With the help of formula.
Explanation:
We can calculate the electric potential of any point through the formula of electric potential which is given below.
Electric potential = Coulomb constant x charge/ distance of separation.
Symbolically it can be written as, V = k q/ r where
V = electric potential
k = Coulomb constant
q = charge
r = distance of separation
If we have all these data, we can simply put the data in the formula and we will get the value of electric potential.
Which of the following describes a mixture?( 2 A combination of two or more substances O A combination of two sources of energy An object made of the same substance A substance that is made up of matter
Answer:
A combination of two or more substances.
A 4.04 kg block slides down a smooth, frictionless plane having an inclination of 30◦. The acceleration of gravity is 9.8 m/s^2. The acceleration of the plane is 4.9
What is the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline?
Answer in units of N.
Answer:
Explanation:
What a lot of words to solve such a simple problem! The perpendicular force is the one that is pushing straight down on the plane. There is no side to side movement here or friction acting on this dimension at all. Perpendicular force is the same as the weight of the block. That's it! Perpendicular force is also normal force which is the same thing as weight:
w = mg so
w = (4.04)(9.8) and
w = 4.0 × 10¹ N
The magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
The given parameter are:
mass M = 4.04 kg
Angle of inclination = 30 degree
Acceleration due to gravity = 9.8 m/s^s
To calculate the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the plane, The force will be the weight of the block which is equal to the normal reaction.
Normal N = mgcosФ
N = 4.04 x 9.8 x cos30
N = 34.28 Newtons
At all point in the plane, the magnitude of the perpendicular force that the block exerts on the surface of the plane will be the same.
Therefore, the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
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In Einstein’s analysis, a photon striking the surface of a conductor is absorbed by an electron. Which statement describes the set of energy transfers that could occur?
A. the electron receives either all or none of the photon's energy
B. The electron may receive any fraction of the photon's energy, including all or none of it
C. The electron may receive only certain quantized amounts of the photon's energy, including all or none of it
Answer:
the correct answer is A
Explanation:
In an Einstein-type analysis, the photon is absorbed, it loses all its energy, therefore the electron must receive all or none of the energy of the incident photon. In a type of inelastic shock.
Let's analyze the different answers
A) true. In photon it is completely absorbed or passes without interaction
B) False. The photon must change energy, but in this case there is no absorption of the photon
C) False. In the insistent analyzes, the quantization of the electron in discrete states is not mentioned.
Therefore the correct answer is A
In the Vector Addition Lab, the following data was collected for determining the displacement from the door of the Physics classroom to another location in the building: 2 m, West; 14.0 m, South; 25.0 m, East; 11.0 m, North; and 2 m, West. The magnitude of the resultant displacement from the physics classroom to the assigned location is closest to ___ meters. (Round to the nearest integer.)
Answer:
21 m
Explanation:
Since the displacement from the door is 2 m West, we have our vector as -2i. The vector representing 14.0 m South is -14.0j. The vector representing 25.0 m East is 25.0i. The vector representing 11.0 m North is 11.0j. And, the vector representing 2.0 m West is -2.0i.
So, to get our position vector at the other location, we add all the vectors together.
So, r = -2i + (-14.0j) + 25.0i + 11.0j - 2i
= -4i + 25.0i - 14.0j + 11.0j
= 21.0i -3j m
Now, if we assume the position vector for the door is at the origin, we have r₀ = 0i + 0j m
So, our displacement from the door is r - r₀ = 21.0i - 3.0j - (0i + 0j) = 21.0i - 3.0j
So, the magnitude of the resultant displacement |r - r₀| = √(21.0² + 3.0²)
= 3.0√(7.0² + 1)
= 3.0√(49 + 1)
= 3.0√50
= 3.0 × 7.0711
= 21.2
≅ 21 m to the nearest integer
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick
Types of energy transformation
Answer:
This is the types of energy transformation
Explanation:
hope it helps
if a car is taken from the garage driven for 100km before returning to the garage after 2 hours what is it average speed?
Answer:
50km/h
Explanation:
Average Speed = Distance/Time
100km/2h = 50km/h
If a rod attached to the approaching charge if the rod consists of "stiff" spring-like bonds for which atoms undergo small oscillations. What can we say, about these springlike bonds when the charge is first, furthest away and second, closest to the source charge
Answer: hello options related to your question is missing attached below is the missing part of your question
answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )
Explanation:
When the Charge is first, Furthest away and second and closest to the source charge. The spring like bonds can be said to have No charge of the length of the bonds expected because the rod did not touch the charge source when Furthest away the bond with charge will be less effective
hhhhhhhhhhhhhhhheeeeeeeeeeeeeeeeeeeeellllllllllllllllllllllllllllllllllpppppppppppp
Answer:
I'm pretty sure the answer is broken
Explanation:
What state of matter did the earth need to be in order for planetary differentiation to occur?
Answer: Gas, liquid, or solid?
I just... I don't know man I suck at physics :(
A tour guide shouts across a canyon. At a temperature of 20 °C, her echo is heard 2.00 s later. How wide is the canyon?
The answer is 340 m I just don't know how to get that....
Explanation:
Sound travels from the tour guide to the other of the canyon and then back, thus hearing the echo. The time of 2.0 s represents the time it takes the sound to make a round trip, therefore it takes 1.0 s for the tour guide's voice to reach the other side of the canyon. At 20°C, the speed of sound is 343 m/s therefore the width of the canyon is
[tex]x = vt = (343\:m/s)(1.0\:s) = 343\:m[/tex]
The canyon in the given question is 340 m wide.
What is echo?Echo is a reflection of sound that comes to the listener after the direct sound, but with a delay. The delay is inversely proportional to the separation between the source and the listener of the reflecting surface.
To hear the echo, the following conditions must be met:
There must be a minimum of 17 meters between the sound source and the reflecting surface, and there must be at least 0.1 seconds between the original sound and its echo.
Given parameters:
When a tour guide shouts across a canyon, her echo is heard 2.00 s later. That means, in two seconds the sound goes to other wall of canyon and reflected back.
At a temperature of 20 °C, velocity of sound is 340 m/s.
So, the wide is the canyon be = velocity of sound × time/2
= 340 m/s ×2 s/2s = 340 m.
Hence, the wide is the canyon be 340 m.
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Derive the relation between wavelength, frequency and speed of sound.
Explanation:
sorry I need some points foe this
HELP ME ILL MARK U THE BRAINLIEST
Another box of weight 1500 N is raised vertically by 3.0 m
calculate the work done on the box
Answer:
[tex]workdone = force \times distance \\ = 1500 \times 3 \\ = 4500 \: joules[/tex]
Answer:
4,500J
Explanation:
Work done = force × distance
1500N × 3m = 4,500 Joules
A cubic box has a 0.8 meter side. Find the volume of air in the box in cubic meter?
Answer:
[tex]V=0.512\ m^3[/tex]
Explanation:
Given that,
The side of a cubic box, s = 0.8 m
We need to find the volume of air in the box.
We know that,
The volume of a cube is given by :
[tex]V=s^3[/tex]
So,
[tex]V=0.8^3\\\\V=0.8\times 0.8\times 0.8\\\\=0.512\ m^3[/tex]
So, the volume of air in the box is [tex]0.512\ m^3[/tex].
how can you account for the differences in the entropies of combination of methyl propane (-1465J/mol K) and butane (1465J/mol K)
Explanation:
The change in entropy is a measure of temperature. When the temperature of a compound or a system increases, there will be more randomness in the system.
The boiling point is directly related to the number of carbon atoms but is indirectly proportional to the branching in a hydrocarbon.
Butane and methyl propane, both have 4 carbon atoms.
But, butane has 4 carbon atoms in a straight chain while methyl propane has 3 carbon atoms in a straight chain and 1 methyl substituent which makes it a branched hydrocarbon.
Thus, the boiling point of methyl propane will be less than the butane. Likewise, the pattern in entropies will be seen.
A 75kg hockey player is skating across the ice at a speed of 6.0m/s. What is the magnitude of the average force required to stop the player in 0.65s?
Answer:
692.31 N
Explanation:
Applying,
F = ma............... Equation 1
Where F = Average force required to stop the player, m = mass of the player, a = acceleration of the player
But,
a = (v-u)/t............ Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............ Equation 3
From the question,
Given: m = 75 kg, u = 6.0 m/s, v = 0 m/s (to stop), t = 0.65 s
Substitute these values into equation 3
F = 75(0-6)/0.65
F = -692.31 N
Hence the average force required to stop the player is 692.31 N
A 15.0 kg crate, initially at rest, slides down a ramp 2.0 m long and inclined at an angle of 20.0° with the horizontal. Using the work-kinetic energy theorem and disregarding friction, find the
velocity of the crate at the bottom of the ramp. (g = 9.81 m/s?)
The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of
F = mg sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N
Then the work done by this force on the crate as it slides down the ramp is
W = F d = (50.3 N) (2.0 m) ≈ 101 J
The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so
W = K = 1/2 mv ^2
Solve for v :
v = √(2W/m) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s
Calcalculate potential energy given to a potato sack having a mass of 2 kg as I raise it to a height of 450 CM
Answer:
8.829 Joules
Explanation:
The potential energy of an object, is the energy it posses (the energy stored within the object) by virtue of its relative elevation or height, position, state, or arrangement
The potential energy of an object raised to a given height, P.E. = m·g·h
Where;
m = The mass of the object
g = The acceleration due to gravity, a constant ≈ 9.81 m/s²
h = The present height of the object
For the potato sack having a mass, m = 2 kg, and raised to a height, h = 450 cm = 0.45 m, we have;
The potential energy given to the potato sack, by raising its height, P.E. is given as follows;
P.E. = 2 kg × 9.81 m/s² × 0.45 m = 8.829 Joules
The potential energy given to the potato sack, P.E. = 8.829 Joules
Q1. What is the mass of a ball that has a kinetic energy of16 J and it is traveling at 4 m/s?
Q2. What is the kinetic energy of a soccer ball which has a mass of 1 kg and is kicked with a velocity of 10 m/s?
Q3.exercise ball is on a table 2 m above the ground. What is the mass of the ball if it has a GPE of 40 ?
Q4.What is the gravitational potential energy (GPE) of a 2 kilogram book that is 20 meter above the ground?
Answer:
Explanation:
Kinetic Energy has a formula of
[tex]KE=\frac{1}{2}mv^2[/tex] and
Potential Energy has a formula of
PE = mgh. The first 2 problems use the KE formula and the next 2 use the PE formula.
Q1. KE = 16 and v = 4 m/s:
[tex]16=\frac{1}{2}m(4)^2[/tex] and
[tex]\frac{2(16)}{16}=m[/tex] so
m = 2 kg
Q2. mass = 1 kg and v = 10 m/s:
[tex]KE=\frac{1}{2}(1)(10)^2[/tex] so
KE = 50 J
Q3. PE = 40, h = 2, g = 9.8:
40 = m(9.8)(2) and
[tex]\frac{40}{(9.8)(2)}=m[/tex] so
m = 2.0 kg
Q4. mass = 2 kg, g = 9.8 m/s/s, h = 20:
PE = 2(9.8)(20) so
PE = 392 J
**I completely disregarded the rules for sig fig's because your numbers were very inexact**
The specific heat capacity of sea water is 4100 J/Kg°C and the boiling point of 100.6 °C. (i) Calculate the energy required to raise the temperature of 0.900 kg of this sea water from 10 °C up to its boiling point. Also mention the equation to be used. *
Answer:
334.314 (kJ)
Explanation:
1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.
2) according to the formula above:
Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).
Liana draws a diagram to show the direction of the electric force acting on a charged particle in a uniform electric field.
Which change would make the diagram correct?
A. Changing the charge to negative
B. Making the field lines point down
C. Changing the force to point right
D. Removing the force arrow
Answer:
changing the force to point right is the correct answer :)
The direction of the force acting on the field should be changed to point towards the right.
What is an electric field?An electric field is referred to as the region where the influence of charge is felt. Thus, the force acts in the direction of the electric field when the field is uniform.
Having said that, it follows that the direction of the force acting on the field should be changed to point towards the right.
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8. A 22 g bullet with a speed of 230 m/s is fired in to a tree and comes to rest 23 cm into
the tree
a) Find the work done by the tree to stop the bullet
b) Find the average force exerted by the tree
Answer:
kinetic energy of 16 J. Determine the velocity of the first toy, and the mass of the ... distance of 12 cm into the tree. ... b) the average force exerted on the bullet while slowing down to a stop.
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A car has a kinetic energy of 103kJ.
The speed of the car is 13.1 m/s.
Calculate the mass of the car.
Give your answer to 2 significant figures.
Answer: 1200kg
Explanation:
KE = (1/2)mv^2
103kJ = 103000J
103000J = (1/2) * m * (13.1m/s)^2
Solve for m
A car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
A car has a kinetic energy of 103 kJ. The speed of the car is 13.1 m/s,
The kinetic energy of the car = 1/2 × mass × velocity
103000 =0.5 × mass × (13.1) ²
The mass of the car = 1200 Kilogram
Thus, if a car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
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Define time period. Give its formula.
Answer:
Part A
Time period, designated by the symbol, 'T', is defines as the time it takes for a complete cycle of an oscillation or vibration (of a wave) to transit through a given point.
The longer the time period of a wave, the lower the frequency of the wave
The unit of the time period is seconds, 's'
Part B
Mathematically, the formula for the time period is presented as follows;
f = 1/T
∴ T = 1/f
f = v/λ
∴ T = λ/v
Where;
v = The velocity of the wave;
λ = The wavelength of the wave
Explanation:
A positively charged rod is brought close to a neutral metal sphere. Explain what
happens to the charges in the neutral sphere as the rod comes close, touches the
sphere, and then moves away. Is the metal sphere still neutral at the end of this
encounter?
Answer:
No, the metal sphere becomes positively charged because electrons are transferred from the sphere to the rod.
What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
please helpppp... thank u ❤️
Answer:
For Ryan:
[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]
For the football kicked:
[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]
Answer:
the highest point for the first question is 0 meters per second
the answer for question 2 is 45 degrees
Which variable is represented by the following symbol? λ
a. Wavelength
b. Amplitude
c. Frequency
d. Velocity
Answer:
A
Explanation:
Wavelength is represented by lambda
A test car and its driver, with a combined mass of 600 kg, are moving along a straight,horizontal track when a malfunction causes the tires to stop rotating. The car skids to a halt with constant acceleration, leaving skid marks on the road during the whole time it skids. Which two of the following measurements, taken together, would allow engineers to find the total mechanical energy dissipated during the skid?
A. The length of the skid marks
B. The contact area of each tire with the track.
C. The coefficent of static frction between the tires and the track.
D. The coefficent of static frction between the tires and the track.
Answer:
The two of the following measurements, when taken together, would allow engineers to find the total mechanical energy dissipated during the skid
B. The contact area of each tire with the track.
C. The co-efficent of static friction between the tires and the track.
D. The co-efficent of static friction between the tires and the track.
Explanation:
